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    Ratio, proportion and rates of change — AQA GCSE Mathematics

    Test yourself on Ratio, proportion and rates of change with AQA GCSE practice questions.

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    Ratio, proportion and rates of change explained

    To divide a quantity in a part : part ratio, add the parts to find the total number of shares, divide the quantity by that total to find one share, then multiply by each part.

    Read the full explanation

    For example, £60 in the ratio 2 : 3 has 5 shares, so one share is £12 and the parts are £24 and £36. For a part : whole ratio such as 2 : 5, the whole is 5 shares and the two parts are 2 shares and 3 shares. To express a division as a ratio, compare the two part amounts in simplest form. Ratio applies to real contexts: convert units before comparing, scale recipes or maps by multiplying all parts, mix ingredients or solutions in the given ratio, and calculate concentrations as a ratio of solute to solution or solvent.

    Your focus

    1. divide a given quantity into two parts in a given part : part or part : whole ratio express the division of a quantity into two parts as a ratio apply ratio to real contexts and problems (such as those involving conversion, comparison, scaling, mixing, concentrations)

    Ratio, proportion and rates of change exam tips

    Quick Revision Summary (Key Takeaway)

    Ratio, proportion and rates of change covers comparing quantities using multiplicative relationships, scaling recipes and maps, sharing amounts in given ratios, and solving problems involving speed, density, pressure and unit conversion. It is a high-weight AQA GCSE topic tested across all tiers, often through multi-step worded problems and ratio-to-fraction or ratio-to-equation methods.

    Topic Overview

    Ratio, proportion and rates of change is a fundamental AQA GCSE Mathematics topic that explores multiplicative relationships between quantities. You will learn to simplify and compare ratios, share amounts in given ratios, solve direct and inverse proportion problems, and work with rates such as speed, density and pressure. This topic appears in both Foundation and Higher tiers and carries significant weight in exams, often combining with algebra, geometry and statistics.

    Mastering this topic is essential because it underpins many real-world applications, from scaling recipes and interpreting maps to calculating fuel efficiency and currency exchange. It also develops proportional reasoning, a key skill for solving multi-step problems and algebraic manipulation. A strong grasp of ratio and proportion will boost your confidence across the entire GCSE Mathematics curriculum.

