Power and efficiency — OCR GCSE Physics
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Power and efficiency explained
Efficiency compares the useful energy a device delivers with the total energy supplied to it.
Read the full explanation
The equation is efficiency = useful output energy transfer (J) ÷ input energy transfer (J). Both quantities are energies in joules, so the division gives a number with no unit; multiply by 100 to express it as a percentage. For example, a lamp supplied with 500 J of electrical energy that transfers 100 J as light has efficiency 100 ÷ 500 = 0.20, or 20%. The remaining 400 J is dissipated to the surroundings, usually by heating. Efficiency can never exceed 1 (100%) because a device cannot output more useful energy than it receives. When applying the equation, identify which value is the input and which is the useful output, keep both in joules, and check that the answer is a sensible fraction below 1.
describe, with examples, the process by which energy is dissipated, so that it is stored in less useful ways
Dissipation is the spreading of energy into the surroundings, usually by heating, so that it becomes stored in less useful ways and is harder to recover for a intended purpose. When a device transfers energy, some is always lost to the environment. A filament lamp, for example, transfers most of its electrical input as thermal energy to the air rather than as light; a moving car transfers energy by friction and air resistance, warming the brakes, tyres and surrounding air. In each case the energy is not destroyed but becomes spread out among many particles, raising their temperature slightly. Because it is dispersed over a large area at a low temperature, it is described as stored in a less useful way and cannot easily be harnessed to do useful work again.
describe how, in different domestic devices, energy is transferred from batteries or the a.c. from the mains (to include: how energy may be wasted in the transfer to and within motors and heating devices)
Domestic devices take energy from a battery (chemical store) or from the mains a.c. supply and transfer it to other stores. In a battery torch, chemical energy in the battery becomes electrical transfer along the wires and then light and thermal energy in the bulb; the thermal energy is wasted to the surroundings. In a mains kettle, the a.c. supply drives current through the heating element, transferring energy electrically to the element's thermal store, then to the water; some heats the kettle body and air. In a motor, such as a fan, electrical transfer becomes kinetic energy of the rotating parts, but friction in bearings and resistance heating in the coils waste energy as thermal energy. Identify the input store, the transfer pathway and the useful and wasted output stores for each device.
describe, with examples, the relationship between the power ratings for domestic electrical appliances and how this is linked to the changes in stored energy when they are in use
A power rating tells you the rate at which an appliance transfers energy: a 2000 W kettle transfers 2000 J each second, while a 100 W lamp transfers 100 J each second. The energy transferred equals power multiplied by time, so a higher-rated appliance changes the stored energy of its surroundings faster. A 2 kW kettle switched on for 300 s transfers 2000 × 300 = 600 000 J, heating the water's thermal store; the same kettle for 60 s transfers 120 000 J. Compare appliances by their ratings: a 2500 W heater warms a room faster than a 1000 W heater because it transfers energy at a greater rate. Match each rating to the store that changes, such as thermal energy of water or kinetic energy of a fan, and use E = P × t to compare.
calculate energy efficiency for any energy transfer
Efficiency compares the useful energy delivered by a transfer with the total energy supplied to it. For any transfer, efficiency = useful energy output ÷ total energy input, and multiplying by 100 gives a percentage. A lamp supplied with 500 J of energy that transfers 100 J as light has efficiency 100 ÷ 500 = 0.20, or 20%; the remaining 400 J is dissipated, mainly by heating the surroundings. The same ratio applies to power, so efficiency = useful power output ÷ total power input. Always identify which quantity is useful and which is total before dividing, keep the units consistent, and check that the answer is below 1 (or below 100%).
describe ways to increase efficiency (Higher tier only)
Efficiency rises when a smaller share of the input energy is dissipated, usually as heat to the surroundings. Ways to achieve this include lubricating moving parts so friction transfers less energy to thermal stores, reducing air resistance by streamlining shapes, and insulating or lagging a device so less heat escapes. Improving the design of a machine, such as using bearings or tighter seals, also cuts wasted transfers. Each measure works by reducing the wasted energy for the same useful output, so the ratio of useful output to total input increases. Explain the mechanism, not just the change: state which wasteful transfer is reduced and why efficiency then rises.
