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    Nuclear instability (A-level only) — AQA A-Level Physics

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    Nuclear instability in AQA A-Level Physics covers why certain nuclei are unstable and undergo radioactive decay, including alpha, beta-minus, beta-plus and gamma emission. Students must apply conservation of nucleon number and charge, use the decay constant and activity equations, and interpret N-Z graphs to predict the mode of decay.

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    Nuclear instability (A-level only) explained

    Nuclear instability (A-level only) covers 4 specification points, including Graph of N against Z for stable nuclei.

    Read the full explanation

    and + Possible decay modes of unstable nuclei…. Open a point below for its explanation and revision guidance.

    Graph of N against Z for stable nuclei.

    A graph of neutron number N against proton number Z for stable nuclei shows a curved band called the line of stability. For light nuclei, the stable ratio N/Z is close to 1. As Z increases, Coulomb repulsion between protons grows, so more neutrons are needed to provide attractive strong nuclear force without adding charge; the line bends upwards, and the stable ratio rises to about 1.5 for heavy nuclei like lead-208. Nuclei above the band are neutron-rich and tend to undergo beta-minus decay. Nuclei below the band are proton-rich and tend to undergo beta-plus decay or electron capture. Very heavy nuclei beyond Z = 83 are unstable and primarily decay by alpha emission to reduce their size, though they can also undergo beta decays within decay chains to adjust their N/Z ratio.

    + Possible decay modes of unstable nuclei including α, β , − β and electron capture.

    Unstable nuclei adjust their proton number Z and neutron number N to move towards stability. An alpha particle is a helium nucleus, ⁴₂He, so alpha emission lowers Z by 2 and N by 2. Beta-minus decay converts a neutron into a proton, emitting an electron and an antineutrino, so Z increases by 1 while N falls by 1. Beta-plus decay converts a proton into a neutron, emitting a positron and a neutrino, so Z decreases by 1 while N rises by 1. Electron capture pulls an inner electron into the nucleus, combining with a proton to form a neutron and a neutrino, again lowering Z by 1 and raising N by 1. Each mode changes the nucleus differently, so the N-Z plot reveals which decay suits a given nuclide.

    Changes in N and Z caused by radioactive decay and representation in simple decay equations.

    Radioactive decay changes the numbers of protons and neutrons in a nucleus, and these changes must be shown in balanced decay equations. For alpha emission, the parent nuclide loses ⁴₂He, so the daughter has A reduced by 4, Z reduced by 2 and N reduced by 2. For beta-minus decay, a neutron becomes a proton, so Z increases by 1, N decreases by 1 and A is unchanged; the equation includes an electron and an antineutrino. For beta-plus decay, a proton becomes a neutron, so Z decreases by 1, N increases by 1 and A is unchanged; the equation includes a positron and a neutrino. Electron capture combines an inner electron with a proton, so Z decreases by 1, N increases by 1 and A is unchanged, with a neutrino emitted. Balancing A and Z on both sides confirms the equation.

    Existence of nuclear excited states; γ ray emission; application eg use of technetium-99m as a γ source in medical diagnosis.

    After alpha or beta decay, a daughter nucleus may be left with excess energy: it is in a nuclear excited state, shown as a higher line on an energy level diagram. It de-excites by emitting a gamma photon, a high-frequency electromagnetic quantum with no mass or charge, so proton and nucleon numbers do not change. Gamma emission usually follows other decay rather than occurring alone. Technetium-99m is a metastable excited state of technetium-99: it decays by gamma emission with a half-life of about six hours, and the gamma photons penetrate tissue, so a detector outside the body can map uptake in organs such as the heart, bones, kidneys and thyroid. The short half-life limits patient dose, and the gamma energy is suitable for detection. A tracer should also be non-toxic and have a known biological pathway.

