AQA · GCSE · Physics

    Course version: 8463 · Version from Sept 2016

    Image height and object height should both be measured in either mm or cm.

    Full specification wording

    Lenses (physics only): Image height and object height should both be measured in either mm or cm.

    Magnification = image height / object height, so it is a ratio of two lengths and has no unit, but only if both heights are measured in the same unit.

    Checked against the AQA 8463 specification (opens in a new tab) on .

    • Point 8 of 9
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Magnification = image height / object height, so it is a ratio of two lengths and has no unit, but only if both heights are measured in the same unit. Measure both in millimetres or both in centimetres; mixing them makes the answer ten times too big or too small. In a diagram question you measure the arrows with a ruler, for example an image 2.0 cm tall and an object 0.8 cm tall, giving a magnification of 2.5. Rearranging lets you find either height, since image height = magnification × object height, so a symbol 1.6 mm tall magnified 3.5 times gives an image height of 5.6 mm. One special case is worth knowing: when the object height is exactly 1 cm, the image height in centimetres is numerically equal to the magnification.

    What earns the marks

    • A correct substitution into magnification = image height / object height.
    • A correct rearrangement when a height is the unknown, such as image height = magnification × object height.
    • The final value, with a unit for a height and no unit for a magnification.

    Common mistakes and how to put them right

    • Measuring the object in millimetres and the image in centimetres, so the magnification is out by a factor of ten.

    • Giving the magnification a unit such as cm or times.

    • Inverting the ratio by dividing object height by image height.

    • Measuring the object and image arrows inconsistently, including the arrow head on one but not the other.

    Exam tips

    • Write the unit next to each measured height before you divide, because that makes a mismatch obvious.
    • Magnification has no unit, so leave the answer as a bare number.
    • Measure with a ruler to the nearest millimetre and quote the values you used in your working.

    Try the lesson

    The start of the Lenses (physics only): Image height and object height should both be measured in either mm or cm. lesson, made from checked teaching notes for this specification point.

    Have a go first

    A student measures an object height as 30 mm and the matching image height as 6 cm. Which statement about these two measurements is correct?

    Listen

    Magnification = image height / object height, so it is a ratio of two lengths and has no unit, but only if both heights are measured in the same unit. Measure both in millimetres or both in centimetres; mixing them makes the answer ten times too big or too small. In a diagram question you measure the arrows with a ruler, for example an image 2.0 cm tall and an object 0.8 cm tall, giving a magnification of 2.5. Rearranging lets you find either height, since image height = magnification × object height, so a symbol 1.6 mm tall magnified 3.5 times gives an image height of 5.6 mm. One special case is worth knowing: when the object height is exactly 1 cm, the image height in centimetres is numerically equal to the magnification. A strong answer earns marks for these points. a correct substitution into magnification = image height / object height. a correct rearrangement when a height is the unknown, such as image height = magnification × object height. the final value, with a unit for a height and no unit for a magnification. Exam tip: Write the unit next to each measured height before you divide, because that makes a mismatch obvious.

    See it

    A flowchart running from top to bottom. The first box says measure object height, which leads to a box saying measure image height. That leads to a decision box asking whether both are in the same unit. The yes branch goes to a box giving magnification equals image height divided by object height. The no branch goes to a box saying convert so both are in mm or both in cm, which then leads to the same magnification box. From the magnification box, two boxes follow: one saying magnification has no unit, and one giving the rearrangement image height equals magnification times object height.
    It shows the steps for measuring both heights in the same unit, calculating magnification, and rearranging the equation to find a height.

    Key words

    Say what each word means before you turn the card.

    magnification ratio

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    same unit for both heights

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    no unit for magnification

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    rearranging the equation

    Try answering aloud or in your head before turning the card.

    See every definition
    magnification ratio
    A ratio of two lengths, image height divided by object height, which has no unit.
    same unit for both heights
    Image height and object height should both be measured in either mm or cm, because mixing them makes the answer ten times too big or too small.
    no unit for magnification
    The final value has a unit for a height and no unit for a magnification, so the answer is left as a bare number.
    rearranging the equation
    Rearranging lets you find either height, since image height = magnification × object height.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A flowchart running from top to bottom. The first box says measure object height, which leads to a box saying measure image height. That leads to a decision box asking whether both are in the same unit. The yes branch goes to a box giving magnification equals image height divided by object height. The no branch goes to a box saying convert so both are in mm or both in cm, which then leads to the same magnification box. From the magnification box, two boxes follow: one saying magnification has no unit, and one giving the rearrangement image height equals magnification times object height.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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