AQA · A-Level · Chemistry

    Course version: 7405 · Version from Sept 2016

    Acidified potassium dichromate(VI) is a suitable oxidising agent.

    Full specification wording

    Oxidation of alcohols: Acidified potassium dichromate(VI) is a suitable oxidising agent.

    The oxidising agent is potassium dichromate(VI) solution acidified with dilute sulfuric acid.

    Checked against the AQA 7405 specification (opens in a new tab) on .

    • Point 5 of 6
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    The oxidising agent is potassium dichromate(VI) solution acidified with dilute sulfuric acid. The orange dichromate ion, Cr₂O₇²⁻, in which chromium is in the +6 state, is reduced to the green Cr³⁺ ion: Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H₂O. The acid supplies the hydrogen ions that half equation needs, so an unacidified solution will not work and the word acidified must appear in your answer. In organic equations you are allowed to write the oxidant simply as [O], which keeps the focus on the organic change. Because the colour change reports on whether oxidation happened, the same reagent doubles as the test-tube test for primary and secondary alcohols and for aldehydes.

    What earns the marks

    • Naming acidified potassium dichromate(VI), stating that it is acidified.
    • The colour change from orange to green.
    • Identifying the change as chromium going from the +6 to the +3 oxidation state.
    • Using [O] correctly in a balanced organic equation.

    Common mistakes and how to put them right

    • Writing "potassium dichromate" without acidified, which loses the reagent mark.

    • Giving the colour change as orange to blue, or yellow to green.

    • Saying the dichromate is reduced to chromium metal rather than to Cr³⁺.

    • Calling the dichromate a catalyst while also using it as the oxidising agent.

    Exam tips

    • AQA treats a reagent as something you could take out of a bottle, so name the acid as well as the dichromate.
    • Learn the two colours as a pair, orange and green, and always say which is the starting colour.
    • Use [O] to balance organic oxidation equations, then check oxygen and hydrogen separately.

    Try the lesson

    The start of the Oxidation of alcohols: Acidified potassium dichromate(VI) is a suitable oxidising agent. lesson, made from checked teaching notes for this specification point.

    Have a go first

    What colour change is seen when acidified potassium dichromate(VI) oxidises an alcohol?

    Listen

    The oxidising agent is potassium dichromate(VI) solution acidified with dilute sulfuric acid. The orange dichromate ion, Cr₂O₇²⁻, in which chromium is in the +6 state, is reduced to the green Cr³⁺ ion: Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H₂O. The acid supplies the hydrogen ions that half equation needs, so an unacidified solution will not work and the word acidified must appear in your answer. In organic equations you are allowed to write the oxidant simply as [O], which keeps the focus on the organic change. Because the colour change reports on whether oxidation happened, the same reagent doubles as the test-tube test for primary and secondary alcohols and for aldehydes. A strong answer earns marks for these points. naming acidified potassium dichromate(VI), stating that it is acidified. the colour change from orange to green. identifying the change as chromium going from the +6 to the +3 oxidation state. using [O] correctly in a balanced organic equation. Exam tip: AQA treats a reagent as something you could take out of a bottle, so name the acid as well as the dichromate.

    See it

    A top-down flowchart. The top node reads 'Acidified potassium dichromate(VI)' and points down to 'Cr₂O₇²⁻, chromium +6'. From there an arrow labelled 'Reduced' leads to 'Cr³⁺, chromium +3'. A separate arrow from 'Cr₂O₇²⁻, chromium +6' leads to 'Orange', and an arrow from 'Cr³⁺, chromium +3' leads to 'Green'. A node 'Acid supplies H⁺ for half equation' points to 'Cr₂O₇²⁻, chromium +6', and a node 'Unacidified solution will not work' points to 'Acid supplies H⁺ for half equation'. From 'Reduced' an arrow leads to 'Colour change reports whether oxidation happened', which points to 'Test-tube test for primary and secondary alcohols and aldehydes'.
    It shows acidified potassium dichromate(VI) being reduced from orange Cr₂O₇²⁻ with chromium at +6 to green Cr³⁺ with chromium at +3, why the acid is needed, and how the colour change acts as a test.

    Key words

    Say what each word means before you turn the card.

    acidified potassium dichromate(VI)

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    orange to green

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    chromium +6 to +3

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    [O] as shorthand oxidant

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    See every definition
    acidified potassium dichromate(VI)
    A suitable oxidising agent, being potassium dichromate(VI) solution acidified with dilute sulfuric acid.
    orange to green
    The colour change seen when the orange dichromate ion is reduced to the green Cr³⁺ ion.
    chromium +6 to +3
    The change in oxidation state identified when the dichromate ion is reduced to the Cr³⁺ ion.
    [O] as shorthand oxidant
    A way of writing the oxidant in organic equations that keeps the focus on the organic change.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The top node reads 'Acidified potassium dichromate(VI)' and points down to 'Cr₂O₇²⁻, chromium +6'. From there an arrow labelled 'Reduced' leads to 'Cr³⁺, chromium +3'. A separate arrow from 'Cr₂O₇²⁻, chromium +6' leads to 'Orange', and an arrow from 'Cr³⁺, chromium +3' leads to 'Green'. A node 'Acid supplies H⁺ for half equation' points to 'Cr₂O₇²⁻, chromium +6', and a node 'Unacidified solution will not work' points to 'Acid supplies H⁺ for half equation'. From 'Reduced' an arrow leads to 'Colour change reports whether oxidation happened', which points to 'Test-tube test for primary and secondary alcohols and aldehydes'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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