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    Gravitational field strength (A-level only) — AQA A-Level Physics

    Teaching note checked against the official specification.

    Gravitational field strength (g) is the gravitational force per unit mass experienced by a small test mass placed at a point in a gravitational field, measured in N kg^-1. For a radial field around a point mass or spherical body, g = GM/r^2, and near Earth's surface g is approximately uniform at 9.81 N kg^-1.

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    Gravitational field strength (A-level only) explained

    A gravitational field is represented by field lines that show the direction of the gravitational force on a small test mass.

    Read the full explanation

    The lines point towards the centre of the mass creating the field, because gravity is always attractive. The spacing of the lines indicates field strength: closer lines mean a stronger field, so near a planet the lines are denser. Around a spherical mass, the lines are radial and evenly spaced at a given distance, while between two masses the pattern shows attraction. Field lines never cross, and their direction is the direction of the force on a positive test mass, which for gravity is towards the attracting mass.

    Read the Gravitational field strength (A-level only) study guideFull revision notes for AQA A-Level Physics

    Your focus

    1. Draw gravitational field lines for an isolated spherical mass and for two masses.
    2. Interpret field-line diagrams to compare gravitational field strength at different points.
    3. Explain the meaning of field-line direction and spacing in terms of force on a test mass.

    Which command word is this?

    Give a precise, formal definition. For gravitational field strength, state 'force per unit mass' and mention it is a vector quantity. Include the equation g = F/m if appropriate.

    Gravitational field strength (A-level only) exam tips

    Topic Overview

    Gravitational field strength is a fundamental concept in A-level Physics that quantifies the gravitational force per unit mass at any point in a gravitational field. It explains why objects fall with the same acceleration regardless of mass and is essential for understanding planetary motion, satellite orbits, and the behaviour of masses in fields. The topic builds on Newton's law of gravitation and introduces the inverse square law for radial fields, linking to gravitational potential and energy.

    In the AQA A-Level specification, this topic is part of the 'Fields and their consequences' unit. It provides the foundation for analysing orbits, escape velocity, and the motion of planets and satellites. Mastery of gravitational field strength is crucial for tackling synoptic questions that combine mechanics, energy, and fields, and it frequently appears in exam calculations and explanations.

    Key Concepts
    • →Gravitational field strength (g) is defined as the gravitational force per unit mass on a small test mass, g = F/m, and is a vector quantity measured in N kg^-1.
    • →For a radial gravitational field produced by a point mass or spherically symmetric body, g = GM/r^2, where M is the mass of the body and r is the distance from its centre.
    • →Near the Earth's surface, the field is approximately uniform, with g ≈ 9.81 N kg^-1, and gravitational force is F = mg.
    • →Inside a uniform solid sphere, g is directly proportional to the distance from the centre (g ∝ r), while outside it follows an inverse square law (g ∝ 1/r^2).
    • →The gravitational field strength is the negative gradient of gravitational potential: g = -dV/dr, linking field strength to potential.
    Marking Points
    • Draw gravitational field lines pointing radially inwards towards the centre of a spherical mass.
    • Use the spacing of field lines to represent the magnitude of gravitational field strength, with closer lines indicating a stronger field.
    • Explain that field lines show the direction of the gravitational force on a small test mass placed in the field.
    • Recognise that field lines do not cross and that the field is radial near an isolated spherical mass.
    • Interpret field-line diagrams for more than one mass, showing the resultant field direction at a point.
    Examiner Tips
    • 💡Use arrows on field lines to show direction clearly, and make the lines meet the surface at right angles for a spherical mass.
    • 💡When comparing two points, refer to the spacing of field lines to justify which has greater gravitational field strength.
    • 💡For two masses, sketch the resultant field pattern and mark the neutral point if it exists, showing where fields cancel.
    • 💡Always write the defining equation and substitute values with units before calculating. This secures method marks even if the final answer is wrong.
    • 💡When explaining field strength, use precise terminology: 'force per unit mass' not 'force per mass' or 'gravitational pull'. Avoid saying 'gravity' when you mean 'gravitational field strength'.
    • 💡For graph questions, label axes with quantities and units, and indicate key features such as the surface value, the inverse square decrease outside, and the linear increase inside a solid sphere.
    Common Mistakes
    • Drawing field lines pointing outwards from a mass; correction: gravitational field lines point inwards because gravity is attractive.
    • Drawing field lines crossing each other; correction: field lines never cross because the field has a single direction at any point.
    • Using evenly spaced lines everywhere around a planet; correction: spacing should increase with distance to show decreasing field strength.
    • Students often think gravitational field strength and gravitational potential are the same thing. Correction: g is force per unit mass (N kg^-1), while V is work done per unit mass (J kg^-1); they are related by g = -dV/dr.
    • Many believe that g is always 9.81 N kg^-1 everywhere on Earth. Correction: g varies with altitude, latitude, and local geology; it decreases with height above the surface according to the inverse square law.
    • Students sometimes assume that inside a planet, g continues to increase as you go deeper. Correction: Inside a uniform sphere, g decreases linearly with distance from the centre, reaching zero at the centre.
    Revision Plan
    1. 1Day 1-2: Review Newton's law of gravitation and the definition of gravitational field strength. Learn the equation g = GM/r^2 and its derivation from F = mg and F = GMm/r^2.
    2. 2Day 3-4: Practice calculations for g at the surface and at altitude for different planets. Include unit conversions and standard form.
    3. 3Day 5-6: Study the variation of g inside and outside a uniform sphere. Sketch and interpret g-r graphs, noting the linear and inverse square regions.
    4. 4Day 7-8: Work through exam-style questions on gravitational field strength, including those linking to gravitational potential and orbital motion. Mark your answers using the mark scheme.
    5. 5Day 9-10: Create a summary sheet with key definitions, equations, graphs, and common pitfalls. Test yourself with active recall prompts and past paper questions.
    Exam Question Types
    • 📋Calculation of gravitational field strength: Use g = GM/r^2 to find g at a planet's surface or at a given altitude. Remember to add the altitude to the planet's radius to find r.
    • 📋Explanation of field strength variation: Describe and explain how g changes inside and outside a planet, often requiring a graph. Use the shell theorem and the concept of enclosed mass.
    • 📋Comparison of gravitational field strength on different planets: Calculate g for two planets and compare, or explain why g differs based on mass and radius.
    • 📋Link to gravitational potential: Given a graph of potential against distance, determine g from the gradient, or vice versa. Use g = -dV/dr.
    Command Word Expectations (AQA)
    Define

