OCR · A-Level · Physics

    Course version: H556 · Version from Sept 2015

    Superposition: (i) λ = ax/D for all waves where a ≪ D

    This relationship links the wavelength λ of any wave to the geometry of a two-source interference pattern.

    Checked against the OCR H556 specification (opens in a new tab) on .

    • Point 7 of 10

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    This relationship links the wavelength λ of any wave to the geometry of a two-source interference pattern. Here a is the separation of the two coherent sources, x is the fringe spacing measured between corresponding points on adjacent maxima, and D is the perpendicular distance from the source plane to the screen. The condition a ≪ D means the source separation is much smaller than the screen distance, so the rays reaching a point on the screen are nearly parallel and the small-angle approximation holds. Rearranged, λ = ax/D. For example, with a = 0.50 mm, x = 2.4 mm and D = 1.20 m, λ = (0.50 × 10⁻³ m × 2.4 × 10⁻³ m) / 1.20 m = 1.0 × 10⁻⁶ m. The equation applies to all waves, including sound and microwaves, provided the geometry condition is met.

    What earns the marks

    • States that λ = ax/D relates wavelength to source separation a, fringe spacing x and screen distance D.
    • Identifies a as the separation of the two coherent sources and x as the spacing between adjacent maxima (or adjacent minima).
    • Identifies D as the perpendicular distance from the sources to the screen, measured along the axis.
    • Applies the condition a ≪ D, which justifies the small-angle approximation used to derive the equation.
    • Rearranges correctly, for example x = λD/a or a = λD/x, and substitutes values with consistent SI units.
    • Recognises that the equation applies to all waves, not only light, when the stated geometry condition is satisfied.

    Common mistakes and how to put them right

    • Confusing a with the slit width.

      Put it right by labelling a as source separation.

    • Measuring x across several fringes and forgetting to divide by the number of intervals.

      Put it right: If n fringes span a distance, x equals that distance divided by n, not by n + 1.

    • Using D as the distance from one slit rather than from the source plane to the screen.

      Put it right by measuring D perpendicular to the plane containing both sources.

    • Mixing units, such as millimetres for a and metres for D, without converting.

      Put it right by converting every length to metres before substituting.

    Exam tips

    • Write the equation, rearrange it symbolically, then substitute values; this secures method credit even if the arithmetic slips.
    • Check the a ≪ D condition in the question before using the equation; if it is not met, the small-angle derivation does not apply.
    • Convert millimetres to metres by multiplying by 10⁻³, and quote the final wavelength with a sensible power of ten and unit.
    • When a question gives the distance across several fringes, count the intervals between them, not the number of bright lines.

    Try the lesson

    The start of the Superposition: (i) λ = ax/D for all waves where a ≪ D lesson, made from checked teaching notes for this specification point.

    Listen

    This relationship links the wavelength λ of any wave to the geometry of a two-source interference pattern. Here a is the separation of the two coherent sources, x is the fringe spacing measured between corresponding points on adjacent maxima, and D is the perpendicular distance from the source plane to the screen. The condition a ≪ D means the source separation is much smaller than the screen distance, so the rays reaching a point on the screen are nearly parallel and the small-angle approximation holds. Rearranged, λ = ax/D. For example, with a = 0.50 mm, x = 2.4 mm and D = 1.20 m, λ = (0.50 × 10⁻³ m × 2.4 × 10⁻³ m) / 1.20 m = 1.0 × 10⁻⁶ m. The equation applies to all waves, including sound and microwaves, provided the geometry condition is met. A strong answer earns marks for these points. States that λ = ax/D relates wavelength to source separation a, fringe spacing x and screen distance D. Identifies a as the separation of the two coherent sources and x as the spacing between adjacent maxima (or adjacent minima). Identifies D as the perpendicular distance from the sources to the screen, measured along the axis. Applies the condition a ≪ D, which justifies the small-angle approximation used to derive the equation. A common slip: Confusing a with the slit width: a is the separation between the two sources, while slit width controls diffraction spreading. Instead, labelling a as source separation. Exam tip: Write the equation, rearrange it symbolically, then substitute values; this secures method credit even if the arithmetic slips.

    See it

    A top-down flowchart. The first box reads 'Two coherent sources, separation a' and points to 'Screen at perpendicular distance D'. That points to 'Condition: a ≪ D', which points to 'Rays reaching a screen point are nearly parallel; small-angle approximation holds'. This points to 'Fringe spacing x between adjacent maxima', which points to 'λ = ax/D'. That points to 'Rearrange: x = λD/a or a = λD/x', which points to 'Substitute values in consistent SI units', which finally points to 'Applies to all waves when a ≪ D'.
    Shows how the source separation a, screen distance D and fringe spacing x combine in λ = ax/D, with the a ≪ D condition enabling the small-angle approximation.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The first box reads 'Two coherent sources, separation a' and points to 'Screen at perpendicular distance D'. That points to 'Condition: a ≪ D', which points to 'Rays reaching a screen point are nearly parallel; small-angle approximation holds'. This points to 'Fringe spacing x between adjacent maxima', which points to 'λ = ax/D'. That points to 'Rearrange: x = λD/a or a = λD/x', which points to 'Substitute values in consistent SI units', which finally points to 'Applies to all waves when a ≪ D'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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