Linear motion — AQA A-Level Physical Education
Test yourself on Linear motion with AQA A-Level practice questions.
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Your focus
- An understanding of the forces acting on a performer during linear motion.
Linear motion exam tips
Quick Revision Summary (Key Takeaway)
Linear motion in AQA A-Level PE describes movement in a straight or curved line where all body parts travel the same distance, same direction, and at the same speed. It is analysed using displacement, velocity, acceleration, and the equations of uniformly accelerated motion, which are essential for biomechanical analysis and improving sports performance.
Topic Overview
Linear motion is a fundamental topic in AQA A-Level Physical Education, focusing on the biomechanics of movement along a straight or curved path. It covers scalar and vector quantities, displacement, velocity, acceleration, and the equations of uniformly accelerated motion. Understanding these concepts allows students to analyse and improve performance in activities such as sprinting, swimming, and cycling.
This topic is essential for the biomechanical analysis section of the specification and provides the mathematical foundation for more complex motion, including projectile motion and angular motion. It also links to Newton's laws of motion and the application of forces, helping students explain how athletes generate speed, decelerate efficiently, and optimise technique.
Key Concepts
- →Scalar quantities (distance, speed) have magnitude only, while vector quantities (displacement, velocity, acceleration) have both magnitude and direction.
- →Displacement is the straight-line distance from start to finish in a specified direction; distance is the total path length covered.
- →Velocity is the rate of change of displacement (v = s/t), and acceleration is the rate of change of velocity (a = (v - u)/t).
- →The equations of uniformly accelerated motion (v = u + at, s = ut + 0.5at^2, v^2 = u^2 + 2as, s = ((u + v)/2)t) are used to solve problems involving constant acceleration.
- →In linear motion, all body parts move the same distance, in the same direction, at the same speed, which is rare in sport but approximated in straight-line sprinting or cycling.
Examiner Tips
- 💡Always show your working and include units in your final answer. Marks are awarded for correct substitution and clear steps, not just the final value.
- 💡When answering longer questions, use correct terminology such as 'displacement', 'velocity', and 'acceleration' rather than 'distance' and 'speed' when direction is involved.
- 💡For graph questions, remember that the gradient of a displacement-time graph gives velocity, and the gradient of a velocity-time graph gives acceleration. The area under a velocity-time graph gives displacement.
Common Mistakes
- Students often think that if an object returns to its starting point, its displacement and velocity are non-zero. In fact, displacement is zero, so average velocity is zero, even though distance and speed are not.
- Many students forget that acceleration can be negative (deceleration) and that the sign indicates direction relative to the chosen positive direction. Always define a positive direction before solving.
- Some students assume that a constant speed means zero acceleration. However, if direction changes, velocity changes, so acceleration is non-zero (e.g., circular motion at constant speed).
Revision Plan
- 1Day 1-2: Learn definitions of scalar and vector quantities, distance vs displacement, speed vs velocity, and acceleration. Create flashcards with examples from sport.
- 2Day 3-4: Memorise the four equations of uniformly accelerated motion and practise rearranging them. Complete basic calculation problems with unit conversions.
- 3Day 5-6: Apply the equations to sporting scenarios such as sprint starts, braking distances, and projectile motion. Draw motion graphs and interpret gradients and areas.
- 4Day 7-8: Attempt exam-style questions, focusing on structured 6-mark answers. Review mark schemes to understand how marks are awarded for method and accuracy.
- 5Day 9-10: Complete a timed past paper question on linear motion, then self-assess using the mark scheme. Revise any weak areas and repeat active recall prompts.
Exam Question Types
- 📋Multiple-choice questions testing definitions and distinctions between scalar and vector quantities, or simple calculations of speed, velocity, and acceleration.
- 📋Short-answer calculations (2-4 marks) requiring use of equations of motion, often with unit conversions. Advice: write down the equation, substitute values with units, and give the answer with correct units and direction if vector.
- 📋Structured 6-mark questions analysing a sporting movement, requiring explanation of displacement, velocity, and acceleration, and application to performance. Advice: use specific sporting examples, correct terminology, and link to technique or safety.
- 📋Graph interpretation questions (4-6 marks) where students must calculate velocity from a displacement-time graph or acceleration from a velocity-time graph, and describe motion. Advice: state the formula, show calculation, and describe the motion in words.
Command Word Expectations (AQA)
You must use the given data and appropriate equations to work out a numerical answer. Marks are awarded for correct substitution, correct working, and the final answer with correct units. No marks for just the answer without working.
You must provide reasons or mechanisms, not just a description. Use cause-and-effect language and correct terminology. For example, explain why a sprinter's acceleration decreases over time, linking to forces and mass.
You must make a judgement based on evidence, considering strengths and weaknesses or different perspectives. For example, evaluate the use of linear motion analysis in improving sprinting technique, weighing benefits against limitations.
How Students Lose Marks (Examiner Pitfalls)
Step-by-Step Worked Solutions
Question: A sprinter accelerates uniformly from rest to 12 m/s in 3.0 s. Calculate: (a) the acceleration, (b) the distance covered during this acceleration.
- 1.Step 1: Identify given facts: initial velocity u = 0 m/s (from rest), final velocity v = 12 m/s, time t = 3.0 s. Acceleration a is unknown, distance s is unknown.
- 2.Step 2: Apply core formula for acceleration: a = (v - u) / t = (12 - 0) / 3.0 = 4.0 m/s^2.
- 3.Step 3: Use equation of motion for distance: s = ut + 0.5at^2 = (0 x 3.0) + (0.5 x 4.0 x 3.0^2) = 0 + 18 = 18 m. Alternatively, s = ((u + v)/2) x t = ((0 + 12)/2) x 3.0 = 18 m.
- 4.Step 4: State final conclusion with units: acceleration = 4.0 m/s^2; distance = 18 m.
Question: A cyclist travelling at 8 m/s applies the brakes and decelerates uniformly at 2 m/s^2. Calculate: (a) the time taken to stop, (b) the braking distance.
- 1.Step 1: Identify given facts: initial velocity u = 8 m/s, final velocity v = 0 m/s (stops), acceleration a = -2 m/s^2 (deceleration). Time t and distance s are unknown.
- 2.Step 2: Use v = u + at to find time: 0 = 8 + (-2)t, so 2t = 8, t = 4 s.
- 3.Step 3: Use s = ut + 0.5at^2 to find distance: s = (8 x 4) + (0.5 x -2 x 4^2) = 32 - 16 = 16 m. Alternatively, s = ((u + v)/2) x t = ((8 + 0)/2) x 4 = 16 m.
- 4.Step 4: State final conclusion with units: time to stop = 4 s; braking distance = 16 m.