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    Engine cycles (A-level only) — AQA A-Level Physics

    Teaching note checked against the official specification.

    Engine cycles describe how a working substance (usually an ideal gas) is taken through a sequence of thermodynamic processes to convert thermal energy into useful work. For AQA A-Level Physics you must be able to sketch and interpret p-V diagrams, apply the first law of thermodynamics to each stage, and calculate the efficiency of ideal cycles such as the Carnot cycle.

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    Engine cycles (A-level only) explained

    Engine cycles (A-level only) covers 2 specification points, including Understanding of a four-stroke petrol engine… and Comparison with the theoretical diagrams for….

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    Open a point below for its explanation and revision guidance.

    Understanding of a four-stroke petrol engine cycle and a diesel engine cycle, and of the corresponding indicator diagrams.

    A four-stroke petrol engine repeats induction, compression, power and exhaust. On a p−V indicator diagram the loop runs clockwise: intake near atmospheric pressure, steep compression, near-vertical pressure rise at ignition, expansion doing work, then exhaust. A diesel engine draws in air only, compresses it enough to raise temperature above the fuel's ignition point, then injects fuel that self-ignites; its diagram shows a longer, higher compression and a broader power loop. The enclosed area equals net work per cycle. Compare the two cycles by compression ratio, ignition method and loop shape, and relate each stroke to the piston positions at top and bottom dead centre.

    Comparison with the theoretical diagrams for these cycles; use of indicator diagrams for predicting and measuring power and efficiency input power = calorific value × fuel flow rate Indicated power as area of p−V loop × no. of cycles per second × no. of cylinders Output or brake power, P = Tω friction power = indicated power – brake power Engine efficiency; overall, thermal and mechanical efficiencies.

    Real indicator diagrams differ from ideal ones: rounded corners, finite combustion time and heat loss reduce the loop area. The loop area gives work per cycle, so indicated power equals area × cycles per second × number of cylinders. Input power comes from calorific value × fuel flow rate. Brake (output) power is measured with a dynamometer using P = Tω, where ω = 2πf. Friction power is indicated power minus brake power. Thermal efficiency compares indicated power with fuel input power, mechanical efficiency compares brake power with indicated power, and overall efficiency combines them (brake power ÷ input power). Work through a numerical example using consistent SI units.

    Your focus

    1. Label the four strokes of petrol and diesel cycles in the correct sequence on a p−V diagram.
    2. Explain how ignition differs between petrol and diesel engines.
    3. Interpret the enclosed area of an indicator diagram as net work per cycle.
    Show all 6 objectives
    1. Calculate indicated, brake and friction power from indicator diagram and dynamometer data.
    2. Determine thermal, mechanical and overall efficiencies for an engine.
    3. Explain why real indicator diagrams differ from theoretical ones.

    Which command word is this?

    You must use the given data and appropriate equations to find a numerical answer. Show your working, include units, and give the answer to an appropriate number of significant figures. Marks are awarded for correct substitution and final answer.

    Engine cycles (A-level only) exam tips

    Topic Overview

    Engine cycles are a core topic in AQA A-Level Physics that connects thermodynamics, energy transfer, and the limits of efficiency. You will study how a working substance, often an ideal gas, is taken through a series of processes such as isothermal, adiabatic, isobaric, and isochoric changes, and how these are represented on pressure-volume (p-V) diagrams. The area enclosed by the cycle represents the net work done per cycle, and the first law of thermodynamics is applied to each stage to track changes in internal energy, heat, and work.

    This topic matters because it explains the fundamental principles behind real engines, refrigerators, and heat pumps, and introduces the Carnot cycle as the theoretical maximum efficiency any heat engine can achieve between two reservoirs. Understanding engine cycles also reinforces key ideas from earlier topics like the ideal gas law, internal energy, and the first law, and it prepares you for synoptic questions that link thermodynamics to practical applications and environmental considerations.

