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    Mass and energy (A-level only) — AQA A-Level Physics

    Teaching note checked against the official specification.

    Mass and energy are interchangeable according to Einstein's mass-energy equivalence principle, E = mc^2, where mass can be converted into energy and vice versa. In AQA A-Level Physics, this explains nuclear binding energy, mass defect, and the energy released in nuclear fission and fusion reactions.

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    Mass and energy (A-level only) explained

    Mass and energy (A-level only) covers 8 specification points, including Atomic mass unit, u.

    Read the full explanation

    and Conversion of units; 1 u = 931.5 MeV.. Open a point below for its explanation and revision guidance.

    Atomic mass unit, u.

    The atomic mass unit, u, is a non-SI unit of mass defined as one twelfth of the mass of a carbon-12 atom in its nuclear and electronic ground state. It provides a convenient scale for atomic and nuclear masses because these are far too small for kilograms to be practical. One u is approximately 1.661 × 10⁻²⁷ kg. In nuclear physics, masses are often quoted in u, and mass differences in nuclear reactions are converted to energy using Einstein’s mass–energy equivalence. For example, the mass defect of a helium-4 nucleus is about 0.0304 u, which corresponds to a binding energy of roughly 28.3 MeV. Students should be able to use u in calculations involving mass defect and energy release, and to convert between u and kg when required.

    Conversion of units; 1 u = 931.5 MeV.

    The conversion 1 u = 931.5 MeV links the atomic mass unit to energy via Einstein’s mass–energy equivalence, E = mc². This allows nuclear masses expressed in u to be converted directly into energy in MeV, which is a convenient unit for nuclear processes. The value arises because 1 u = 1.661 × 10⁻²⁷ kg, and multiplying by c² (where c = 3.00 × 10⁸ m s⁻¹) gives approximately 1.492 × 10⁻¹⁰ J, which is equivalent to 931.5 MeV. In calculations, if a mass defect is given in u, the energy released can be found by multiplying the mass defect by 931.5 MeV u⁻¹. For example, a mass defect of 0.020 u corresponds to 0.020 × 931.5 = 18.63 MeV. Students should be able to perform such conversions and use them in nuclear reaction problems.

    Fission and fusion processes.

    Fission splits a heavy nucleus (e.g., uranium-235) into two smaller nuclei after absorbing a neutron, releasing neutrons and energy. Fusion joins two light nuclei (e.g., deuterium and tritium) to form a heavier nucleus, releasing energy. In both processes, the total product mass is slightly less than the reactant mass; this mass defect appears as energy via ΔE = Δmc². The energy arises because the product nuclei sit higher on the binding-energy-per-nucleon curve, closer to the iron-56 peak, meaning they have a higher binding energy per nucleon than the reactants. Fission is used in nuclear reactors to generate power, while fusion is the process that powers stars.

    Simple calculations from nuclear masses of energy released in fission and fusion reactions.

    To find the energy released in a fission or fusion reaction, first write the balanced nuclear equation and identify the masses of all reactants and products. The total mass before the reaction minus the total mass after the reaction gives the mass difference Δm. Convert Δm from atomic mass units to kilograms if necessary, using 1 u = 1.66 × 10⁻²⁷ kg, then calculate energy with ΔE = Δmc². A common method is to work in atomic mass units and use the energy equivalent 1 u = 931.5 MeV, but the same result follows from SI units. The energy appears mainly as kinetic energy of the product nuclei and neutrons, and for fusion also as energy of emitted particles or radiation.

    Graph of average binding energy per nucleon against nucleon number.

    The graph plots average binding energy per nucleon, in MeV, on the vertical axis against nucleon number A on the horizontal axis. Average binding energy per nucleon equals the total binding energy of the nucleus divided by A, so it measures how tightly each nucleon is held. The curve rises steeply from hydrogen and helium, peaks near iron-56 at roughly 8.8 MeV per nucleon, then falls slowly towards uranium. A higher value means a more stable nucleus, because more energy must be supplied per nucleon to separate the nucleus into free nucleons. The mass defect relates to binding energy through E = mc², so the graph is a stability map of the nuclides.

    Students may be expected to identify, on the plot, the regions where nuclei will release energy when undergoing fission/fusion.

