AQA · GCSE · Combined Science

    Course version: 8464 · Version from Sept 2018

    Acceleration: distance, s, in metres, m

    Distance, s, is the length of the path travelled by an object, measured in metres (m).

    Checked against the AQA 8464 specification (opens in a new tab) on .

    • Point 19 of 21

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Distance, s, is the length of the path travelled by an object, measured in metres (m). It is a scalar quantity, so it has magnitude only and no direction. In acceleration problems, s usually means the distance moved during the time interval over which the acceleration acts. For example, using v² − u² = 2 × a × s, if a car accelerates from 0 to 10 m/s at 2 m/s², s = 100 ÷ 4 = 25 m. Distance is not the same as displacement: displacement is the straight-line distance in a stated direction. Convert units before substituting: 250 cm = 2.5 m and 1.2 km = 1200 m. On a velocity–time graph, distance travelled equals the total area between the line and the time axis, treating all areas as positive.

    What earns the marks

    • State that s is the distance travelled along the path and is measured in metres, m.
    • Recognise that distance is a scalar quantity, having magnitude but no direction.
    • Convert distances given in cm, km or mm into metres before substitution.
    • Calculate distance for uniform acceleration using v² − u² = 2 × a × s when u, v and a are known.
    • Find distance from the area under a velocity–time graph, treating all areas (even those below the time axis) as positive path lengths.
    • Distinguish distance s from displacement, which includes direction and treats areas below the time axis as negative.

    Common mistakes and how to put them right

    • Confusing distance with displacement.

      Put it right by noting that distance is scalar and displacement is a vector.

    • Forgetting to convert cm or km to m.

      Put it right by dividing cm by 100 or multiplying km by 1000.

    • Treating areas below the time axis as negative when calculating distance.

      Put it right by adding the absolute values of all areas to find total distance.

    Exam tips

    • Write the unit m with every distance value and check that all quantities are in SI units before calculating.
    • For velocity–time graphs, split the area into rectangles and triangles, then add their absolute values to find total distance s.
    • Remember that distance can never be negative; if a calculation yields a negative value for distance, check your signs for acceleration and displacement.

    Try the lesson

    The start of the Acceleration: distance, s, in metres, m lesson, made from checked teaching notes for this specification point.

    Have a go first

    A cyclist travels a distance of 250 m. What is this distance in metres, written using the symbol for distance?

    Listen

    Distance, s, is the length of the path travelled by an object, measured in metres (m). It is a scalar quantity, so it has magnitude only and no direction. In acceleration problems, s usually means the distance moved during the time interval over which the acceleration acts. For example, using v² − u² = 2 × a × s, if a car accelerates from 0 to 10 m/s at 2 m/s², s = 100 ÷ 4 = 25 m. Distance is not the same as displacement: displacement is the straight-line distance in a stated direction. Convert units before substituting: 250 cm = 2.5 m and 1.2 km = 1200 m. On a velocity–time graph, distance travelled equals the total area between the line and the time axis, treating all areas as positive. A strong answer earns marks for these points. State that s is the distance travelled along the path and is measured in metres, m. Recognise that distance is a scalar quantity, having magnitude but no direction. Convert distances given in cm, km or mm into metres before substitution. Calculate distance for uniform acceleration using v² − u² = 2 × a × s when u, v and a are known. A common slip: Confusing distance with displacement. Instead, noting that distance is scalar and displacement is a vector. Exam tip: Write the unit m with every distance value and check that all quantities are in SI units before calculating.

    See it

    A top-down flowchart. The top node reads 'Distance s: length of path travelled'. Six arrows lead from it to nodes below: 'Measured in metres, m'; 'Scalar: magnitude only, no direction'; 'Convert units before substituting: cm ÷ 100, km × 1000'; 'Uniform acceleration: v² − u² = 2 × a × s'; 'Velocity–time graph: total area between line and time axis, all areas positive'; and 'Not the same as displacement: displacement is straight-line distance in a stated direction'.
    It shows what distance s is, its unit and scalar nature, unit conversion, the two ways of finding it, and how it differs from displacement.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The top node reads 'Distance s: length of path travelled'. Six arrows lead from it to nodes below: 'Measured in metres, m'; 'Scalar: magnitude only, no direction'; 'Convert units before substituting: cm ÷ 100, km × 1000'; 'Uniform acceleration: v² − u² = 2 × a × s'; 'Velocity–time graph: total area between line and time axis, all areas positive'; and 'Not the same as displacement: displacement is straight-line distance in a stated direction'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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