OCR · A-Level · Physics

    Course version: H556 · Version from Sept 2015

    Centripetal force: (c) centripetal acceleration; a = v²/r; a = ω²r

    Centripetal acceleration is the acceleration of a body moving in a circle at constant speed.

    Checked against the OCR H556 specification (opens in a new tab) on .

    • Point 3 of 4
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Centripetal acceleration is the acceleration of a body moving in a circle at constant speed. Because velocity is a vector, its direction changes continuously, so the body accelerates even though its speed is constant. This acceleration acts towards the centre of the circle, perpendicular to the instantaneous velocity. For a body moving at speed v on a circle of radius r, the magnitude is a = v²/r. Since v = ωr, substituting gives a = (ωr)²/r = ω²r, so a = ω²r. For example, a ball whirled on a 0.50 m string at 4.0 m s⁻¹ has a = (4.0)²/0.50 = 32 m s⁻², directed towards the centre. Angular speed ω is measured in rad s⁻¹, so ω²r gives m s⁻².

    What earns the marks

    • States that centripetal acceleration is directed towards the centre of the circular path, perpendicular to the instantaneous velocity.
    • Uses a = v²/r correctly, substituting speed in m s⁻¹ and radius in m, to obtain acceleration in m s⁻².
    • Uses a = ω²r correctly, with ω in rad s⁻¹ and r in m, to obtain acceleration in m s⁻².
    • Explains that speed is constant but velocity changes direction, so the body accelerates.
    • Links the two forms through v = ωr, showing a = v²/r and a = ω²r are equivalent.

    Common mistakes and how to put them right

    • Thinking a body moving at constant speed in a circle has zero acceleration.

      Put it right by noting velocity changes direction, so acceleration is non-zero and directed towards the centre.

    • Treating centripetal acceleration as directed outwards or along the tangent.

      Put it right by stating it always points towards the centre, perpendicular to velocity.

    • Using diameter in place of radius in a = v²/r.

      Put it right by halving any diameter before substituting.

    • Mixing units by using ω in degrees per second or revolutions per minute.

      Put it right by converting to rad s⁻¹ before using a = ω²r.

    Exam tips

    • Check whether the question gives v or ω, then choose a = v²/r or a = ω²r to avoid an unnecessary conversion step.
    • Convert any angular speed in rev min⁻¹ to rad s⁻¹ by multiplying by 2π and dividing by 60 before substituting.
    • State the direction of the acceleration as towards the centre whenever the question asks for a vector quantity.

    Try the lesson

    The start of the Centripetal force: (c) centripetal acceleration; a = v²/r; a = ω²r lesson, made from checked teaching notes for this specification point.

    Listen

    Centripetal acceleration is the acceleration of a body moving in a circle at constant speed. Because velocity is a vector, its direction changes continuously, so the body accelerates even though its speed is constant. This acceleration acts towards the centre of the circle, perpendicular to the instantaneous velocity. For a body moving at speed v on a circle of radius r, the magnitude is a = v²/r. Since v = ωr, substituting gives a = (ωr)²/r = ω²r, so a = ω²r. For example, a ball whirled on a 0.50 m string at 4.0 m s⁻¹ has a = (4.0)²/0.50 = 32 m s⁻², directed towards the centre. Angular speed ω is measured in rad s⁻¹, so ω²r gives m s⁻². A strong answer earns marks for these points. States that centripetal acceleration is directed towards the centre of the circular path, perpendicular to the instantaneous velocity. Uses a = v²/r correctly, substituting speed in m s⁻¹ and radius in m, to obtain acceleration in m s⁻². Uses a = ω²r correctly, with ω in rad s⁻¹ and r in m, to obtain acceleration in m s⁻². Explains that speed is constant but velocity changes direction, so the body accelerates. A common slip: Thinking a body moving at constant speed in a circle has zero acceleration. Instead, noting velocity changes direction, so acceleration is non-zero and directed towards the centre. Exam tip: Check whether the question gives v or ω, then choose a = v²/r or a = ω²r to avoid an unnecessary conversion step.

    Key words

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    Centripetal acceleration

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    Vector nature of velocity and acceleration

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    Centripetal acceleration magnitude and direction

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    Relationship between linear and angular speed

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    See every definition
    Centripetal acceleration
    The acceleration of a body moving in a circle at constant speed, acting towards the centre of the circle and perpendicular to the instantaneous velocity.
    Vector nature of velocity and acceleration
    Because velocity is a vector, its direction changes continuously, so the body accelerates even though its speed is constant.
    Centripetal acceleration magnitude and direction
    For a body moving at speed v on a circle of radius r the magnitude is a = v²/r, directed towards the centre.
    Relationship between linear and angular speed
    Since v = ωr, substituting gives a = (ωr)²/r = ω²r, so a = ω²r.

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