Skip to topic
    ← Back to course topics

    Linear motion — AQA A-Level Physical Education

    Test yourself on Linear motion with AQA A-Level practice questions.

    Start free

    7 days Premium · Then free forever · No card, no charge

    Your focus

    1. An understanding of the forces acting on a performer during linear motion.

    Linear motion exam tips

    Quick Revision Summary (Key Takeaway)

    Linear motion in AQA A-Level PE describes movement in a straight or curved line where all body parts travel the same distance, same direction, and at the same speed. It is analysed using displacement, velocity, acceleration, and the equations of uniformly accelerated motion, which are essential for biomechanical analysis and improving sports performance.

    Topic Overview

    Linear motion is a fundamental topic in AQA A-Level Physical Education, focusing on the biomechanics of movement along a straight or curved path. It covers scalar and vector quantities, displacement, velocity, acceleration, and the equations of uniformly accelerated motion. Understanding these concepts allows students to analyse and improve performance in activities such as sprinting, swimming, and cycling.

    This topic is essential for the biomechanical analysis section of the specification and provides the mathematical foundation for more complex motion, including projectile motion and angular motion. It also links to Newton's laws of motion and the application of forces, helping students explain how athletes generate speed, decelerate efficiently, and optimise technique.

    Key Concepts
    • →Scalar quantities (distance, speed) have magnitude only, while vector quantities (displacement, velocity, acceleration) have both magnitude and direction.
    • →Displacement is the straight-line distance from start to finish in a specified direction; distance is the total path length covered.
    • →Velocity is the rate of change of displacement (v = s/t), and acceleration is the rate of change of velocity (a = (v - u)/t).
    • →The equations of uniformly accelerated motion (v = u + at, s = ut + 0.5at^2, v^2 = u^2 + 2as, s = ((u + v)/2)t) are used to solve problems involving constant acceleration.
    • →In linear motion, all body parts move the same distance, in the same direction, at the same speed, which is rare in sport but approximated in straight-line sprinting or cycling.
    Examiner Tips
    • 💡Always show your working and include units in your final answer. Marks are awarded for correct substitution and clear steps, not just the final value.
    • 💡When answering longer questions, use correct terminology such as 'displacement', 'velocity', and 'acceleration' rather than 'distance' and 'speed' when direction is involved.
    • 💡For graph questions, remember that the gradient of a displacement-time graph gives velocity, and the gradient of a velocity-time graph gives acceleration. The area under a velocity-time graph gives displacement.
    Common Mistakes
    • Students often think that if an object returns to its starting point, its displacement and velocity are non-zero. In fact, displacement is zero, so average velocity is zero, even though distance and speed are not.
    • Many students forget that acceleration can be negative (deceleration) and that the sign indicates direction relative to the chosen positive direction. Always define a positive direction before solving.
    • Some students assume that a constant speed means zero acceleration. However, if direction changes, velocity changes, so acceleration is non-zero (e.g., circular motion at constant speed).
    Revision Plan
    1. 1Day 1-2: Learn definitions of scalar and vector quantities, distance vs displacement, speed vs velocity, and acceleration. Create flashcards with examples from sport.
    2. 2Day 3-4: Memorise the four equations of uniformly accelerated motion and practise rearranging them. Complete basic calculation problems with unit conversions.
    3. 3Day 5-6: Apply the equations to sporting scenarios such as sprint starts, braking distances, and projectile motion. Draw motion graphs and interpret gradients and areas.
    4. 4Day 7-8: Attempt exam-style questions, focusing on structured 6-mark answers. Review mark schemes to understand how marks are awarded for method and accuracy.
    5. 5Day 9-10: Complete a timed past paper question on linear motion, then self-assess using the mark scheme. Revise any weak areas and repeat active recall prompts.
    Exam Question Types
    • 📋Multiple-choice questions testing definitions and distinctions between scalar and vector quantities, or simple calculations of speed, velocity, and acceleration.
    • 📋Short-answer calculations (2-4 marks) requiring use of equations of motion, often with unit conversions. Advice: write down the equation, substitute values with units, and give the answer with correct units and direction if vector.
    • 📋Structured 6-mark questions analysing a sporting movement, requiring explanation of displacement, velocity, and acceleration, and application to performance. Advice: use specific sporting examples, correct terminology, and link to technique or safety.
    • 📋Graph interpretation questions (4-6 marks) where students must calculate velocity from a displacement-time graph or acceleration from a velocity-time graph, and describe motion. Advice: state the formula, show calculation, and describe the motion in words.
    Command Word Expectations (AQA)
    Calculate

    You must use the given data and appropriate equations to work out a numerical answer. Marks are awarded for correct substitution, correct working, and the final answer with correct units. No marks for just the answer without working.

    Explain

    You must provide reasons or mechanisms, not just a description. Use cause-and-effect language and correct terminology. For example, explain why a sprinter's acceleration decreases over time, linking to forces and mass.