    Energy is released when the products have a higher average binding energy per nucleon than the reactants, because the increase in binding energy per nucleon corresponds to a decrease in total mass, converted by E = mc². On the graph, fusion of light nuclei moves them up the steep left-hand side towards the peak, so energy is released. Fission of heavy nuclei splits them into mid-mass fragments nearer the peak, also releasing energy. The region around the maximum near iron-56 is where little or no energy is released by either process. Reading the graph means comparing the starting and finishing heights on the vertical axis.

    Appreciation that knowledge of the physics of nuclear energy allows society to use science to inform decision making.

    Physics does not decide policy, but it supplies the evidence on which sound decisions rest. In nuclear energy, mass–energy equivalence explains why fission releases energy: the products have slightly less mass than the reactants, and the missing mass appears as kinetic energy via ΔE = Δmc². Knowing this lets society compare nuclear power with alternatives on quantities such as energy released per kilogram of fuel, carbon dioxide emissions and radioactive waste. Students should trace a clear chain: nuclear physics gives data, data informs risk–benefit analysis, and citizens, scientists and governments then weigh that evidence alongside economic, ethical and environmental factors. For example, calculating the energy from the fission of 1 kg of uranium‑235 shows why a small fuel mass can supply a large city, which informs debate about fuel security and waste storage.

    Bertozzi’s experiment as direct evidence for the variation of kinetic energy with speed.

    Bertozzi accelerated electrons along a linear tube and timed their travel over a measured distance, giving their speed directly. Crucially, he measured the kinetic energy delivered by the electrons independently using calorimetry, by recording the temperature rise of an aluminium target they struck. Plotting kinetic energy against speed showed that at low speeds, energy rose as ½mv². However, as v approached c, the energy increased steeply while the speed levelled off below c. This provides direct evidence that kinetic energy does not follow the classical formula at relativistic speeds and that no massive particle reaches the speed of light. The relativistic expression Eₖ = (γ − 1)mc² fits the experimental data perfectly.

    Your focus

    1. Define the atomic mass unit and state its value in kilograms.
    2. Convert between mass in u and mass in kg.
    3. Apply the atomic mass unit in calculations of mass defect and energy release.
    Show all 24 objectives
    1. State and use the conversion factor 1 u = 931.5 MeV.
    2. Convert between mass in u and energy in MeV in nuclear contexts.
    3. Apply the conversion to solve problems involving mass defect and energy release.
    4. Describe the changes to nuclei that occur in fission and fusion processes.
    5. Explain why fission and fusion release energy in terms of mass difference and binding energy per nucleon.
    6. Distinguish between the conditions and products of fission and fusion.
    7. Calculate the mass difference in a given fission or fusion reaction from nuclear masses.
    8. Convert a mass difference into energy using ΔE = Δmc² or the equivalent energy of 1 u.
    9. Present the energy released with correct units and explain its origin in the reaction.
    10. Sketch and interpret the graph of average binding energy per nucleon against nucleon number.
    11. Calculate average binding energy per nucleon from total binding energy and nucleon number.
    12. Relate the peak of the curve to the stability of nuclei near iron-56.
    13. Identify on the graph the regions where fusion and fission release energy.
    14. Compare average binding energy per nucleon for reactants and products to decide whether energy is released.
    15. Explain energy release in terms of mass defect and E = mc².
    16. Explain how ΔE = Δmc² accounts for the energy released in nuclear processes.
    17. Use given data to compare the energy available from nuclear fuel with that from other fuels.
    18. Discuss how scientific evidence can inform, but not replace, societal decisions about energy use.
    19. Describe how Bertozzi measured electron speed via time of flight and kinetic energy independently via calorimetry.
    20. Interpret the kinetic energy–speed relationship and explain why it supports special relativity.
    21. Apply Eₖ = (γ − 1)mc² to show the divergence from classical predictions at high speed.

    Which command word is this?

    You must use the given data and equations to find a numerical answer. Show all working, including unit conversions, and give your final answer with appropriate units and significant figures. Marks are awarded for correct substitution and final value.

    Mass and energy (A-level only) exam tips

    Topic Overview

    This topic explores the profound relationship between mass and energy as described by Einstein's famous equation E = mc^2. You will learn how mass can be converted into energy in nuclear processes, and how the tiny mass defects in nuclei account for the enormous energy released in fission and fusion. It builds on your understanding of atomic structure, the nucleus, and conservation laws from earlier in the course.

