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    Electric potential (A-level only) — AQA A-Level Physics

    Teaching note checked against the official specification.

    Electric potential at a point is the work done per unit positive charge in bringing a small positive test charge from infinity to that point, measured in volts (J C^-1). It is a scalar quantity, and the potential due to a point charge is given by V = kQ/r, where k = 1/(4*pi*epsilon_0).

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    Electric potential (A-level only) explained

    Electric potential (A-level only) covers 3 specification points, including Understanding of definition of absolute… and Work done in moving charge Q given by ∆ W = Q….

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    Understanding of definition of absolute electric potential, including zero value at infinity, and of electric potential difference.

    Absolute electric potential V at a point is the work done per unit positive charge in bringing a small positive test charge from infinity to that point, so V = W/Q. The zero of potential is defined at infinity, where the field is zero. For a point charge Q, V = kQ/r, a scalar that is positive near a positive charge and negative near a negative charge. Electric potential difference between two points is the work done per unit charge in moving a positive charge between them, ΔV = W/Q, and is the quantity measured by a voltmeter. For example, moving a 2 C charge through a potential difference of 3 V requires 6 J of work. Students should calculate V for point charges, find potential differences, and relate them to energy transfers.

    Work done in moving charge Q given by ∆ W = Q ∆ V Equipotential surfaces.

    Electric potential V at a point is the work done per unit positive charge in bringing a small positive test charge from infinity to that point. The work done W in moving charge Q through a potential difference ΔV is W = QΔV. This applies whether the field is uniform or non-uniform, provided ΔV is the potential difference between the start and end points. For example, moving 2.0 C through a potential difference of 5.0 V requires W = 2.0 × 5.0 = 10 J. Equipotential surfaces are surfaces on which V is constant; they are always perpendicular to electric field lines. In a uniform field, they are parallel planes; around a point charge, they are concentric spheres. The equation links energy transfer to potential difference and charge, and is central to understanding capacitors, particle accelerators and circuits.

    No work done moving charge along an equipotential surface.

    An equipotential surface is a surface on which the electric potential is constant. Since potential difference ΔV between any two points on the surface is zero, the work done W = QΔV is also zero. This is because the electric force is always perpendicular to the equipotential surface, so the component of force along the direction of motion is zero. For example, moving a charge around a circular equipotential centred on a point charge requires no work, even though the charge experiences a force. This principle is used in understanding conductors in electrostatic equilibrium, where the surface is an equipotential, and in the design of particle accelerators where particles move along equipotentials without energy change.

    Your focus

    1. Define absolute electric potential and state the zero reference at infinity.
    2. Calculate electric potential for point charges and potential difference between two points.
    3. Relate potential difference to work done and energy transferred using ΔV = W/Q.
    Show all 9 objectives
    1. Define electric potential and use the equation W = QΔV to solve problems involving energy transfer.
    2. Describe and sketch equipotential surfaces for uniform and radial electric fields.
    3. Explain the relationship between equipotential surfaces and electric field lines, including why no work is done when moving along an equipotential.
    4. Explain why no work is done when a charge moves along an equipotential surface.
    5. Apply the equation W = QΔV to situations where ΔV = 0.
    6. Relate the concept of zero work done to the perpendicularity of electric force and displacement.

    Which command word is this?

    Give a precise, formal definition. For electric potential, you must state 'work done per unit positive charge in bringing a small positive test charge from infinity to that point'. Missing key phrases loses marks.

    Electric potential (A-level only) exam tips

    Topic Overview

    Electric potential is a fundamental concept in A-level Physics that describes the electric potential energy per unit charge at a point in an electric field. It allows us to analyse fields without considering the test charge, and it is crucial for understanding how charges move and how energy is stored in electric fields. This topic extends your knowledge of electric fields and gravitational fields, highlighting the similarities between the two.

    In the AQA A-level specification, electric potential is a key part of the 'Fields and their consequences' module. You will learn to calculate potential due to point charges, understand equipotential surfaces, and relate potential to field strength. This concept is essential for later topics such as capacitance and the motion of charged particles in electric fields, and it frequently appears in exam questions involving calculations and explanations.

