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    Topic 15: Transition Metals — Edexcel A-Level Chemistry

    Test yourself on Topic 15: Transition Metals with PEARSON EDEXCEL A-Level practice questions.

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    Topic 15: Transition Metals explained

    This topic introduces the concept of oxidation numbers as a systematic method for classifying redox reactions, including disproportionation.

    Read the full explanation

    Students learn to define oxidation and reduction in terms of electron transfer and changes in oxidation number, and apply these principles to write and balance ionic half-equations.

    What to demonstrate

    1. Correct calculation of oxidation numbers in compounds and ions, including peroxides and metal hydrides.
    2. Correct identification of oxidation and reduction based on electron transfer and oxidation number changes.
    3. Correct identification of oxidising and reducing agents.
    Show all 6 objectives
    1. Correct identification of disproportionation reactions.
    2. Correct use of Roman numerals to indicate oxidation numbers.
    3. Correct construction of full ionic equations from ionic half-equations.

    Topic 15: Transition Metals exam tips

    Topic Overview

    Transition metals are elements found in the d-block of the periodic table, specifically in groups 3-12, that form at least one stable ion with a partially filled d-subshell. This topic explores their unique properties, including variable oxidation states, formation of coloured compounds, catalytic activity, and complex ion formation. Understanding transition metals is crucial for A-Level Chemistry as it connects electronic configuration to observable chemical behaviour, and has real-world applications in industrial catalysis, biological systems (e.g., haemoglobin), and materials science.

    The key to mastering this topic lies in the d-orbital splitting in complex ions, which explains colour and magnetic properties. You'll learn about ligand substitution reactions, the chelate effect, and how to predict stability constants. This topic builds on earlier work on atomic structure, bonding, and redox reactions, and is assessed through both multiple-choice and extended-response questions, often requiring you to apply concepts to unfamiliar contexts.

    Transition metals are not just theoretical; they are essential in everyday life. For example, iron in haemoglobin transports oxygen, platinum catalysts are used in catalytic converters, and vanadium(V) oxide is used in the Contact process. By the end of this topic, you should be able to explain why these elements are so versatile and how their properties arise from their electronic configurations.