    Key Concepts
    • →A cyclic process returns the system to its initial state, so the net change in internal energy over one complete cycle is zero (delta U = 0).
    • →On a p-V diagram, the work done by the gas in a process is the area under the curve; for a complete cycle, the net work done is the area enclosed by the loop.
    • →The direction of the cycle indicates its function: clockwise cycles are heat engines (net work done by the gas), anticlockwise cycles are refrigerators or heat pumps (net work done on the gas).
    • →The Carnot cycle consists of two reversible isothermal processes and two reversible adiabatic processes, and its efficiency depends only on the absolute temperatures of the hot and cold reservoirs: efficiency = 1 - (T_C / T_H).
    • →The first law of thermodynamics, delta U = Q + W (where W is work done on the gas), applies to each stage of a cycle and is essential for calculating unknown quantities.
    Marking Points
    • Identifies the four strokes in order as induction, compression, power (expansion) and exhaust, linking each to piston motion between top dead centre and bottom dead centre.
    • Describes the petrol cycle: fuel–air mixture drawn in, compressed, ignited by a spark, hot gas expands doing work, burnt gas expelled.
    • Describes the diesel cycle: air alone drawn in and compressed to a high pressure and temperature, fuel injected and self-ignited, expansion then exhaust.
    • Reads an indicator diagram: the enclosed loop area represents net work done per cycle and the loop direction shows whether work is done by or on the gas.
    • Compares the cycles, noting the diesel's higher compression ratio, higher peak pressure and ignition by compression heating rather than a spark.
    • Relates the near-vertical sections of the diagram to rapid combustion at approximately constant volume and the sloping sections to compression and expansion.
    • Explains that real diagrams have rounded corners and lower peak pressures than theoretical ones because combustion takes time and heat is lost.
    • Calculates indicated power as the p−V loop area multiplied by cycles per second and by the number of cylinders.
    • Calculates input power as calorific value of the fuel multiplied by the fuel flow rate, converting units such as kW and MJ kg⁻¹ consistently.
    • Uses P = Tω with ω = 2πf to find brake power from measured torque and rotational frequency.
    • Obtains friction power by subtracting brake power from indicated power.
    • Distinguishes thermal efficiency (indicated power ÷ input power), mechanical efficiency (brake power ÷ indicated power) and overall efficiency (brake power ÷ input power).
    Examiner Tips
    • 💡Sketch both diagrams side by side and label the strokes, axes and enclosed area before writing prose.
    • 💡Use comparative language such as higher compression ratio and greater peak pressure when contrasting diesel with petrol.
    • 💡Link each diagram feature to the physical event in the cylinder so explanations stay causal rather than descriptive.
    • 💡Write the defining equation before substituting numbers, and state units with every answer.
    • 💡Show the conversion of fuel flow rate to kg s⁻¹ and calorific value to J kg⁻¹ explicitly.
    • 💡Check that brake power is less than indicated power and that all efficiencies lie between 0 and 1.
    • 💡Always label the axes of p-V diagrams with quantity and unit (e.g., p / Pa, V / m^3) and indicate the direction of the cycle with arrows. This helps you and the examiner track the processes.
    • 💡When using the first law, write down your sign convention explicitly before substituting values. AQA expects you to use delta U = Q + W with W as work done on the system, so be consistent.
    • 💡For efficiency calculations, convert temperatures to kelvin and show the formula clearly. Remember that efficiency is a ratio and has no units; express it as a decimal or percentage as requested.
    Common Mistakes
    • Treating the four strokes as simultaneous rather than sequential; correct by tracking one cylinder through two crankshaft revolutions.
    • Believing the spark plug ignites fuel throughout the power stroke; correct by stating ignition occurs at one point near top dead centre.
    • Assuming the diesel cycle compresses a fuel–air mixture; correct by stating only air is compressed and fuel is injected near the end of compression.
    • Confusing the loop area with peak pressure; correct by explaining that area gives net work per cycle while peak pressure is a single point on the curve.
    • Using the wrong area or forgetting the number of cylinders when finding indicated power; correct by multiplying loop area by cycles per second and cylinder count.
    • Mixing units such as kW, MJ kg⁻¹ and g s⁻¹; correct by converting all quantities to SI before substituting.
    • Using ω in rev s⁻¹ instead of rad s⁻¹; correct by applying ω = 2πf.
    • Treating overall efficiency as the sum of thermal and mechanical efficiencies; correct by treating it as their product.
    • Students often think that because a cycle returns to its starting point, no heat is exchanged. In fact, heat is absorbed and released in different parts of the cycle, and the net heat absorbed equals the net work done.
    • Many believe that the area under a p-V curve always represents work done by the gas. It only does so for expansion; for compression, the area represents work done on the gas, and the sign must be considered.
    • Some students assume that all heat engines can achieve 100% efficiency. The Carnot efficiency sets a theoretical upper limit, and real engines are less efficient due to friction and other irreversibilities.
    Revision Plan
    1. 1Week 1: Start by revising the first law of thermodynamics and the ideal gas law. Then learn to identify and sketch the four basic processes on p-V diagrams, noting the shape of each curve and the work done.
    2. 2Week 1: Practice applying the first law to each process type, calculating changes in internal energy, heat, and work. Use past paper questions to test your understanding of sign conventions.
    3. 3Week 2: Study the Carnot cycle in detail, including its four stages and why it is the most efficient cycle. Derive and use the efficiency formula.
    4. 4Week 2: Work through exam-style questions on engine cycles, focusing on calculating net work done, efficiency, and interpreting p-V diagrams. Review mark schemes to understand common pitfalls.
    5. 5Ongoing: Create a summary sheet with key formulas, sign conventions, and cycle directions. Use active recall to test yourself on definitions and processes.
    Exam Question Types
    • 📋Calculation of efficiency or work done from a p-V diagram or given data. Advice: Identify the hot and cold temperatures, use the Carnot formula if applicable, and show all steps clearly.
    • 📋Explanation of the first law applied to a specific process in a cycle. Advice: State the sign convention, identify whether Q, W, or delta U is zero, and explain the physical meaning.
    • 📋Sketching and interpreting p-V diagrams for a given cycle. Advice: Label axes, draw curves correctly (isotherms as smooth curves, adiabats steeper), and indicate direction with arrows.
    • 📋Comparison of real and ideal cycles, or discussion of efficiency limits. Advice: Refer to the Carnot cycle as the ideal, mention irreversible processes, and use correct terminology.
    Command Word Expectations (AQA)
    Calculate

