AQA · A-Level · Chemistry

    Course version: 7405 · Version from Sept 2016

    An asymmetric carbon atom is chiral and gives rise to optical isomers…

    Full specification wording

    Optical isomerism (A-level only): An asymmetric carbon atom is chiral and gives rise to optical isomers (enantiomers), which exist as non super- imposable mirror images and differ in their effect on plane polarised light.

    The two forms are called enantiomers.

    Checked against the AQA 7405 specification (opens in a new tab) on .

    • Point 2 of 4
    • 2 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    The two forms are called enantiomers. Draw them by putting two bonds in the plane of the paper, one on a wedge coming towards you and one on a dashed line going away, then draw the mirror image on the other side of a mirror line. However you rotate one, it will not superimpose on the other. Physically they are identical in every property that does not itself involve chirality, so they have the same melting point, the same solubility and the same reactions with ordinary reagents. Two things do differ: they rotate the plane of plane polarised light by equal amounts in opposite directions, one clockwise and one anticlockwise, and they behave differently in a chiral environment, which is why an enzyme or a receptor accepts one enantiomer and rejects the other.

    What earns the marks

    • Drawing the two enantiomers as three-dimensional mirror images either side of a mirror line.
    • Using a wedge and a dashed bond to show the arrangement in space.
    • Saying the two structures cannot be superimposed.
    • Saying they rotate plane polarised light by equal amounts in opposite directions.

    Common mistakes and how to put them right

    • Drawing the second structure as the first one rotated, so the two are actually the same molecule.

    • Drawing flat structures with no wedge or dashed bond and calling them enantiomers.

    • Saying one enantiomer rotates the plane of polarised light and the other does not.

    • Assuming an enzyme acts equally well on both enantiomers of a substrate, which AQA sets as an incorrect statement.

    Exam tips

    • Draw the mirror line first, then build the second structure group by group as a reflection.
    • Check your pair by mentally rotating one; if it lands on the other, redraw it.
    • Say "equal but opposite" about the rotation, since both halves of the phrase carry credit.

    Try the lesson

    The start of the Optical isomerism (A-level only): An asymmetric carbon atom is chiral and gives rise to optical isomers (enantiomers), which exist as non super- imposable mirror images and differ in their effect on plane polarised light. lesson, made from checked teaching notes for this specification point.

    Have a go first

    Which feature must a carbon atom in an organic molecule have for it to be described as an asymmetric carbon atom?

    Listen

    The two forms are called enantiomers. Draw them by putting two bonds in the plane of the paper, one on a wedge coming towards you and one on a dashed line going away, then draw the mirror image on the other side of a mirror line. However you rotate one, it will not superimpose on the other. Physically they are identical in every property that does not itself involve chirality, so they have the same melting point, the same solubility and the same reactions with ordinary reagents. Two things do differ: they rotate the plane of plane polarised light by equal amounts in opposite directions, one clockwise and one anticlockwise, and they behave differently in a chiral environment, which is why an enzyme or a receptor accepts one enantiomer and rejects the other. A strong answer earns marks for these points. drawing the two enantiomers as three-dimensional mirror images either side of a mirror line. using a wedge and a dashed bond to show the arrangement in space. saying the two structures cannot be superimposed. saying they rotate plane polarised light by equal amounts in opposite directions. Exam tip: Draw the mirror line first, then build the second structure group by group as a reflection.

    See it

    A top-down flowchart. The top node reads 'Asymmetric carbon atom is chiral' and points down to 'Optical isomers (enantiomers)'. From that node four branches lead down. The first reads 'Non-superimposable mirror images'. The second reads 'Differ in effect on plane polarised light' and leads to 'Rotate plane polarised light by equal amounts in opposite directions'. The third reads 'Identical in properties not involving chirality' and leads to 'Same melting point, solubility and reactions with ordinary reagents'. The fourth reads 'Behave differently in a chiral environment' and leads to 'Enzyme or receptor accepts one enantiomer and rejects the other'.
    It shows how an asymmetric carbon atom gives rise to enantiomers and how their properties are the same or differ.

    Key words

    Say what each word means before you turn the card.

    enantiomers

    Try answering aloud or in your head before turning the card.

    non-superimposable

    Try answering aloud or in your head before turning the card.

    See every definition
    enantiomers
    Optical isomers that exist as non-superimposable mirror images and differ in their effect on plane polarised light.
    non-superimposable
    However you rotate one, it will not superimpose on the other.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The top node reads 'Asymmetric carbon atom is chiral' and points down to 'Optical isomers (enantiomers)'. From that node four branches lead down. The first reads 'Non-superimposable mirror images'. The second reads 'Differ in effect on plane polarised light' and leads to 'Rotate plane polarised light by equal amounts in opposite directions'. The third reads 'Identical in properties not involving chirality' and leads to 'Same melting point, solubility and reactions with ordinary reagents'. The fourth reads 'Behave differently in a chiral environment' and leads to 'Enzyme or receptor accepts one enantiomer and rejects the other'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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