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    Newton’s laws of motion — AQA A-Level Physics

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    Newton's laws of motion form the foundation of classical mechanics, describing how forces affect the motion of objects. The first law defines inertia and equilibrium, the second law quantifies the relationship between force, mass, and acceleration (F = ma), and the third law states that forces always occur in equal and opposite pairs.

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    Newton’s laws of motion explained

    Newton’s laws of motion covers 2 specification points, including Knowledge and application of the three laws of… and F = ma for situations where the mass is….

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    Open a point below for its explanation and revision guidance.

    Knowledge and application of the three laws of motion in appropriate situations.

    Newton’s three laws describe how forces change motion. The first law: a body stays at rest or moves at constant velocity unless a resultant external force acts; this defines inertia and explains why seatbelts are needed. The second law: resultant force equals rate of change of momentum, so for constant mass F = ma; a 2 kg trolley pushed with 6 N accelerates at 3 m s⁻². The third law: if A exerts a force on B, B exerts an equal magnitude, opposite direction force on A, acting on a different body; for example, a swimmer pushes water backwards and water pushes the swimmer forwards. Apply each law by identifying the body, listing forces, finding the resultant, then predicting motion.

    F = ma for situations where the mass is constant.

    When mass is constant, Newton’s second law becomes F = ma, where F is the resultant force in newtons, m is mass in kilograms and a is acceleration in metres per second squared. Use it to find any one quantity from the other two: a 1500 kg car with a resultant forward force of 3000 N accelerates at 2 m s⁻². Always find the resultant force by vector addition first, then substitute. The equation is vectorial, so acceleration is in the same direction as the resultant force. Rearranged forms a = F ÷ m and m = F ÷ a are equally valid. For motion on a slope, resolve weight into components parallel and perpendicular to the slope before applying F = ma along the direction of motion.

    Your focus

    1. State each of Newton’s three laws accurately.
    2. Identify action–reaction pairs acting on different bodies.
    3. Apply the laws to predict motion or calculate resultant force in a given situation.
    Show all 6 objectives
    1. Calculate resultant force, mass or acceleration using F = ma.
    2. Resolve forces to find the resultant along the direction of motion.
    3. Explain why F = ma applies only when mass is constant.

    Which command word is this?

    A brief answer with no explanation required. E.g., 'State Newton's second law.' Answer: 'The resultant force on an object is directly proportional to the rate of change of momentum, and for constant mass, F = ma.'

    Newton’s laws of motion exam tips

    Topic Overview

    Newton's laws of motion are three fundamental principles that describe the relationship between the motion of an object and the forces acting on it. They form the basis of classical mechanics and are essential for understanding topics such as dynamics, momentum, and energy. In AQA A-Level Physics, you will apply these laws to solve problems involving constant and non-constant acceleration, equilibrium, and systems of connected bodies.

    These laws are crucial because they allow you to predict how objects move under the influence of forces, from everyday situations like a car accelerating to more complex scenarios like a rocket launching. They also underpin many other areas of physics, including circular motion, oscillations, and gravitational fields. A solid grasp of Newton's laws is therefore essential for success in both exams and practical work.

