Pearson Edexcel · GCSE · Physics

    Course version: 1PH0 · Version from Sept 2016

    Analyse velocity/time graphs to: a compare acceleration from gradients…

    Full specification wording

    Topic 2 – Motion and forces: 2.10 Analyse velocity/time graphs to: a compare acceleration from gradients qualitatively b calculate the acceleration from the gradient (for uniform acceleration only) c determine the distance travelled using the area between the graph line and the time axis (for uniform acceleration only)

    A velocity/time graph plots velocity on the vertical axis against time on the horizontal axis.

    Checked against the Pearson Edexcel 1PH0 specification (opens in a new tab) on .

    • Point 10 of 32

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    A velocity/time graph plots velocity on the vertical axis against time on the horizontal axis. The gradient of the line gives acceleration: a steeper line means greater acceleration, a horizontal line means zero acceleration (constant velocity), and a line sloping down means deceleration. To calculate acceleration for uniform acceleration, pick two points on a straight section and divide the change in velocity by the change in time, giving m/s². The area between the graph line and the time axis gives the distance travelled; for a straight-line section this area is a rectangle or triangle, so distance = area, in metres. For example, a triangle of base 4 s and height 10 m/s has area ½ × 4 × 10 = 20 m. Use gradient for acceleration and area for distance, and apply the calculation methods only where acceleration is uniform.

    What earns the marks

    • Compares gradients qualitatively, stating that a steeper gradient means greater acceleration.
    • Calculates acceleration as the gradient, dividing change in velocity by change in time with unit m/s².
    • Determines distance travelled from the area between the graph line and the time axis, in metres.
    • Splits a compound area into rectangles and triangles and sums them to find total distance.
    • Applies the gradient and area methods only to sections of uniform acceleration.
    • Reads values from the axes accurately, including the time interval chosen for the gradient.

    Common mistakes and how to put them right

    • Reads the height of the line as distance.

      Put it right: Use the area under the line for distance and the gradient for acceleration.

    • Divides time by velocity when finding the gradient.

      Put it right: Divide change in velocity by change in time.

    • Treats a curved section as uniform acceleration.

      Put it right: Apply the calculation methods only to straight-line sections.

    • Omits units or mixes them.

      Put it right: Give acceleration in m/s² and distance in m.

    Exam tips

    • Mark the two points you use for the gradient and show the change in velocity and change in time clearly.
    • Shade the area you are calculating and label each rectangle or triangle before adding them.
    • Check that a steeper line gives a larger acceleration value, as a quick sanity check.

    Try the lesson

    The start of the Topic 2 – Motion and forces: 2.10 Analyse velocity/time graphs to: a compare acceleration from gradients qualitatively b calculate the acceleration from the gradient (for uniform acceleration only) c determine the distance travelled using the area between the graph line and the time axis (for uniform acceleration only) lesson, made from checked teaching notes for this specification point.

    Have a go first

    On a velocity/time graph, a horizontal line at 6 m/s from 0 s to 4 s represents motion with which property?

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    Test your understanding of Topic 2 – Motion and forces: 2.10 Analyse velocity/time graphs to: a compare acceleration from gradients qualitatively b calculate the acceleration from the gradient (for uniform acceleration only) c determine the distance travelled using the area between the graph line and the time axis (for uniform acceleration only)

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