    Your focus

    1. Describe the shape of the graph of N against Z for stable nuclei.
    2. Explain how the balance between the strong nuclear force and electrostatic repulsion changes the stable N/Z ratio with increasing Z.
    3. Predict the likely decay mode of a nuclide from its position relative to the line of stability, including alpha and beta decays for heavy nuclei.
    Show all 12 objectives
    1. Identify alpha, beta-minus, beta-plus and electron capture as possible decay modes of unstable nuclei.
    2. Describe the change in N and Z produced by each decay mode.
    3. Use the N-Z plot to predict the likely decay mode of a given nuclide.
    4. Write balanced decay equations for alpha, beta-minus, beta-plus and electron capture.
    5. Calculate changes in N and Z from a given decay equation.
    6. Check conservation of nucleon number and charge in nuclear equations.
    7. Describe how nuclear excited states arise and how gamma emission returns a nucleus to a lower energy state.
    8. Explain why gamma-emitting tracers such as technetium-99m can be detected outside the body and used in diagnosis.
    9. Relate the half-life and properties of a gamma source to its suitability and safety in medical imaging.

    Which command word is this?

    A brief, factual answer with no explanation required. For example, 'State the type of decay that occurs in a neutron-rich nucleus' expects 'beta-minus decay'.

    Nuclear instability (A-level only) exam tips

    Topic Overview

    Nuclear instability explains why some atomic nuclei are unstable and undergo radioactive decay. You will study the four main types of decay (alpha, beta-minus, beta-plus and gamma), the changes they cause in the nucleus, and how to represent them with balanced nuclear equations. The topic also introduces the N-Z graph, which shows how the ratio of neutrons to protons determines the stability of a nucleus and predicts the likely mode of decay.

    This topic is fundamental to understanding radioactivity, nuclear energy and medical physics. It builds on your knowledge of atomic structure and the strong nuclear force from earlier in the A-level course. Exam questions often require you to apply conservation laws, interpret decay equations, and perform calculations involving activity, decay constant and half-life, making it a key area for both mathematical and explanatory skills.