    Key Concepts
    • →Newton's first law: An object remains at rest or moves with constant velocity unless acted upon by a resultant force. This introduces the concept of inertia and equilibrium.
    • →Newton's second law: The resultant force acting on an object is directly proportional to the rate of change of momentum. For constant mass, F = ma, where F is the resultant force, m is mass, and a is acceleration.
    • →Newton's third law: If object A exerts a force on object B, then object B exerts an equal and opposite force on object A. These forces are of the same type and act on different objects.
    • →Free-body diagrams: Essential for identifying all forces acting on a single object and resolving them to find the resultant force.
    • →Equilibrium: When the resultant force on an object is zero, it is in equilibrium and its acceleration is zero (it may be at rest or moving with constant velocity).
    Marking Points
    • State the first law as constant velocity or rest when the resultant force is zero, and link it to inertia.
    • Use the second law as resultant force equals rate of change of momentum, reducing to F = ma when mass is constant.
    • State the third law as two forces equal in magnitude, opposite in direction, of the same type, acting on two different bodies.
    • Apply the laws to a named situation by drawing a free-body diagram and resolving forces before calculating acceleration or identifying equilibrium.
    • Distinguish equilibrium (zero resultant force, constant velocity) from a body with a non-zero resultant force, which accelerates.
    • Identify F as the resultant force, found by adding all forces as vectors, not any single applied force.
    • Substitute consistent SI units: newtons, kilograms and metres per second squared.
    • Rearrange F = ma correctly to calculate acceleration or mass when required.
    • Resolve forces on a slope or at an angle before applying F = ma along the chosen direction.
    • Interpret a negative acceleration as deceleration or acceleration opposite to the chosen positive direction.
    Examiner Tips
    • 💡Name the law you are using and quote its condition before substituting values.
    • 💡Draw and label a free-body diagram; examiners reward clear force identification.
    • 💡Check units and directions: acceleration is in the direction of the resultant force.
    • 💡Write the equation, rearrange symbolically, then substitute numbers to reduce arithmetic slips.
    • 💡State the direction of the resultant force and acceleration in your answer.
    • 💡For slope problems, show the resolved weight component before using F = ma.
    • 💡Always draw a clear free-body diagram for each object in a problem. Label all forces and indicate directions. This helps you avoid missing forces and makes your reasoning clear to the examiner.
    • 💡When using F = ma, ensure you use the resultant force. If forces are at angles, resolve them into perpendicular components before summing.
    • 💡In explanations, be precise about which object forces act on. For Newton's third law, state the two objects involved and the type of force (e.g., gravitational, contact).
    Common Mistakes
    • Treating action and reaction as balanced forces on one body; correct by stating they act on different bodies and never cancel for a single object.
    • Assuming a moving object always has a resultant force; correct by noting constant velocity means zero resultant force.
    • Using F = ma with F as any single force rather than the resultant force; correct by summing vector forces first.
    • Forgetting to subtract friction or drag from the driving force; correct by calculating the resultant force first.
    • Mixing grams with kilograms or kilometres per hour with metres per second; correct by converting to SI units before substitution.
    • Treating F = ma as valid when mass changes, such as a rocket burning fuel; correct by using the momentum form for variable mass.
    • Misconception: Newton's third law pairs cancel out because they are equal and opposite. Correction: They act on different objects, so they do not cancel; each force affects a different body.
    • Misconception: An object moving at constant speed has no forces acting on it. Correction: It may have balanced forces (resultant force zero), but individual forces can still be present.
    • Misconception: Mass and weight are the same. Correction: Mass is a scalar measure of inertia (kg), while weight is a force (N) given by W = mg, where g is the gravitational field strength.
    Revision Plan
    1. 1Day 1-2: Review the three laws and their statements. Learn definitions and units. Practice identifying Newton's third law pairs in simple scenarios.
    2. 2Day 3-4: Master free-body diagrams. Draw diagrams for objects on inclines, in lifts, and connected by strings. Resolve forces into components.
    3. 3Day 5-6: Apply Newton's second law to solve problems with constant acceleration. Include problems with friction and tension. Check your answers for reasonableness.
    4. 4Day 7-8: Tackle more complex problems: systems of connected masses, objects in equilibrium, and motion with variable acceleration (using calculus if required).
    5. 5Day 9-10: Practice exam-style questions under timed conditions. Review mark schemes to understand what examiners expect. Focus on explanation questions and calculations.
    Exam Question Types
    • 📋Calculation of resultant force or acceleration using F = ma: Often involves resolving forces or using kinematics to find acceleration first. Advice: Draw a free-body diagram, resolve forces, and show all steps clearly.
    • 📋Explanation of Newton's third law in a given context: E.g., explain the forces involved when a person walks or a rocket accelerates. Advice: State the two objects, the type of force, and that the forces are equal in magnitude and opposite in direction.
    • 📋Analysis of motion with equilibrium: E.g., a car moving at constant speed, or an object on an inclined plane. Advice: State that resultant force is zero, resolve forces parallel and perpendicular to the plane, and solve for unknowns.
    • 📋Practical-based question: E.g., describe an experiment to investigate Newton's second law. Advice: Include measurements of mass, force, and acceleration; mention controlling variables and using light gates or data loggers.
    Command Word Expectations (AQA)
    State

    A brief answer with no explanation required. E.g., 'State Newton's second law.' Answer: 'The resultant force on an object is directly proportional to the rate of change of momentum, and for constant mass, F = ma.'

    Explain

    Provide a detailed account including reasons or mechanisms. E.g., 'Explain why a skydiver reaches terminal velocity.' Answer: 'As speed increases, drag increases; eventually drag equals weight, resultant force is zero, so acceleration is zero and velocity is constant.'

    Calculate

    Show your working, substitute values into the correct equation, and give the answer with appropriate units and significant figures. E.g., 'Calculate the acceleration.' Answer: 'a = F/m = 20/5 = 4 m/s^2.'

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often confuse Newton's third law pairs with balanced forces acting on the same object, leading to incorrect explanations of motion.
    ❌ Weak Answer (Loses Marks):The forces are equal and opposite so the object is in equilibrium.
    Example improved answer:Newton's third law pairs act on different objects, so they do not cancel out. For example, when a book rests on a table, the weight of the book acts on the table and the normal contact force from the table acts on the book. These are equal in magnitude and opposite in direction but act on different bodies, so they cannot be added to give zero net force on the book. The book is in equilibrium because the normal contact force on the book equals the weight of the book, both acting on the same object.
    Examiner Tip: Always state which object each force acts on. If the forces act on the same object, they can be balanced; if they act on different objects, they are a Newton's third law pair.
    Pitfall: In calculations using F = ma, students frequently forget to resolve forces or include all forces acting on the object, leading to incorrect net force.
    ❌ Weak Answer (Loses Marks):F = ma, so a = F/m = 10/2 = 5 m/s^2.
    Example improved answer:First, identify all forces acting on the object: weight (mg) downwards, normal contact force (N) upwards, and applied force (F) horizontally. Resolve vertically: N = mg = 2 * 9.81 = 19.62 N. Resolve horizontally: net force = F - friction = 10 - 2 = 8 N. Then apply Newton's second law: a = net force / mass = 8 / 2 = 4 m/s^2.
    Examiner Tip: Always draw a free-body diagram, resolve forces into components, and calculate the net force before applying F = ma. Check units and significant figures.
    Step-by-Step Worked Solutions

    Question: A car of mass 1200 kg accelerates uniformly from rest to 20 m/s in 8.0 s. Calculate the average resultant force acting on the car.