    Key Concepts
    • →Electric potential at a point is the work done per unit positive charge in bringing a small positive test charge from infinity to that point. It is a scalar quantity measured in volts (V), where 1 V = 1 J C^-1.
    • →The electric potential due to a point charge Q at a distance r is given by V = kQ/r, where k = 1/(4*pi*epsilon_0) = 8.99x10^9 N m^2 C^-2. The potential is positive for positive charges and negative for negative charges, and it approaches zero at infinity.
    • →The total electric potential at a point due to several point charges is the algebraic sum of the potentials due to each charge individually. This is because potential is a scalar quantity.
    • →The electric field strength E is related to the potential gradient by E = -dV/dr. The negative sign indicates that the electric field points in the direction of decreasing potential.
    • →Equipotential surfaces are surfaces on which the electric potential is constant. No work is done when a charge moves along an equipotential surface, and the electric field lines are always perpendicular to these surfaces.
    Marking Points
    • Defines absolute electric potential as work done per unit positive charge in bringing a small positive test charge from infinity to the point: V = W/Q.
    • States that the zero of electric potential is at infinity, where the electric field is zero.
    • Uses V = kQ/r for the potential at distance r from a point charge Q, recognising that V is a scalar and can be positive or negative.
    • Defines electric potential difference as the work done per unit positive charge in moving between two points: ΔV = W/Q.
    • Calculates potential difference from the potentials at two points, ΔV = V₂ − V₁, and uses it to find energy transferred W = QΔV.
    • Uses correct units: volts (V) or joules per coulomb (J C⁻¹) for potential and potential difference.
    • State that electric potential V is work done per unit positive charge: V = W/Q, with the test charge brought from infinity.
    • Use W = QΔV to calculate energy transferred when charge Q moves through a potential difference ΔV, ensuring consistent signs for energy gain or loss.
    • Define an equipotential surface as a surface where the electric potential is constant, so ΔV = 0 between any two points on it.
    • Explain that equipotential surfaces are always perpendicular to electric field lines, and sketch them for a uniform field (parallel planes) and a radial field (concentric spheres).
    • Relate the direction of motion to work done: if a positive charge moves to a higher potential, work is done on the charge; if it moves to a lower potential, the field does work.
    • State that on an equipotential surface, the potential difference between any two points is zero (ΔV = 0).
    • Apply W = QΔV to show that if ΔV = 0, then W = 0, regardless of the magnitude of Q.
    • Explain that the electric force is perpendicular to the equipotential surface, so the force has no component along the displacement.
    • Relate this to the definition of work done: W = Fs cosθ, where θ = 90°, so cos90° = 0 and W = 0.
    • Give a practical example, such as a charge moving on a spherical equipotential around a point charge, or a charge moving along the surface of a charged conductor.
    Examiner Tips
    • 💡When calculating potential due to several point charges, sum the scalar values algebraically, taking account of positive and negative charges.
    • 💡Use ΔV = W/Q to link potential difference to energy transfer, and rearrange carefully to find W, Q or ΔV as required.
    • 💡Check the sign of your answer: potential near a positive charge is positive, and near a negative charge is negative, relative to infinity.
    • 💡When calculating work done, write the equation W = QΔV, substitute values with units, and state the direction of energy transfer (work done on or by the field).
    • 💡For equipotential sketches, always draw field lines first, then add equipotentials perpendicular to them, labelling values of potential if given.
    • 💡If a question asks about moving a charge along an equipotential, immediately state that ΔV = 0, so W = 0, and explain that the electric force is perpendicular to the displacement.
    • 💡When asked why no work is done, explicitly state that ΔV = 0 and that the electric force is perpendicular to the displacement.
    • 💡Use the equation W = QΔV to justify the zero work done, and mention that Q is not zero but ΔV is zero.
    • 💡If a diagram is given, identify the equipotential surface and show that the path lies along it, then explain the perpendicularity of force and motion.
    • 💡Always define electric potential precisely: 'work done per unit positive charge in bringing a small positive test charge from infinity to that point'. Missing 'per unit positive charge' or 'from infinity' loses marks.
    • 💡When calculating potential due to multiple charges, show each calculation separately and then sum them algebraically. This makes your method clear and helps you avoid sign errors.
    • 💡Remember that electric field strength is the negative gradient of potential: E = -dV/dr. In graphs of V against r, the gradient gives -E, and you may be asked to interpret such graphs.
    Common Mistakes
    • Treating electric potential as a vector and adding potentials with direction; correction: potential is a scalar, so add or subtract algebraic values including signs.
    • Forgetting that the zero of potential is at infinity and using a finite reference point; correction: always state that V = 0 at infinity when defining absolute potential.
    • Confusing potential with potential energy; correction: potential is energy per unit charge, while potential energy is QV for a charge Q at potential V.
    • Confusing electric potential V with electric potential energy: V is per unit charge, while potential energy is QV. Correction: always divide or multiply by Q as appropriate.
    • Using W = QΔV with ΔV as a magnitude and ignoring the sign of the charge or the potential change, leading to incorrect energy direction. Correction: include signs or state clearly whether energy is gained or lost.
    • Drawing equipotential surfaces that cross or are not perpendicular to field lines. Correction: equipotentials must be perpendicular to field lines everywhere and can never intersect.
    • Assuming that because a force acts on the charge, work must be done. Correction: work depends on the component of force along the displacement; perpendicular forces do no work.
    • Thinking that moving along an equipotential changes the potential energy of the charge. Correction: potential energy depends on potential, which is constant, so it does not change.
    • Confusing equipotential surfaces with electric field lines. Correction: equipotentials are perpendicular to field lines and represent constant potential, while field lines show the direction of force on a positive charge.
    • Students often think electric potential is a vector and try to add potentials using vector addition. In fact, electric potential is a scalar, so you simply add the potentials algebraically, taking into account their signs.
    • Many students confuse electric potential (V) with electric potential energy (U). Potential is energy per unit charge (V = U/q), while potential energy is the energy a specific charge possesses at a point (U = qV).
    • Students frequently forget that the electric potential at infinity is defined as zero. This leads to errors when calculating potential differences or work done in moving charges from infinity.
    Revision Plan
    1. 1Start by revising the definition of electric potential and the formula V = kQ/r. Practice calculating potential for single point charges, ensuring you convert units correctly.
    2. 2Move on to multiple charges: learn to calculate the total potential at a point by summing individual potentials algebraically. Work through examples with both positive and negative charges.
    3. 3Study the relationship between electric field and potential: understand that E = -dV/dr and practice interpreting graphs of V against r, including finding gradients.
    4. 4Learn about equipotential surfaces and their properties, including how they relate to field lines and work done. Sketch equipotential lines for simple charge configurations.
    5. 5Complete past paper questions on electric potential, focusing on calculation and explanation questions. Review mark schemes to understand what examiners expect.
    Exam Question Types
    • 📋Calculation of electric potential at a point due to one or more point charges. Advice: always write the formula, substitute values with units, and keep track of signs. For multiple charges, calculate each potential separately before summing.
    • 📋Explanation questions on the definition of electric potential and why it is a scalar. Advice: use precise wording: 'work done per unit positive charge in bringing a small positive test charge from infinity to that point'. Emphasise that potential is scalar and add algebraically.
    • 📋Graph interpretation: given a graph of electric potential V against distance r, determine the electric field strength at a point by finding the negative gradient. Advice: draw a tangent, calculate gradient, and remember the negative sign indicates direction.
    • 📋Comparison of electric and gravitational potential: discuss similarities and differences. Advice: focus on the inverse square law, scalar nature, and the fact that gravitational potential is always negative while electric potential can be positive or negative.
    Command Word Expectations (AQA)
    Define

