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    Equilibria — Eduqas A-Level Chemistry

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    Equilibria explained

    This topic covers the quantitative treatment of chemical equilibria, focusing on the calculation and significance of equilibrium constants (Kp and Kc).

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    It also extends to acid-base equilibria, including the study of strong and weak acids/bases, pH calculations, buffer solutions, and the use of titration curves.

    What to demonstrate

    1. Effect of temperature on Kp and Kc for exothermic and endothermic reactions
    2. Calculation of Kp and Kc values and equilibrium quantities from given data
    3. Significance of the magnitude of an equilibrium constant regarding the position of equilibrium
    Show all 11 objectives
    1. Lowry-Bronsted theory of acids and bases
    2. Differences between strong and weak acids/bases using acid dissociation constant (Ka)
    3. Ionic product of water (Kw)
    4. Calculations involving pH, Kw, Ka, and pKa for strong and weak acids/bases
    5. Shapes of titration curves for various acid-base combinations
    6. Mode of action of buffer solutions and relevant calculations
    7. Hydrolysis of salts
    8. Selection of suitable indicators for acid-base titrations

    Equilibria exam tips

    Topic Overview

    Equilibria is a fundamental topic in A-Level Chemistry that explores the dynamic balance between forward and reverse reactions in a closed system. For WJEC A-Level students, this topic builds on kinetics and energetics, introducing the concept of reversible reactions that do not go to completion. Understanding equilibria is crucial for explaining industrial processes like the Haber process and Contact process, where yield optimisation is key. The topic also introduces Le Chatelier's principle and the equilibrium constant Kc, which quantifies the position of equilibrium.

    Equilibria matters because it bridges theoretical chemistry with real-world applications. In industry, controlling conditions such as temperature, pressure, and concentration allows chemists to maximise product yield while minimising costs and energy use. For example, in the Haber process for ammonia production, a compromise between rate and yield is struck using a moderate temperature and high pressure. This topic also lays the groundwork for acid-base equilibria and buffer solutions, which are essential in biological systems and analytical chemistry.

    Within the WJEC A-Level specification, equilibria is typically studied after kinetics and energetics, as it requires an understanding of reaction rates and enthalpy changes. Students will encounter both qualitative predictions using Le Chatelier's principle and quantitative calculations involving Kc. Mastery of this topic is essential for success in exams, as it frequently appears in multiple-choice, structured, and extended-response questions. It also forms the basis for more advanced topics like redox equilibria and electrochemical cells.