    Understanding mass-energy equivalence is crucial for explaining nuclear stability, the energy output of stars, and the operation of nuclear power stations. It also provides a foundation for later topics such as particle physics and cosmology. In AQA A-Level Physics, this topic is assessed in both calculation-heavy questions and extended explanations, so you must be confident with both the maths and the physical principles.

    Key Concepts
    • →Mass-energy equivalence: E = mc^2, where E is energy in joules, m is mass in kg, and c is the speed of light in vacuum (3.00 x 10^8 m s^-1).
    • →Mass defect: the difference between the mass of a nucleus and the sum of the masses of its individual protons and neutrons.
    • →Binding energy: the energy equivalent of the mass defect, representing the energy required to separate a nucleus into its constituent nucleons.
    • →Binding energy per nucleon: total binding energy divided by nucleon number; peaks at iron-56, indicating maximum nuclear stability.
    • →Nuclear fission and fusion: both release energy because the products have higher binding energy per nucleon than the reactants, resulting in a mass defect that is converted into energy.
    Marking Points
    • State that the atomic mass unit is defined as one twelfth of the mass of a carbon-12 atom.
    • Recall that 1 u ≈ 1.661 × 10⁻²⁷ kg.
    • Use u as a unit of mass in nuclear calculations, such as mass defect.
    • Convert mass in u to energy using the equivalence 1 u = 931.5 MeV.
    • Explain why u is used instead of kg for atomic and nuclear masses.
    • State the conversion factor 1 u = 931.5 MeV.
    • Convert mass defect in u to energy in MeV by multiplying by 931.5.
    • Convert energy in MeV to mass in u by dividing by 931.5.
    • Use the conversion in calculations involving nuclear binding energy or reaction energy.
    • Explain the origin of the conversion factor from E = mc².
    • Fission: a heavy nucleus absorbs a neutron and splits into two smaller nuclei, releasing two or three neutrons and energy.
    • Fusion: two light nuclei combine to form a heavier nucleus, releasing energy.
    • In both processes the total mass after the reaction is less than the total mass before, and the mass difference Δm corresponds to energy released by ΔE = Δmc².
    • The energy release is linked to an increase in binding energy per nucleon of the products compared with the reactants, placing them higher on the curve.
    • Write a balanced nuclear equation for the fission or fusion reaction, ensuring nucleon number and proton number are conserved.
    • Calculate the total mass of reactants and the total mass of products using the nuclear masses supplied.
    • Find the mass difference Δm = total mass of reactants − total mass of products.
    • Convert Δm to kilograms if using SI units, or use the energy equivalent of 1 u, before applying ΔE = Δmc².
    • State the energy released with an appropriate unit, such as J or MeV, and link it to the kinetic energy of the products.
    • Average binding energy per nucleon is total binding energy divided by nucleon number A, with units of MeV per nucleon.
    • The curve rises sharply for light nuclei, reaches a broad maximum around A = 56 near iron, then decreases gradually for heavy nuclei.
    • A larger value of average binding energy per nucleon indicates a more stable nucleus because more energy is needed per nucleon to separate it.
    • Binding energy arises from the mass defect, calculated using E = mc², where m is the difference between the mass of separate nucleons and the nuclear mass.
    • The graph is a smooth curve through nuclide data, not a straight line, and the peak region is broad rather than a single sharp point.
    • Energy is released when the average binding energy per nucleon increases from reactants to products, because the total mass decreases.
    • Fusion releases energy for light nuclei on the rising left-hand region of the curve, where products lie closer to the peak.
    • Fission releases energy for heavy nuclei on the falling right-hand region, where mid-mass fragments lie closer to the peak.
    • The change in binding energy per nucleon multiplied by the number of nucleons gives the total energy released, consistent with E = mc².
    • Nuclei near the maximum around iron-56 are the most stable, so reactions producing them release little further energy.
    • State that mass–energy equivalence, ΔE = Δmc², explains the energy released when a nucleus undergoes fission or fusion.
    • Explain that the total mass of the products of fission is slightly less than the mass of the original nucleus plus neutron, and this mass difference appears as energy.
    • Use quantitative data, such as energy released per kilogram of fuel, to compare nuclear energy with fossil fuels in a decision-making context.
    • Describe how scientific evidence about energy release, waste and safety feeds into public and political decisions alongside economic, ethical and environmental considerations.
    • Recognise that physics can quantify risks and benefits but cannot by itself settle questions of value or policy.
    • Describes the method for speed: electrons are accelerated through a known potential difference and their flight time over a measured distance gives speed.
    • Explains that kinetic energy is determined independently using calorimetry, by measuring the temperature rise of a target struck by the electrons.
