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    Appendix 4: Formulae and statistical tables - Wilcoxon Signed Ranks test process — Edexcel A-Level Psychology

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    Appendix 4: Formulae and statistical tables - Wilcoxon Signed Ranks test process explained

    Wilcoxon's signed ranks test is the test of difference for a repeated measures or matched pairs design when the data are ordinal, or interval data you are unwilling to treat as normally distributed; Wilcoxon set it out in 1945 as the nonparametric partner of the related samples t test. Everything downstream depends on this first subtraction being carried out the same way on every row: condition one minus condition two for all participants, so that somebody who improved and somebody who deteriorated finish with opposite signs. Those signs carry the information the test later uses, which is why they stay in the table even though the ranking stage looks only at size. Subtracting in a different order on different rows is the error that quietly converts a significant result into a null one.

    Rank the differences giving the smallest difference Rank 1

    Ranking converts sizes into positions, and that is what makes the test nonparametric: the actual magnitudes stop mattering and only their order counts. Set the sign aside, arrange the sizes from smallest upwards, and award position one to the smallest, position two to the next, and so on to the largest. Tied values share the mean of the positions they would have filled, so two differences competing for third and fourth place each take three and a half and the next difference takes five. Because magnitude information is deliberately thrown away, this test has a little less power than the related samples t test when the data genuinely are normal, and that loss of power is the price paid for making no assumption about the shape of the distribution.

    Note: do not rank any differences of 0 and when adding the number of scores, do not count those with a difference of 0, and ignore the signs when calculating the difference

    There are two instructions here and a reason behind each. A participant whose values are identical in both conditions has moved in neither direction, so that row can support neither total and is removed before ranking; left in, it would seize the first position and push every other position up. Removing it also shrinks the sample used in the final comparison, and since the critical value falls as the sample shrinks, discarded ties make significance harder to reach, which matters in a study where many participants did not change. The second instruction is narrower than it looks: size alone decides the positions, but the plus and minus labels stay in the table, because the two totals are built out of them.

    Add up the ranks for positive differences

    Once every usable difference carries a position, those positions are sorted by the sign that was set aside earlier, and one total is assembled from the rows where the subtraction came out above zero. That total measures how much of the overall change ran in that direction, which is why the answer has to state which condition was taken from which before the number means anything. A useful arithmetic check comes free: the two totals must come to the sum of all positions awarded, which is the number of positions multiplied by one more than that number, then halved, so eight usable differences must always produce totals that come to thirty six between them.

    Add up the ranks for negative differences

    The second total is assembled from the rows where the subtraction came out below zero, meaning the value in the second condition was the larger. A small worked example makes the pattern visible: with nine participants, one of them unchanged and therefore discarded, eight positions are awarded and the two totals must come to thirty six between them, so totals of thirty three and three describe a sample in which almost everybody moved the same way, while totals of nineteen and seventeen describe a sample that barely moved at all. Since the test reads whichever total is smaller, a nearly empty total on one side is the evidence for the alternative hypothesis rather than an untidy result to be explained away.

    T is the figure that is the smallest when the ranks are totalled (may be positive or negative)

    The calculated statistic is whichever of the two rank totals is smaller, and its size carries the whole logic of the test: if everybody changed in the same direction, one total collapses towards nothing, so a small calculated value is evidence of a consistent difference. Compare it with the critical value read from the board's table at the adjusted sample size, for a one tailed or two tailed hypothesis, at the five per cent level. Significance demands that the calculated value be equal to or smaller than the critical value, which is the reverse of the rule used with chi-squared and catches out anyone who learns one direction and applies it everywhere. Retaining the null hypothesis when the value is larger is a probabilistic decision, not a proof that the conditions are identical.

    N is the number of scores left, ignore those with 0 difference.

    The sample size the table is read at is the count of participants who actually produced a difference, so a study of fifteen people in which three scored the same twice is read at twelve. Getting that count wrong changes the row of the table and therefore the decision reached. The count also governs power: with ten usable differences and a two tailed test at the five per cent level the calculated value must be eight or lower, and with only five usable differences no result can reach that level two tailed at all, which is a fair evaluation point about small scale repeated measures studies. Quoting the adjusted figure beside the statistic lets a reader check the comparison, which is part of what makes a study replicable.

    The calculated value must be equal to or less than the critical value in this table for significance to be shown.

