AQA · A-Level · Chemistry

    Course version: 7405 · Version from Sept 2016

    Acid–base equilibria involve the transfer of protons.

    Full specification wording

    Brønsted–Lowry acid–base equilibria in aqueous solution (A-level only): Acid–base equilibria involve the transfer of protons.

    Every acid and base reaction is a proton changing owner, so every one contains two conjugate pairs whose members differ by exactly one H⁺.

    Checked against the AQA 7405 specification (opens in a new tab) on .

    • Point 3 of 3
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Every acid and base reaction is a proton changing owner, so every one contains two conjugate pairs whose members differ by exactly one H⁺. In CH₃COOH + NH₃ ⇌ CH₃COO⁻ + NH₄⁺ the pairs are CH₃COOH with CH₃COO⁻ and NH₄⁺ with NH₃. Each acid is paired with the base that came from it by losing the proton, not with the base it reacted with. Because these are equilibria, the reaction need not go to completion, and the position tells you about relative strengths: the equilibrium always lies away from the stronger acid and towards the weaker one. That is why the conjugate base of a strong acid, such as Cl⁻, is an extremely poor base; it has almost no tendency to take the proton back.

    What earns the marks

    • Identifying both conjugate acid and base pairs in a given equation.
    • Showing the proton being transferred from the acid to the base.
    • Stating that the members of a pair differ by one H⁺.
    • Deducing which side the equilibrium lies on from the relative strengths of the two acids.

    Common mistakes and how to put them right

    • Pairing an acid with the base on the opposite side of the equation rather than with its own conjugate.

    • Saying the members of a conjugate pair differ by a hydrogen atom instead of a proton.

    • Using a single arrow, so the reaction is treated as going to completion.

    • Treating water as a spectator when it is in fact one member of a conjugate pair.

    Exam tips

    • Label the pairs as acid 1 / base 1 and acid 2 / base 2 across the equation; the numbering makes the pairing obvious.
    • The stronger acid is always on the side the equilibrium lies away from.

    Try the lesson

    The start of the Brønsted–Lowry acid–base equilibria in aqueous solution (A-level only): Acid–base equilibria involve the transfer of protons. lesson, made from checked teaching notes for this specification point.

    Have a go first

    In the Brønsted–Lowry model, which particle is transferred when an acid reacts with a base?

    Listen

    Every acid and base reaction is a proton changing owner, so every one contains two conjugate pairs whose members differ by exactly one H⁺. In CH₃COOH + NH₃ ⇌ CH₃COO⁻ + NH₄⁺ the pairs are CH₃COOH with CH₃COO⁻ and NH₄⁺ with NH₃. Each acid is paired with the base that came from it by losing the proton, not with the base it reacted with. Because these are equilibria, the reaction need not go to completion, and the position tells you about relative strengths: the equilibrium always lies away from the stronger acid and towards the weaker one. That is why the conjugate base of a strong acid, such as Cl⁻, is an extremely poor base; it has almost no tendency to take the proton back. A strong answer earns marks for these points. identifying both conjugate acid and base pairs in a given equation. showing the proton being transferred from the acid to the base. stating that the members of a pair differ by one H⁺. deducing which side the equilibrium lies on from the relative strengths of the two acids. Exam tip: Label the pairs as acid 1 / base 1 and acid 2 / base 2 across the equation; the numbering makes the pairing obvious.

    See it

    A left-to-right flowchart with four nodes. CH₃COOH, labelled acid 1, has an arrow labelled 'loses H⁺' to CH₃COO⁻, labelled base 1. NH₃, labelled base 2, has an arrow labelled 'gains H⁺' to NH₄⁺, labelled acid 2. A dotted arrow links CH₃COOH and CH₃COO⁻ with the label 'conjugate pair, differ by one H⁺', and another dotted arrow links NH₄⁺ and NH₃ with the same label, showing each acid paired with the base it forms by losing a proton.
    It shows the two conjugate acid–base pairs in CH₃COOH + NH₃ ⇌ CH₃COO⁻ + NH₄⁺, with the proton transferred from the acid to the base.

    Key words

    Say what each word means before you turn the card.

    proton transfer

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    conjugate pairs

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    position of equilibrium

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    relative acid strength

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    See every definition
    proton transfer
    Acid–base equilibria involve the transfer of protons from the acid to the base.
    conjugate pairs
    Each acid is paired with the base that came from it by losing the proton, and the members of a pair differ by one H⁺.
    position of equilibrium
    Because these are equilibria, the reaction need not go to completion, and the position tells you about relative strengths.
    relative acid strength
    The equilibrium always lies away from the stronger acid and towards the weaker one.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 2 boxes numbered instead of named. A left-to-right flowchart with four nodes. CH₃COOH, labelled acid 1, has an arrow labelled 'loses H⁺' to CH₃COO⁻, labelled base 1. NH₃, labelled base 2, has an arrow labelled 'gains H⁺' to NH₄⁺, labelled acid 2. A dotted arrow links CH₃COOH and CH₃COO⁻ with the label 'conjugate pair, differ by one H⁺', and another dotted arrow links NH₄⁺ and NH₃ with the same label, showing each acid paired with the base it forms by losing a proton.
    • 1Box 1

    • 2Box 2

    0 of 2 labelled

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