    Key Concepts
    • →Electronic configuration of transition metals and their ions: the 4s orbital fills before 3d, but is lost first when forming ions (e.g., Fe: [Ar] 3d⁶4s², Fe²⁺: [Ar] 3d⁶, Fe³⁺: [Ar] 3d⁵).
    • →Variable oxidation states: due to the small energy difference between 3d and 4s orbitals, transition metals can lose different numbers of electrons (e.g., Mn from +2 to +7).
    • →Formation of coloured compounds: caused by d-d electron transitions when light is absorbed; the colour observed is complementary to the absorbed wavelength.
    • →Catalytic behaviour: transition metals and their compounds act as catalysts by providing a surface for adsorption (heterogeneous) or by changing oxidation states (homogeneous).
    • →Complex ion formation: ligands (e.g., H₂O, NH₃, Cl⁻) donate lone pairs to the central metal ion, forming coordinate bonds; shapes include octahedral, tetrahedral, and square planar.
    Marking Points
    • Correct calculation of oxidation numbers in compounds and ions, including peroxides and metal hydrides.
    • Correct identification of oxidation and reduction based on electron transfer and oxidation number changes.
    • Correct identification of oxidising and reducing agents.
    • Correct identification of disproportionation reactions.
    • Correct use of Roman numerals to indicate oxidation numbers.
    • Correct construction of full ionic equations from ionic half-equations.
    Examiner Tips
    • 💡Always check that the sum of oxidation numbers in a neutral compound equals zero and in an ion equals the charge of the ion.
    • 💡Remember that oxidising agents are reduced (gain electrons) and reducing agents are oxidised (lose electrons).
    • 💡When balancing half-equations, ensure the total charge on both sides is equal.
    • 💡Practice identifying oxidation numbers in various contexts, especially for s- and p-block elements.
    • 💡When explaining colour, always state that light is absorbed to excite an electron from a lower d-orbital to a higher d-orbital, and the complementary colour is transmitted/reflected. Mention that the energy gap (ΔE) depends on the ligand and oxidation state.
    • 💡For catalysis questions, distinguish between heterogeneous (different phase, e.g., Fe in Haber process) and homogeneous (same phase, e.g., Fe²⁺/Fe³⁺ in the iodide-peroxodisulfate reaction). Explain how the catalyst provides an alternative pathway with lower activation energy.
    • 💡In complex ion questions, remember to state the coordination number, shape, and bond angle. For example, [Cu(H₂O)₆]²⁺ is octahedral (coordination number 6), but [CuCl₄]²⁻ is tetrahedral (coordination number 4) due to Jahn-Teller distortion or ligand size.
    Common Mistakes
    • Confusing the direction of electron transfer in oxidation and reduction.
    • Incorrectly assigning oxidation numbers in complex ions or species.
    • Failing to balance both atoms and charges when constructing ionic half-equations.
    • Misidentifying the species being oxidised or reduced in a disproportionation reaction.
    • Misconception: All d-block elements are transition metals. Correction: Only those that form ions with a partially filled d-subshell are transition metals. Scandium (Sc³⁺: [Ar]) and zinc (Zn²⁺: [Ar] 3d¹⁰) are not transition metals.
    • Misconception: The 4s orbital is filled before 3d, so it is always higher in energy. Correction: In isolated atoms, 4s is lower in energy, but in ions, 4s is higher, so electrons are removed from 4s first.
    • Misconception: Colour in transition metal compounds is always due to d-d transitions. Correction: Some colours arise from charge transfer (e.g., permanganate ion, MnO₄⁻, is purple due to O→Mn charge transfer).
    Frequently Asked Questions
    Why do transition metals have variable oxidation states?
    Transition metals have variable oxidation states because the energy difference between the 3d and 4s orbitals is small, allowing them to lose different numbers of electrons. For example, iron can form Fe²⁺ (losing 2 electrons) and Fe³⁺ (losing 3 electrons). The stability of each oxidation state depends on factors like the ligand and pH.
    How do I predict the colour of a transition metal complex?
    The colour depends on the energy gap (ΔE) between the split d-orbitals, which is influenced by the metal ion, its oxidation state, and the ligand. Strong field ligands (e.g., CN⁻) cause large splitting, absorbing higher energy light (blue/violet), so the complex appears yellow/orange. Weak field ligands (e.g., H₂O) cause small splitting, absorbing lower energy light (red/orange), so the complex appears blue/green. You can use the spectrochemical series to compare ligands.
    What is the chelate effect and why does it happen?
    The chelate effect is the increased stability of complexes formed with multidentate ligands (e.g., EDTA) compared to similar monodentate ligands (e.g., H₂O). This is due to a favourable entropy change: when a multidentate ligand replaces several monodentate ligands, the number of free particles increases, leading to a positive ΔS, which makes ΔG negative and the reaction spontaneous.
    Why is [Cu(H2O)6]2+ blue but [Cu(NH3)4(H2O)2]2+ deep blue?
    Both complexes are octahedral, but NH₃ is a stronger field ligand than H₂O, causing a larger d-orbital splitting (ΔE). This means [Cu(NH₃)₄(H₂O)₂]²⁺ absorbs higher energy light (shorter wavelength) than [Cu(H₂O)₆]²⁺. The complementary colour shifts from blue to deep blue/violet as the absorbed light moves from red to yellow.
    How do transition metals act as catalysts?
    Transition metals can act as heterogeneous catalysts (e.g., iron in the Haber process) by providing a surface for reactants to adsorb, weakening bonds and lowering activation energy. They can also act as homogeneous catalysts (e.g., Fe²⁺/Fe³⁺ in the iodide-peroxodisulfate reaction) by changing oxidation states, providing an alternative reaction pathway with a lower activation energy.
    What is the difference between a ligand and a chelating agent?
    A ligand is any molecule or ion that donates a lone pair to a metal ion to form a coordinate bond. A chelating agent is a multidentate ligand that can form two or more coordinate bonds with the same metal ion, creating a ring structure. For example, EDTA is a chelating agent with six donor atoms, while water is a monodentate ligand.