    Wilcoxon's signed ranks test, published by Frank Wilcoxon in 1945, is the inferential test for a difference between two sets of scores drawn from a repeated measures or matched pairs design when the data are at least ordinal. You find the difference for each pair, discard any pair whose difference is zero and shrink the sample size accordingly, rank the remaining differences by size while ignoring plus and minus signs, then total the ranks that carry the less frequent sign. That smaller rank total is the observed statistic, and the table is entered with the number of non-zero pairs, the significance level, normally five per cent, and whether the hypothesis was directional or non-directional. A large and consistent shift in one direction pushes the rank total down, which is why a small observed figure is the evidence of an effect here and the reverse of what chi-squared or Spearman needs.

    Your focus

    1. Calculate the difference between two scores by taking one from the other
    2. Rank the differences giving the smallest difference Rank 1
    3. Note: do not rank any differences of 0 and when adding the number of scores, do not count those with a difference of 0, and ignore the signs when calculating the difference
    Show all 8 objectives
    1. Add up the ranks for positive differences
    2. Add up the ranks for negative differences
    3. T is the figure that is the smallest when the ranks are totalled (may be positive or negative)
    4. N is the number of scores left, ignore those with 0 difference.
    5. The calculated value must be equal to or less than the critical value in this table for significance to be shown.

    Appendix 4: Formulae and statistical tables - Wilcoxon Signed Ranks test process exam tips

    Quick Revision Summary (Key Takeaway)

    The Wilcoxon Signed Ranks test is a non-parametric statistical test used in Pearson Edexcel A-Level Psychology to analyse differences between two related conditions using ordinal or interval data. For a result to be statistically significant, the calculated value of T must be less than or equal to the critical value found in the statistical tables for the chosen significance level.

    Topic Overview

    The Wilcoxon Signed Ranks test is a core non-parametric statistical tool specified in Appendix 4 of the Pearson Edexcel A-Level Psychology specification. It evaluates whether there is a statistically significant difference between two sets of scores obtained from related data, such as a repeated measures design or matched pairs design, where the data is at least ordinal level.

    Mastering this process is essential for Paper 1, Paper 2, and Paper 3 research methods questions. Students must be able to justify the choice of test, calculate the test statistic T by ranking signed differences, handle tied ranks and zero differences, and accurately interpret critical value tables to accept or reject hypotheses.