    Key Concepts
    • →Dynamic equilibrium: In a closed system, the rates of forward and reverse reactions are equal, and concentrations of reactants and products remain constant. This is a dynamic state, not static.
    • →Le Chatelier's principle: If a system at equilibrium is subjected to a change in concentration, temperature, or pressure, the equilibrium shifts to counteract the change. This predicts the effect of altering conditions.
    • →Equilibrium constant Kc: For a reaction aA + bB ⇌ cC + dD, Kc = [C]^c[D]^d / [A]^a[B]^b at a given temperature. Kc is constant at constant temperature and indicates the extent of reaction.
    • →Effect of temperature on Kc: For exothermic reactions, increasing temperature decreases Kc (equilibrium shifts left). For endothermic reactions, increasing temperature increases Kc (equilibrium shifts right).
    • →Heterogeneous equilibria: Pure solids and liquids are omitted from the Kc expression because their concentrations are constant. Only gases and aqueous species are included.
    Marking Points
    • Effect of temperature on Kp and Kc for exothermic and endothermic reactions
    • Calculation of Kp and Kc values and equilibrium quantities from given data
    • Significance of the magnitude of an equilibrium constant regarding the position of equilibrium
    • Lowry-Bronsted theory of acids and bases
    • Differences between strong and weak acids/bases using acid dissociation constant (Ka)
    • Ionic product of water (Kw)
    • Calculations involving pH, Kw, Ka, and pKa for strong and weak acids/bases
    • Shapes of titration curves for various acid-base combinations
    • Mode of action of buffer solutions and relevant calculations
    • Hydrolysis of salts
    • Selection of suitable indicators for acid-base titrations
    Examiner Tips
    • 💡Always check the stoichiometry of the balanced equation before writing the expression for Kc or Kp
    • 💡Ensure units are calculated correctly for every equilibrium constant expression
    • 💡Use a pH probe for titration practicals to obtain accurate data for curve plotting
    • 💡Practice converting between pH, [H+], Ka, and pKa fluently
    • 💡Remember that Kw is temperature dependent
    • 💡When using Le Chatelier's principle, always state the change, then the effect on the equilibrium position, and finally the effect on yield. For example: 'Increasing temperature favours the endothermic direction, so equilibrium shifts left, decreasing yield of product.'
    • 💡In Kc calculations, ensure you use equilibrium concentrations, not initial concentrations. Set up an ICE table (Initial, Change, Equilibrium) to track changes. Remember to check units: Kc has no units if the sum of coefficients is equal on both sides; otherwise, units are (mol dm^-3)^Δn.
    • 💡For heterogeneous equilibria, do not include solids or pure liquids in the Kc expression. This is a common error. For example, for CaCO3(s) ⇌ CaO(s) + CO2(g), Kc = [CO2].
    Common Mistakes
    • Incorrectly identifying the effect of temperature on the value of equilibrium constants
    • Confusing the units for Kp and Kc or failing to include them
    • Errors in logarithmic calculations for pH and pKa
    • Misinterpreting the magnitude of K as a direct measure of reaction rate
    • Failing to account for stoichiometry in equilibrium expressions
    • Incorrectly identifying the components of a buffer solution
    • Misconception: At equilibrium, the concentrations of reactants and products are equal. Correction: Equilibrium means the rates are equal, not the concentrations. The concentrations are constant but not necessarily equal.
    • Misconception: Adding a catalyst changes the position of equilibrium. Correction: A catalyst speeds up both forward and reverse reactions equally, so it does not shift the position of equilibrium; it only helps reach equilibrium faster.
    • Misconception: Changing pressure only affects equilibria involving gases. Correction: While pressure changes primarily affect gaseous equilibria, they can also affect equilibria involving liquids if the volume change is significant, but this is rare. For A-Level, focus on gases.
    Frequently Asked Questions
    What is the difference between a closed system and an open system in equilibria?
    A closed system is one where no matter can enter or leave, but energy can be exchanged with the surroundings. This is essential for equilibrium because if reactants or products could escape, the system would never reach a constant composition. In an open system, matter can be lost (e.g., gas escaping), so equilibrium cannot be established. For example, a sealed flask is a closed system, while an open beaker is an open system.
    How do I calculate Kc from equilibrium concentrations?
    First, write the balanced chemical equation. Then, write the expression for Kc: products over reactants, each raised to the power of its stoichiometric coefficient. Substitute the equilibrium concentrations (in mol dm^-3) into the expression. For example, for N2(g) + 3H2(g) ⇌ 2NH3(g), Kc = [NH3]^2 / ([N2][H2]^3). If the concentrations at equilibrium are [N2] = 0.5 M, [H2] = 1.0 M, [NH3] = 0.2 M, then Kc = (0.2)^2 / (0.5 × 1.0^3) = 0.04 / 0.5 = 0.08 (units: mol^-2 dm^6).
    Why does increasing temperature affect the equilibrium constant?
    The equilibrium constant Kc is temperature-dependent because it is related to the thermodynamic equilibrium constant, which depends on ΔG° = -RT ln K. For an exothermic reaction, increasing temperature adds heat, which the system counteracts by favouring the endothermic reverse reaction, thus decreasing Kc. For an endothermic reaction, increasing temperature favours the forward reaction, increasing Kc. This is consistent with Le Chatelier's principle.
    What is the effect of a catalyst on equilibrium?
    A catalyst speeds up both the forward and reverse reactions equally by providing an alternative pathway with lower activation energy. It does not change the position of equilibrium or the value of Kc. It only helps the system reach equilibrium faster. This is important in industrial processes to save time and energy without affecting yield.
    How do I know if a reaction is at equilibrium?
    A reaction is at equilibrium when the concentrations of reactants and products remain constant over time. This can be checked by measuring concentrations at intervals; if they stop changing, equilibrium is reached. Alternatively, you can calculate the reaction quotient Qc (using initial or current concentrations) and compare it to Kc. If Qc = Kc, the system is at equilibrium. If Qc < Kc, the forward reaction is favoured; if Qc > Kc, the reverse reaction is favoured.
    Why are solids and pure liquids omitted from the Kc expression?
    Solids and pure liquids have constant concentrations (their density is constant) and do not change during the reaction. Including them would not affect the value of Kc because their 'concentration' is effectively constant and incorporated into the equilibrium constant. For example, in the reaction CaCO3(s) ⇌ CaO(s) + CO2(g), the Kc expression is simply [CO2] because the solids' concentrations are constant.