    Key Concepts
    • →Alpha decay emits a helium nucleus (4/2 He), reducing the nucleon number by 4 and the proton number by 2. Beta-minus decay emits an electron and an antineutrino, increasing the proton number by 1. Beta-plus decay emits a positron and a neutrino, decreasing the proton number by 1. Gamma emission releases excess energy without changing the nucleon or proton number.
    • →The N-Z graph plots neutron number against proton number for stable nuclides. The line of stability shows that light stable nuclei have N approximately equal to Z, while heavier stable nuclei have N greater than Z. Nuclei above the line are neutron-rich and undergo beta-minus decay; those below are proton-rich and undergo beta-plus decay or electron capture.
    • →Conservation laws in nuclear decay: nucleon number (mass number) and charge (proton number) must be conserved in all nuclear equations. Lepton number is also conserved, which is why neutrinos and antineutrinos are included in beta decay equations.
    • →The activity A of a radioactive source is the number of decays per second, measured in becquerels (Bq). Activity decreases exponentially with time: A = A0 e^(-lambda t), where lambda is the decay constant. The decay constant is related to half-life by lambda = ln(2) / t_half.
    • →The number of undecayed nuclei N also decreases exponentially: N = N0 e^(-lambda t). The activity is proportional to the number of undecayed nuclei, so A = lambda N.
    Marking Points
    • Plot N on the vertical axis and Z on the horizontal axis, with stable nuclei forming a narrow curved band.
    • State that light stable nuclei have N approximately equal to Z, giving a ratio close to 1.
    • Explain that heavier stable nuclei need a higher N/Z ratio, up to about 1.5, because of increasing Coulomb repulsion between protons.
    • Identify neutron-rich nuclei above the band as likely beta-minus emitters and proton-rich nuclei below the band as likely beta-plus emitters or electron capturers.
    • Relate alpha emission of very heavy nuclei to overall instability beyond Z = 83, noting that beta decays also occur in heavy decay chains.
    • Use the graph to predict a likely decay mode for a given nuclide from its position relative to the band.
    • Alpha emission removes two protons and two neutrons, so the daughter nuclide has Z decreased by 2 and N decreased by 2, with mass number A decreased by 4.
    • Beta-minus decay changes a neutron into a proton, so Z increases by 1 and N decreases by 1 while A stays constant; an electron and an antineutrino are emitted.
    • Beta-plus decay changes a proton into a neutron, so Z decreases by 1 and N increases by 1 while A stays constant; a positron and a neutrino are emitted.
    • Electron capture combines an inner-shell electron with a proton to form a neutron, so Z decreases by 1 and N increases by 1 while A stays constant; a neutrino is emitted.
    • The N-Z plot shows that neutron-rich nuclides tend to undergo beta-minus decay, proton-rich nuclides tend to undergo beta-plus decay or electron capture, and heavy nuclides tend to undergo alpha emission.
    • In alpha decay, the equation shows the parent nuclide producing a daughter with A decreased by 4 and Z decreased by 2, plus a ⁴₂He particle.
    • In beta-minus decay, the equation shows the parent nuclide producing a daughter with Z increased by 1 and A unchanged, plus an electron and an antineutrino.
    • In beta-plus decay, the equation shows the parent nuclide producing a daughter with Z decreased by 1 and A unchanged, plus a positron and a neutrino.
    • In electron capture, the equation shows the parent nuclide combining with an electron to produce a daughter with Z decreased by 1 and A unchanged, plus a neutrino.
    • Conservation of A and Z must hold on both sides of every decay equation.
    • States that a nucleus can exist in excited states after alpha or beta decay, with energy above the ground state.
    • Describes gamma emission as a photon emitted when the nucleus drops to a lower energy state, with no change in proton or nucleon number.
    • Explains that gamma photons are electromagnetic radiation with no mass and no charge, so they are highly penetrating.
    • Describes technetium-99m as a metastable gamma-emitting source used as a medical tracer.
    • Explains that the gamma radiation is detected outside the body to reveal the distribution of the tracer in an organ.
    • Links the roughly six-hour half-life to a useful balance between sufficient activity for imaging and a limited radiation dose to the patient.
    • Recognises that a suitable tracer must also be non-toxic and follow a known biological pathway to the target organ.
    Examiner Tips
    • 💡Sketch the axes with N vertical and Z horizontal and label the line of stability before adding any nuclide.
    • 💡Quote the approximate stable N/Z ratio for light and heavy nuclei to support your explanation.
    • 💡When predicting decay, state whether the nuclide is above or below the band and name the decay mode that moves it towards the band.
    • 💡Write the parent and daughter nuclides with correct A and Z before balancing any decay equation.
    • 💡Check conservation of A and Z after every decay to confirm the mode is consistent.
    • 💡Use the N-Z plot to justify why a particular nuclide decays by one mode rather than another.
    • 💡Balance A and Z separately before checking the particle emitted.
    • 💡Use the periodic table or data sheet to confirm the chemical symbol of the daughter nuclide.
    • 💡Include the neutrino or antineutrino in beta and electron capture equations where required.
    • 💡Use the term metastable when describing technetium-99m, and quote its half-life as approximately six hours.
    • 💡When explaining medical use, structure the answer as uptake, gamma emission, external detection and image formation.
    • 💡State explicitly that gamma emission leaves proton and nucleon numbers unchanged, since this is a common discriminator in mark schemes.
