Skip to topic
    ← Back to course topics

    E3b — AQA GCSE Statistics

    Test yourself on E3b with AQA GCSE practice questions.

    Start free

    7 days Premium · Then free forever · No card, no charge

    Your focus

    1. Compare different data sets using appropriate calculated or given measure of spread: range.

    E3b exam tips

    Quick Revision Summary (Key Takeaway)

    E3b in AQA GCSE Statistics covers the use and interpretation of the Normal distribution, including its properties, standardised scores (z-scores), and the 68-95-99.7 rule. Students must apply the Normal distribution to solve real-world problems and critically evaluate its suitability for given data sets.

    Topic Overview

    E3b is a key topic in AQA GCSE Statistics that focuses on the Normal distribution, a continuous probability distribution that is symmetric and bell-shaped. You will learn to recognise when data can be modelled by a Normal distribution, calculate probabilities using standardised scores, and apply the 68-95-99.7 rule to interpret data spread.

    Understanding the Normal distribution is essential for analysing real-world data in fields such as science, economics, and social studies. It also forms the foundation for more advanced statistical concepts like confidence intervals and hypothesis testing, making it a crucial part of your GCSE Statistics course.

    Key Concepts
    • →The Normal distribution is a continuous probability distribution defined by its mean (μ) and standard deviation (σ), with a symmetric bell-shaped curve.
    • →The standard Normal distribution has mean 0 and standard deviation 1, and any Normal variable can be standardised using z = (x - μ) / σ.
    • →The 68-95-99.7 rule states that approximately 68% of data lies within 1 standard deviation of the mean, 95% within 2, and 99.7% within 3.
    • →Probabilities for Normally distributed data are found by calculating the area under the curve, often using z-tables or calculator functions.
    • →The Normal distribution is used to model many natural phenomena, but it is not suitable for skewed or discrete data.
    Examiner Tips
    • 💡Always sketch the Normal curve and shade the relevant area to avoid errors with tails.
    • 💡Show all steps in standardisation, including the formula, substitution, and final probability, to gain method marks even if the final answer is wrong.
    • 💡When interpreting the Normal distribution, explicitly refer to the mean, standard deviation, and the 68-95-99.7 rule in your explanation.
    Common Mistakes
    • Students often think all symmetric data is Normally distributed, but it must also be bell-shaped and follow the 68-95-99.7 rule.
    • When calculating probabilities, students sometimes forget to standardise or use the wrong inequality (e.g., P(X > x) instead of P(X < x)).
    • Students may confuse the standard deviation with the variance; remember variance is σ², and standard deviation is σ.
    Revision Plan
    1. 1Day 1-2: Revise the properties of the Normal distribution and the 68-95-99.7 rule. Practice identifying Normally distributed data from histograms.
    2. 2Day 3-4: Learn the standardisation formula and practice converting between x-values and z-scores. Use z-tables to find probabilities.
    3. 3Day 5-6: Work through exam-style questions on finding probabilities, percentiles, and interquartile range. Check your answers against mark schemes.
    4. 4Day 7-8: Review common misconceptions and examiner insights. Create flashcards for key formulas and definitions.
    5. 5Day 9-10: Complete a timed past paper section on E3b, focusing on accuracy and showing full working.
    Exam Question Types
    • 📋Calculation of probabilities: Given mean and standard deviation, find the probability of a value being greater or less than a certain number. Advice: Always standardise and sketch the curve.
    • 📋Interpretation of the 68-95-99.7 rule: Explain what percentage of data lies within certain intervals. Advice: Memorise the percentages and relate them to the context.
    • 📋Assessing normality: Given a data set or graph, decide if the Normal distribution is a suitable model. Advice: Check symmetry, bell shape, and the 68-95-99.7 rule.
    • 📋Finding percentiles or IQR: Use the Normal distribution to find quartiles or other percentiles. Advice: Remember to convert z-scores back to original units.
    Command Word Expectations (AQA)
    Calculate

    You must show all steps of your working, including the standardisation formula and substitution, to gain full marks. A correct answer without working may only get 1 mark.

    Explain

    You must give reasons for your answer, referring to the properties of the Normal distribution such as symmetry, bell shape, and the 68-95-99.7 rule. Use full sentences.

    Interpret

    You must relate your calculation back to the context of the problem, stating what the probability or value means in real-world terms.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often assume any symmetric data follows a Normal distribution without checking for other key features like the bell shape, mean = median = mode, and the 68-95-99.7 rule.
    ❌ Weak Answer (Loses Marks):The data is symmetric so it is Normally distributed.
    Example improved answer:The data is symmetric and approximately bell-shaped, with mean, median and mode all close to 50. Approximately 68% of values lie within one standard deviation of the mean, 95% within two, and 99.7% within three, which is consistent with a Normal distribution.
    Examiner Tip: Always check all three conditions: symmetry, bell shape, and the 68-95-99.7 rule. Mention each explicitly to secure full marks.
    Pitfall: When calculating probabilities using the Normal distribution, students forget to standardise the value using z = (x - mean) / standard deviation, or they use the wrong tail.
    ❌ Weak Answer (Loses Marks):P(X > 70) = 0.5 because 70 is above the mean.
    Example improved answer:First standardise: z = (70 - 60) / 8 = 1.25. Then P(Z > 1.25) = 1 - P(Z < 1.25) = 1 - 0.8944 = 0.1056. So the probability is approximately 0.106.
    Examiner Tip: Always write down the standardisation formula, substitute correctly, and sketch the Normal curve to identify the correct area.
    Step-by-Step Worked Solutions

