OCR · A-Level · Physics

    Course version: H556 · Version from Sept 2015

    Centripetal force: (i) centripetal force; F = mv²/r; F = mω²r

    Centripetal force is the resultant force that keeps a body moving in a circular path.

    Checked against the OCR H556 specification (opens in a new tab) on .

    • Point 4 of 4
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Centripetal force is the resultant force that keeps a body moving in a circular path. It acts towards the centre of the circle, perpendicular to the body's velocity, and changes the direction of motion without changing speed. By Newton's second law, F = ma, and substituting the centripetal acceleration gives F = mv²/r. Since v = ωr, substituting gives F = m(ωr)²/r = mω²r, so F = mω²r. For example, a 0.20 kg mass moving at 3.0 m s⁻¹ on a 0.60 m radius needs F = 0.20 × (3.0)²/0.60 = 3.0 N towards the centre. The force is provided by a real interaction such as tension, friction or gravity, not by a new outward force.

    What earns the marks

    • States that centripetal force is the resultant force directed towards the centre of the circular path.
    • Applies F = mv²/r correctly, using mass in kg, speed in m s⁻¹ and radius in m to obtain force in N.
    • Applies F = mω²r correctly, using ω in rad s⁻¹ and r in m to obtain force in N.
    • Explains that the centripetal force is provided by a real force such as tension, friction or gravitational attraction.
    • Links the two forms through v = ωr, showing F = mv²/r and F = mω²r are equivalent.

    Common mistakes and how to put them right

    • Inventing an outward centrifugal force as the reaction to the centripetal force.

      Put it right by stating that the centripetal force is the resultant inward force and any outward sensation arises from inertia.

    • Using diameter instead of radius in F = mv²/r.

      Put it right by halving the diameter before substituting.

    • Forgetting to square the speed or angular speed.

      Put it right by checking the exponent in the equation before calculating.

    • Using ω in rev s⁻¹ rather than rad s⁻¹.

      Put it right by multiplying revolutions per second by 2π.

    Exam tips

    • Identify which real force supplies the centripetal force before substituting numbers, as questions often ask for this explanation.
    • Choose F = mv²/r when speed is given and F = mω²r when angular speed or period is given.
    • Check that the final force is quoted with a direction towards the centre when the question asks for a vector.

    Try the lesson

    The start of the Centripetal force: (i) centripetal force; F = mv²/r; F = mω²r lesson, made from checked teaching notes for this specification point.

    Listen

    Centripetal force is the resultant force that keeps a body moving in a circular path. It acts towards the centre of the circle, perpendicular to the body's velocity, and changes the direction of motion without changing speed. By Newton's second law, F = ma, and substituting the centripetal acceleration gives F = mv²/r. Since v = ωr, substituting gives F = m(ωr)²/r = mω²r, so F = mω²r. For example, a 0.20 kg mass moving at 3.0 m s⁻¹ on a 0.60 m radius needs F = 0.20 × (3.0)²/0.60 = 3.0 N towards the centre. The force is provided by a real interaction such as tension, friction or gravity, not by a new outward force. A strong answer earns marks for these points. States that centripetal force is the resultant force directed towards the centre of the circular path. Applies F = mv²/r correctly, using mass in kg, speed in m s⁻¹ and radius in m to obtain force in N. Applies F = mω²r correctly, using ω in rad s⁻¹ and r in m to obtain force in N. Explains that the centripetal force is provided by a real force such as tension, friction or gravitational attraction. A common slip: Inventing an outward centrifugal force as the reaction to the centripetal force. Instead, stating that the centripetal force is the resultant inward force and any outward sensation arises from inertia. Exam tip: Identify which real force supplies the centripetal force before substituting numbers, as questions often ask for this explanation.

    See it

    A top-down flowchart. The top node reads 'Centripetal force: resultant force towards centre of circle'. It branches to three paths. The left path goes to 'Acts perpendicular to velocity', then to 'Changes direction of motion, not speed'. The middle path goes to 'Newton's second law: F = ma', then to 'Substitute centripetal acceleration: F = mv²/r', then to 'Use v = ωr', then to 'F = m(ωr)²/r = mω²r'. The right path goes to 'Provided by a real force: tension, friction or gravity'.
    Shows that centripetal force is the resultant inward force, how F = mv²/r leads to F = mω²r via v = ωr, and that a real force provides it.

    Key words

    Say what each word means before you turn the card.

    Centripetal force

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    Newton's second law in circular motion

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    Real forces providing circular motion

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    Relationship between linear and angular quantities

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    See every definition
    Centripetal force
    The resultant force that keeps a body moving in a circular path, acting towards the centre of the circle and perpendicular to the body's velocity.
    Newton's second law in circular motion
    F = ma, and substituting the centripetal acceleration gives F = mv²/r.
    Real forces providing circular motion
    The force is provided by a real interaction such as tension, friction or gravity, not by a new outward force.
    Relationship between linear and angular quantities
    Since v = ωr, substituting gives F = m(ωr)²/r = mω²r, so F = mω²r.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The top node reads 'Centripetal force: resultant force towards centre of circle'. It branches to three paths. The left path goes to 'Acts perpendicular to velocity', then to 'Changes direction of motion, not speed'. The middle path goes to 'Newton's second law: F = ma', then to 'Substitute centripetal acceleration: F = mv²/r', then to 'Use v = ωr', then to 'F = m(ωr)²/r = mω²r'. The right path goes to 'Provided by a real force: tension, friction or gravity'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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