    Key Concepts
    • →Test criteria: Used for a test of difference, a repeated measures or matched pairs design (related data), and ordinal or interval/ratio data.
    • →Zero difference exclusion: Any participant scoring identically across both conditions (difference = 0) is excluded, which directly reduces the value of N used for critical tables.
    • →Ranking absolute values: Differences are ordered from smallest to largest irrespective of mathematical sign (+ or -), with tied scores assigned the mean of the ranks they span.
    • →Test statistic T: Calculated T is defined as the smaller sum of the assigned signed ranks (T = min(sum R+, sum R-)).
    • →Significance threshold rule: For the Wilcoxon test, the observed value of T must be less than or equal to the critical value to achieve significance at the designated alpha level.
    Marking Points
    • State the design first: paired values only exist because the same participants, or matched pairs, were tested under both conditions.
    • Work in a consistent direction, for example condition A minus condition B on every row, recording a minus sign wherever the second value is the larger.
    • Keep the sign in the difference column, since it is what separates the two rank totals later; only the ranking stage treats a difference purely as a size.
    • Justify the test as well as performing it: ordinal or skewed interval data, a repeated measures design, and a hypothesis predicting a difference rather than an association.
    • Rank the size of each difference only; the sign is set aside here and recovered when the ranks are sorted into totals.
    • The smallest difference takes the first position and ranking runs upwards, so the largest difference carries the highest position.
    • Share tied positions: give each tied difference the mean of the positions they would have occupied, then resume at the next unused position.
    • Explain why ranking is used at all: positions can be assigned to scores that are ordered but not equally spaced, which is what lets ordinal data into the test.
    • A row showing no change is discarded before ranking, because a participant who scored the same twice offers no evidence for either direction of change.
    • The sample size used at the end counts only participants who produced a non zero difference, so recalculate it after the discards instead of using the number of people tested.
    • Positions are awarded to the size of a difference, so minus four and plus four compete for the same position; the signs return when the positions are sorted into two totals.
    • Explain the consequence for the decision: discarding ties lowers the sample size, the critical value drops with it, and the test becomes more conservative.
    • Group the positions by the sign of the difference each came from, then total those belonging to the rows above zero.
    • Say what a positive difference means in this particular table, since that depends entirely on which condition was subtracted from which.
    • Check the arithmetic: the two totals together must equal the sum of all positions awarded, which is the number of positions multiplied by one more than that number, then halved.
    • Interpret the pair of totals: a large imbalance between them is what a significant result reflects, whereas nearly equal totals mean the conditions barely differed.
    • Total the positions attached to the rows whose difference carried a minus sign, keeping the discarded unchanged rows out of both totals.
    • Relate the pair of totals to the hypothesis: a small total on one side against a large one on the other means most participants changed in the same direction.
    • Report both totals, because the statistic is defined by comparing them and a single total on its own cannot be checked by anybody reading the report.
    • Recognise that the data being added here are ordinal, since it is positions rather than raw magnitudes that are summed.
    • Identify the statistic as the smaller of the two rank totals and state its value plainly before comparing it with anything.
    • Compare it with the critical value taken from the table at the adjusted sample size, for the correct number of tails and at the five per cent significance level.
    • Apply the comparison in the right direction: the result counts as significant only where the calculated value is equal to or smaller than the critical value.
    • Write the conclusion in the terms of the study, rejecting the null hypothesis and stating the direction of the difference, or retaining it, and note that the probability of a type one error was held at five per cent.
    • Define the figure as the count of non zero differences rather than the number of people who took part in the study.
    • Use it to enter the table of critical values: this figure picks the row, while the number of tails and the significance level pick the column.
    • Report it with the statistic so the comparison can be checked, for example a calculated value of six against a critical value of eight for ten usable differences, two tailed.
    • Comment on power where the question invites evaluation, since a small number of usable differences makes a significant result unlikely even when a real effect exists.
    • Credit comes from naming the test and justifying it in the same breath: a test of difference, a related design of repeated measures or matched pairs, and data that are ordinal or can be ranked.
    • Say that the figure used to enter the table is the number of pairs that produced a non-zero difference rather than the number of participants tested, and state the significance level and whether a one tailed or two tailed value is being read.
    • State the decision in the examiner's language: because the observed statistic is smaller than or the same as the tabled figure at five per cent, the null hypothesis is rejected and the difference is described as significant.
    • A mark is available for the direction rule itself, that Wilcoxon and Mann-Whitney are the tests where a small observed figure signals significance while chi-squared, Spearman and the t tests need a large one.
    Examiner Tips
    • 💡The skills paper sets this as a partly completed table and asks for the missing values, so show the subtraction rather than only the answer.
    • 💡Calculation items are often paired with a short justification of the test, so learn the design, the level of measurement and the hypothesis type as one package.
    • 💡Read the stem for one tailed or two tailed wording, because that choice decides which column of the table of critical values you will need at the end.
    • 💡The paper usually supplies a table with one or two positions missing, so practise finishing a ranking under time rather than starting one from scratch.
    • 💡Show the ranks in a column beside the differences, because a marker awarding method marks has to see where each number came from.
    • 💡If the data contain ties, mention them in an explain answer, since tied ranks are a recognised limitation of rank based tests.
    • 💡Stems are written with one or two unchanged pairs in the table on purpose, so scan that column before starting to rank.
    • 💡A short explain item often asks why a participant was excluded; answer in terms of the absence of a direction of change, not by reciting the rule.
    • 💡Quote the sample size you finally used beside the statistic, because the comparison with the critical value cannot be credited without it.
    • 💡Show both totals even where the question asks only for the final statistic, because method marks are available for the two sums.
    • 💡Use the arithmetic check before moving on, since a total that fails it points to a ranking error that would otherwise carry through to the conclusion.
    • 💡In an explain answer, link the larger total to the direction stated in the hypothesis rather than simply quoting the figure.
    • 💡Lay the working out as a labelled column, because a marker credits a correctly totalled column even where the final comparison goes astray.