    • 💡Link the short half-life to patient safety and to practical imaging time rather than listing it without comment.
    • 💡Mention one named organ or application, such as heart, bone or kidney imaging, to make the application concrete.
    • 💡Always balance nuclear equations for both nucleon number (top) and proton number (bottom). Include the neutrino or antineutrino in beta decay equations to conserve lepton number; omitting them loses marks.
    • 💡When using exponential decay equations, convert half-life to seconds and ensure time is in seconds. Show your value of the decay constant to at least 3 significant figures before calculating the final answer.
    • 💡For 'explain' questions about stability, refer explicitly to the neutron-to-proton ratio and the balance between the strong nuclear force and electrostatic repulsion. Use the N-Z graph to justify your answer.
    Common Mistakes
    • Assuming the line of stability is straight with N = Z for all nuclei; correction: it curves upwards so heavy stable nuclei have more neutrons than protons.
    • Thinking that any nucleus with N greater than Z is unstable; correction: many light stable nuclei have N slightly greater than Z, and stability depends on the position relative to the band.
    • Assuming heavy nuclei (Z > 83) only decay by alpha emission; correction: while alpha decay reduces overall mass, heavy nuclei also undergo beta decay to correct their N/Z ratio during decay chains.
    • Treating beta-minus decay as loss of an electron from the nucleus; the correction is that a neutron transforms into a proton and the emitted electron is created in the decay.
    • Confusing beta-plus decay with electron capture because both lower Z by 1; the correction is that beta-plus emits a positron while electron capture absorbs an inner electron.
    • Assuming alpha emission changes only Z; the correction is that both Z and N fall by 2 and A falls by 4.
    • Writing a beta-minus decay equation without the antineutrino; the correction is to include the antineutrino so lepton number is conserved.
    • Changing A during beta decay; the correction is that A remains constant because only a neutron-proton conversion occurs.
    • Omitting the electron in an electron capture equation; the correction is to show the captured electron on the left-hand side.
    • Saying gamma emission changes the element: correct this by stating that gamma emission alters neither proton number nor nucleon number, so the nuclide stays the same.
    • Confusing gamma rays with alpha or beta particles: correct this by describing gamma as uncharged electromagnetic radiation with no mass, unlike charged, massive alpha and beta emissions.
    • Claiming technetium-99m is a stable or permanent source: correct this by describing it as metastable, decaying by gamma emission with a half-life of about six hours.
    • Treating the gamma photons as the imaging agent itself: correct this by explaining that the tracer is taken up by the organ and the emitted gamma photons are detected externally.
    • Students often think that beta particles come from the electron shells of the atom. In fact, beta-minus particles are created in the nucleus when a neutron transforms into a proton, and beta-plus particles are created when a proton transforms into a neutron.
    • Many students believe that gamma decay changes the element. Gamma emission only releases excess energy as a photon; it does not change the proton number or nucleon number, so the element remains the same.
    • Students sometimes assume that after one half-life, all nuclei have decayed. In reality, half-life is a statistical concept: after one half-life, half of the original nuclei remain undecayed, but individual decay events are random.
    Revision Plan
    1. 1Day 1-2: Review atomic structure and the strong nuclear force. Learn the definitions of alpha, beta-minus, beta-plus and gamma decay, and practise writing balanced nuclear equations for each type.
    2. 2Day 3-4: Study the N-Z graph and the line of stability. For each region (above, below, and on the line), identify the likely decay mode and explain why in terms of the neutron-to-proton ratio.
    3. 3Day 5-6: Learn the equations for activity and number of nuclei: A = A0 e^(-lambda t), N = N0 e^(-lambda t), lambda = ln(2)/t_half, and A = lambda N. Practise calculations with different time units.
    4. 4Day 7-8: Complete past-paper questions on nuclear instability, focusing on 4-6 mark explanations and calculations. Mark your answers using the mark scheme and note recurring errors.
    5. 5Day 9-10: Create a summary sheet with all key equations, decay types, and graph features. Test yourself with active recall prompts and flashcards, then attempt a timed exam-style question under pressure.
    Exam Question Types
    • 📋Nuclear equation completion: You are given a decay equation with a missing particle or daughter nucleus and must balance nucleon and proton numbers. Advice: always check both top and bottom numbers, and remember to include neutrinos/antineutrinos for beta decay.
    • 📋Calculation of activity or number of nuclei after a given time: You may need to find the decay constant from half-life, then use A = A0 e^(-lambda t) or N = N0 e^(-lambda t). Advice: convert all times to seconds and show your working clearly.
    • 📋Explain why a particular nucleus is unstable and predict its decay mode: You must refer to the N-Z graph and the neutron-to-proton ratio. Advice: use precise terms like 'neutron-rich' or 'proton-rich' and link to the specific decay process.
    • 📋Graph interpretation: You may be asked to identify a decay from an N-Z graph or sketch the position of a daughter nucleus. Advice: remember that alpha decay moves the nucleus down and left by 2 protons and 2 neutrons; beta-minus moves it up and left (Z increases by 1, N decreases by 1).
    Command Word Expectations (AQA)
    State

