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    Using ultrasound — OCR A-Level Physics

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    Using ultrasound explained

    Ultrasound is a longitudinal wave with a frequency above 20 kHz, the upper limit of normal human hearing.

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    In a longitudinal wave, particles oscillate parallel to the direction of energy transfer, producing compressions and rarefactions. For example, a 2.5 MHz ultrasound pulse used in medical imaging has a frequency of 2.5 × 10⁶ Hz, far above 20 kHz. The wave travels through a medium at a speed determined by the medium's properties, and its frequency remains constant when crossing boundaries, while wavelength changes. In an MCQ, you may be asked to identify the correct definition, compare ultrasound with audible sound, or calculate frequency from period using f = 1/T. Always check that the stated frequency exceeds 20 kHz and that the wave is described as longitudinal, not transverse.

    (b) piezoelectric effect; ultrasound transducer as a device that emits and receives ultrasound

    The piezoelectric effect is the production of a potential difference across certain crystals when they are mechanically deformed, and the reverse effect where an applied potential difference causes the crystal to change shape. An ultrasound transducer uses a piezoelectric crystal, such as quartz or lead zirconate titanate, to emit and receive ultrasound. In emission, an alternating potential difference is applied across the crystal, causing it to vibrate at the driving frequency and produce ultrasound. In reception, incoming ultrasound waves deform the crystal, generating a small alternating potential difference that can be detected and processed. In an MCQ, you may need to identify the correct sequence or distinguish emission from reception. Remember that the same transducer can perform both functions, often switching rapidly between them.

    (c) ultrasound A-scan and B-scan

    Ultrasound A-scan and B-scan are two display modes used in medical imaging. An A-scan (amplitude scan) displays the amplitude of reflected ultrasound pulses against time or depth on a single axis, producing a one-dimensional trace with peaks corresponding to boundaries between media. It is used, for example, in measuring the length of the eye or detecting flaws in materials. A B-scan (brightness scan) uses the same pulse-echo principle but displays the intensity of reflections as brightness on a two-dimensional image, building up a cross-sectional picture by scanning the transducer across the region. In an MCQ, you may be asked to match each scan type to its display or application. Remember that A-scan gives depth information along a line, while B-scan gives a 2D image.

    (d) acoustic impedance of a medium; Z = ρc

    Acoustic impedance Z of a medium is the product of its density ρ and the speed of ultrasound c in that medium, given by Z = ρc. The SI unit of Z is kg m⁻² s⁻¹, which is equivalent to Pa s m⁻¹. Acoustic impedance determines how much ultrasound is reflected at a boundary between two media: a large difference in Z produces a strong reflection, while a small difference produces weak reflection. For example, the acoustic impedance of soft tissue is about 1.6 × 10⁶ kg m⁻² s⁻¹, and that of air is much lower, so ultrasound is almost totally reflected at a tissue–air boundary. In an MCQ, you may be asked to calculate Z from ρ and c, or to compare reflection at different boundaries. Ensure you use consistent SI units: density in kg m⁻³ and speed in m s⁻¹.

    (e) reflection of ultrasound at a boundary; Iᵣ/I₀ = (Z₂ − Z₁)²/(Z₂ + Z₁)²

    When ultrasound meets a boundary between two media, part of the wave is reflected and part is transmitted. The reflected fraction depends on the acoustic impedances Z₁ and Z₂ of the two media. The intensity reflection coefficient is Iᵣ/I₀ = (Z₂ − Z₁)²/(Z₂ + Z₁)². Here I₀ is the incident intensity and Iᵣ is the reflected intensity. If Z₁ = Z₂, the numerator is zero, so no reflection occurs. A large impedance mismatch gives strong reflection. For example, at a soft-tissue–air boundary, Z₂ is much smaller than Z₁, so the fraction reflected is close to 1. This is why a coupling gel is needed in scanning. In an MCQ, you may be asked to calculate the ratio, identify the condition for maximum reflection, or explain why a gel improves transmission.

    (f) impedance

    Acoustic impedance Z is a property of a medium that describes how much resistance it offers to the passage of ultrasound. It is defined as Z = ρc, where ρ is the density of the medium and c is the speed of ultrasound in that medium. The unit of Z is kg m⁻² s⁻¹. Values differ widely between media: air has a very low impedance, soft tissue is intermediate, and bone has a high impedance. This matters because the fraction of ultrasound reflected at a boundary depends on the difference in impedance between the two media. In an MCQ, you may be asked to calculate Z from density and speed, to identify its unit, or to compare impedances of different media.