    • 💡Where the table is already part filled, check the given positions against the differences before totalling, since questions sometimes plant an error for you to spot.
    • 💡An explain item may ask what a very small total indicates, so be ready to write about consistency of change across participants.
    • 💡The tables are printed in the paper, so practise reading the correct row and column at speed rather than trying to memorise values.
    • 💡A frequent three or four mark item supplies the calculated value and the table and asks you to state and justify the conclusion, so always finish with a sentence about the hypothesis.
    • 💡Where the stem gives a directional hypothesis, use the one tailed column and say in your answer why you did.
    • 💡Count the usable differences as you cross off the unchanged pairs; the arithmetic in these items is easy and it is the bookkeeping that loses marks.
    • 💡Questions asking you to evaluate a study's statistics reward a comment on sample size and power, so keep one sentence prepared.
    • 💡State the figure in your concluding sentence together with the number of tails and the level, in the format the mark scheme models.
    • 💡Questions usually supply a small table of before and after scores and ask you to calculate the statistic, so practise laying out columns for difference, sign and rank and show the working, because method marks survive an arithmetic slip.
    • 💡Another frequent version gives the observed figure and the critical value and asks what the comparison shows; answer with the comparison, then the decision about the null hypothesis, then the level of significance, in that order.
    • 💡Be ready to justify the choice of test against Mann-Whitney U, since the only thing separating them in most stems is whether the design is related or independent groups.
    • 💡Use of inferential statistics is nomothetic and reductionist, so an evaluation question can be turned towards what a group level probability says about any individual participant.
    • 💡Always state the three justification criteria explicitly when asked why Wilcoxon was chosen: 'difference', 'repeated measures (or matched pairs)', and 'at least ordinal data'.
    • 💡Show full workings when summing positive and negative ranks; writing out 'Sum of + ranks = ...' and 'Sum of - ranks = ...' secures working marks even if a minor arithmetic slip occurs.
    • 💡When concluding significance, quote all four elements: the calculated T value, the critical value, the N value, and the p level (including one-tailed vs two-tailed).
    Common Mistakes
    • Always taking the smaller value from the larger, so every difference comes out positive and one of the two rank totals ends up empty.
    • Dropping the minus signs at this stage because a later instruction mentions ignoring them, when they are ignored only while ranking.
    • Choosing this test for an independent groups design, where Mann-Whitney is the test that actually fits.
    • Ranking from largest downwards, which reverses every position and produces the wrong statistic while the arithmetic still looks tidy.
    • Ranking signed values, so every negative difference sits below every positive one and the two totals become meaningless.
    • Giving two tied differences consecutive positions instead of the shared mean, which shifts every position that follows and corrupts both totals.
    • Ranking the unchanged rows as though they were the smallest differences, which lifts every other position by one and alters both totals.
    • Dropping the unchanged rows from the ranking but still counting them in the sample size, so the wrong row of the table of critical values is read.
    • Reading the instruction about signs as permission to delete them, and then being unable to separate the positive from the negative total.
    • Adding the differences rather than their positions, which yields a number that looks plausible but cannot be compared with any critical value.
    • Including the discarded unchanged rows in the total, or counting a shared position twice after a tie.
    • Reporting the total without saying which condition scored higher, so the result cannot be tied back to the hypothesis.
    • Carrying the minus signs into the total and producing a negative number, when it is the positions and not the differences that are being added.
    • Assuming this total is always the one used, rather than whichever of the two totals turns out to be smaller.
    • Counting a shared position in both totals after a tie, so the two sums exceed the total that the arithmetic check predicts.
    • Taking the larger total as the statistic, which nearly always exceeds the critical value and produces a confident but wrong conclusion of no difference.
    • Importing the greater than rule from chi-squared, so a genuinely significant result is reported as non significant.
    • Reporting significance without naming the level, the number of tails or the sample size, all of which the mark scheme expects alongside the decision itself.
    • Using the original number of participants, which sends you to the wrong row and usually to a critical value that is far too generous.
    • Confusing this count with the number of conditions, or with degrees of freedom, which belongs to other tests entirely.
    • Treating a non significant result from a handful of usable differences as proof that the conditions do not differ, rather than as a study with too little power to tell.
    • Keeping pairs whose difference is zero in the count, which inflates the sample size, sends the student to the wrong row of the table and often flips a significant result into a non-significant one.
    • Ranking the differences with their plus and minus signs attached, or ranking the raw scores instead of the differences, so the rank totals are already meaningless before the table is opened.
    • Taking the larger of the two rank totals, or importing the greater than rule from chi-squared, so a genuine effect is written up as no effect.
    • Writing that the result proves the hypothesis. Examiners want the null hypothesis rejected, with a five per cent probability that the result is due to chance, not proof.
    • Retaining zero differences in the sample size: Students frequently leave difference scores of zero in the ranking process or keep the original N when consulting the statistical table, resulting in the selection of the wrong critical value.
    • Ranking including the sign: Students occasionally rank negative differences as smaller than positive differences (e.g. treating -5 as smaller than +1) rather than ranking the absolute magnitude of the differences.
    • Confusing the decision rule: Many candidates default to the assumption that calculated values must always exceed critical values, incorrectly concluding that higher T values indicate statistical significance.
    Revision Plan
    1. 1Week 1 (Day 1-2): Master the three justification conditions for Wilcoxon versus Mann-Whitney U, Sign test, and related t-test.
    2. 2Week 1 (Day 3-5): Practice calculating difference scores, omitting zero scores, and resolving tied ranks with fractional values across small mock datasets.
    3. 3Week 2 (Day 1-3): Practice summing positive and negative ranks to derive calculated T, then using Pearson Edexcel statistical tables to identify correct critical values.
    4. 4Week 2 (Day 4-5): Write full analytical conclusions linking calculated T, critical values, alpha levels, and contextual hypothesis acceptance or rejection.
    Exam Question Types
    • 📋Short-answer calculation (2-4 marks): Calculating difference scores, ranking, and identifying T from a provided data table.
    • 📋Test justification (2-3 marks): Explaining why the Wilcoxon Signed Ranks test is appropriate for a described empirical scenario.
    • 📋Critical table interpretation (3-4 marks): Identifying the critical value given specific parameters (N, tails, p-value) and writing a formal statistical conclusion.
    Command Word Expectations (PEARSON EDEXCEL)
    Justify