    Give a precise, formal definition. For gravitational field strength, state 'force per unit mass' and mention it is a vector quantity. Include the equation g = F/m if appropriate.

    Calculate

    Show all working, substitute numerical values into the correct equation, and give the final answer with the correct unit (N kg^-1). Use standard form and significant figures as required.

    Explain

    Provide a reasoned account using correct physics principles. For example, explain why g decreases with altitude by referring to the inverse square law and the increasing distance from the centre of the Earth.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often confuse gravitational field strength (g) with gravitational potential (V) or gravitational potential energy (Ep), leading to incorrect units and equations in calculations.
    ❌ Weak Answer (Loses Marks):g is the gravitational potential energy per unit mass, so g = Ep/m and is measured in J kg^-1.
    Example improved answer:Gravitational field strength at a point is the gravitational force per unit mass exerted on a small test mass placed at that point. It is a vector quantity, measured in N kg^-1, and for a radial field g = GM/r^2. Gravitational potential is a scalar quantity, measured in J kg^-1, defined as the work done per unit mass in bringing a small test mass from infinity to that point, V = -GM/r.
    Examiner Tip: Always check the units: if the answer requires N kg^-1, you are dealing with field strength; if J kg^-1, it is potential. Write the defining equation and units before substituting numbers.
    Pitfall: When calculating gravitational field strength inside a planet or at a distance from a non-spherical mass, students incorrectly apply the inverse square law without considering the distribution of mass or the shell theorem.
    ❌ Weak Answer (Loses Marks):Inside a uniform sphere, g = GM/r^2 still applies, so g increases as r decreases towards the centre.
    Example improved answer:For a uniform spherical shell, the gravitational field inside the shell is zero. For a uniform solid sphere, only the mass enclosed within radius r contributes to the field at that radius, so g = (G M_enclosed)/r^2 = (4/3)πGρr, which increases linearly with r from the centre to the surface. Outside the sphere, g = GM/r^2. The shell theorem justifies treating a spherically symmetric mass as a point mass at its centre for external points.
    Examiner Tip: Sketch the g-r graph for a solid sphere: zero at centre, linear increase to surface, then inverse square decrease outside. Label key points and use the graph to support your explanation.
    Step-by-Step Worked Solutions

    Question: Calculate the gravitational field strength at the surface of Mars. The mass of Mars is 6.42 × 10^23 kg and its mean radius is 3.39 × 10^6 m. Gravitational constant G = 6.67 × 10^-11 N m^2 kg^-2.

    1. 1.Step 1: Identify given facts: M = 6.42 × 10^23 kg, r = 3.39 × 10^6 m, G = 6.67 × 10^-11 N m^2 kg^-2.
    2. 2.Step 2: Apply the formula for gravitational field strength at the surface of a spherical body: g = GM/r^2.
    3. 3.Step 3: Substitute values: g = (6.67 × 10^-11 × 6.42 × 10^23) / (3.39 × 10^6)^2.
    4. 4.Step 4: Calculate numerator: 6.67 × 10^-11 × 6.42 × 10^23 = 4.28 × 10^13 N m^2 kg^-1.
    5. 5.Step 5: Calculate denominator: (3.39 × 10^6)^2 = 1.15 × 10^13 m^2.
    6. 6.Step 6: Divide: g = 4.28 × 10^13 / 1.15 × 10^13 = 3.72 N kg^-1.
    7. 7.Step 7: State final answer with unit: g = 3.72 N kg^-1.
    Final Answer: The gravitational field strength at the surface of Mars is 3.72 N kg^-1.

