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    Pressure in a fluid 2 (HT only) — AQA GCSE Physics

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    Pressure in a fluid 2 (HT only) explained

    The pressure at a depth in a liquid comes from the weight of the liquid above, so it depends on how deep you are, on how dense the liquid is and on the gravitational field strength.

    Read the full explanation

    It does not depend on the width of the container or on the total volume: a narrow tube and a wide tank filled to the same depth give the same pressure at the bottom, because a wider column of liquid has more weight but spreads it over proportionally more area. Every value must be in base units, so a depth in centimetres becomes metres and a density in grams per cubic centimetre becomes kilograms per cubic metre. At 3.0 m down in water of density 1000 kg/m³, with g taken as 9.8 N/kg, the pressure due to the water is about 29 kPa, on top of atmospheric pressure.

    Students should be able to calculate the differences in pressure at different depths in a liquid.

    A pressure difference between two depths needs only the difference in height, because the density and the field strength are the same at both. A diver ten metres deeper than another is at a pressure about 101 kPa greater in sea water, which is roughly one extra atmosphere for every ten metres of depth. The same idea explains why a dam is built much thicker at its base than at the top, why a water tank in a roof space gives good pressure at a ground-floor tap, and why the lowest hole in a punctured bottle squirts furthest. If a question asks for the absolute pressure at a depth rather than the difference, add atmospheric pressure, normally taken as about 100 kPa, to the pressure due to the liquid.

    A partially (or totally) submerged object experiences a greater pressure on the bottom surface than on the top surface.

    Pressure in a liquid grows with depth, so the lower face of a submerged block sits deeper than the upper face and the liquid pushes harder on it. Both pushes are normal to their faces, up on the bottom and down on the top, and the difference between them depends on the vertical height of the block and the density of the liquid, not on how deep the block is overall. The side faces are pushed inwards equally from both directions, so those forces cancel. A brick a tenth of a metre tall lying on the floor of a pool has about one kilopascal more pressure on its underside than on its top, and multiplying that difference by the area of the face gives the extra upward force.

    This creates a resultant force upwards.

    The downward push on the top face and the upward push on the bottom face do not cancel, because the bottom lies deeper and the pressure there is greater. Subtracting one from the other leaves a resultant that points straight up. Its size is the pressure difference multiplied by the area of the face, and that works out to be the weight of the fluid the object has pushed out of the way. This is why a stone feels lighter under water and why a boat with a large submerged volume can support a heavy load. The upward resultant does not depend on what the object is made of, only on the volume submerged and the density of the fluid, so a steel block and a wooden block of the same size receive exactly the same upward push.

    This force is called the upthrust.

    Upthrust is the name for that upward resultant, and it is a contact force, so mark schemes accept it alongside tension and the normal contact force when examples are asked for. It always acts upwards through the submerged volume and is equal in size to the weight of the fluid displaced. Whether an object rises, sinks or stays put depends on how the upthrust compares with the weight. A brick resting on the floor of a pool is held still by three forces: its weight downwards, the upthrust upwards and the normal contact force from the floor upwards, so the weight equals the upthrust plus the contact force. A helium balloon rises because the upthrust from the air exceeds its weight, and a floating object has settled where upthrust and weight are equal.

    Students should be able to describe the factors which influence floating and sinking.

    An object floats when it can displace a weight of fluid equal to its own weight before it is fully under. Push a solid object right under and it displaces its own volume, so the upthrust is the weight of that volume of fluid: if the object's density is lower than the fluid's, that upthrust beats its weight and the object rises until only part of it is submerged; if its density is higher, the upthrust is too small and it sinks. The factors are therefore the density of the object, the density of the fluid and the volume submerged. Shape matters only because it changes the volume displaced - a steel sheet sinks, but the same steel formed into a hull encloses air, has a much lower average density and floats. Salt water is denser than fresh, so objects float higher in it.

    Your focus

    1. Calculate the pressure due to a column of liquid from its depth and density.
    2. Explain why pressure in a liquid increases with depth and with the density of the liquid.
    3. Justify why the width of a container does not change the pressure at a given depth.
    Show all 18 objectives
    1. Calculate the difference in pressure between two depths in a liquid.
    2. Explain why a dam wall is built thicker at its base.
    3. Decide when atmospheric pressure must be added to a calculated liquid pressure.
    4. Explain why the pressure on the base of a submerged block exceeds the pressure on its top.
    5. Describe why the sideways forces on a submerged block cancel.
    6. Predict how the pressure difference changes when a taller block is submerged.
    7. Calculate the upward resultant force from the pressures on the top and bottom faces of a block.
    8. Explain why the upward resultant equals the weight of the fluid displaced.
    9. Predict whether two blocks of equal volume but different material receive the same upward force.
    10. Name and draw the upthrust acting on a submerged object.
    11. State the relationship between upthrust and the weight of fluid displaced.
    12. Explain the force balance that keeps a brick stationary on the floor of a pool.
    13. Predict whether an object floats or sinks by comparing its density with that of the fluid.
    14. Explain why a hollow steel hull floats while a solid steel block sinks.
    15. Describe how the submerged volume of a floating object adjusts until upthrust equals weight.