    • States the key result: measured speed approaches but never reaches c, while kinetic energy continues to rise without limit.
    • Uses Eₖ = (γ − 1)mc² to show that the classical ½mv² result fails when v is a significant fraction of c.
    • Explains that the experiment supports special relativity rather than classical mechanics because the classical prediction diverges from the data at high speed.
    • Recognises that the result implies a limiting speed c for massive particles and links this to the relativistic increase of energy.
    Examiner Tips
    • 💡Learn the definition of u precisely, including the carbon-12 reference.
    • 💡In calculations, keep track of units and convert to kg if the equation requires SI units.
    • 💡Use the conversion 1 u = 931.5 MeV to simplify energy calculations in nuclear reactions.
    • 💡Memorise the conversion factor 1 u = 931.5 MeV for quick calculations.
    • 💡When using E = mc², ensure mass is in kg and energy in J, or use the direct u to MeV conversion.
    • 💡Check that your final answer has the correct unit and magnitude.
    • 💡When asked to describe fission or fusion, name the nuclei involved and state what happens to them before discussing energy.
    • 💡Use the binding-energy-per-nucleon curve to justify why energy is released: products must have higher binding energy per nucleon than reactants.
    • 💡Lay out the calculation in clear steps: balanced equation, total reactant mass, total product mass, mass difference, then energy.
    • 💡Keep track of units throughout; if masses are in u, either convert to kg or use the u-to-energy equivalence consistently.
    • 💡Check that the sign of the energy released is positive and that the magnitude is reasonable for a nuclear reaction.
    • 💡Label both axes with quantity and unit, for example average binding energy per nucleon / MeV and nucleon number A.
    • 💡Quote the peak position approximately, for example around A = 56, and its value near 8.8 MeV per nucleon, rather than claiming an exact universal figure.
    • 💡When explaining stability, refer to energy required per nucleon to separate the nucleus, not to the total energy alone.
    • 💡Mark arrows on the graph showing light nuclei moving up towards the peak for fusion and heavy nuclei moving towards the peak for fission.
    • 💡State the direction of change in average binding energy per nucleon explicitly, then link it to the mass decrease and energy release.
    • 💡Use the phrase per nucleon when comparing values, and avoid quoting a single fixed energy release for all reactions.
    • 💡Link every decision-making point back to a specific physics quantity, such as Δm, ΔE or energy per kilogram, rather than writing general opinions.
    • 💡When asked to evaluate, give both a benefit and a limitation of using nuclear energy, and state which evidence supports each.
    • 💡Use correct units and powers of ten, for example writing energy in J or MJ kg⁻¹, and keep the mass difference in kg when using ΔE = Δmc².
    • 💡Describe the independent measurements of speed (time of flight) and kinetic energy (calorimetry) separately, because the strength of the evidence depends on them being measured by different means.
    • 💡Sketch or interpret the graph shape: classical ½mv² rising as a parabola against the relativistic curve that steepens near c.
    • 💡Use the phrase direct evidence and explain what would be expected classically, so the contrast with the data is explicit.
    • 💡Quote the limiting behaviour of speed near c rather than saying electrons were stopped or slowed.
    • 💡Always show your unit conversions clearly. In calculations, convert atomic mass units (u) to kilograms (kg) before using E = mc^2. Remember 1 u = 1.66 x 10^-27 kg.
    • 💡When explaining binding energy, use precise language: 'the energy required to separate a nucleus into its individual protons and neutrons' or 'the energy released when a nucleus forms from its constituent nucleons'.
    • 💡For graph questions on binding energy per nucleon, label axes correctly (binding energy per nucleon / MeV on y-axis, nucleon number A on x-axis), mark the peak at A=56, and annotate regions where fusion and fission occur.
    Common Mistakes
    • Confusing the atomic mass unit with the relative atomic mass; correction: u is a unit of mass, while relative atomic mass is a dimensionless ratio.
    • Using 1 u = 1.66 × 10⁻²⁷ kg without recognising it is an approximation; correction: use the more precise value 1.661 × 10⁻²⁷ kg when needed.
    • Forgetting to convert mass from u to kg before using SI equations; correction: either convert to kg or use the energy equivalent 1 u = 931.5 MeV directly.
    • Using 1 u = 931.5 MeV as a mass conversion without recognising it is an energy equivalent; correction: it converts mass in u to energy in MeV.
    • Forgetting to multiply by the number of particles when calculating total energy release; correction: ensure the mass defect used corresponds to the total number of nuclei involved.
    • Mixing units, such as using MeV with kg without conversion; correction: consistently use either u and MeV or kg and J.
    • Thinking that mass is destroyed in fission and fusion; the correct idea is that mass is converted into energy, so total mass-energy is conserved.
    • Believing that fission releases energy because the nucleus is unstable, without linking the release to the increase in binding energy per nucleon of the products.