    Question: A satellite of mass 500 kg is in a circular orbit at a height of 400 km above the Earth's surface. Calculate the gravitational field strength at this altitude and the gravitational force acting on the satellite. Earth's mass = 5.97 × 10^24 kg, Earth's radius = 6.37 × 10^6 m, G = 6.67 × 10^-11 N m^2 kg^-2.

    1. 1.Step 1: Identify given facts: M = 5.97 × 10^24 kg, R = 6.37 × 10^6 m, h = 400 km = 4.00 × 10^5 m, m = 500 kg, G = 6.67 × 10^-11 N m^2 kg^-2.
    2. 2.Step 2: Calculate orbital radius: r = R + h = 6.37 × 10^6 + 4.00 × 10^5 = 6.77 × 10^6 m.
    3. 3.Step 3: Apply g = GM/r^2: g = (6.67 × 10^-11 × 5.97 × 10^24) / (6.77 × 10^6)^2.
    4. 4.Step 4: Calculate numerator: 6.67 × 10^-11 × 5.97 × 10^24 = 3.98 × 10^14 N m^2 kg^-1.
    5. 5.Step 5: Calculate denominator: (6.77 × 10^6)^2 = 4.58 × 10^13 m^2.
    6. 6.Step 6: Divide: g = 3.98 × 10^14 / 4.58 × 10^13 = 8.69 N kg^-1.
    7. 7.Step 7: Calculate gravitational force: F = mg = 500 × 8.69 = 4.35 × 10^3 N.
    8. 8.Step 8: State final answers with units: g = 8.69 N kg^-1, F = 4.35 × 10^3 N.
    Final Answer: The gravitational field strength at 400 km altitude is 8.69 N kg^-1, and the gravitational force on the 500 kg satellite is 4.35 × 10^3 N.
    Active Recall Memory Test
    Define gravitational field strength and state its SI unit.
    Key Fact: Gravitational field strength at a point is the gravitational force per unit mass exerted on a small test mass placed at that point. Its SI unit is N kg^-1 (newtons per kilogram).
    Write the equation for gravitational field strength at a distance r from the centre of a spherically symmetric mass M.
    Key Fact: g = GM/r^2, where G is the gravitational constant (6.67 × 10^-11 N m^2 kg^-2).
    How does gravitational field strength vary inside a uniform solid sphere?
    Key Fact: Inside a uniform solid sphere, g is directly proportional to the distance r from the centre: g = (4/3)πGρr, so it increases linearly from zero at the centre to its maximum at the surface.
    What is the relationship between gravitational field strength and gravitational potential?
    Key Fact: Gravitational field strength is the negative gradient of gravitational potential: g = -dV/dr. This means g is equal to the negative of the slope of a graph of V against r.
    Frequently Asked Questions
    What is gravitational field strength in simple terms?
    Gravitational field strength (g) is the gravitational force experienced per unit mass at a point in a gravitational field. It tells you how strong the gravitational pull is at that location. For example, on Earth's surface, g is about 9.81 N kg^-1, meaning a 1 kg mass experiences a gravitational force of 9.81 N. It is a vector quantity, directed towards the centre of the mass creating the field.
    How do you calculate gravitational field strength?
    For a point mass or spherically symmetric body, use g = GM/r^2, where G is the gravitational constant (6.67 × 10^-11 N m^2 kg^-2), M is the mass of the body, and r is the distance from its centre. For a uniform field near a planet's surface, g = F/m, where F is the gravitational force on a mass m. Always ensure r is the distance from the centre, so add the altitude to the planet's radius if necessary.
    Why does gravitational field strength decrease with altitude?
    Gravitational field strength follows an inverse square law with distance from the centre of the mass: g ∝ 1/r^2. As you go higher above a planet's surface, the distance r from the centre increases, so g decreases. For example, at an altitude equal to Earth's radius, g is one quarter of its surface value. This decrease is why astronauts experience weightlessness in orbit, although they are still within Earth's gravitational field.
    What is the difference between gravitational field strength and gravitational potential?
    Gravitational field strength (g) is a vector quantity representing the force per unit mass (N kg^-1) at a point. Gravitational potential (V) is a scalar quantity representing the work done per unit mass (J kg^-1) to bring a small test mass from infinity to that point. They are related by g = -dV/dr, meaning field strength is the negative gradient of potential. Both are negative for attractive fields, but g is always directed towards the mass, while V is a scalar.
    How does gravitational field strength vary inside a planet?
    Inside a uniform solid sphere, gravitational field strength is directly proportional to the distance from the centre: g = (4/3)πGρr. This means g increases linearly from zero at the centre to its maximum at the surface. This occurs because only the mass enclosed within the radius r contributes to the field at that point, according to the shell theorem. Outside the sphere, g follows the inverse square law, g = GM/r^2.
    What is the value of g on other planets?
    The value of g on a planet depends on its mass and radius: g = GM/R^2. For example, on Mars, g ≈ 3.72 N kg^-1; on Jupiter, g ≈ 24.8 N kg^-1; on the Moon, g ≈ 1.62 N kg^-1. These values are calculated using the planet's mass and mean radius. Comparing g values helps understand differences in weight and projectile motion on different celestial bodies.