Relative formula mass — AQA GCSE Chemistry
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Relative formula mass (Mr) of a compound is the sum of the relative atomic masses (Ar) of all the atoms shown in its chemical formula. It is a fundamental calculation in quantitative chemistry essential for determining moles, percentage composition, and reacting masses.
Relative formula mass explained
Relative formula mass covers 2 specification points, including In a balanced chemical equation, the sum of… and Students should be able to calculate the….
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In a balanced chemical equation, the sum of the relative formula masses of the reactants in the quantities shown equals the sum of the relative formula masses of the products in the quantities shown.
A balanced equation shows the same number of each type of atom on both sides, so the total mass is conserved. Relative formula mass, Mᵣ, is the sum of the relative atomic masses of all atoms in a formula. To check conservation, multiply each species' Mᵣ by its coefficient in the equation, then sum for reactants and for products. For example, in 2H₂ + O₂ → 2H₂O: reactants give 2 × 2 = 4 for H₂ plus 32 for O₂, totalling 36; products give 2 × 18 = 36. The totals match, confirming mass conservation. This method also supports reacting mass calculations and shows why coefficients matter in quantitative work.
Students should be able to calculate the percentage by mass in a compound given the relative formula mass and the relative atomic masses.
Percentage by mass shows the contribution of one element to the total mass of a compound. First calculate the relative formula mass, Mᵣ, by summing all relative atomic masses in the formula. Then find the total mass of the element of interest by multiplying its relative atomic mass by the number of its atoms in the formula. Divide that element's total mass by Mᵣ and multiply by 100. For example, in CO₂, Mᵣ = 12 + (2 × 16) = 44; carbon contributes 12 ÷ 44 × 100 = 27.3% and oxygen contributes 32 ÷ 44 × 100 = 72.7%. The percentages should sum to 100%, which is a useful check.
Your focus
- Calculate relative formula masses from relative atomic masses.
- Use coefficients to find total masses of reactants and products.
- Verify that a balanced equation conserves mass.
Show all 6 objectives
- Calculate the percentage by mass of an element in a compound.
- Use relative atomic masses and relative formula mass correctly.
- Check percentage composition answers by summing to 100%.
Relative formula mass exam tips
Topic Overview
Relative formula mass (represented as Mr) is the sum of the relative atomic masses (Ar) of all the atoms present in a given chemical formula. It applies to both simple molecular substances like carbon dioxide and giant ionic structures like sodium chloride.
Mastering Mr calculations is the cornerstone of GCSE quantitative chemistry. It serves as the primary gateway calculation required for determining moles, theoretical yields, percentage composition by mass, and titration stoichiometry.
Key Concepts
- →Relative atomic mass (Ar) is found on the Periodic Table as the top/larger number for each element (mass number).
- →Subscripts inside a chemical formula indicate the exact number of atoms of that preceding element; brackets multiply everything inside them.
- →Relative formula mass is a ratio compared to carbon-12 and therefore does not have units.
- →Balancing numbers (stoichiometric coefficients) placed in front of chemical formulas are ignored when calculating standard Mr.
Marking Points
- Relative formula mass is the sum of relative atomic masses of all atoms in the formula.
- Each species' Mᵣ must be multiplied by its coefficient in the balanced equation.
- The total Mᵣ of reactants equals the total Mᵣ of products when the equation is balanced.
- Conservation of mass follows from equal numbers of each atom on both sides.
- Worked check: 2H₂ + O₂ → 2H₂O gives 36 = 36 using Mᵣ values H₂ = 2, O₂ = 32, H₂O = 18.
- This principle underpins reacting mass and percentage yield calculations.
- Calculate Mᵣ by summing the relative atomic masses of all atoms in the formula.
- Find the total mass of the chosen element using its relative atomic mass and atom count.
- Divide the element's total mass by Mᵣ and multiply by 100 to obtain percentage by mass.
- Worked example: in CO₂, carbon is 12 ÷ 44 × 100 = 27.3% and oxygen is 32 ÷ 44 × 100 = 72.7%.
- The percentages of all elements in a compound should sum to 100%.
- Give answers to an appropriate number of significant figures, typically three.
Examiner Tips
- 💡Write the Mᵣ of each species clearly beside its formula before multiplying by coefficients.
- 💡Show the multiplication step, for example 2 × 18 = 36, so the examiner can follow your reasoning.
- 💡Check that the equation is balanced before using it for mass calculations.