    • Confusing the two processes, for example describing fusion as the splitting of a heavy nucleus; the correction is to state that fusion joins light nuclei while fission splits a heavy nucleus.
    • Subtracting masses in the wrong order, giving a negative mass difference; the correction is to subtract total product mass from total reactant mass.
    • Forgetting to convert atomic mass units to kilograms before using ΔE = Δmc² in SI units; the correction is to multiply by 1.66 × 10⁻²⁷ kg per u.
    • Using the mass of a whole atom instead of the nuclear mass when the question specifies nuclear masses; the correction is to use the values given and not add or remove electron masses unless instructed.
    • Treating the vertical axis as total binding energy rather than binding energy per nucleon; correct this by dividing total binding energy by A before plotting or reading values.
    • Assuming the most stable nucleus has the largest nucleon number; correct this by identifying the peak near iron-56 as the region of greatest stability.
    • Confusing binding energy with the energy released in a reaction; correct this by using differences in binding energy per nucleon between initial and final nuclei to find energy release.
    • Claiming fission releases energy because heavy nuclei are unstable in a general sense; correct this by comparing binding energy per nucleon of the heavy nucleus with that of its fragments.
    • Stating that fusion always releases energy for any two nuclei; correct this by restricting energy-releasing fusion to light nuclei whose products move towards the peak.
    • Using total binding energy instead of binding energy per nucleon when comparing reactants and products; correct this by comparing values per nucleon before multiplying by nucleon number.
    • Treating mass as being converted into energy in a vague everyday sense; the correction is that a measurable mass difference Δm corresponds to energy ΔE = Δmc².
    • Assuming that scientific knowledge automatically determines the best policy; the correction is that decisions also depend on costs, risks, ethics and public values.
    • Confusing the energy released per fission with the energy released per kilogram of fuel; the correction is that per-kilogram values require the number of nuclei in the sample, found using Avogadro's constant.
    • Claiming Bertozzi measured kinetic energy solely from the accelerating voltage: the error misses the independent verification; the correction is that he used calorimetry (target temperature rise) to measure kinetic energy independently.
    • Stating that electrons exceeded the speed of light at the highest energies: the correction is that measured speeds approached c asymptotically and never surpassed it.
    • Using Eₖ = ½mv² for the high-speed data: the correction is to use the relativistic expression Eₖ = (γ − 1)mc² when v is comparable to c.
    • Students often think mass is 'lost' in nuclear reactions. In fact, mass is converted into energy, and the total mass-energy is conserved. The missing mass appears as energy (often kinetic energy of products).
    • Many believe that binding energy is stored in the nucleus. Actually, binding energy is the energy required to break the nucleus apart; it is released when the nucleus forms. A higher binding energy per nucleon means a more stable nucleus.
    • Some students confuse the mass defect with the mass of the missing particles. The mass defect is simply the difference in mass before and after the reaction, not a physical missing piece.
    Revision Plan
    1. 1Start by reviewing the definition of mass defect and binding energy. Use the equation E = mc^2 to calculate energy from mass defect, practising unit conversions between u, kg, J, and MeV.
    2. 2Draw and annotate the binding energy per nucleon graph. Memorise the key features: peak at iron-56, values for light and heavy nuclei, and the regions where fusion and fission release energy.
    3. 3Work through past paper questions on fission and fusion calculations. Focus on setting out calculations clearly, showing the mass defect, conversion to kg, and final energy in J or MeV.
    4. 4Create flashcards for key definitions and common misconceptions. Test yourself on explaining why fusion releases energy for light nuclei and why fission releases energy for heavy nuclei.
    5. 5Attempt extended-response questions (6 marks) on nuclear stability and energy release. Practise structuring your answers with clear definitions, explanations, and examples.
    Exam Question Types
    • 📋Calculation questions: Calculate the energy released in a fission or fusion reaction given masses in u. Advice: Always convert to kg, use E = mc^2, and check units. Show all steps.
    • 📋Graph interpretation: Sketch or interpret the binding energy per nucleon curve. Advice: Label axes, mark the peak, and explain the significance of the shape for fusion and fission.
    • 📋Explanation questions: Explain what is meant by mass defect and binding energy, and how they relate to nuclear stability. Advice: Use precise definitions and link to E = mc^2.
    • 📋Extended writing: Discuss the conditions necessary for fusion and why it is difficult to achieve on Earth. Advice: Include temperature, pressure, and Coulomb barrier, and relate to binding energy.
    Command Word Expectations (AQA)
    Calculate

