Topic 11: Equilibrium II — Edexcel A-Level Chemistry
Test yourself on Topic 11: Equilibrium II with PEARSON EDEXCEL A-Level practice questions.
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Topic 11: Equilibrium II explained
This topic introduces the concept of oxidation numbers as a systematic method for classifying redox reactions, including disproportionation.
Read the full explanation
Students learn to define oxidation and reduction in terms of electron transfer and changes in oxidation number, and apply these principles to write and balance ionic half-equations.
What to demonstrate
- Correct calculation of oxidation numbers in compounds and ions, including peroxides and metal hydrides.
- Correct identification of oxidation and reduction based on electron transfer and oxidation number changes.
- Correct identification of oxidising and reducing agents.
Show all 6 objectives
- Correct identification of disproportionation reactions.
- Correct use of Roman numerals to indicate oxidation numbers.
- Correct construction of full ionic equations from ionic half-equations.
Topic 11: Equilibrium II exam tips
Quick Revision Summary (Key Takeaway)
Equilibrium II in Edexcel A-Level Chemistry covers the equilibrium constant Kc, the effect of changing conditions on equilibrium position, and the industrial applications of equilibrium principles, including the Haber and Contact processes. It builds on dynamic equilibrium concepts, introducing quantitative calculations and Le Chatelier's principle in real-world contexts.
Topic Overview
Equilibrium II extends the concept of dynamic equilibrium introduced in earlier topics, focusing on the quantitative treatment of equilibrium using the equilibrium constant, Kc. This topic is central to understanding how far reactions proceed and how conditions can be manipulated to maximise product yield in industrial processes. It is a key area for exam questions, often combining calculations with explanations of Le Chatelier's principle.
The topic begins with the derivation and use of the equilibrium constant expression for homogeneous reactions, including calculations of Kc from equilibrium concentrations and the reverse. It then explores the effect of changing concentration, pressure, and temperature on the position of equilibrium, and how these principles are applied in the Haber process and the Contact process. Understanding these concepts is crucial for success in A-Level Chemistry, as they are frequently assessed in both multiple-choice and extended response questions.
Moreover, Equilibrium II links to thermodynamics and kinetics, as the position of equilibrium is related to the Gibbs free energy change, and the rate of reaching equilibrium is governed by kinetics. This topic also has significant real-world relevance, as it underpins the optimisation of industrial chemical processes, making it a favourite for context-based exam questions.
Key Concepts
- →The equilibrium constant Kc is the ratio of product concentrations to reactant concentrations, each raised to the power of their stoichiometric coefficients, at equilibrium.
- →Kc is temperature-dependent; changing temperature changes the value of Kc, while adding a catalyst or changing pressure/concentration does not.
- →Le Chatelier's principle: if a system at equilibrium is subjected to a change in concentration, pressure, or temperature, the equilibrium shifts to counteract the change.
- →Industrial processes like the Haber process use a compromise between yield (equilibrium position) and rate (kinetics) to optimise production.
- →Units of Kc vary depending on the stoichiometry of the reaction and must be calculated from the expression.
Marking Points
- Correct calculation of oxidation numbers in compounds and ions, including peroxides and metal hydrides.
- Correct identification of oxidation and reduction based on electron transfer and oxidation number changes.
- Correct identification of oxidising and reducing agents.
- Correct identification of disproportionation reactions.
- Correct use of Roman numerals to indicate oxidation numbers.
- Correct construction of full ionic equations from ionic half-equations.
Examiner Tips
- 💡Always check that the sum of oxidation numbers in a neutral compound equals zero and in an ion equals the charge of the ion.
- 💡Remember that oxidising agents are reduced (gain electrons) and reducing agents are oxidised (lose electrons).
- 💡When balancing half-equations, ensure the total charge on both sides is equal.
- 💡Practice identifying oxidation numbers in various contexts, especially for s- and p-block elements.
- 💡Always write the Kc expression with square brackets and correct powers; this is a common source of method marks.