    (acoustic) matching; special gel used in ultrasound scanning

    Acoustic matching is the technique of choosing a coupling medium whose acoustic impedance is close to that of the skin, so that ultrasound passes efficiently from the transducer into the body. In ultrasound scanning, a special gel is applied between the transducer and the skin. The gel has an acoustic impedance similar to that of soft tissue, so it reduces the impedance mismatch at the skin surface. Without the gel, an air layer would cause almost total reflection because air has a very low impedance compared with skin. The gel also fills any irregularities between the transducer and the skin, ensuring good contact. In an MCQ, you may be asked why the gel is used, what property it must have, or what happens if it is omitted.

    (g) Doppler effect in ultrasound; speed of blood in the patient; Δf/f = (2v cos θ)/c for determining the speed v of blood.

    The Doppler effect occurs when ultrasound is reflected from moving blood cells. The frequency of the reflected wave is shifted by an amount Δf compared with the transmitted frequency f. The speed v of the blood can be found using Δf/f = (2v cos θ)/c, where c is the speed of ultrasound in blood and θ is the angle between the ultrasound beam and the direction of blood flow. The factor 2 arises because the ultrasound is Doppler shifted twice: once on the way to the moving cells and once on the way back. The cos θ term accounts for the component of blood velocity along the beam. In an MCQ, you may be asked to calculate v, to explain the factor 2, or to describe how θ affects the measurement.

    Your focus

    1. State that ultrasound is a longitudinal wave with frequency greater than 20 kHz.
    2. Distinguish ultrasound from audible sound and infrasound by frequency range.
    3. Describe particle oscillation in a longitudinal wave as parallel to energy transfer.
    Show all 24 objectives
    1. Describe the piezoelectric effect as a reversible conversion between mechanical deformation and potential difference.
    2. Explain how a piezoelectric crystal in a transducer emits ultrasound when an alternating potential difference is applied.
    3. Explain how a piezoelectric crystal in a transducer receives ultrasound by generating a potential difference.
    4. Describe how an A-scan displays reflected ultrasound amplitude against time or depth.
    5. Describe how a B-scan builds a two-dimensional image from reflection brightness.
    6. Distinguish between the uses of A-scan and B-scan in medical and industrial contexts.
    7. Define acoustic impedance as Z = ρc and state its SI unit.
    8. Calculate acoustic impedance from density and ultrasound speed.
    9. Explain how differences in acoustic impedance affect reflection at boundaries.
    10. State the equation for the intensity reflection coefficient at a boundary.
    11. Calculate the fraction of ultrasound intensity reflected given two acoustic impedances.
    12. Explain why reflection is strong at a soft-tissue–air boundary and why coupling gel is used.
    13. Define acoustic impedance and state its unit.
    14. Calculate acoustic impedance from density and speed of ultrasound.
    15. Compare acoustic impedances of different media and relate them to reflection.
    16. Explain the purpose of acoustic matching in ultrasound scanning.
    17. Describe the role of the special gel in reducing reflection at the skin surface.
    18. Relate the gel's acoustic impedance to that of soft tissue.
    19. State the equation for the Doppler shift in ultrasound and explain each term.
    20. Calculate the speed of blood from a measured frequency shift.
    21. Explain the role of the angle θ and the factor 2 in the Doppler equation.