    Provide precise reasons linked directly to the context of the study: reference the test of difference, the related design (repeated measures/matched pairs), and the ordinal/interval nature of the data.

    Calculate

    Complete mathematical operations showing clear, sequential steps (calculating differences, ranking, summing signed ranks, and selecting the minimum sum) to arrive at calculated T.

    Explain whether...

    Make an explicit comparison between the calculated value and the critical value, state whether the null or experimental hypothesis is accepted, and cite the significance level and test directionality.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Retaining participants with a difference score of zero in the sample size (N) when determining the critical value.
    ❌ Weak Answer (Loses Marks):The researcher used N = 10 because there were 10 participants in the study, and compared T to the critical value for 10.
    Example improved answer:Because Participant 4 showed a difference score of zero (no change between condition A and condition B), their data must be discarded from the ranking process. This reduces the effective sample size from N = 10 to N = 9 when identifying the critical value from the Wilcoxon table.
    Examiner Tip: Always scan your difference column for zeros first; cross them out immediately and write down your adjusted N before ranking to avoid using the wrong row in the critical values table.
    Pitfall: Applying the incorrect decision rule by stating the calculated value of T must be greater than or equal to the critical value.
    ❌ Weak Answer (Loses Marks):The result is significant because calculated T = 6 is less than the critical value of 8, so the experimental hypothesis is rejected.
    Example improved answer:The result is statistically significant at p <= 0.05 (one-tailed, N = 8) because the calculated value of T (T = 6) is less than the critical value of 8. Therefore, the null hypothesis is rejected and the directional hypothesis is accepted.
    Examiner Tip: Memorise the critical value rule mnemonic: tests with the letter 'r' in their name (e.g. Spearman's rho, Chi-square) require calculated >= critical, whereas Wilcoxon (no 'r') requires calculated T <= critical value.
    Step-by-Step Worked Solutions

    Question: A psychologist conducted a repeated-measures experiment investigating whether a caffeine drink improves reaction time (in seconds). The difference scores (Condition B minus Condition A) for 7 participants are: -0.4, +0.2, 0.0, -0.6, +0.3, -0.8, +0.5. Calculate the value of T for the Wilcoxon Signed Ranks test.

