OCR · A-Level · Physics

    Course version: H556 · Version from Sept 2015

    (b) elastic potential energy; E = 1/2 Fx; E = 1/2 kx²

    Full specification wording

    Mechanical properties of matter: (b) elastic potential energy; E = 1/2 Fx; E = 1/2 kx²

    Elastic potential energy is the energy stored in a material when it is stretched or compressed elastically, and it is recovered when the deforming force is removed.

    Checked against the OCR H556 specification (opens in a new tab) on .

    • Point 2 of 7
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Elastic potential energy is the energy stored in a material when it is stretched or compressed elastically, and it is recovered when the deforming force is removed. For a material obeying Hooke's law, the stored energy equals the work done, which is the area under the force–extension graph: E = ½Fx, where F is the final force and x is the extension. Since F = kx, substituting gives E = ½kx², where k is the force constant in N m⁻¹. Both expressions apply only while the limit of proportionality is not exceeded.

    For example: A spring of force constant 200 N m⁻¹ stretched by 0.10 m stores E = ½ × 200 × (0.10)² = 1.0 J.

    What earns the marks

    • Elastic potential energy is the energy stored when a material is elastically stretched or compressed.
    • E = ½Fx applies to a straight-line force–extension graph through the origin, where F is the final force and x the extension.
    • E = ½kx² follows from substituting F = kx, with k the force constant in N m⁻¹.
    • The expressions apply only up to the limit of proportionality; beyond it the stored energy is not given by these equations.

    Common mistakes and how to put them right

    • Using the full force throughout the extension.

      Put it right: The average force is ½F, which is why the factor ½ appears.

    • Forgetting to square the extension in E = ½kx².

      Put it right: Square x before multiplying.

    • Applying the equations beyond the limit of proportionality.

      Put it right: They hold only for straight-line Hooke's law behaviour.

    Exam tips

    • Write down the equation, substitute values with units, then evaluate to avoid order-of-operation errors.
    • Check that the extension is in metres before squaring it in E = ½kx².
    • If the material has been stretched beyond the limit of proportionality, state that these equations no longer apply.

    Try the lesson

    The start of the Mechanical properties of matter: (b) elastic potential energy; E = 1/2 Fx; E = 1/2 kx² lesson, made from checked teaching notes for this specification point.

    Listen

    Elastic potential energy is the energy stored in a material when it is stretched or compressed elastically, and it is recovered when the deforming force is removed. For a material obeying Hooke's law, the stored energy equals the work done, which is the area under the force–extension graph: E = ½Fx, where F is the final force and x is the extension. Since F = kx, substituting gives E = ½kx², where k is the force constant in N m⁻¹. Both expressions apply only while the limit of proportionality is not exceeded. For example, a spring of force constant 200 N m⁻¹ stretched by 0.10 m stores E = ½ × 200 × (0.10)² = 1.0 J. A strong answer earns marks for these points. Elastic potential energy is the energy stored when a material is elastically stretched or compressed. E = ½Fx applies to a straight-line force–extension graph through the origin, where F is the final force and x the extension. E = ½kx² follows from substituting F = kx, with k the force constant in N m⁻¹. The expressions apply only up to the limit of proportionality; beyond it the stored energy is not given by these equations. A common slip: Using the full force throughout the extension. Instead, the average force is ½F, which is why the factor ½ appears. Exam tip: Write down the equation, substitute values with units, then evaluate to avoid order-of-operation errors.

    See it

    A top-down flowchart. The first box says a material is stretched or compressed elastically, leading to a box saying energy is stored as elastic potential energy. That leads to a box saying the work done is the area under the force–extension graph, which leads to the equation E = ½Fx. An arrow labelled 'Substitute F = kx' leads to the equation E = ½kx², and a final arrow leads to a box stating this is valid only up to the limit of proportionality.
    It shows how elastic potential energy is stored, how the work done gives E = ½Fx, and how substituting F = kx gives E = ½kx², valid only up to the limit of proportionality.

    Put it in order

    Put these steps in the order they happen.

    1. 1. Valid only up to the limit of proportionality
    2. 2. E = ½kx²
    3. 3. Work done = area under force–extension graph
    4. 4. Substitute F = kx
    5. 5. Material stretched or compressed elastically
    6. 6. Energy stored as elastic potential energy
    7. 7. E = ½Fx

    Key words

    Say what each word means before you turn the card.

    Elastic potential energy

    Try answering aloud or in your head before turning the card.

    Hooke's law

    Try answering aloud or in your head before turning the card.

    Force constant

    Try answering aloud or in your head before turning the card.

    Limit of proportionality

    Try answering aloud or in your head before turning the card.

    See every definition
    Elastic potential energy
    The energy stored in a material when it is stretched or compressed elastically, recovered when the deforming force is removed.
    Hooke's law
    Behaviour in which the force–extension graph is a straight line through the origin, so that F = kx.
    Force constant
    The constant k in F = kx, measured in N m⁻¹.
    Limit of proportionality
    The point up to which the expressions for stored energy apply; beyond it the stored energy is not given by these equations.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The first box says a material is stretched or compressed elastically, leading to a box saying energy is stored as elastic potential energy. That leads to a box saying the work done is the area under the force–extension graph, which leads to the equation E = ½Fx. An arrow labelled 'Substitute F = kx' leads to the equation E = ½kx², and a final arrow leads to a box stating this is valid only up to the limit of proportionality.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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