    You must use the given data and appropriate equations to find a numerical answer. Show your working, include units, and give the answer to an appropriate number of significant figures. Marks are awarded for correct substitution and final answer.

    Explain

    You must provide a reasoned justification for a physical situation, often using the first law or the properties of the cycle. Use correct terminology and link cause and effect. Typically 2-3 marks for a clear, logical sequence.

    Sketch

    You must draw a diagram that shows the correct shape and key features of the cycle, such as the axes, direction, and relative positions of curves. It does not need to be to scale, but must be qualitatively correct. Labels and arrows are essential.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often confuse the direction of a cycle on a p-V diagram and incorrectly state that work is done on the gas when the cycle is clockwise.
    ❌ Weak Answer (Loses Marks):The cycle is clockwise so work is done on the gas and the engine is a refrigerator.
    Example improved answer:A clockwise cycle on a p-V diagram represents a heat engine because the net work done by the gas is positive (the expansion work is greater than the compression work). The area enclosed by the cycle equals the net work done by the gas per cycle. A refrigerator would require a anticlockwise cycle where net work is done on the gas.
    Examiner Tip: Always state the direction of the cycle and link it to the sign of the net work done. Remember: clockwise = engine, anticlockwise = refrigerator.
    Pitfall: When applying the first law of thermodynamics, students frequently forget that work done by the gas is positive and work done on the gas is negative, leading to sign errors in internal energy calculations.
    ❌ Weak Answer (Loses Marks):For an isothermal expansion, delta U = Q + W, and since temperature is constant, delta U = 0, so Q = -W. Therefore heat is released.
    Example improved answer:For an isothermal expansion of an ideal gas, delta U = 0 because internal energy depends only on temperature. Using the first law in the form delta U = Q + W, where W is work done on the gas, we have 0 = Q + W, so Q = -W. Since the gas expands, W is negative (work done on the gas is negative), so Q is positive: heat is absorbed by the gas. This matches the physical requirement that the gas must absorb heat to do work while maintaining constant temperature.
    Examiner Tip: Define your sign convention explicitly before substituting numbers. In AQA, the first law is usually written as delta U = Q + W, where W is work done on the system. Be consistent.
    Step-by-Step Worked Solutions

    Question: A fixed mass of ideal gas is taken through a Carnot cycle between a hot reservoir at 500 K and a cold reservoir at 300 K. The gas absorbs 2000 J of heat from the hot reservoir during the isothermal expansion. Calculate the maximum theoretical efficiency of the cycle and the work done per cycle.

    1. 1.Step 1: Identify the temperatures of the hot and cold reservoirs: T_H = 500 K, T_C = 300 K.
    2. 2.Step 2: Use the Carnot efficiency formula: efficiency = 1 - (T_C / T_H).
    3. 3.Step 3: Substitute values: efficiency = 1 - (300 / 500) = 1 - 0.6 = 0.4 or 40%.
    4. 4.Step 4: Calculate work done per cycle using efficiency = W / Q_H, so W = efficiency x Q_H = 0.4 x 2000 J = 800 J.
    Final Answer: Maximum theoretical efficiency = 0.40 (40%). Work done per cycle = 800 J.

    Question: An ideal gas undergoes a cyclic process consisting of three stages: A to B is an isothermal expansion at 400 K absorbing 1200 J of heat; B to C is an isochoric cooling to 300 K; C to A is an isothermal compression at 300 K releasing 900 J of heat, followed by an isochoric heating back to 400 K. Calculate the net work done by the gas per cycle and state whether it is an engine or a refrigerator.

