Pearson Edexcel · GCSE · Physics

    Course version: 1PH0 · Version from Sept 2016

    Use the equation: (final velocity)² ((metre/second)², (m/s)²) – (initial…

    Full specification wording

    Topic 2 – Motion and forces: 2.9 Use the equation: (final velocity)² ((metre/second)², (m/s)²) – (initial velocity)² ((metre/second)², (m/s)²) = 2 × acceleration (metre per second squared, m/s²) × distance (metre, m) v² − u² = 2 × a × x

    This equation links four quantities for motion along a straight line with uniform acceleration: final velocity v, initial velocity u, acceleration a and distance (displacement) x.

    Checked against the Pearson Edexcel 1PH0 specification (opens in a new tab) on .

    • Point 9 of 32

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    This equation links four quantities for motion along a straight line with uniform acceleration: final velocity v, initial velocity u, acceleration a and distance (displacement) x. The squared velocities carry units of (m/s)², acceleration carries m/s² and distance carries m, so the right-hand side gives m/s² × m = m²/s², matching the left-hand side. To use it, list v, u, a and x, convert all speeds to m/s and distances to m, then substitute. Example: a car speeds up from u = 5 m/s to v = 25 m/s over x = 120 m. Then v² − u² = 625 − 25 = 600 (m/s)², so a = 600 ÷ (2 × 120) = 600 ÷ 240 = 2.5 m/s². Rearranged forms let you find v, u or x. The equation applies only when acceleration is constant and motion is in one direction.

    What earns the marks

    • Selects the equation v² − u² = 2 × a × x and identifies the unknown quantity before substituting.
    • Converts velocities to m/s and distance to m before squaring or multiplying.
    • Squares the velocities correctly, keeping the unit (m/s)² on each squared term.
    • Rearranges the equation correctly, for example a = (v² − u²) ÷ (2 × x) or x = (v² − u²) ÷ (2 × a).
    • States the final answer with the correct unit, such as m/s² for acceleration or m for distance.
    • Recognises that the equation requires uniform acceleration along a straight line.

    Common mistakes and how to put them right

    • Squares only the number and drops the unit.

      Put it right: Keep (m/s)² on each squared velocity term.

    • Subtracts u from v before squaring.

      Put it right: Square each velocity first, then subtract.

    • Forgets the factor of 2 on the acceleration × distance side.

      Put it right: Include 2 × a × x.

    • Uses the equation when acceleration changes.

      Put it right: Apply it only to uniform acceleration in one direction.

    Exam tips

    • Write down v, u, a and x with units before choosing the rearrangement, so the unknown is clear.
    • Check the units of both sides: (m/s)² must equal m/s² × m, which is m²/s².
    • Estimate the answer first, then check the calculated value is sensible for the situation described.

    Try the lesson

    The start of the Topic 2 – Motion and forces: 2.9 Use the equation: (final velocity)² ((metre/second)², (m/s)²) – (initial velocity)² ((metre/second)², (m/s)²) = 2 × acceleration (metre per second squared, m/s²) × distance (metre, m) v² − u² = 2 × a × x lesson, made from checked teaching notes for this specification point.

    Have a go first

    A cyclist starts from rest and accelerates at 2 m/s² over a distance of 9 m. Using v² − u² = 2 × a × x, what is the final velocity v?

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    Test your understanding of Topic 2 – Motion and forces: 2.9 Use the equation: (final velocity)² ((metre/second)², (m/s)²) – (initial velocity)² ((metre/second)², (m/s)²) = 2 × acceleration (metre per second squared, m/s²) × distance (metre, m) v² − u² = 2 × a × x

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