OCR · GCSE · Physics
Course version: J249 · Version from Sept 2018
Recall and apply: potential difference (V) = current (A) × resistance (Ω)
Full specification wording
Simple circuits: recall and apply: potential difference (V) = current (A) × resistance (Ω)
For a component, potential difference, current and resistance are linked by V = I × R, where V is in volts (V), I in amperes (A) and R in ohms (Ω).
Checked against the OCR J249 specification (opens in a new tab) on .
- Point 1 of 14
- 4 key terms
Study notes
From the checked teaching notes for this specification point.
The idea
For a component, potential difference, current and resistance are linked by V = I × R, where V is in volts (V), I in amperes (A) and R in ohms (Ω). Potential difference is the energy transferred per unit charge, current is the rate of charge flow and resistance opposes that flow. To apply the relationship, identify the two known values, keep units as volts, amperes and ohms, then multiply current by resistance to find potential difference, or rearrange to I = V ÷ R or R = V ÷ I. For example, a current of 0.5 A through a 12 Ω resistor gives V = 0.5 × 12 = 6 V. In a multiple-choice question, calculate first, then match your value and unit to an option, checking whether the question asks for V, I or R.
What earns the marks
- Selects the option that applies V = I × R with current in amperes and resistance in ohms.
- Rearranges the relationship correctly to find current as potential difference divided by resistance.
- Rearranges the relationship correctly to find resistance as potential difference divided by current.
- Matches the calculated value to the correct unit of volts, amperes or ohms as requested.
Common mistakes and how to put them right
Adds current and resistance instead of multiplying them.
Put it right: Multiply the two values to find potential difference.
Divides resistance by current when finding potential difference.
Put it right: Multiply current by resistance instead.
Reports resistance in volts.
Put it right: Give resistance in ohms and potential difference in volts.
Exam tips
- Write V = I × R and substitute the given values before checking the options.
- Decide which quantity the question asks for, then rearrange before calculating.
- Check that the unit of your answer matches the quantity requested.
Try the lesson
The start of the Simple circuits: recall and apply: potential difference (V) = current (A) × resistance (Ω) lesson, made from checked teaching notes for this specification point.
Have a go first
A wire carries a current of 2 A and has a resistance of 5 Ω. What is the potential difference across the wire?
Listen
For a component, potential difference, current and resistance are linked by V = I × R, where V is in volts (V), I in amperes (A) and R in ohms (Ω). Potential difference is the energy transferred per unit charge, current is the rate of charge flow and resistance opposes that flow. To apply the relationship, identify the two known values, keep units as volts, amperes and ohms, then multiply current by resistance to find potential difference, or rearrange to I = V ÷ R or R = V ÷ I. For example, a current of 0.5 A through a 12 Ω resistor gives V = 0.5 × 12 = 6 V. In a multiple-choice question, calculate first, then match your value and unit to an option, checking whether the question asks for V, I or R. A strong answer earns marks for these points. Selects the option that applies V = I × R with current in amperes and resistance in ohms. Rearranges the relationship correctly to find current as potential difference divided by resistance. Rearranges the relationship correctly to find resistance as potential difference divided by current. Matches the calculated value to the correct unit of volts, amperes or ohms as requested. Exam tip: Write V = I × R and substitute the given values before checking the options.
See it
Key words
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Potential difference
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Current
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Resistance
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Using and rearranging equations
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See every definition
- Potential difference
- The energy transferred per unit charge, measured in volts (V).
- Current
- The rate of charge flow, measured in amperes (A).
- Resistance
- Opposes the flow of charge and is measured in ohms (Ω).
- Using and rearranging equations
- Identify the two known values, keep units as volts, amperes and ohms, then multiply current by resistance to find potential difference, or rearrange to find current or resistance.
Label the diagram
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1Box 1
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