    A brief, factual answer with no explanation required. For example, 'State the type of decay that occurs in a neutron-rich nucleus' expects 'beta-minus decay'.

    Explain

    You must give a reason or mechanism, often linking cause and effect. For example, 'Explain why a proton-rich nucleus undergoes beta-plus decay' requires you to state that the nucleus has too many protons relative to neutrons, and that beta-plus decay converts a proton into a neutron to move towards stability.

    Calculate

    You must show your working, use the correct equation, substitute values with units, and give the final answer to an appropriate number of significant figures with the correct unit.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often write that beta-minus decay involves an electron being emitted from the electron shell rather than from the nucleus, or they fail to include the antineutrino in the decay equation.
    ❌ Weak Answer (Loses Marks):In beta-minus decay, a neutron turns into a proton and an electron is emitted from the atom. The equation is n -> p + e-.
    Example improved answer:In beta-minus decay, a neutron inside the nucleus transforms into a proton, and the nucleus emits an electron and an electron antineutrino. The decay equation is n -> p + e- + anti-nu_e. This increases the proton number by 1 while the nucleon number stays the same, moving the nucleus towards the line of stability on the N-Z graph.
    Examiner Tip: Always state that the electron and antineutrino are emitted from the nucleus, not the electron shells, and include the antineutrino to conserve lepton number. Write the full nuclear equation with mass and charge numbers balanced.
    Pitfall: When calculating activity or number of nuclei remaining after a given time, students frequently use the half-life directly in the decay equation without converting to the decay constant, or they mix up units of time.
    ❌ Weak Answer (Loses Marks):A = A0 e^(-t/half-life). I just put the half-life in the formula.
    Example improved answer:The decay constant lambda is related to half-life by lambda = ln(2) / t_half. Convert the half-life to seconds first, then calculate lambda. Use A = A0 e^(-lambda t) with t in the same time unit as lambda. Alternatively, for whole numbers of half-lives, use A = A0 / 2^n where n = t / t_half.
    Examiner Tip: Always convert half-life to seconds before finding lambda, and check that the time t is in seconds. Show the value of lambda to at least 3 significant figures in your working to avoid rounding errors in the final answer.
    Step-by-Step Worked Solutions

    Question: A radioactive isotope has a half-life of 12.0 days. A sample initially contains 4.8 x 10^20 nuclei. Calculate the number of nuclei remaining after 36.0 days.

    1. 1.Step 1: Identify given facts: half-life t_half = 12.0 days, initial number N0 = 4.8 x 10^20, total time t = 36.0 days.
    2. 2.Step 2: Determine the number of half-lives: n = t / t_half = 36.0 / 12.0 = 3.0 half-lives.
    3. 3.Step 3: Apply the decay equation: N = N0 / 2^n = 4.8 x 10^20 / 2^3 = 4.8 x 10^20 / 8.
    4. 4.Step 4: Calculate final value: N = 6.0 x 10^19 nuclei.
    Final Answer: 6.0 x 10^19 nuclei remain after 36.0 days.

    Question: A nucleus of uranium-238 (Z=92) undergoes alpha decay. Write the nuclear equation and state the resulting element.