- 💡When explaining equilibrium shifts, explicitly state 'the equilibrium shifts to the right/left' and justify using Le Chatelier's principle.
- 💡In industrial context questions, remember to discuss both yield and rate, and mention the compromise conditions used.
Common Mistakes
- Confusing the direction of electron transfer in oxidation and reduction.
- Incorrectly assigning oxidation numbers in complex ions or species.
- Failing to balance both atoms and charges when constructing ionic half-equations.
- Misidentifying the species being oxidised or reduced in a disproportionation reaction.
- Misconception: A catalyst changes the position of equilibrium. Correction: A catalyst speeds up both forward and reverse reactions equally, so it does not shift the position; it only helps reach equilibrium faster.
- Misconception: Increasing pressure always increases yield. Correction: Pressure only affects reactions with a change in the number of moles of gas; if the number of moles is equal, pressure has no effect.
- Misconception: Kc changes with concentration or pressure. Correction: Kc is constant at a given temperature; only temperature changes Kc.
Revision Plan
- 1Week 1: Review dynamic equilibrium and Le Chatelier's principle from Topic 10. Then learn how to write Kc expressions and calculate Kc from given equilibrium concentrations. Practice 5-10 calculation questions.
- 2Week 2: Study the effect of changing conditions on equilibrium position and Kc. Apply these to the Haber and Contact processes. Practice past paper questions, focusing on 6-mark explanations.
- 3Day 10-14: Consolidate by attempting full past papers under timed conditions. Review mark schemes to understand command words and required detail.
Exam Question Types
- 📋Calculations of Kc from equilibrium concentrations, including determining units.
- 📋Explaining the effect of changes in pressure, temperature, or concentration on equilibrium position using Le Chatelier's principle.
- 📋6-mark extended response questions on industrial processes, requiring discussion of compromise conditions.
- 📋Multiple-choice questions testing understanding of factors that affect Kc and equilibrium position.
Command Word Expectations (PEARSON EDEXCEL)
Show all working, use the correct formula, and include units in the final answer. Method marks are awarded for correct substitution even if arithmetic is wrong.
Give a reason or justification for a statement. Use scientific principles (e.g., Le Chatelier's principle) and link cause and effect clearly.
Give a brief, precise answer without explanation. Often used for recalling definitions or values.
How Students Lose Marks (Examiner Pitfalls)
Step-by-Step Worked Solutions
Question: For the reaction N2(g) + 3H2(g) ⇌ 2NH3(g), at equilibrium at 400°C, the concentrations are [N2] = 0.10 mol dm^-3, [H2] = 0.30 mol dm^-3, and [NH3] = 0.20 mol dm^-3. Calculate Kc and state its units.
- 1.Step 1: Write the balanced equation and the equilibrium constant expression: Kc = [NH3]^2 / ([N2][H2]^3).
- 2.Step 2: Substitute the equilibrium concentrations into the expression: Kc = (0.20)^2 / (0.10 * (0.30)^3).
- 3.Step 3: Calculate: Kc = 0.04 / (0.10 * 0.027) = 0.04 / 0.0027 = 14.8.
- 4.Step 4: Determine units: (mol dm^-3)^2 / ((mol dm^-3)(mol dm^-3)^3) = mol^-2 dm^6.
Question: In the Haber process, N2(g) + 3H2(g) ⇌ 2NH3(g) ΔH = -92 kJ mol^-1. Explain, using Le Chatelier's principle, the effect of increasing pressure on the yield of ammonia and why a compromise pressure is used industrially.
- 1.Step 1: Identify the number of moles of gas on each side: reactants = 4 moles, products = 2 moles.
- 2.Step 2: Apply Le Chatelier's principle: increasing pressure shifts equilibrium to the side with fewer gas moles, which is the product side, increasing yield of ammonia.
- 3.Step 3: Discuss compromise: high pressure increases yield but is expensive and requires stronger equipment; a moderate pressure (e.g., 200 atm) is used to balance yield and cost.
- 4.Step 4: Also consider that high pressure may cause safety risks and energy costs.