    Give a precise, formal definition. For electric potential, you must state 'work done per unit positive charge in bringing a small positive test charge from infinity to that point'. Missing key phrases loses marks.

    Calculate

    Show your working clearly, including the formula, substitution, and final answer with correct units and significant figures. Marks are awarded for correct substitution and accurate arithmetic.

    Explain

    Provide a reasoned argument that links cause and effect. For example, explaining why electric potential is zero at the midpoint between two equal and opposite charges: because the potentials due to each charge are equal in magnitude but opposite in sign, so they sum to zero.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often confuse electric potential (V) with electric potential energy (U) and forget that potential is per unit charge. They also incorrectly treat potential as a vector and attempt to add components.
    ❌ Weak Answer (Loses Marks):The potential at a point is the energy needed to bring a charge there. It is a vector so you add them using Pythagoras.
    Example improved answer:Electric potential at a point is the work done per unit positive charge in bringing a small positive test charge from infinity to that point. It is a scalar quantity, so the total potential at a point due to multiple charges is the algebraic sum of the individual potentials. The unit is the volt (V), which is equivalent to joule per coulomb (J C^-1).
    Examiner Tip: Always emphasise 'per unit positive charge' and state that potential is scalar. When combining potentials, add them algebraically, taking account of the sign of each charge.
    Pitfall: In calculations involving two point charges, students frequently forget to convert distances from cm to m, or they incorrectly use the distance between charges instead of the distance from each charge to the point of interest.
    ❌ Weak Answer (Loses Marks):V = (9x10^9 * 2x10^-6) / 0.05 = 3.6x10^5 V. Then V_total = 3.6x10^5 + 3.6x10^5 = 7.2x10^5 V.
    Example improved answer:First convert all distances to metres: 5 cm = 0.05 m. Calculate the potential due to each charge separately using V = kQ/r. For the positive charge: V1 = (8.99x10^9 * 2.0x10^-6) / 0.05 = 3.596x10^5 V. For the negative charge: V2 = (8.99x10^9 * -2.0x10^-6) / 0.05 = -3.596x10^5 V. Then sum algebraically: V_total = V1 + V2 = 0 V. This is because the point is equidistant from equal and opposite charges.
    Examiner Tip: Always write down the formula, substitute values with units, and keep track of signs. For multiple charges, calculate each potential separately before summing. Check that your final answer has the correct unit (V).
    Step-by-Step Worked Solutions

    Question: Calculate the electric potential at a distance of 3.0 cm from a point charge of +4.5 nC in a vacuum. Use k = 1/(4*pi*epsilon_0) = 8.99x10^9 N m^2 C^-2.