    Key Concepts
    • →A ratio compares quantities of the same kind; it can be simplified by dividing all parts by their highest common factor.
    • →To share an amount in a given ratio, add the parts to find the total number of parts, divide the amount by this total to find one part, then multiply by each ratio part.
    • →Direct proportion means as one quantity increases, the other increases at the same rate (e.g. cost per item); inverse proportion means as one increases, the other decreases (e.g. more workers take less time).
    • →Rates of change compare two different units, such as speed (distance/time), density (mass/volume) and pressure (force/area).
    • →Unit conversion is crucial: convert all quantities to consistent units before calculating, and always include units in your final answer.
    Marking Points
    • Add the parts of a part : part ratio to find the total number of shares.
    • Divide the quantity by the total number of shares to find the value of one share.
    • Multiply the value of one share by each part to find the two required amounts.
    • For a part : whole ratio, subtract the given part from the whole to find the other part before sharing.
    • Express a division of a quantity into two parts as a ratio by comparing the two amounts and simplifying.
    • Apply ratio to real contexts such as unit conversion, comparison, scaling, mixing and concentrations.
    Examiner Tips
    • 💡Write down the total number of shares before dividing the quantity.
    • 💡Check that the two amounts add back to the original quantity.
    • 💡In real contexts, identify the units and convert them before setting up the ratio.
    • 💡Always show your working, especially when sharing in a ratio: write the total number of parts and the value of one part. This secures method marks even if you make an arithmetic slip.
    • 💡In worded problems, underline the key information and units. Convert all units to a consistent system before calculating to avoid losing accuracy marks.
    • 💡For 'show that' or 'prove' questions, set up an equation using the given ratio and solve algebraically. Do not just substitute numbers; show each step clearly.
    Common Mistakes
    • Dividing the quantity by the number of parts instead of the total number of shares: for example, sharing £60 in the ratio 2 : 3 by dividing by 2 and by 3. Correction: add 2 + 3 = 5 shares, so one share is £12, giving £24 and £36.
    • Treating a part : whole ratio as a part : part ratio: for example, reading 2 : 5 as two parts to five parts. Correction: the whole is 5 shares, so the parts are 2 shares and 3 shares.
    • Forgetting to convert units before applying a ratio in a real context: for example, mixing 200 ml with 1 litre as 200 : 1. Correction: convert to the same unit, giving 200 : 1000, then simplify to 1 : 5.
    • Students often treat a ratio as a fraction, e.g. writing 2:3 as 2/3 instead of recognising it as 2 parts to 3 parts. Correction: a ratio compares parts, while a fraction compares a part to the whole.
    • When solving inverse proportion, students may use direct proportion methods, leading to incorrect scaling. Correction: in inverse proportion, the product of the two quantities is constant, so use y = k/x.
    • Students forget to convert units before calculating rates, e.g. mixing minutes and hours. Correction: always convert to the same unit (e.g. hours) before dividing.
    Revision Plan
    1. 1Day 1-2: Revise the basics of ratio: simplifying, equivalent ratios, and sharing in a given ratio. Complete practice questions from your textbook or online resources.
    2. 2Day 3-4: Focus on direct and inverse proportion. Learn the formulas y = kx and y = k/x, and practise identifying which type of proportion a problem involves.
    3. 3Day 5-6: Study rates of change: speed, density, pressure, and unit conversion. Solve problems that require converting between units (e.g. km/h to m/s).
    4. 4Day 7-8: Attempt mixed exam-style questions, including multi-step problems that combine ratio with algebra or geometry. Time yourself to build exam stamina.
    5. 5Day 9-10: Review your mistakes using a mark scheme. Create a flashcard of key formulas and common pitfalls, then do a final past paper under timed conditions.
    Exam Question Types
    • 📋Sharing an amount in a given ratio: often a 3-4 mark question. Advice: always show the total number of parts and the value of one part.
    • 📋Direct and inverse proportion word problems: may involve scaling recipes, currency conversion, or work rates. Advice: identify the type of proportion first and use the unitary method or formula.
    • 📋Rates of change calculations: speed, density, pressure, or unit conversion. Advice: convert units before calculating and state the correct unit in your answer.
    • 📋Ratio to equation problems: e.g. 'The ratio of boys to girls is 3:4. There are 12 more girls than boys. How many students are there?' Advice: let the parts be 3x and 4x, form an equation, and solve.
    Command Word Expectations (AQA)
    Calculate

    Work out a numerical answer using the given information. You must show sufficient working to demonstrate the method, and give the answer with correct units where applicable.

    Show that

    Prove a given result by showing each step of your working clearly. The final answer is given, so you must justify each stage, often using algebra or logical reasoning.

    Solve

    Find the value(s) of an unknown quantity by setting up and solving an equation or using proportional reasoning. Show all steps and check your answer.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students confuse part-to-part ratios with part-to-whole fractions when sharing an amount, leading to incorrect denominators and lost method marks.
    ❌ Weak Answer (Loses Marks):Share 60 in the ratio 2:3. Student writes 2/3 of 60 = 40 and 3/2 of 60 = 90, then gives 40 and 90 as the shares.
    Example improved answer:Total parts = 2 + 3 = 5. One part = 60 / 5 = 12. Shares are 2 x 12 = 24 and 3 x 12 = 36. Check: 24 + 36 = 60 and 24:36 simplifies to 2:3.
    Examiner Tip: Always add the ratio parts to find the total number of parts, then divide the amount by that total to find one part. Write the check 'sum of shares equals original amount' to secure the final mark.
    Pitfall: In rates of change problems, students mix units (e.g. minutes with hours) or forget to convert, producing numerically correct but unit-inconsistent answers.
    ❌ Weak Answer (Loses Marks):A car travels 150 km in 2 hours 30 minutes. Student writes speed = 150 / 2.5 = 60 km/h but then states 60 km/min or omits units entirely.
    Example improved answer:Convert 2 hours 30 minutes to 2.5 hours. Speed = distance / time = 150 / 2.5 = 60 km/h. State the unit clearly as km/h.
    Examiner Tip: Underline the units in the question before calculating. Convert all time to hours (or all to minutes) consistently, and always write the unit in your final answer to secure the accuracy mark.
    Step-by-Step Worked Solutions

    Question: A recipe for 4 people uses 300 g of flour and 200 g of butter. How much flour and butter are needed for 10 people?