    1. 1.Step 1: Identify given facts: mass m = 1200 kg, initial velocity u = 0 m/s, final velocity v = 20 m/s, time t = 8.0 s.
    2. 2.Step 2: Calculate acceleration using a = (v - u) / t = (20 - 0) / 8.0 = 2.5 m/s^2.
    3. 3.Step 3: Apply Newton's second law: F = ma = 1200 * 2.5 = 3000 N.
    4. 4.Step 4: State final answer with unit: The average resultant force is 3000 N.
    Final Answer: 3000 N

    Question: A skydiver of mass 80 kg falls vertically. At a particular instant, the drag force acting upwards is 200 N. Calculate the acceleration of the skydiver at this instant.

    1. 1.Step 1: Identify forces: weight W = mg = 80 * 9.81 = 784.8 N downwards; drag D = 200 N upwards.
    2. 2.Step 2: Calculate resultant force: F_net = W - D = 784.8 - 200 = 584.8 N downwards.
    3. 3.Step 3: Apply Newton's second law: a = F_net / m = 584.8 / 80 = 7.31 m/s^2 downwards.
    4. 4.Step 4: State final answer: acceleration is 7.3 m/s^2 downwards (to 2 s.f.).
    Final Answer: 7.3 m/s^2 downwards
    Active Recall Memory Test
    State Newton's first law of motion.
    Key Fact: An object remains at rest or moves with constant velocity unless acted upon by a resultant force.
    What is the equation for Newton's second law when mass is constant?
    Key Fact: F = ma, where F is the resultant force, m is mass, and a is acceleration.
    Give an example of a Newton's third law pair of forces.
    Key Fact: When you push a wall, the wall pushes back on you with an equal and opposite force. These forces act on different objects (you and the wall).
    What is the condition for an object to be in equilibrium?
    Key Fact: The resultant force acting on the object is zero, so its acceleration is zero (it is at rest or moving with constant velocity).
    Frequently Asked Questions
    What is Newton's second law in simple terms?
    Newton's second law states that the acceleration of an object is directly proportional to the resultant force acting on it and inversely proportional to its mass. In equation form, F = ma, where F is the resultant force in newtons, m is mass in kilograms, and a is acceleration in metres per second squared. This means a larger force causes a larger acceleration, while a larger mass makes it harder to accelerate.
    How do I identify Newton's third law pairs?
    Newton's third law pairs always involve two objects and two forces of the same type. To identify them, ask: 'What is exerting a force on what?' For example, if a book rests on a table, the book exerts a downward contact force on the table, and the table exerts an upward contact force on the book. These are a third law pair because they are equal in magnitude, opposite in direction, act on different objects, and are both contact forces. Remember that weight and normal contact force are not a third law pair because they are different types of forces and act on the same object.
    What is the difference between mass and weight in Newton's laws?
    Mass is a scalar quantity that measures the amount of matter in an object and its resistance to acceleration (inertia). It is measured in kilograms (kg) and does not change with location. Weight is a vector force caused by gravity acting on mass, given by W = mg, where g is the gravitational field strength (about 9.81 N/kg on Earth). Weight is measured in newtons (N) and varies with location. In Newton's second law, F = ma uses mass, while weight is a force that must be included in the resultant force.
    How do I solve problems with connected masses using Newton's laws?
    For connected masses (e.g., two blocks tied by a string), treat the system as a whole to find the acceleration, then analyse individual objects to find internal forces like tension. First, draw free-body diagrams for each object. For the whole system, the resultant force is the sum of external forces, and the total mass is the sum of individual masses, so a = F_net / (m1 + m2). Then, for one object, apply F = ma to find tension. Remember that the string is inextensible, so both objects have the same acceleration, and the tension is the same throughout a massless string.
    Why does a rocket accelerate upwards if the forces are equal and opposite?
    A rocket accelerates upwards because the forces in Newton's third law act on different objects. The rocket exerts a downward force on the exhaust gases, and the exhaust gases exert an equal and opposite upward force on the rocket. The upward force on the rocket is greater than the downward weight of the rocket (at least during launch), so there is a resultant upward force causing acceleration. The downward force on the gases does not act on the rocket, so it does not cancel the upward force.
    What is terminal velocity and how does it relate to Newton's laws?
    Terminal velocity is the constant speed reached by a falling object when the drag force equals its weight. Initially, weight is greater than drag, so there is a resultant downward force and the object accelerates. As speed increases, drag increases until it equals weight. At this point, the resultant force is zero (Newton's first law), so acceleration is zero and the object falls at a constant speed. This is an application of Newton's second law: when F_net = 0, a = 0.