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    Dynamics — OCR A-Level Physics

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    Dynamics explained

    Newton's second law states that the net force acting on an object equals its mass multiplied by its acceleration, written F = ma.

    Read the full explanation

    The force in the equation is the resultant of all forces acting on the object, not any single applied force, and the acceleration is in the same direction as that resultant. The equation applies instantaneously to constant-mass systems, even if the acceleration is non-uniform, and it links cause and effect: a larger net force gives a larger acceleration, while a larger mass gives a smaller acceleration for the same net force. For example, a 2.0 kg trolley pushed by a resultant force of 6.0 N accelerates at 3.0 m s⁻², since 6.0 N ÷ 2.0 kg = 3.0 m s⁻².

    (b) the newton as the unit of force

    The newton is the SI unit of force, defined as the force that gives a mass of one kilogram an acceleration of one metre per second squared. In base units this is written 1 N = 1 kg m s⁻², which follows directly from F = ma. Because the newton is a derived unit, it can always be broken down into kilograms, metres and seconds, which is useful for checking that equations are homogeneous. For example, a resultant force of 5 N acting on a 2 kg mass produces an acceleration of 2.5 m s⁻², and the unit of that result, m s⁻², matches the base-unit form of the newton divided by the kilogram.

    (c) weight of an object; W = mg

    Weight is the gravitational force acting on an object, calculated as W = mg, where m is mass in kilograms and g is gravitational field strength in newtons per kilogram (N kg⁻¹). On Earth, g ≈ 9.81 N kg⁻¹, so a 2.0 kg mass has weight W = 2.0 × 9.81 = 19.62 N. Weight is a vector directed towards the centre of the gravitating body. Mass is a scalar measure of inertia, constant everywhere, while weight varies with g. In an MCQ, you may be asked to calculate weight, identify units, or distinguish mass from weight. Always convert grams to kilograms before substituting. The equation applies to a uniform gravitational field, which is a good approximation near a planet's surface.

    (d) the terms tension, normal contact force, upthrust and friction

    Tension is the pulling force transmitted through a string, rope or cable when it is stretched. Normal contact force acts perpendicular to a surface where two objects touch. Upthrust is the upward force exerted by a fluid on an object immersed in it, due to pressure differences. Friction opposes relative motion or the tendency of relative motion between surfaces in contact. In MCQs, you may identify which force acts in a given situation, or match descriptions to terms. For example, a book on a table experiences a normal contact force upwards; a submerged ball experiences upthrust; a box sliding on a floor experiences friction; a hanging mass experiences tension in the string. Recognise the direction and origin of each force.

    (e) free-body diagrams

    A free-body diagram shows a single object isolated from its surroundings, with all external forces acting on it represented as arrows. Each arrow's length indicates magnitude and its direction shows the force's direction. The object is drawn as a simple shape or dot. Forces to include: weight, normal contact force, tension, friction, upthrust, applied forces. Do not include forces the object exerts on other things. For example, a block on a rough slope has weight downwards, normal contact force perpendicular to the slope, and friction along the slope. In MCQs, you may select the correct diagram or identify a missing force. Ensure arrows start from the object and are labelled.

    (f) one- and two-dimensional motion under constant force.

    Motion under constant force involves constant acceleration, described by the equations of motion (suvat): v = u + at, s = ut + ½at², v² = u² + 2as, s = ½(u + v)t. In one dimension, motion is along a straight line; in two dimensions, motion can be split into independent perpendicular components, often horizontal and vertical. For projectile motion, horizontal acceleration is zero (constant velocity) and vertical acceleration is g downwards. For example, a ball thrown horizontally: horizontal distance x = uₓt, vertical drop y = ½gt². In MCQs, you may calculate a quantity using suvat, resolve vectors, or identify independence of components. Always define a positive direction and use consistent signs.

    (a) drag as the frictional force experienced by an object travelling through a fluid

    Drag is a contact force that opposes the motion of an object through a fluid, where a fluid is any liquid or gas. It acts along the line of motion but in the opposite direction to velocity, so it always removes kinetic energy from the object. Unlike solid friction, drag depends strongly on speed and on the shape and size of the object. For example, a skydiver falling at 50 m s⁻¹ experiences far greater drag than the same skydiver moving at 5 m s⁻¹. Drag arises because the object must push fluid aside and because fluid layers slide past one another, producing viscous forces. In this section you treat drag as a resistive force to be included in free-body diagrams and in Newton's second law calculations.