    Pressure in a fluid 2 (HT only) exam tips

    Marking Points
    • one mark for the equation pressure = height of the column × density × gravitational field strength
    • one mark for the height taken as the depth below the surface of the liquid
    • one mark for density in kilograms per cubic metre and depth in metres
    • one mark for the calculated pressure in pascals or kilopascals
    • one mark for using the difference in depth between the two points
    • one mark for a correct substitution into pressure = height × density × gravitational field strength
    • one mark for the pressure difference in pascals or kilopascals
    • one mark for adding atmospheric pressure where the total pressure is asked for
    • one mark for the bottom surface lying deeper in the liquid than the top surface
    • one mark for pressure in a liquid increasing with depth
    • one mark for the greater pressure producing a greater upward force on the bottom face
    • one mark for the horizontal forces on the side faces cancelling
    • one mark for the upward force on the base exceeding the downward force on the top
    • one mark for the resultant of those two forces acting upwards
    • one mark for its size found from the pressure difference multiplied by the area
    • one mark for linking that resultant to the weight of the fluid displaced
    • one mark for upthrust named as the upward force from a fluid on a submerged object
    • one mark for upthrust equal to the weight of the fluid displaced
    • one mark for identifying upthrust as a contact force
    • one mark for the balance of weight, upthrust and normal contact force on an object resting on the bottom
    • one mark for comparing the density of the object with the density of the fluid
    • one mark for floating when the upthrust is equal to the weight of the object
    • one mark for the upthrust equal to the weight of fluid displaced by the submerged volume
    • one mark for explaining a hollow shape as lowering the average density of the object
    Examiner Tips
    • 💡Measure the height downwards from the surface of the liquid to the point in question.
    • 💡For an explain question, write more liquid above, so greater weight, so greater pressure.
    • 💡Underline whether the question wants the pressure at a depth or the difference between two depths.
    • 💡Use one hundred kilopascals for every ten metres of water as a quick check on the answer.
    • 💡Draw the arrows: a long one pointing up on the base and a short one pointing down on the top.
    • 💡Say greater depth, so greater pressure, in as many words; it is the linking mark.
    • 💡Two forces in, one resultant out; show the subtraction in your working.
    • 💡Keep this force separate from the weight, because the question usually asks only about the fluid forces.
    • 💡Label the upthrust on any diagram of an object in a fluid, even a sinking one.
    • 💡For an object resting on the bottom, expect three vertical forces rather than two.
    • 💡Compare two densities in the first sentence of any floating or sinking answer.
    • 💡For a ship, use the phrase average density including the air inside.
    Common Mistakes
    • using the height of the container rather than the depth below the liquid surface
    • assuming a wider tank gives a greater pressure at the same depth
    • leaving the density in grams per cubic centimetre
    • measuring the depth upwards from the bottom of the container
    • using the deeper depth alone when the question asks for a difference
    • adding atmospheric pressure to a difference, where it cancels out
    • converting kilopascals into pascals the wrong way round
    • assuming the pressure difference depends on the shape of the container
    • claiming the pressure difference depends on how deep the whole object is rather than on its height
    • forgetting that the liquid also pushes down on the top surface
    • saying the side faces experience no pressure at all
    • confusing the pressure difference between the faces with the total pressure at the bottom
    • saying the water only pushes upwards, ignoring the downward force on the top surface
    • assuming the upward resultant depends on the material the object is made of
    • calculating the resultant from the pressure at the bottom alone
    • confusing the resultant of the fluid forces with the overall resultant including the weight
    • writing that the upthrust on a brick lying on the bottom is zero
    • saying upthrust equals the weight of the object rather than the weight of the fluid displaced
    • listing upthrust as a non-contact force alongside gravity and magnetism
    • leaving the normal contact force out of the force balance for an object resting on the bottom
    • saying heavy objects sink and light ones float, with no mention of density or volume
    • claiming a steel ship floats because of its shape, without mentioning the enclosed air or the average density
    • stating that a floating object has no weight acting on it
    • ignoring the density of the fluid, so treating fresh and salt water as identical