Pearson Edexcel · GCSE · Physics

    Course version: 1PH0 · Version from Sept 2016

    Use the equation: force on a conductor at right angles to a magnetic field…

    Full specification wording

    Topic 12 – Magnetism and the motor effect: 12.13 Use the equation: force on a conductor at right angles to a magnetic field carrying a current (newton, N) = magnetic flux density (tesla, T or newton per ampere metre, N/A m) × current (ampere, A) × length (metre, m)

    The force on a straight conductor is largest when the conductor sits at right angles to the magnetic field, and it is then given by F = B × I × l.

    Checked against the Pearson Edexcel 1PH0 specification (opens in a new tab) on .

    • Point 13 of 13

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    The force on a straight conductor is largest when the conductor sits at right angles to the magnetic field, and it is then given by F = B × I × l. Here B is the magnetic flux density in tesla (T), equivalently newton per ampere metre (N/A m); I is the current in ampere (A); and l is the length of conductor inside the field in metre (m). Check the units: T × A × m gives N, because 1 T = 1 N/(A m). Worked example: a 0.20 m length of wire carries 3.0 A at right angles to a field of flux density 0.50 T, so F = 0.50 × 3.0 × 0.20 = 0.30 N. If the wire lies along the field, the force falls to zero, so the right-angle condition matters.

    What earns the marks

    • Selects the relationship force = magnetic flux density × current × length for a conductor at right angles to the field.
    • Substitutes values in consistent SI units of tesla, ampere and metre before multiplying.
    • Calculates the force in newton by multiplying flux density, current and length together.
    • Recognises that the force is greatest at right angles to the field and zero when the conductor lies along the field.
    • Converts a flux density given in newton per ampere metre to tesla using the equivalence 1 T = 1 N/(A m).

    Common mistakes and how to put them right

    • Adds the three quantities instead of multiplying them.

      Put it right: Multiply flux density, current and length to obtain the force.

    • Uses the length in centimetre without converting to metre.

      Put it right: Divide by 100 so the length is in metre before substituting.

    • Treats the force as independent of the angle between wire and field.

      Put it right: State that the full equation applies at right angles and the force is zero when the wire lies along the field.

    Exam tips

    • Write the equation first, then substitute numbers with their units so the newton result can be checked from T × A × m.
    • Convert every length to metre and every current to ampere before multiplying, and keep the flux density in tesla.
    • Read the stem for the phrase at right angles; if the wire is described as parallel to the field, the force is zero rather than B × I × l.

    Try the lesson

    The start of the Topic 12 – Magnetism and the motor effect: 12.13 Use the equation: force on a conductor at right angles to a magnetic field carrying a current (newton, N) = magnetic flux density (tesla, T or newton per ampere metre, N/A m) × current (ampere, A) × length (metre, m) lesson, made from checked teaching notes for this specification point.

    Have a go first

    A straight wire of length 0.50 m carries a current of 4.0 A at right angles to a magnetic field of flux density 0.20 T. Calculate the force on the wire.

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    Test your understanding of Topic 12 – Magnetism and the motor effect: 12.13 Use the equation: force on a conductor at right angles to a magnetic field carrying a current (newton, N) = magnetic flux density (tesla, T or newton per ampere metre, N/A m) × current (ampere, A) × length (metre, m)

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