    (b) factors affecting drag for an object travelling through air

    For an object moving through air, the size of the drag force depends on several factors. Speed is the most important: drag increases as speed increases, and at higher speeds drag grows roughly with the square of speed. The cross-sectional area of the object also matters, because a larger area pushes more air aside. The shape of the object affects how smoothly air flows around it, so a streamlined shape reduces drag compared with a blunt shape. The density of the air is another factor, since denser air provides more resistance. Surface roughness can also influence drag by changing the flow near the surface. In calculations you may be told which factors are held constant so that you can isolate the effect of one variable.

    (c) motion of objects falling in a uniform gravitational field in the presence of drag

    When an object falls in a uniform gravitational field with drag present, its acceleration is not constant. At release, speed is zero so drag is zero and the object accelerates at g. As speed rises, drag increases, reducing the resultant force and therefore the acceleration. The object reaches terminal velocity, a constant maximum speed, when drag equals weight and the resultant force is zero. Before terminal velocity, the object accelerates at a continuously decreasing rate. A velocity–time graph shows a curve with its maximum gradient at t=0, which then continuously flattens as terminal velocity is approached. The same analysis applies to an object projected upwards, where weight and drag both act downwards.

    (d)

    This row is a guided reading entry for section 3.2.1 Dynamics. The statement is empty, so there is no assessed content to teach here. Use this row to direct learners to the relevant specification statements (a), (b) and (c) on drag, factors affecting drag in air, and motion of falling objects with drag. Learners should read the specification text alongside their textbook or class notes, then check that they can define drag, list the factors affecting drag in air, and explain terminal velocity using the balance of weight and drag. No marks are awarded for this row; it is a study guide only.

    (i) terminal velocity

    Terminal velocity is the constant velocity reached by a falling object when the resultant force on it is zero. As an object falls through a fluid, its weight acts downwards while drag and upthrust act upwards. Drag increases with speed, so the resultant downward force decreases and acceleration falls. Eventually drag plus upthrust equals weight, the resultant force is zero, and velocity stays constant. For a skydiver, terminal velocity is reached before the parachute opens; opening the parachute increases drag, so the skydiver decelerates to a new, lower terminal velocity. The key idea is that zero resultant force means zero acceleration, not zero velocity.

    (ii) techniques and procedures used to determine terminal velocity in fluids.

    To determine terminal velocity in a fluid, release an object into a tall column of fluid and measure its velocity after it has had time to reach constant speed. A common method uses a tall measuring cylinder of glycerol or oil with a ball bearing or small sphere. Mark two horizontal lines a known distance apart near the bottom of the column, where the sphere is already moving at terminal velocity. Use a stopwatch or light gates to measure the time taken to travel between the lines, then calculate velocity as distance divided by time. Repeat and average to reduce random error. The sphere must be small and the fluid deep enough that terminal velocity is reached before the timing section.

    Your focus

    1. State and apply the relationship net force = mass × acceleration.
    2. Determine the resultant force on an object from a free-body diagram.
    3. Solve problems involving force, mass and instantaneous acceleration in one dimension.
    Show all 36 objectives
    1. State the definition of the newton in terms of mass and acceleration.
    2. Express the newton in SI base units as kg m s⁻².
    3. Use base-unit analysis to check the consistency of force equations.
    4. State that weight is the gravitational force on an object and is calculated using W = mg.
    5. Distinguish between mass and weight in terms of scalar/vector nature and units.
    6. Calculate weight from mass using an appropriate value of g, with correct unit conversion.
    7. Define tension, normal contact force, upthrust and friction.
    8. Identify which force acts in a given physical situation.
    9. Describe the direction and origin of each force.
    10. Draw a free-body diagram for an object in a given situation.
    11. Identify all external forces acting on an object.
    12. Use free-body diagrams to determine resultant force and motion.
    13. Apply the suvat equations to one-dimensional motion under constant force.
    14. Resolve motion into perpendicular components and solve two-dimensional problems.
    15. Analyse projectile motion by treating horizontal and vertical components independently.
    16. Define drag as a frictional force opposing motion through a fluid.
    17. Recognise that gases as well as liquids are fluids for the purpose of drag.
    18. Represent drag correctly on a free-body diagram with direction opposite to velocity.
    19. List the factors that affect drag on an object moving through air.
    20. Explain how speed, area, shape and air density each influence drag.
    21. Apply the idea of controlled variables when comparing drag in different situations.
    22. Describe how drag changes during the fall of an object in a uniform gravitational field.
    23. Explain why acceleration decreases continuously and eventually becomes zero at terminal velocity.
    24. Interpret a velocity–time graph for an object falling with drag, noting the decreasing gradient.
    25. Locate and read the specification statements on drag and terminal velocity.
    26. Summarise the key ideas from statements (a), (b) and (c) in your own words.
    27. Self-assess understanding by explaining terminal velocity without notes.
    28. Define terminal velocity as motion at constant velocity with zero resultant force.
    29. Describe how drag and upthrust change as a falling object's speed increases.
    30. Explain why opening a parachute produces a new, lower terminal velocity.
    31. Describe a procedure to measure terminal velocity of a sphere falling in a fluid.
    32. Calculate terminal velocity from measured distance and time.
    33. Evaluate sources of error and explain how repeats improve reliability.