    You must use the given data and equations to find a numerical answer. Show all working, including unit conversions, and give your final answer with appropriate units and significant figures. Marks are awarded for correct substitution and final value.

    Explain

    You must give reasons or mechanisms, not just a description. For example, explain why energy is released in fission by referring to the increase in binding energy per nucleon and the mass defect. Use correct terminology and link cause and effect.

    Describe

    You must give a detailed account of the main features or steps. For example, describe how the binding energy per nucleon varies with nucleon number, including the shape of the graph and key values. No explanation of why is required unless asked.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often forget to convert mass from atomic mass units (u) to kilograms (kg) before using E = mc^2, leading to incorrect energy values by a factor of (1.66 x 10^-27)^2.
    ❌ Weak Answer (Loses Marks):Using mass in u directly in E = mc^2 and giving an answer in joules without conversion.
    Example improved answer:First convert mass defect from u to kg using 1 u = 1.66 x 10^-27 kg. Then apply E = mc^2 with c = 3.00 x 10^8 m s^-1. For example, a mass defect of 0.002 u becomes 0.002 x 1.66 x 10^-27 = 3.32 x 10^-30 kg, giving E = 3.32 x 10^-30 x (3.00 x 10^8)^2 = 2.99 x 10^-13 J.
    Examiner Tip: Always write down the conversion factor and show the unit conversion explicitly. Examiners award marks for correct substitution even if the final arithmetic is wrong, but only if units are consistent.
    Pitfall: Confusing mass defect with binding energy, or failing to link the two in explanations of nuclear stability.
    ❌ Weak Answer (Loses Marks):Stating that mass defect is the energy released without explaining that it is the difference between the mass of the separated nucleons and the mass of the nucleus.
    Example improved answer:Mass defect is the difference between the total mass of the individual protons and neutrons in a nucleus and the actual mass of the nucleus. This missing mass is converted into energy (binding energy) according to E = mc^2, which is released when the nucleus forms and must be supplied to break it apart.
    Examiner Tip: Use precise definitions: mass defect is a mass difference, binding energy is the energy equivalent. Always relate them using E = mc^2 and mention that binding energy per nucleon determines nuclear stability.
    Step-by-Step Worked Solutions

    Question: Calculate the energy released in the following fission reaction: U-235 + n -> Ba-141 + Kr-92 + 3n. The masses are: U-235 = 235.0439 u, n = 1.0087 u, Ba-141 = 140.9144 u, Kr-92 = 91.9262 u. Give your answer in MeV.

    1. 1.Step 1: Calculate total mass before reaction: m_initial = 235.0439 + 1.0087 = 236.0526 u.
    2. 2.Step 2: Calculate total mass after reaction: m_final = 140.9144 + 91.9262 + 3(1.0087) = 235.8667 u.
    3. 3.Step 3: Mass defect delta_m = 236.0526 - 235.8667 = 0.1859 u.
    4. 4.Step 4: Convert mass defect to kg: 0.1859 x 1.66 x 10^-27 = 3.086 x 10^-28 kg.
    5. 5.Step 5: Calculate energy using E = delta_m c^2 = 3.086 x 10^-28 x (3.00 x 10^8)^2 = 2.777 x 10^-11 J.
    6. 6.Step 6: Convert to MeV: 2.777 x 10^-11 / 1.60 x 10^-13 = 173.6 MeV.
    Final Answer: The energy released is approximately 174 MeV.