    Using ultrasound exam tips

    Marking Points
    • Ultrasound is a longitudinal wave.
    • Its frequency is greater than 20 kHz.
    • In a longitudinal wave, particle oscillations are parallel to the direction of energy transfer.
    • Audible sound for humans typically spans 20 Hz to 20 kHz, so ultrasound lies above this range.
    • Frequency remains constant when a wave crosses a boundary; wavelength and speed may change.
    • The piezoelectric effect involves converting between mechanical deformation and potential difference in a crystal.
    • An ultrasound transducer contains a piezoelectric crystal.
    • In emission, an alternating potential difference is applied, causing the crystal to vibrate and produce ultrasound.
    • In reception, incident ultrasound deforms the crystal, producing a potential difference.
    • The same transducer can both emit and receive ultrasound.
    • A-scan displays reflected pulse amplitude against time or depth on a one-dimensional trace.
    • B-scan displays reflection intensity as brightness to form a two-dimensional image.
    • Both A-scan and B-scan rely on pulse-echo reflection at boundaries between media.
    • A-scan is used for depth measurement along a single line, such as eye length or flaw detection.
    • B-scan is used for cross-sectional imaging, such as foetal scanning.
    • Acoustic impedance Z is defined as Z = ρc, where ρ is density and c is the speed of ultrasound in the medium.
    • The SI unit of Z is kg m⁻² s⁻¹.
    • A large difference in acoustic impedance between two media causes a large proportion of ultrasound to be reflected.
    • A small difference in acoustic impedance causes little reflection and most ultrasound to be transmitted.
    • Acoustic impedance depends on both the density of the medium and the speed of ultrasound in it.
    • State that the intensity reflection coefficient gives the fraction of incident intensity reflected at a boundary.
    • Use the equation Iᵣ/I₀ = (Z₂ − Z₁)²/(Z₂ + Z₁)² correctly, squaring the difference and the sum.
    • Recognise that reflection is zero when the two acoustic impedances are equal.
    • Recognise that reflection is large when the impedance mismatch is large.
    • Relate strong reflection at a soft-tissue–air boundary to the need for coupling gel.
    • Define acoustic impedance as Z = ρc, where ρ is density and c is the speed of ultrasound in the medium.
    • State the unit of acoustic impedance as kg m⁻² s⁻¹.
    • Calculate acoustic impedance from given values of density and speed.
    • Compare acoustic impedances of different media, such as air, soft tissue and bone.
    • Relate impedance mismatch to the intensity reflection coefficient.
    • State that acoustic matching aims to reduce the impedance mismatch between the transducer and the skin.
    • Explain that the gel has an acoustic impedance similar to that of soft tissue.
    • Explain that without the gel, an air layer causes almost total reflection of ultrasound.
    • Describe how the gel improves transmission of ultrasound into the body.
    • Recognise that the gel also ensures good acoustic contact by filling irregularities.
    • State that the Doppler effect causes a change in frequency when ultrasound is reflected from moving blood cells.
    • Use the equation Δf/f = (2v cos θ)/c to determine the speed v of blood.
    • Explain that the factor 2 arises because the ultrasound is Doppler shifted twice.
    • Explain that θ is the angle between the ultrasound beam and the direction of blood flow.
    • Recognise that the measured frequency shift depends on cos θ, so the beam should be as parallel as possible to the flow for maximum sensitivity.
    Examiner Tips
    • 💡Underline the words 'longitudinal' and 'greater than 20 kHz' in the question before choosing an option.
    • 💡If a period is given, calculate f = 1/T and compare the result with 20 kHz.
    • 💡Eliminate options that describe ultrasound as electromagnetic or transverse.
    • 💡Link each stage to the correct energy transfer: electrical to mechanical for emission, mechanical to electrical for reception.
    • 💡Use the phrase 'alternating potential difference' when describing emission.
    • 💡Check whether the question asks about emission, reception, or both before selecting an option.
    • 💡Use the first letter as a memory aid: A for amplitude, B for brightness.
    • 💡Link each scan to a typical application: A-scan for distance measurement, B-scan for imaging.
    • 💡Check whether the question asks about the display method or the underlying principle; both use pulse-echo.
    • 💡Write down Z = ρc and substitute values with units before calculating.
    • 💡Check that density is in kg m⁻³ and speed is in m s⁻¹ to obtain Z in kg m⁻² s⁻¹.
    • 💡When comparing boundaries, calculate the difference in Z or the ratio to judge reflection strength.
    • 💡Check whether the question asks for a ratio, a percentage or a fraction; convert carefully if needed.
    • 💡If one impedance is much larger than the other, the ratio approaches 1; use this to sanity-check your answer.
    • 💡Remember that the equation is symmetric: swapping Z₁ and Z₂ gives the same result.