    1. 1.Step 1: For the isothermal expansion A to B, delta U = 0, so Q_AB = 1200 J and W_AB = -1200 J (work done on gas). Thus work done by gas = +1200 J.
    2. 2.Step 2: For the isochoric cooling B to C, no work is done (W = 0) and Q_BC is negative (heat released).
    3. 3.Step 3: For the isothermal compression C to A, delta U = 0, so Q_CA = -900 J (heat released) and W_CA = +900 J (work done on gas). Thus work done by gas = -900 J.
    4. 4.Step 4: The isochoric heating from A to C? Wait, the cycle is A-B-C-A, so the final isochoric heating is from C to A? Actually the description says C to A is isothermal compression at 300 K, then isochoric heating back to 400 K. That would be a four-stage cycle. Let's correct: The cycle is A to B (isothermal expansion at 400 K, Q=+1200 J), B to C (isochoric cooling to 300 K), C to D (isothermal compression at 300 K, Q=-900 J), D to A (isochoric heating to 400 K). Net work done by gas = work done by gas in A to B + work done by gas in C to D = 1200 J + (-900 J) = 300 J. Since net work done by gas is positive, it is an engine.
    5. 5.Step 5: Check: Net heat absorbed = Q_AB + Q_CD = 1200 J + (-900 J) = 300 J, which equals net work done, consistent with first law for a cycle (delta U = 0).
    Final Answer: Net work done by the gas per cycle = 300 J. The cycle is a heat engine because net work is done by the gas.
    Active Recall Memory Test
    What does the area enclosed by a cycle on a p-V diagram represent?
    Key Fact: The net work done by the gas per cycle.
    State the four stages of the Carnot cycle in order.
    Key Fact: 1. Reversible isothermal expansion (heat absorbed from hot reservoir). 2. Reversible adiabatic expansion (temperature drops to cold reservoir temperature). 3. Reversible isothermal compression (heat rejected to cold reservoir). 4. Reversible adiabatic compression (temperature rises back to hot reservoir temperature).
    What is the efficiency of a Carnot engine operating between 500 K and 400 K?
    Key Fact: Efficiency = 1 - (400/500) = 0.2 or 20%.
    For an isothermal process, what is the change in internal energy and how does the first law simplify?
    Key Fact: For an isothermal process on an ideal gas, delta U = 0, so the first law becomes Q = -W, meaning heat absorbed equals work done by the gas.
    Frequently Asked Questions
    What is the difference between a heat engine and a refrigerator in terms of p-V diagrams?
    A heat engine operates on a clockwise cycle on a p-V diagram, meaning the net work done by the gas is positive. A refrigerator operates on an anticlockwise cycle, meaning net work is done on the gas. In both cases, the area enclosed represents the magnitude of the net work per cycle, but the direction indicates the energy transfer.
    Why can't a real engine achieve the Carnot efficiency?
    The Carnot efficiency is an idealised upper limit that assumes reversible processes and no energy losses. Real engines suffer from friction, heat losses to the surroundings, and irreversible processes such as rapid expansion or turbulence. These factors increase the entropy of the universe and reduce the useful work output, so real efficiencies are always lower.
    How do I calculate the work done in an isobaric process?
    For an isobaric (constant pressure) process, the work done by the gas is given by W = p * delta V, where p is the constant pressure and delta V is the change in volume. If the gas expands, delta V is positive and work is done by the gas; if it compresses, delta V is negative and work is done on the gas. Always use SI units: pressure in pascals and volume in cubic metres.
    What is the first law of thermodynamics and how is it applied to a cycle?
    The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system plus the work done on the system: delta U = Q + W. For a complete cycle, the system returns to its initial state, so delta U = 0. Therefore, the net heat absorbed equals the net work done by the gas: Q_net = -W_net (if W is work done on the gas). This is a powerful tool for analysing cycles.
    What are the key features of a p-V diagram for an isothermal process?
    An isothermal process on a p-V diagram is represented by a smooth curve that follows the equation pV = constant, so it is a hyperbola. The curve is steeper at higher pressures and shallower at lower pressures. For an ideal gas, the internal energy remains constant, so any heat absorbed is entirely converted into work done by the gas (or vice versa).
    How do I determine the direction of a cycle on a p-V diagram from a description?
    The direction is determined by the sequence of processes. If the cycle involves an expansion at higher pressure and a compression at lower pressure, it will be clockwise (engine). If the compression occurs at higher pressure and expansion at lower pressure, it will be anticlockwise (refrigerator). You can also track the changes: expansion moves to the right, compression to the left, and the relative pressures determine whether the loop goes clockwise or anticlockwise.