    1. 1.Step 1: Identify given facts: Q = +4.5 nC = 4.5x10^-9 C, r = 3.0 cm = 0.030 m, k = 8.99x10^9 N m^2 C^-2.
    2. 2.Step 2: Apply the formula for electric potential due to a point charge: V = kQ/r.
    3. 3.Step 3: Substitute values: V = (8.99x10^9 * 4.5x10^-9) / 0.030.
    4. 4.Step 4: Calculate: V = (40.455) / 0.030 = 1348.5 V.
    5. 5.Step 5: State final answer with correct unit and significant figures: V = 1.3x10^3 V (or 1350 V).
    Final Answer: The electric potential at 3.0 cm from the charge is approximately 1.3x10^3 V.

    Question: Two point charges, Q1 = +6.0 nC and Q2 = -6.0 nC, are separated by a distance of 12.0 cm. Calculate the electric potential at the midpoint between them.

    1. 1.Step 1: Identify given facts: Q1 = +6.0x10^-9 C, Q2 = -6.0x10^-9 C, distance between charges = 12.0 cm = 0.120 m, so midpoint is 0.060 m from each charge.
    2. 2.Step 2: Use the principle that electric potential is a scalar and the total potential is the algebraic sum of individual potentials: V_total = V1 + V2.
    3. 3.Step 3: Calculate V1 due to Q1: V1 = kQ1/r = (8.99x10^9 * 6.0x10^-9) / 0.060 = 899 V.
    4. 4.Step 4: Calculate V2 due to Q2: V2 = kQ2/r = (8.99x10^9 * -6.0x10^-9) / 0.060 = -899 V.
    5. 5.Step 5: Sum: V_total = 899 + (-899) = 0 V.
    Final Answer: The electric potential at the midpoint is 0 V.
    Active Recall Memory Test
    Define electric potential at a point.
    Key Fact: Electric potential at a point is the work done per unit positive charge in bringing a small positive test charge from infinity to that point.
    What is the formula for the electric potential due to a point charge?
    Key Fact: V = kQ/r, where k = 1/(4*pi*epsilon_0) = 8.99x10^9 N m^2 C^-2, Q is the charge, and r is the distance from the charge.
    Is electric potential a scalar or vector? How do you combine potentials from multiple charges?
    Key Fact: Electric potential is a scalar. The total potential at a point is the algebraic sum of the potentials due to each charge individually.
    What is the relationship between electric field strength and electric potential?
    Key Fact: Electric field strength is the negative gradient of electric potential: E = -dV/dr. The negative sign indicates that the field points in the direction of decreasing potential.
    Frequently Asked Questions
    What is the difference between electric potential and electric potential energy?
    Electric potential (V) at a point is the work done per unit positive charge in bringing a small positive test charge from infinity to that point, measured in volts (J C^-1). Electric potential energy (U) is the energy a specific charge q possesses at that point, given by U = qV, measured in joules (J). In short, potential is per unit charge, while potential energy depends on the charge placed in the field.
    Why is electric potential a scalar quantity?
    Electric potential is a scalar because it is defined in terms of work done (a scalar) per unit charge. Work is a scalar quantity, and dividing by charge (also scalar) yields a scalar. This means that when combining potentials from multiple charges, you simply add them algebraically, taking into account their signs, without needing to consider direction.
    How do you calculate the electric potential at a point due to multiple point charges?
    To find the total electric potential at a point due to several point charges, calculate the potential due to each charge individually using V = kQ/r, where r is the distance from that charge to the point of interest. Then sum these potentials algebraically, including their signs (positive for positive charges, negative for negative charges). This works because electric potential is a scalar quantity.
    What is an equipotential surface and why is it important?
    An equipotential surface is a surface on which the electric potential is constant everywhere. No work is done when a charge moves along an equipotential surface because there is no change in potential. Equipotential surfaces are always perpendicular to electric field lines, and they help visualise electric fields. For a point charge, equipotential surfaces are concentric spheres.
    How does electric potential relate to electric field strength?
    Electric field strength E is related to the rate of change of electric potential with distance. Specifically, E = -dV/dr, where dV/dr is the potential gradient. The negative sign indicates that the electric field points in the direction of decreasing potential. This means that if you have a graph of potential V against distance r, the gradient at any point gives the negative of the electric field strength at that point.
    Why is the electric potential at infinity taken as zero?
    The electric potential at infinity is defined as zero because the electric force between charges approaches zero as the distance between them becomes infinitely large. This provides a convenient reference point for calculating potential differences. By defining V = 0 at infinity, the potential at any finite distance from a point charge is given by V = kQ/r, which simplifies calculations and aligns with the definition of potential as work done per unit charge from infinity.