    • 💡In multiple-choice questions, eliminate options that are greater than 1 or negative, since a fraction of intensity reflected cannot be outside 0 to 1.
    • 💡Check that density is in kg m⁻³ and speed is in m s⁻¹ before multiplying.
    • 💡Use the unit to check your calculation: kg m⁻³ × m s⁻¹ = kg m⁻² s⁻¹.
    • 💡Remember that impedance is a property of the medium, not of the wave.
    • 💡In multiple-choice questions, eliminate options with incorrect units or unrealistic magnitudes.
    • 💡Link the gel to the equation for intensity reflection: a smaller difference in Z gives a smaller reflected fraction.
    • 💡Remember that the gel is not a medicine; it is a coupling medium.
    • 💡If asked why not use water, note that gel is more convenient and stays in place, but the key physics is impedance matching.
    • 💡In multiple-choice questions, choose the option that mentions impedance matching or reducing reflection at the skin surface.
    • 💡Check that the angle θ is measured between the beam and the direction of flow, not between the beam and the vessel wall.
    • 💡If the beam is perpendicular to the flow, cos 90° = 0, so no Doppler shift is detected.
    • 💡Use consistent units: Δf and f in Hz, v and c in m s⁻¹.
    • 💡In multiple-choice questions, eliminate options that omit the factor 2 or use sin θ instead of cos θ.
    Common Mistakes
    • Describing ultrasound as a transverse wave: correct this by stating that ultrasound is longitudinal, with compressions and rarefactions.
    • Confusing the 20 kHz threshold with 20 Hz: correct this by remembering that ultrasound is above 20 kHz, while infrasound is below 20 Hz.
    • Thinking frequency changes when ultrasound enters a different medium: correct this by stating that frequency is set by the source and stays constant; speed and wavelength change.
    • Stating that the piezoelectric effect only converts sound to electricity: correct this by explaining that it is reversible and can convert electrical energy to mechanical vibration and vice versa.
    • Believing that the transducer only emits or only receives: correct this by noting that a single transducer can do both, often alternating roles.
    • Confusing the piezoelectric effect with the photoelectric effect: correct this by linking piezoelectricity to mechanical stress and crystal deformation, not to light.
    • Confusing A-scan and B-scan displays: correct this by remembering that A-scan shows amplitude versus depth (1D) and B-scan shows brightness (2D).
    • Thinking B-scan does not use pulses: correct this by stating that both modes use pulsed ultrasound and detect reflections.
    • Assuming A-scan produces a two-dimensional image: correct this by noting that A-scan is a one-dimensional trace of amplitude against time or depth.
    • Using density in g cm⁻³ without converting to kg m⁻³: correct this by converting to SI units before calculating Z.
    • Thinking that a large impedance difference means most ultrasound is transmitted: correct this by stating that a large difference causes strong reflection.
    • Confusing acoustic impedance with electrical impedance: correct this by defining Z as the product of density and ultrasound speed, with units kg m⁻² s⁻¹.
    • Forgetting to square the numerator and denominator; the correct form has both squared.
    • Mixing up Z₁ and Z₂; the equation is symmetric in Z₁ and Z₂, so the order does not change the result, but substituting the wrong values does.
    • Assuming that a large impedance difference gives a small reflected fraction; in fact a large difference gives a reflected fraction close to 1.
    • Using the equation for amplitude reflection rather than intensity reflection; the intensity ratio involves the square of the impedance difference over the sum.
    • Confusing acoustic impedance with electrical impedance; they are different quantities with different units.
    • Using the wrong unit, such as kg m⁻² s⁻² or kg m⁻³ s⁻¹; the correct unit is kg m⁻² s⁻¹.
    • Forgetting that c is the speed of ultrasound in the medium, not the speed of sound in air.
    • Mixing up density and speed when substituting into Z = ρc.
    • Thinking the gel is used to clean the skin or to cool the transducer; its main purpose is acoustic matching.
    • Believing the gel increases the speed of ultrasound in tissue; it does not change the speed in tissue, it reduces reflection at the surface.
    • Assuming the gel must have a very different impedance from skin to work; it must have a similar impedance.
    • Forgetting that air has very low acoustic impedance, which is why an air gap causes strong reflection.
    • Forgetting the factor 2 in the equation; the correct form has 2v cos θ in the numerator.
    • Using the speed of sound in air instead of the speed of ultrasound in blood; c must be the speed in the medium being scanned.
    • Confusing θ with the angle of reflection; θ is the angle between the beam and the direction of blood flow.
    • Assuming that a larger angle θ gives a larger frequency shift; in fact, cos θ decreases as θ increases, so the shift decreases.