    1. 1.Step 1: Omit the zero difference score. Participant 3 has a difference of 0.0, leaving N = 6 usable difference scores: -0.4, +0.2, -0.6, +0.3, -0.8, +0.5.
    2. 2.Step 2: Rank the absolute differences (ignoring the signs) from smallest to largest: 0.2 (rank 1) 0.3 (rank 2) 0.4 (rank 3) 0.5 (rank 4) 0.6 (rank 5) 0.8 (rank 6).
    3. 3.Step 3: Re-assign the original positive and negative signs to the ranks: Rank 1 (+0.2) = +1 Rank 2 (+0.3) = +2 Rank 3 (-0.4) = -3 Rank 4 (+0.5) = +4 Rank 5 (-0.6) = -5 Rank 6 (-0.8) = -6.
    4. 4.Step 4: Sum the positive ranks and sum the negative ranks separately: Sum of positive ranks (sum of R+) = 1 + 2 + 4 = 7. Sum of negative ranks (sum of R-) = 3 + 5 + 6 = 14.
    5. 5.Step 5: Identify the calculated value of T, which is the smaller of the two sums of ranks: T = min(7, 14) = 7.
    Final Answer: The calculated value of T is 7.

    Question: A researcher obtained a calculated Wilcoxon value of T = 11 with an adjusted sample size of N = 10. The directional hypothesis predicts that participants will recall significantly more words in silence than with background noise. Using p <= 0.05, explain whether the researcher should accept or reject their null hypothesis if the critical value for a one-tailed test at N = 10 is 10.

    1. 1.Step 1: Identify the key test parameters: one-tailed (directional) hypothesis, alpha level p <= 0.05, N = 10, calculated T = 11, critical value = 10.
    2. 2.Step 2: State the Wilcoxon decision rule: for a result to be statistically significant, the calculated value of T must be less than or equal to the critical value.
    3. 3.Step 3: Compare calculated T to the critical value: calculated T (11) is greater than the critical value (10).
    4. 4.Step 4: Draw conclusion regarding hypotheses: because calculated T exceeds the critical value, the difference is not statistically significant at p <= 0.05. The researcher must accept the null hypothesis and reject the directional hypothesis.
    Final Answer: The null hypothesis must be accepted because calculated T (11) is greater than the critical value (10) for a one-tailed test at p <= 0.05 (N = 10), indicating that the observed difference is not statistically significant.
    Active Recall Memory Test
    What three conditions must be satisfied to select the Wilcoxon Signed Ranks test?
    Key Fact: A test of difference, a related experimental design (repeated measures or matched pairs), and ordinal or interval/ratio data.
    How do you handle a difference score of zero when conducting a Wilcoxon Signed Ranks test?
    Key Fact: Drop the zero score entirely from the ranking process and subtract 1 from N for every zero dropped.
    What is the decision rule for determining significance with the Wilcoxon Signed Ranks test?
    Key Fact: The calculated value of T must be less than or equal to the critical value found in the statistical table (calculated T <= critical value).
    If two participants share tied ranks in positions 4 and 5, what rank value is assigned to each?
    Key Fact: A rank of 4.5 is assigned to each participant ((4 + 5) / 2 = 4.5).
    Frequently Asked Questions
    Why does calculated T have to be less than or equal to the critical value in Wilcoxon?
    The test statistic T represents the sum of the ranks for the less frequent sign. If there is a massive, consistent difference between conditions, almost all ranks will have the same sign, making the sum of the minority ranks very small. Therefore, a smaller T indicates a more extreme, systematic difference between conditions, which is why calculated T must be equal to or lower than the critical threshold to demonstrate significance.
    What happens if the sum of positive ranks equals the sum of negative ranks?
    If the sum of positive ranks equals the sum of negative ranks, calculated T takes that shared value. In practice, this indicates that differences are evenly split in magnitude across both directions, suggesting no systematic effect, which will almost always result in an insignificant calculated T value well above the critical table threshold.
    How do I deal with three tied difference scores?
    Add the rank positions the three scores would have occupied and divide the total by 3. For example, if three tied scores occupy ranks 3, 4, and 5, calculate (3 + 4 + 5) / 3 = 4.0. Assign a rank of 4.0 to each of those three scores, and the next highest absolute score will receive rank 6.
    Can the Wilcoxon Signed Ranks test be used on interval data?
    Yes. While parametric tests like the related t-test are preferred for normally distributed interval or ratio data, the Wilcoxon test can be used if interval data violates parametric assumptions, such as having significant skewness, non-homogeneity of variance, or a small sample size.
    What is the difference between the Sign test and the Wilcoxon Signed Ranks test?
    Both tests are used for related designs testing for difference. However, the Sign test only considers the direction (+ or -) of the difference, treating all changes identically regardless of scale, which discards magnitude data. The Wilcoxon Signed Ranks test incorporates both the direction and the relative magnitude of differences by ranking them, making it a considerably more powerful statistical test.