    Question: The heights of adult males in a town are Normally distributed with mean 175 cm and standard deviation 7 cm. Find the probability that a randomly chosen adult male is taller than 185 cm.

    1. 1.Step 1: Identify given facts: mean (μ) = 175 cm, standard deviation (σ) = 7 cm, x = 185 cm.
    2. 2.Step 2: Standardise using z = (x - μ) / σ = (185 - 175) / 7 = 10 / 7 ≈ 1.43.
    3. 3.Step 3: Use the Normal distribution table or calculator to find P(Z > 1.43) = 1 - P(Z < 1.43) = 1 - 0.9236 = 0.0764.
    4. 4.Step 4: State final conclusion: The probability is approximately 0.076 or 7.6%.
    Final Answer: The probability that a randomly chosen adult male is taller than 185 cm is approximately 0.076 (7.6%).

    Question: A machine fills bags of sugar. The masses are Normally distributed with mean 1000 g and standard deviation 15 g. Find the interquartile range of the masses.

    1. 1.Step 1: The lower quartile (Q1) corresponds to the 25th percentile, so P(Z < z1) = 0.25. From tables, z1 ≈ -0.674.
    2. 2.Step 2: Convert z1 back to x: x1 = μ + z1σ = 1000 + (-0.674)(15) = 1000 - 10.11 = 989.89 g.
    3. 3.Step 3: The upper quartile (Q3) corresponds to the 75th percentile, so P(Z < z3) = 0.75. From tables, z3 ≈ 0.674.
    4. 4.Step 4: Convert z3 back to x: x3 = 1000 + (0.674)(15) = 1000 + 10.11 = 1010.11 g.
    5. 5.Step 5: Calculate IQR = Q3 - Q1 = 1010.11 - 989.89 = 20.22 g.
    Final Answer: The interquartile range of the masses is approximately 20.22 g.
    Active Recall Memory Test
    What are the three key features of a Normal distribution?
    Key Fact: Symmetric, bell-shaped, and follows the 68-95-99.7 rule (approximately 68% within 1 standard deviation, 95% within 2, 99.7% within 3).
    What is the formula to standardise a value from a Normal distribution?
    Key Fact: z = (x - μ) / σ, where x is the value, μ is the mean, and σ is the standard deviation.
    What percentage of data lies within two standard deviations of the mean in a Normal distribution?
    Key Fact: Approximately 95%.
    How do you find the interquartile range of a Normal distribution?
    Key Fact: Find the z-scores for the 25th and 75th percentiles (approximately -0.674 and 0.674), convert them to x-values using x = μ + zσ, and subtract the lower from the upper.
    Frequently Asked Questions
    What is the Normal distribution in GCSE Statistics?
    The Normal distribution is a continuous probability distribution that is symmetric and bell-shaped, defined by its mean and standard deviation. It is used to model many real-world phenomena where data clusters around the mean. In AQA GCSE Statistics, you need to know its properties, how to standardise values, and how to calculate probabilities.
    How do I know if data is Normally distributed?
    You should check for three things: the data is symmetric, the shape is approximately bell-shaped, and the 68-95-99.7 rule holds (about 68% of data within 1 standard deviation of the mean, 95% within 2, and 99.7% within 3). If these conditions are met, the Normal distribution is a suitable model.
    What is the 68-95-99.7 rule?
    The 68-95-99.7 rule, also called the empirical rule, states that for a Normal distribution, approximately 68% of the data lies within one standard deviation of the mean, 95% within two standard deviations, and 99.7% within three standard deviations. This rule helps you quickly estimate probabilities and check normality.
    How do I calculate probabilities using the Normal distribution?
    First, standardise the value using z = (x - μ) / σ. Then use a standard Normal table or calculator to find the probability associated with that z-score. Remember to consider whether you need the area to the left, right, or between two values. Always sketch the curve to avoid mistakes.
    What is a z-score in Statistics?
    A z-score, or standardised score, tells you how many standard deviations a value is from the mean. It is calculated as z = (x - μ) / σ. Z-scores allow you to compare values from different Normal distributions and find probabilities using the standard Normal distribution with mean 0 and standard deviation 1.
    Why is the Normal distribution important?
    The Normal distribution is important because many natural and social phenomena follow it, such as heights, weights, and test scores. It allows statisticians to make predictions and calculate probabilities. It also underpins more advanced statistical techniques like confidence intervals and hypothesis testing, which you may study later.