- 💡Use a periodic table with relative atomic masses and round consistently as instructed.
- 💡Write down Mᵣ first and label it clearly before starting the percentage calculation.
- 💡Show the numerator as the element's total mass and the denominator as Mᵣ, then multiply by 100.
- 💡Check that the percentages for all elements add up to 100% as a final verification.
- 💡State the element and the compound in your answer, for example 'percentage by mass of carbon in CO₂'.
- 💡Always show full working out showing the sum of (Ar x count) so you can still earn method marks if you make an arithmetic slip on your calculator.
- 💡Double check values from the provided AQA Periodic Table — do not guess or memorise Ar values, as small differences (e.g., Cu = 63.5, Cl = 35.5) will penalise you.
Common Mistakes
- Forgetting to multiply Mᵣ by the coefficient, so comparing 2 + 32 with 18; the correction is to include coefficients, giving 36 = 36.
- Adding relative atomic masses incorrectly, such as using the wrong value for an element; the correction is to use the periodic table values accurately and sum every atom.
- Assuming an unbalanced equation still conserves mass; the correction is that coefficients must first balance the equation before totals can be compared.
- Dividing by the element's mass instead of Mᵣ; the correction is to divide the element's total mass by the compound's Mᵣ.
- Forgetting to multiply the relative atomic mass by the number of atoms of that element; the correction is to include the atom count, for example 2 × 16 for oxygen in CO₂.
- Rounding intermediate values too early, causing a final answer that is slightly wrong; the correction is to keep full values during the calculation and round only at the end.
- Using the atomic number (bottom number) instead of the relative atomic mass (top number) on the Periodic Table.
- Adding coefficients into the Mr calculation (e.g., treating 3CO2 as having an Mr of 3 x 44 = 132 instead of 44).
- Multiplying parts of a hydrated salt formula rather than adding (e.g., treating the dot in CuSO4.5H2O as a multiplication sign instead of adding 5 waters).
Revision Plan
- 1Day 1: Practice identifying the mass number (Ar) versus atomic number on the AQA Periodic Table for common elements.
- 2Day 2: Work through 10 basic compounds containing no brackets (e.g., CO2, H2SO4, NaCl).
- 3Day 3: Practice 10 complex compounds containing brackets and hydrated salts (e.g., Mg(NO3)2, Fe2(SO4)3, Na2CO3.10H2O).
- 4Day 4: Attempt exam questions combining Mr calculations with percentage by mass and mole calculations.
Exam Question Types
- 📋Direct 1-2 mark retrieval questions asking to calculate the Mr of a named or drawn compound.
- 📋Multi-step quantitative questions where calculating Mr is an unprompted, essential first step to find moles or reacting mass.
- 📋Percentage by mass questions where students must divide the total Ar of one element by the whole compound Mr and multiply by 100.
Command Word Expectations (AQA)
Students must arrive at a numerical answer showing clear mathematical steps, using correct values from the Periodic Table.
Students must provide every intermediate arithmetic step to prove a given final value, leaving no logical gaps.
How Students Lose Marks (Examiner Pitfalls)
Step-by-Step Worked Solutions
Question: Calculate the relative formula mass (Mr) of aluminium sulfate, Al2(SO4)3. Relative atomic masses (Ar): Al = 27, S = 32, O = 16.
- 1.Step 1: Identify the number of each type of atom in the formula Al2(SO4)3: 2 aluminium atoms, 3 sulfur atoms (1 x 3), and 12 oxygen atoms (4 x 3).
- 2.Step 2: Multiply the quantity of each atom by its respective relative atomic mass: Al = 2 x 27 = 54; S = 3 x 32 = 96; O = 12 x 16 = 192.
- 3.Step 3: Sum the total masses together: 54 + 96 + 192 = 342.
Question: Calculate the relative formula mass (Mr) of hydrated copper(II) sulfate, CuSO4.5H2O. Relative atomic masses (Ar): Cu = 63.5, S = 32, O = 16, H = 1.
- 1.Step 1: Calculate the Mr of the anhydrous salt, CuSO4: Cu = 63.5, S = 32, O = 4 x 16 = 64. Total for CuSO4 = 63.5 + 32 + 64 = 159.5.
- 2.Step 2: Calculate the Mr of one water molecule (H2O): (2 x 1) + 16 = 18. Then multiply by the dot number (5): 5 x 18 = 90.
- 3.Step 3: Add the mass of the water of crystallisation to the anhydrous salt: 159.5 + 90 = 249.5.