    1. 1.Step 1: Identify the given ratio of people to ingredients: 4 people use 300 g flour and 200 g butter.
    2. 2.Step 2: Find the amount per person by dividing by 4: flour per person = 300 / 4 = 75 g, butter per person = 200 / 4 = 50 g.
    3. 3.Step 3: Multiply by 10 people: flour = 75 x 10 = 750 g, butter = 50 x 10 = 500 g.
    4. 4.Step 4: State final answer with units: 750 g flour and 500 g butter.
    Final Answer: 750 g of flour and 500 g of butter are needed for 10 people.

    Question: A map has a scale of 1:25000. The distance between two towns on the map is 8 cm. Calculate the real distance in kilometres.

    1. 1.Step 1: Identify the scale 1:25000 means 1 cm on the map represents 25000 cm in real life.
    2. 2.Step 2: Multiply the map distance by the scale factor: 8 x 25000 = 200000 cm.
    3. 3.Step 3: Convert centimetres to kilometres: 200000 / 100000 = 2 km (since 1 km = 100000 cm).
    4. 4.Step 4: State final answer with units: 2 km.
    Final Answer: The real distance between the two towns is 2 km.
    Active Recall Memory Test
    How do you share an amount in a given ratio?
    Key Fact: Add the parts of the ratio to find the total number of parts, divide the amount by this total to find the value of one part, then multiply by each part of the ratio.
    What is the difference between direct and inverse proportion?
    Key Fact: In direct proportion, as one quantity increases, the other increases at the same rate (y = kx). In inverse proportion, as one quantity increases, the other decreases (y = k/x).
    What is the formula for speed, and what units must be consistent?
    Key Fact: Speed = distance / time. Units must be consistent: if distance is in km and time in hours, speed is in km/h. Convert minutes to hours by dividing by 60.
    How do you convert a ratio to a fraction?
    Key Fact: To find the fraction of the total that one part represents, write that part as the numerator and the sum of all parts as the denominator. For example, in the ratio 2:3, the first part is 2/5 of the total.
    Frequently Asked Questions
    How do I solve ratio problems with 3 parts?
    Treat a three-part ratio the same as a two-part ratio: add all three parts to find the total number of parts, divide the total amount by this sum to find one part, then multiply by each part. For example, to share 120 in the ratio 2:3:5, total parts = 10, one part = 12, shares are 24, 36 and 60.
    What is the unitary method in proportion?
    The unitary method involves finding the value of a single unit first, then multiplying to find the required value. For example, if 5 pens cost 2 pounds, one pen costs 40p, so 8 pens cost 3.20 pounds. It works for both direct and inverse proportion.
    How do I know if a question is direct or inverse proportion?
    Look for the relationship: if both quantities increase together (e.g. more hours worked, more pay), it is direct proportion. If one increases while the other decreases (e.g. more workers, less time), it is inverse proportion. In inverse proportion, the product of the two quantities is constant.
    What are the most common mistakes in ratio and proportion exams?
    Common mistakes include confusing part-to-part ratios with part-to-whole fractions, forgetting to convert units before calculating rates, and using direct proportion when inverse proportion is required. Always read the question carefully, underline key information, and check your answer for reasonableness.
    How is ratio and proportion tested in AQA GCSE Maths?
    AQA GCSE Maths tests ratio and proportion through worded problems, often in real-life contexts such as recipes, maps, currency conversion, and speed calculations. Questions can be worth 2 to 5 marks and may require multiple steps, including setting up and solving equations. It appears in both Foundation and Higher tiers.
    What is the formula for density and pressure?
    Density = mass / volume, and pressure = force / area. These are rates of change that compare two different units. Always ensure units are consistent (e.g. mass in kg, volume in m^3 for density in kg/m^3) and state the correct compound unit in your answer.