    Dynamics exam tips

    Marking Points
    • The net force on an object equals its mass multiplied by its acceleration, F = ma.
    • The force in the equation is the resultant of all forces acting on the object, not a single applied force.
    • The acceleration is in the same direction as the net force.
    • For a constant mass, acceleration is directly proportional to the net force and inversely proportional to the mass.
    • The equation applies instantaneously to constant-mass systems, including those with non-uniform acceleration, and the newton is defined so that 1 N = 1 kg m s⁻².
    • The newton is the SI unit of force.
    • One newton is the force that gives a mass of one kilogram an acceleration of one metre per second squared.
    • In base units, 1 N = 1 kg m s⁻².
    • The newton is a derived unit, obtained from the relationship F = ma.
    • Base-unit analysis of the newton can be used to check the homogeneity of force equations.
    • Weight is the gravitational force on an object, given by W = mg.
    • m is mass in kg; g is gravitational field strength in N kg⁻¹.
    • Weight is a vector directed towards the centre of the gravitating body.
    • Mass is a scalar and constant; weight varies with gravitational field strength.
    • Typical value on Earth: g ≈ 9.81 N kg⁻¹, so W = mg gives weight in newtons.
    • Correct unit conversion: 1 g = 1 × 10⁻³ kg before substitution.
    • Tension is a pulling force in a string, rope or cable.
    • Normal contact force acts perpendicular to a surface at the point of contact.
    • Upthrust is an upward force on an object in a fluid due to pressure difference.
    • Friction opposes relative motion or the tendency of relative motion between surfaces.
    • Each force has a specific direction and origin; identify them from the physical situation.
    • A free-body diagram shows one object isolated with all external forces acting on it.
    • Forces are represented by arrows; length indicates magnitude, direction indicates direction.
    • Only forces acting on the object are included, not forces it exerts on other objects.
    • Common forces: weight, normal contact force, tension, friction, upthrust, applied force.
    • The diagram helps analyse equilibrium or acceleration using Newton's laws.
    • Constant force produces constant acceleration, so the suvat equations apply.
    • In one dimension, motion is along a straight line; use suvat with consistent signs.
    • In two dimensions, resolve motion into perpendicular components that are independent.
    • For projectile motion, horizontal acceleration is zero and vertical acceleration is g downwards.
    • Use suvat separately for each direction; time is common to both.
    • Define a positive direction and apply signs consistently.
    • Drag is a force that opposes the motion of an object through a fluid.
    • A fluid includes both liquids and gases, so air counts as a fluid.
    • Drag acts in the direction opposite to the object's velocity.
    • Drag is a contact or resistive force, not a field force such as weight.
    • Drag magnitude depends on speed, shape and size of the object, unlike simple solid friction.
    • Drag on an object in air increases as the object's speed increases.
    • A larger cross-sectional area produces a larger drag force.
    • A streamlined shape reduces drag compared with a blunt or flat shape.
    • Air density affects drag: denser air gives greater drag for the same object and speed.
    • Surface roughness or texture can affect drag by altering the airflow near the surface.
    • Initially the object accelerates at g because drag is zero at zero speed.
    • As speed increases, drag increases and the resultant force decreases, so acceleration decreases.
    • Terminal velocity is reached when drag equals weight, so resultant force and acceleration are zero.
    • At terminal velocity the object moves at constant speed in a straight line.
    • A velocity–time graph for the fall has its steepest gradient at t=0 and continuously flattens until it becomes horizontal at terminal velocity.
    • Terminal velocity occurs when the resultant force on a falling object is zero.
    • At terminal velocity the object moves at constant velocity, so acceleration is zero.
    • Weight acts downwards; drag and upthrust act upwards through the fluid.
    • Drag increases with speed until drag plus upthrust balances weight.
    • A change in shape or area, such as opening a parachute, changes the terminal velocity.
    • Use a tall column of fluid so the object reaches terminal velocity before measurements begin.
    • Measure a known distance between two marks or light gates.
    • Time the object over that distance using a stopwatch or light gates.
    • Calculate velocity using v = s / t.
    • Repeat measurements and calculate a mean to reduce random error.
