AQA · A-Level · Chemistry

    Course version: 7405 · Version from Sept 2016

    Chlorine atoms are formed in the upper atmosphere when ultraviolet…

    Full specification wording

    Ozone depletion: Chlorine atoms are formed in the upper atmosphere when ultraviolet radiation causes C–Cl bonds in chlorofluorocarbons (CFCs) to break.

    Chlorofluoroalkanes were chosen as refrigerants and solvents because they are unreactive, non-flammable and non-toxic.

    Checked against the AQA 7405 specification (opens in a new tab) on .

    • Point 2 of 6
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Chlorofluoroalkanes were chosen as refrigerants and solvents because they are unreactive, non-flammable and non-toxic. That stability is exactly the problem: nothing destroys them at ground level, so over years they drift up into the stratosphere. There the ultraviolet radiation is energetic enough to break a bond homolytically, one electron going to each atom. It is the C–Cl bond that breaks, not C–F, because C–Cl has the lower bond enthalpy; if a question supplies the two values, quote both, but it is the comparison that carries the mark. For dichlorodifluoromethane the step is CCl₂F₂ → •CClF₂ + Cl•. The species released is a chlorine atom with an unpaired electron, written Cl•, not a chloride ion; the whole catalytic cycle that follows depends on that.

    What earns the marks

    • Homolytic fission of the C–Cl bond caused by ultraviolet radiation.
    • Showing the product as a chlorine radical, Cl•, with the dot.
    • Stating that C–Cl breaks in preference to C–F because it has the lower bond enthalpy.
    • Explaining that the compound is unreactive enough to survive until it reaches the upper atmosphere.

    Common mistakes and how to put them right

    • Breaking the C–F bond, which is stronger and therefore not the one that breaks.

    • Writing Cl⁻ instead of Cl•, which turns a radical mechanism into an ionic one.

    • Describing the fission as heterolytic, giving a pair of ions.

    • Saying the chlorofluorocarbon molecule itself destroys ozone, rather than the radical released from it.

    Exam tips

    • Where the question supplies the two bond enthalpies, quote both to justify which bond breaks; it is the comparison that earns the mark.
    • Write every radical with its dot, including in the equation for the fission step.
    • Link the stability of the compound to the fact that it reaches the stratosphere at all.

    Try the lesson

    The start of the Ozone depletion: Chlorine atoms are formed in the upper atmosphere when ultraviolet radiation causes C–Cl bonds in chlorofluorocarbons (CFCs) to break. lesson, made from checked teaching notes for this specification point.

    Have a go first

    How are chlorine atoms formed from chlorofluorocarbons (CFCs) in the upper atmosphere?

    Listen

    Chlorofluoroalkanes were chosen as refrigerants and solvents because they are unreactive, non-flammable and non-toxic. That stability is exactly the problem: nothing destroys them at ground level, so over years they drift up into the stratosphere. There the ultraviolet radiation is energetic enough to break a bond homolytically, one electron going to each atom. It is the C–Cl bond that breaks, not C–F, because C–Cl has the lower bond enthalpy; if a question supplies the two values, quote both, but it is the comparison that carries the mark. For dichlorodifluoromethane the step is CCl₂F₂ → •CClF₂ + Cl•. The species released is a chlorine atom with an unpaired electron, written Cl•, not a chloride ion; the whole catalytic cycle that follows depends on that. A strong answer earns marks for these points. homolytic fission of the C–Cl bond caused by ultraviolet radiation. showing the product as a chlorine radical, Cl•, with the dot. stating that C–Cl breaks in preference to C–F because it has the lower bond enthalpy. explaining that the compound is unreactive enough to survive until it reaches the upper atmosphere. Exam tip: Where the question supplies the two bond enthalpies, quote both to justify which bond breaks; it is the comparison that earns the mark.

    See it

    A top-down flowchart with seven nodes. The first node, CFC released at ground level, leads to a second node, unreactive so survives and drifts up, which leads to a third node, reaches upper atmosphere. That leads to a fourth node, ultraviolet radiation, which leads to a fifth node, C–Cl bond breaks homolytically. The fifth node branches to two final nodes: chlorine radical Cl• formed, and C–F bond not broken: higher bond enthalpy.
    It shows how an unreactive CFC drifts to the upper atmosphere, where ultraviolet radiation breaks the C–Cl bond homolytically to release a chlorine radical.

    Key words

    Say what each word means before you turn the card.

    chlorofluorocarbons

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    homolytic fission by ultraviolet

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    C–Cl weaker than C–F

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    chlorine radical

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    See every definition
    chlorofluorocarbons
    Compounds whose C–Cl bonds are broken by ultraviolet radiation in the upper atmosphere.
    homolytic fission by ultraviolet
    Breaking of a bond by ultraviolet radiation with one electron going to each atom.
    C–Cl weaker than C–F
    The carbon–chlorine bond has the lower bond enthalpy, so it breaks in preference to the carbon–fluorine bond.
    chlorine radical
    A chlorine atom with an unpaired electron, written Cl•, not a chloride ion.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart with seven nodes. The first node, CFC released at ground level, leads to a second node, unreactive so survives and drifts up, which leads to a third node, reaches upper atmosphere. That leads to a fourth node, ultraviolet radiation, which leads to a fifth node, C–Cl bond breaks homolytically. The fifth node branches to two final nodes: chlorine radical Cl• formed, and C–F bond not broken: higher bond enthalpy.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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