    1. 1.Step 1: Write the general alpha decay equation: parent nucleus -> daughter nucleus + alpha particle (4/2 He).
    2. 2.Step 2: Apply conservation of nucleon number: 238 = A + 4, so A = 234.
    3. 3.Step 3: Apply conservation of proton number: 92 = Z + 2, so Z = 90.
    4. 4.Step 4: Identify the element with Z = 90 from the periodic table: thorium (Th).
    5. 5.Step 5: Write the full equation: 238/92 U -> 234/90 Th + 4/2 He.
    Final Answer: 238/92 U -> 234/90 Th + 4/2 He. The resulting element is thorium-234.
    Active Recall Memory Test
    What is the change in nucleon number and proton number for alpha decay?
    Key Fact: Nucleon number decreases by 4, proton number decreases by 2.
    Write the equation relating decay constant to half-life.
    Key Fact: lambda = ln(2) / t_half
    What particle is emitted in beta-plus decay and how does it affect the nucleus?
    Key Fact: A positron and a neutrino are emitted. A proton is converted into a neutron, so the proton number decreases by 1 and the neutron number increases by 1.
    State the equation for activity in terms of the number of undecayed nuclei.
    Key Fact: A = lambda N
    Frequently Asked Questions
    What is nuclear instability in A-level physics?
    Nuclear instability refers to the condition where a nucleus has an imbalance of protons and neutrons, making it unstable and likely to undergo radioactive decay. In AQA A-Level Physics, you study how the neutron-to-proton ratio determines stability, and how alpha, beta and gamma decay change the nucleus to move it towards the line of stability on the N-Z graph. You also learn to write balanced nuclear equations and perform calculations involving activity and half-life.
    How do you know if a nucleus will undergo alpha or beta decay?
    You can predict the decay mode by looking at the position of the nucleus on the N-Z graph relative to the line of stability. If the nucleus is very heavy (A > 200) and has too many protons and neutrons, it is likely to undergo alpha decay, which reduces both numbers. If the nucleus is neutron-rich (above the line), it undergoes beta-minus decay; if it is proton-rich (below the line), it undergoes beta-plus decay or electron capture. Gamma decay often follows alpha or beta decay to release excess energy.
    What is the difference between beta-minus and beta-plus decay?
    In beta-minus decay, a neutron in the nucleus converts into a proton, emitting an electron and an electron antineutrino. This increases the proton number by 1 and decreases the neutron number by 1. In beta-plus decay, a proton converts into a neutron, emitting a positron and an electron neutrino. This decreases the proton number by 1 and increases the neutron number by 1. Both processes conserve nucleon number but change the proton number, moving the nucleus towards stability.
    Why is a neutrino emitted in beta decay?
    A neutrino (or antineutrino) is emitted in beta decay to conserve lepton number and energy. In beta-minus decay, an electron is created along with an antineutrino to conserve lepton number (electron lepton number: 0 = +1 -1). In beta-plus decay, a positron is created along with a neutrino. The neutrino carries away some energy and momentum, which explains the continuous energy spectrum of beta particles observed experimentally.
    How do you calculate the decay constant from half-life?
    The decay constant lambda is related to the half-life t_half by the equation lambda = ln(2) / t_half. First, ensure the half-life is in seconds. Then divide ln(2) (approximately 0.693) by the half-life in seconds to find lambda in s^-1. For example, if the half-life is 12 days, convert to seconds (12 x 24 x 3600 = 1,036,800 s), then lambda = 0.693 / 1,036,800 = 6.68 x 10^-7 s^-1.
    What is the N-Z graph and how is it used in exams?
    The N-Z graph plots neutron number (N) against proton number (Z) for stable and unstable nuclei. Stable nuclei form a band called the line of stability. Nuclei above this line are neutron-rich and undergo beta-minus decay; those below are proton-rich and undergo beta-plus decay or electron capture. In exams, you may be asked to identify the type of decay from a given position on the graph, or to sketch the position of a daughter nucleus after a specified decay. Remember that alpha decay moves the nucleus down and left by 2 protons and 2 neutrons, while beta decay moves it diagonally across the graph.