    Question: Explain what is meant by binding energy per nucleon and describe how it varies with nucleon number. Include a sketch of the graph and explain the significance of the maximum.

    1. 1.Step 1: Define binding energy per nucleon: the energy required to remove one nucleon from a nucleus, equal to total binding energy divided by nucleon number A.
    2. 2.Step 2: Describe the graph: it rises steeply for small A, peaks around A = 56 (iron-56) at about 8.8 MeV per nucleon, then gradually decreases for larger A.
    3. 3.Step 3: Explain significance: the maximum at iron-56 means it is the most stable nucleus. Nuclei with lower binding energy per nucleon can undergo fusion (light nuclei) or fission (heavy nuclei) to move towards the peak, releasing energy.
    4. 4.Step 4: Relate to mass defect: binding energy per nucleon is directly proportional to mass defect per nucleon, so the peak corresponds to the greatest mass defect per nucleon.
    Final Answer: Binding energy per nucleon is the average energy needed to remove a nucleon. It peaks at about 8.8 MeV for iron-56, indicating maximum stability. Fusion of light nuclei and fission of heavy nuclei both release energy as they move towards this peak.
    Active Recall Memory Test
    State Einstein's mass-energy equivalence equation and define each term with its SI unit.
    Key Fact: E = mc^2, where E is energy in joules (J), m is mass in kilograms (kg), and c is the speed of light in vacuum, 3.00 x 10^8 m s^-1.
    What is mass defect and how is it related to binding energy?
    Key Fact: Mass defect is the difference between the mass of a nucleus and the sum of the masses of its individual nucleons. It is related to binding energy by E = mc^2, where E is the binding energy.
    At what nucleon number does the binding energy per nucleon reach its maximum, and what is the significance?
    Key Fact: It peaks at A = 56 (iron-56) with a value of about 8.8 MeV per nucleon. This indicates that iron-56 is the most stable nucleus; fusion of lighter nuclei and fission of heavier nuclei both release energy as they move towards this peak.
    Why is energy released in nuclear fission?
    Key Fact: Energy is released because the fission products have a higher binding energy per nucleon than the original heavy nucleus. The increase in binding energy corresponds to a mass defect, which is converted into energy according to E = mc^2.
    Frequently Asked Questions
    What is the difference between mass defect and binding energy?
    Mass defect is the difference in mass between a nucleus and its separated nucleons, measured in kg or u. Binding energy is the energy equivalent of that mass defect, calculated using E = mc^2, and is measured in joules or MeV. Essentially, mass defect is the 'missing mass' that has been converted into the energy that holds the nucleus together.
    Why do we use E = mc^2 in nuclear physics?
    E = mc^2 shows that mass and energy are interchangeable. In nuclear reactions, small changes in mass result in large energy changes because c^2 is a very large number. This equation allows us to calculate the energy released in fission and fusion from the measured mass defect.
    How do I convert atomic mass units (u) to kilograms?
    Use the conversion factor 1 u = 1.66 x 10^-27 kg. Multiply the mass in u by this factor to get the mass in kg. For example, 4.0026 u becomes 4.0026 x 1.66 x 10^-27 = 6.644 x 10^-27 kg. Always convert to kg before using E = mc^2 to ensure your energy is in joules.
    Why does fusion release energy for light nuclei but require energy for heavy nuclei?
    Fusion releases energy when the product has a higher binding energy per nucleon than the reactants. For light nuclei (A < 56), fusion moves them towards the peak of the binding energy curve, increasing stability and releasing energy. For heavy nuclei (A > 56), fusion would move them away from the peak, decreasing stability, so energy would be required rather than released.
    What is the significance of the peak in the binding energy per nucleon graph?
    The peak at A = 56 (iron-56) represents the most stable nucleus, with the highest binding energy per nucleon (about 8.8 MeV). Nuclei lighter than this can undergo fusion to move towards the peak, releasing energy. Nuclei heavier than this can undergo fission to move towards the peak, also releasing energy. This explains why both fission and fusion can release energy.
    How do I calculate the energy released in a nuclear reaction?
    First, calculate the total mass before and after the reaction. Find the mass defect (difference in mass). Convert the mass defect to kg using 1 u = 1.66 x 10^-27 kg. Then use E = mc^2 with c = 3.00 x 10^8 m s^-1 to find the energy in joules. If needed, convert to MeV using 1 MeV = 1.60 x 10^-13 J. Always show your working and units.