AQA · GCSE · Mathematics

    Course version: 8300 · Version from Sept 2015

    Solve problems involving direct and inverse proportion, including…

    Full specification wording

    Ratio, proportion and rates of change: solve problems involving direct and inverse proportion, including graphical and algebraic representations

    Direct proportion means one quantity is a constant multiple of another, so y = kx and the graph is a straight line through the origin.

    Checked against the AQA 8300 specification (opens in a new tab) on .

    • Point 11 of 21
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Direct proportion means one quantity is a constant multiple of another, so y = kx and the graph is a straight line through the origin. Inverse proportion means the product is constant, so y = k/x and the graph is a curve that never touches the axes. To solve a problem, first decide which relationship fits the wording, then find k from a given pair of values, then substitute the required value. For example, if 4 pens cost £6, the unit rate is £1.50, so 10 pens cost £15. Graphically, direct proportion passes through (0, 0); inverse proportion has a decreasing curve. Algebraically, rearrange to find k before answering the question asked.

    What earns the marks

    • Identify whether the relationship is direct (y = kx) or inverse (y = k/x) from the wording of the problem.
    • Find the constant of proportionality k by substituting a known pair of values into the correct equation.
    • Use the value of k to calculate the unknown quantity, showing the substitution clearly.
    • Interpret a direct proportion graph as a straight line through the origin and an inverse proportion graph as a curve with constant product.
    • Solve algebraic proportion problems by forming and solving an equation such as 4k = 6 or k/4 = 6.

    Common mistakes and how to put them right

    • Assuming every proportion is direct.

      Put it right: If doubling one quantity halves the other, the relationship is inverse, so use y = k/x rather than y = kx.

    • Forgetting to find k first.

      Put it right: Substituting values straight into y = kx without calculating k gives an incorrect answer; always find k from the given pair.

    • Misreading a graph: a straight line through the origin shows direct proportion, while a curve that gets closer to the axes shows inverse proportion; do not treat a curve as a straight line.

    • Using the wrong operation when rearranging.

      Put it right: For inverse proportion, multiply the known pair to find k, then divide k by the new value.

    Exam tips

    • Underline the words 'direct' or 'inverse' in the question and write the matching equation before doing any arithmetic.
    • Show the step where you calculate k, because method marks are often available even if the final value is wrong.
    • Check your answer by substituting back into the original relationship: for direct proportion the ratio should stay constant, and for inverse proportion the product should stay constant.

    Try the lesson

    The start of the Ratio, proportion and rates of change: solve problems involving direct and inverse proportion, including graphical and algebraic representations lesson, made from checked teaching notes for this specification point.

    Have a go first

    The cost of pens is directly proportional to the number of pens bought. If 6 pens cost £9, work out the cost of 15 pens.

    Listen

    Direct proportion means one quantity is a constant multiple of another, so y = kx and the graph is a straight line through the origin. Inverse proportion means the product is constant, so y = k/x and the graph is a curve that never touches the axes. To solve a problem, first decide which relationship fits the wording, then find k from a given pair of values, then substitute the required value. For example, if 4 pens cost £6, the unit rate is £1.50, so 10 pens cost £15. Graphically, direct proportion passes through (0, 0); inverse proportion has a decreasing curve. Algebraically, rearrange to find k before answering the question asked. A strong answer earns marks for these points. Identify whether the relationship is direct (y = kx) or inverse (y = k/x) from the wording of the problem. Find the constant of proportionality k by substituting a known pair of values into the correct equation. Use the value of k to calculate the unknown quantity, showing the substitution clearly. Interpret a direct proportion graph as a straight line through the origin and an inverse proportion graph as a curve with constant product. Exam tip: Underline the words 'direct' or 'inverse' in the question and write the matching equation before doing any arithmetic.

    See it

    A flowchart running top to bottom. The first box says to decide whether the relationship is direct or inverse from the wording. A decision box asks which relationship fits. The direct branch leads to writing y = kx and the inverse branch leads to writing y = k/x. Both branches lead to a box saying to find k by substituting a known pair of values. The next box says to use the value of k to calculate the unknown quantity, and the final box says to check the result by substituting back.
    A step-by-step process for solving direct and inverse proportion problems, from deciding the relationship to checking the answer.

    Watch it explained

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    Read the described scene instead

    This lesson looks at direct and inverse proportion. You will connect the wording of a problem to an equation, to a graph, and to a numerical answer. The key question is whether one quantity is a constant multiple of the other, or whether their product stays constant. Direct proportion means y equals k x, so the graph is a straight line through the origin. Inverse proportion means y equals k over x, so the product x y is constant and the graph is a curve that never touches the axes. Here k is the constant of proportionality. To solve a proportion problem, first decide which relationship fits the wording. Then find the constant of proportionality k by substituting a known pair of values into the correct equation. Next, use k to calculate the unknown quantity, showing the substitution clearly. Finally, check whether the ratio or the product stays constant. Pause here and decide whether the pen problem is direct or inverse. Four pens cost six pounds. Because the cost per pen is constant, this is direct proportion. The unit rate is one pound fifty per pen. So ten pens cost fifteen pounds. You can also write y equals k x, with k equal to one point five, then substitute x equals ten. Do not assume every proportion is direct. If doubling one quantity halves the other, the relationship is inverse, so use y equals k over x. Always find k before substituting; otherwise the answer is likely wrong. On a graph, a straight line through the origin shows direct proportion, while a curve approaching the axes shows inverse proportion. For inverse proportion, multiply the known pair to find k, then divide k by the new value. Remember that direct proportion is a constant ratio and a straight-line graph through the origin. Inverse proportion is a constant product and a reciprocal curve. In both cases, find k from a known pair, then substitute the required value. Move between the algebraic equation, the graph, and the numerical answer, checking that the ratio or product remains constant.

    Key words

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    Direct proportion

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    Inverse proportion

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    Constant of proportionality k

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    Graphical representation

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    See every definition
    Direct proportion
    One quantity is a constant multiple of another, so y = kx and the graph is a straight line through the origin.
    Inverse proportion
    The product is constant, so y = k/x and the graph is a curve that never touches the axes.
    Constant of proportionality k
    Found by substituting a known pair of values into the correct equation before calculating the unknown quantity.
    Graphical representation
    Direct proportion passes through (0, 0), while inverse proportion has a decreasing curve.

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