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    Vectors (A2 Unit 4: Applied Mathematics B) — WJEC A-Level Mathematics

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    Vectors (A2 Unit 4: Applied Mathematics B) explained

    Three-dimensional vectors represent positions, velocities and forces using orthogonal unit vectors i, j and k along the x, y and z axes: r = xi + yj + zk, or as a column vector (x, y, z)ᵀ.

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    Magnitude extends Pythagoras: |r| = √(x² + y² + z²). The distance between A(x₁, y₁, z₁) and B(x₂, y₂, z₂) is |AB| = √((x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²), where AB = r_B − r_A. A unit vector is r̂ = r / |r|. The scalar product is a · b = a_x b_x + a_y b_y + a_z b_z, and a · b = |a||b|cos θ gives the angle between vectors, so cos θ = (a · b)/(|a||b|). For example, if a = i + 2j + 2k and b = 2i − j + 2k, then a · b = 2 − 2 + 4 = 4, |a| = |b| = 3, so cos θ = 4/9 and θ ≈ 63.6°.

    Your focus

    1. Represent 3D vectors using unit vectors i, j, k and column vector notation.
    2. Calculate magnitudes and distances between points in three-dimensional Cartesian space.
    3. Construct unit vectors parallel to given three-dimensional vectors.
    Show all 4 objectives
    1. Use the scalar product to find the angle between two 3D vectors and to test perpendicularity.

    Vectors (A2 Unit 4: Applied Mathematics B) exam tips

    Marking Points
    • Calculate the magnitude of a 3D vector using |r| = √(x² + y² + z²), including all three components.
    • Find the displacement vector between two 3D points using AB = r_B − r_A, then calculate its magnitude for the distance.
    • Construct a unit vector in a specified 3D direction by dividing each component by the magnitude: r̂ = r / |r|.
    • Evaluate the scalar product a · b = a_x b_x + a_y b_y + a_z b_z and use a · b = |a||b|cos θ to find the angle between two 3D vectors.
    • Use the scalar product to test perpendicularity: a · b = 0 exactly when non-zero vectors a and b are perpendicular.
    Examiner Tips
    • 💡Use column vector notation (x, y, z)ᵀ to keep the i, j and k components aligned and reduce transcription errors.
    • 💡To find an angle, compute the scalar product and both magnitudes separately before dividing; this makes each step checkable and earns method marks even if the final value is wrong.
    Common Mistakes
    • Omitting the z-component when computing magnitudes or distances in three dimensions; the correction is to include all three squared components under the square root.
    • Subtracting position vectors in the reverse order when finding displacement AB; the correction is to use B − A, since AB means from A to B.
    • Forgetting to divide by both magnitudes when finding an angle, using cos θ = a · b instead of cos θ = (a · b)/(|a||b|); the correction is to compute |a| and |b| first and divide by their product.