    Evaluate

    You must make a judgement based on evidence, considering strengths and weaknesses or different perspectives. For example, evaluate the use of linear motion analysis in improving sprinting technique, weighing benefits against limitations.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often confuse distance with displacement and speed with velocity, leading to incorrect sign usage and lost marks in calculations.
    ❌ Weak Answer (Loses Marks):The athlete ran 400 m, so displacement is 400 m and velocity is 400 / 50 = 8 m/s.
    Example improved answer:Distance is the total path length covered (400 m), but displacement is the straight-line distance from start to finish with direction. On a 400 m track, one lap returns to the start, so displacement is 0 m. Therefore average velocity = displacement / time = 0 / 50 = 0 m/s, while average speed = distance / time = 400 / 50 = 8 m/s.
    Examiner Tip: Always state whether the quantity is scalar or vector, and check if the start and finish points differ. If they are the same, displacement is zero, regardless of distance covered.
    Pitfall: When using the equations of motion, students frequently fail to convert units (e.g., km/h to m/s) or forget to state the direction of vector quantities.
    ❌ Weak Answer (Loses Marks):u = 36, a = 2, t = 5, so v = 36 + (2 x 5) = 46 m/s.
    Example improved answer:First convert initial velocity: 36 km/h = 36 x (1000/3600) = 10 m/s. Using v = u + at: v = 10 + (2 x 5) = 20 m/s in the direction of motion. The final velocity is 20 m/s, not 46 m/s, because the initial velocity was not converted to SI units.
    Examiner Tip: Always write down the given values with their units, convert all to SI (m, s, m/s, m/s^2) before substituting, and include direction in your final answer for vector quantities.
    Step-by-Step Worked Solutions

    Question: A sprinter accelerates uniformly from rest to 12 m/s in 3.0 s. Calculate: (a) the acceleration, (b) the distance covered during this acceleration.

    1. 1.Step 1: Identify given facts: initial velocity u = 0 m/s (from rest), final velocity v = 12 m/s, time t = 3.0 s. Acceleration a is unknown, distance s is unknown.
    2. 2.Step 2: Apply core formula for acceleration: a = (v - u) / t = (12 - 0) / 3.0 = 4.0 m/s^2.
    3. 3.Step 3: Use equation of motion for distance: s = ut + 0.5at^2 = (0 x 3.0) + (0.5 x 4.0 x 3.0^2) = 0 + 18 = 18 m. Alternatively, s = ((u + v)/2) x t = ((0 + 12)/2) x 3.0 = 18 m.
    4. 4.Step 4: State final conclusion with units: acceleration = 4.0 m/s^2; distance = 18 m.
    Final Answer: Acceleration = 4.0 m/s^2; distance covered = 18 m.

    Question: A cyclist travelling at 8 m/s applies the brakes and decelerates uniformly at 2 m/s^2. Calculate: (a) the time taken to stop, (b) the braking distance.

    1. 1.Step 1: Identify given facts: initial velocity u = 8 m/s, final velocity v = 0 m/s (stops), acceleration a = -2 m/s^2 (deceleration). Time t and distance s are unknown.
    2. 2.Step 2: Use v = u + at to find time: 0 = 8 + (-2)t, so 2t = 8, t = 4 s.
    3. 3.Step 3: Use s = ut + 0.5at^2 to find distance: s = (8 x 4) + (0.5 x -2 x 4^2) = 32 - 16 = 16 m. Alternatively, s = ((u + v)/2) x t = ((8 + 0)/2) x 4 = 16 m.
    4. 4.Step 4: State final conclusion with units: time to stop = 4 s; braking distance = 16 m.
    Final Answer: Time to stop = 4 s; braking distance = 16 m.
    Active Recall Memory Test
    Define displacement and state its SI unit.
    Key Fact: Displacement is the straight-line distance from start to finish in a specified direction. SI unit: metre (m).
    Write down the four equations of uniformly accelerated motion.
    Key Fact: 1) v = u + at; 2) s = ut + 0.5at^2; 3) v^2 = u^2 + 2as; 4) s = ((u + v)/2)t.
    What does the gradient of a velocity-time graph represent?
    Key Fact: The gradient of a velocity-time graph represents acceleration.
    Explain why a runner on a circular track at constant speed has changing velocity.
    Key Fact: Velocity is a vector quantity, so it depends on both speed and direction. On a circular track, direction is constantly changing, so velocity changes even if speed is constant.
    Frequently Asked Questions
    What is the difference between linear motion and projectile motion?
    Linear motion occurs along a straight or curved line where all body parts move the same distance, direction, and speed. Projectile motion is a form of two-dimensional motion where an object moves under gravity alone, following a parabolic path. In A-Level PE, linear motion is often the starting point before analysing more complex projectile motion in sports like shot put or long jump.
    How do I know when to use the equations of motion?
    Use the equations of uniformly accelerated motion when acceleration is constant (uniform) and motion is in a straight line. Identify the known quantities (u, v, a, t, s) and choose the equation that includes the unknown you need. If acceleration is not constant, you cannot use these equations and would need graphical or calculus methods, which are not required at A-Level PE.
    Why is displacement zero when a runner completes one lap of a track?
    Displacement is the straight-line distance from start to finish in a specified direction. When a runner completes one lap, they finish at the same point they started, so the straight-line distance is zero. However, the distance covered is the full lap length, so average speed is non-zero while average velocity is zero.
    What is the difference between speed and velocity?
    Speed is a scalar quantity, meaning it has magnitude only. Velocity is a vector quantity, meaning it has both magnitude and direction. For example, a car travelling at 30 m/s has a speed of 30 m/s, but its velocity could be 30 m/s north. In sport, velocity is more useful for analysing performance because direction affects technique and outcome.
    How is linear motion used in sports like sprinting?
    In sprinting, linear motion is used to analyse the athlete's acceleration phase, maximum velocity, and deceleration. Coaches use equations of motion to calculate acceleration from split times and to determine the optimal distance for reaching top speed. Understanding linear motion helps improve technique, such as drive phase mechanics and braking strategies in team sports.
    Do I need to memorise all the equations of motion for the exam?
    Yes, you should memorise the four equations of uniformly accelerated motion as they are not always provided in the exam. However, some exam boards may provide them in a formulae sheet, so check the specification. Even if provided, you must know how to select and apply the correct equation to solve problems accurately.