    • Control variables such as temperature, fluid depth and sphere size to make results reliable.
    Examiner Tips
    • 💡Draw a free-body diagram and resolve forces before calculating the resultant force to substitute into F = ma.
    • 💡Check that all quantities are in SI units, converting grams to kilograms and so on, before substituting.
    • 💡State the direction of the acceleration alongside its magnitude, since the equation is a vector relationship.
    • 💡Convert all quantities to SI base units before substituting into F = ma so the answer comes out in newtons.
    • 💡Use base-unit analysis to check that both sides of an equation have the same units.
    • 💡Give the direction of a force as well as its magnitude when the question asks for the force.
    • 💡Underline the mass value and its unit in the question; convert to kg immediately if it is in grams.
    • 💡Write the equation W = mg, substitute numbers with units, and give the answer in newtons.
    • 💡Check whether the question asks for weight or mass; the unit N indicates weight, kg indicates mass.
    • 💡Read the scenario carefully and identify the contact surfaces or fluid involved.
    • 💡Match the direction of the force to the term: upthrust is always upward, normal contact force is perpendicular to the surface.
    • 💡For friction, ask whether it is opposing motion or the tendency of motion.
    • 💡Draw the object as a dot or simple box and draw all forces starting from it.
    • 💡Label each arrow clearly (e.g. W, N, T, F) and ensure directions are correct.
    • 💡Check that you have not included any internal forces or forces on other objects.
    • 💡List the suvat variables you know and the one you need before choosing an equation.
    • 💡For two-dimensional motion, draw a diagram and resolve initial velocity into components.
    • 💡Use the same time t for horizontal and vertical parts of projectile motion.
    • 💡Read the stem carefully to check whether the object is in a liquid or a gas; both are fluids.
    • 💡When a free-body diagram is required, draw the drag arrow clearly opposite to the velocity arrow.
    • 💡Use the phrase 'opposes motion' rather than 'slows down' to show precise physical language.
    • 💡When comparing two objects, identify which factors are controlled and which are changed.
    • 💡Use the term 'cross-sectional area' rather than just 'size' for precision.
    • 💡Link shape to airflow: streamlined shapes allow air to flow smoothly, reducing drag.
    • 💡Sketch the velocity–time graph starting with a steep gradient that continuously flattens to a horizontal section to show terminal velocity.
    • 💡State the condition for terminal velocity as drag equals weight, giving zero resultant force.
    • 💡Use the terms 'resultant force' and 'acceleration' together to explain the changing motion.
    • 💡Read statements (a), (b) and (c) as a single topic rather than in isolation.
    • 💡After reading, close the book and write down the definition of drag and the condition for terminal velocity.
    • 💡Use the specification wording to check that your notes cover every clause before moving on.
    • 💡State clearly that resultant force is zero at terminal velocity.
    • 💡Link constant velocity to zero acceleration in your explanation.
    • 💡Use a free-body diagram to show weight downwards and drag plus upthrust upwards.
    • 💡When a parachute opens, explain that increased drag causes deceleration to a lower terminal velocity.
    • 💡Describe the apparatus clearly, including a tall measuring cylinder and two marks.
    • 💡State the equation v = s / t and define each symbol.
    • 💡Explain how you know terminal velocity has been reached, for example by checking that times between successive equal distances are equal.
    • 💡Mention one control variable and one safety precaution, such as using a clamped cylinder to avoid spills.
    Common Mistakes
    • Substituting a single applied force into F = ma instead of the resultant of all forces acting on the object.
    • Treating mass and weight as the same quantity: mass is measured in kilograms, while weight is a force measured in newtons.
    • Assuming F = ma only applies to constant acceleration: correct this by remembering it applies instantaneously to non-uniform acceleration as long as mass is constant.
    • Writing the newton as a base unit rather than a derived unit: it is defined in terms of kilograms, metres and seconds.
    • Confusing the newton with the kilogram: the kilogram measures mass, while the newton measures force.
    • Omitting the direction when stating a force in newtons: force is a vector quantity, so its direction matters.
    • Using the wrong base-unit form, such as kg m s⁻¹, instead of kg m s⁻², when checking an equation.
    • Confusing mass and weight: mass is a scalar measure of inertia in kg, while weight is a force in N; correct by stating W = mg and using newtons for weight.
    • Using grams directly in W = mg: this gives a value 1000 times too large; correct by converting mass to kilograms first.
    • Treating g as 10 N kg⁻¹ when the question expects 9.81 N kg⁻¹: this loses precision; correct by using the value given or the standard 9.81 N kg⁻¹ unless told otherwise.
    • Thinking weight is always the same everywhere: weight depends on g, so it changes on other planets or at altitude; correct by recognising g varies.
    • Calling the normal contact force 'normal force' without specifying it is perpendicular to the surface; correct by stating it acts at right angles to the contact surface.
    • Thinking upthrust depends on the object's weight rather than the fluid displaced; correct by linking upthrust to fluid pressure difference and Archimedes' principle.
    • Believing friction always opposes motion; friction can also cause motion (e.g. walking) by opposing the tendency of relative motion; correct by stating it opposes relative motion or its tendency.
    • Confusing tension with compression; tension pulls, compression pushes; correct by noting tension is a pulling force in a stretched string.
    • Including forces that the object exerts on other objects; correct by showing only forces acting on the chosen object.
    • Drawing weight as a line from the centre but forgetting to label it; correct by labelling each arrow with the type of force.
    • Omitting the normal contact force when an object rests on a surface; correct by including a force perpendicular to the surface.
    • Drawing arrows with incorrect relative lengths when magnitudes are known; correct by scaling arrow lengths to represent relative magnitudes.
    • Using suvat equations when acceleration is not constant; correct by checking that the force is constant before applying them.
    • Mixing up horizontal and vertical components in projectile motion; correct by treating them separately with their own suvat calculations.
    • Forgetting that vertical acceleration is g downwards and taking it as positive when upward is positive; correct by assigning signs consistently.
    • Assuming horizontal velocity changes in projectile motion; correct by recognising horizontal acceleration is zero (ignoring air resistance).
    • Thinking drag only acts in liquids: correct this by noting that gases such as air are fluids, so a falling object in air experiences drag.
    • Treating drag as a constant force like weight: correct this by recognising that drag changes with speed and can vary during motion.
    • Drawing drag in the same direction as velocity: correct this by always drawing the drag arrow opposing the velocity vector.
    • Assuming drag depends only on speed: correct this by recalling that area, shape and air density also matter.
    • Thinking a heavier object always has more drag: correct this by noting that drag depends on shape, area and speed, not directly on mass.
    • Believing a streamlined shape increases drag: correct this by stating that streamlining reduces drag by allowing smoother airflow.
    • Thinking acceleration stays equal to g throughout the fall: correct this by noting that drag reduces the resultant force as speed increases.
    • Believing the object stops accelerating only when it hits the ground: correct this by identifying terminal velocity as the point where drag equals weight.
    • Thinking the velocity-time graph steepens initially: correct this by remembering the maximum acceleration, and thus maximum gradient, is at the instant of release.
    • Treating this empty row as an examinable statement: correct this by recognising it is a guided reading entry with no assessed content.
    • Skipping the linked statements (a), (b) and (c): correct this by reading them together as one topic on drag and terminal velocity.
    • Memorising definitions without checking understanding: correct this by explaining each idea in your own words and testing yourself with past-paper questions.
    • Thinking terminal velocity means the object has stopped: it is moving at constant velocity, not at rest.
    • Believing acceleration is maximum at terminal velocity: acceleration is zero because the resultant force is zero.
    • Ignoring upthrust and treating drag alone as balancing weight: in a fluid, drag plus upthrust balances weight.
    • Assuming terminal velocity is the same for all objects: it depends on weight, shape and the fluid.
    • Timing from the moment of release: the object is still accelerating, so measure only after it has reached constant speed.
    • Using a short fluid column: the object may not reach terminal velocity before the timing section.
    • Measuring distance with a ruler without accounting for parallax: read the scale at eye level.
    • Taking only one reading: repeat and average to reduce random error.