explain ways of reducing unwanted energy transfer (to include: lubrication and thermal insulation)
Unwanted energy transfer happens whenever energy moves from a useful store into the surroundings, usually by heating. Lubrication reduces unwanted transfer where surfaces rub: oil or grease between moving parts reduces friction, so less energy is transferred by heating to the parts and surroundings and more stays in the kinetic store of the moving object. Thermal insulation reduces unwanted transfer by conduction, convection and radiation from a warm object such as a house. Materials with low thermal conductivity, trapped air and reflective surfaces slow the rate at which energy passes to the cooler surroundings. In both cases the method works by reducing the rate of transfer, not by creating energy, and the total energy is conserved.
describe how the rate of cooling of a building is affected by the thickness and thermal conductivity of its walls (qualitative only)
A warm building cools because energy is transferred through its walls to the cooler outside. The rate of cooling depends on the walls' thickness and thermal conductivity, treated qualitatively here. A thicker wall slows the rate of energy transfer, so the building cools more slowly. A wall made from a material of lower thermal conductivity, such as one containing trapped air or insulating foam, also slows the transfer and so reduces the cooling rate. Combining greater thickness with lower thermal conductivity gives the slowest cooling. A thin wall of a good conductor lets energy pass quickly, so the building cools fastest. The comparison is about rate, not total energy, and energy is conserved throughout.
Your focus
- State the equation linking efficiency to useful output and input energy transfer.
- Calculate efficiency from given energy values in joules.
- Express an efficiency as a fraction or a percentage and explain why it has no unit.
Show all 24 objectives
- Describe the process of energy dissipation by heating to the surroundings.
- Give examples of devices or processes in which energy is dissipated.
- Explain why dissipated energy is stored in less useful ways.
- Describe how energy is transferred from a battery or the mains a.c. supply in a named domestic device
- Identify the useful output store and the wasted thermal energy for a motor and for a heating device
- Explain why energy is described as wasted rather than destroyed in a transfer
- Describe the relationship between an appliance's power rating and the rate at which it transfers energy
- Use E = P × t to compare the energy transferred by two domestic appliances
- Link a named appliance's rating to the change in a named energy store while it is in use
- Identify the useful energy output and total energy input for a given transfer.
- Calculate efficiency as a fraction and convert it to a percentage.
- Apply the efficiency ratio to power as well as energy.
- Describe measures that reduce wasted energy in a transfer.
- Explain how each measure raises the useful-to-total energy ratio.
- Apply efficiency reasoning to a named device or machine.
- Explain how lubrication reduces unwanted energy transfer by friction between moving surfaces.
- Explain how thermal insulation reduces unwanted energy transfer from a warm object to cooler surroundings.
- Apply the principle of conservation of energy to justify why reducing unwanted transfer keeps energy in useful stores.
- Describe how increasing wall thickness affects the rate of cooling of a building.
- Describe how the thermal conductivity of wall material affects the rate of cooling of a building.
- Compare walls of different thickness and conductivity to identify which gives the slowest rate of cooling.
Power and efficiency exam tips
Marking Points
- Selects the relationship efficiency = useful output energy transfer ÷ input energy transfer.
- Substitutes energies in joules for both the useful output and the input.
- Calculates a value below 1 and, where required, converts it to a percentage by multiplying by 100.
- States that efficiency has no unit because joules divide by joules.
- Describes dissipation as energy spreading to the surroundings, typically by heating.
- Explains that dissipated energy becomes stored in less useful ways and is difficult to recover.
- Gives a relevant example, such as a lamp heating its surroundings or friction warming brakes and air.
- Recognises that total energy is conserved even though useful energy decreases.
- Identifies the battery as a store of chemical energy and the mains a.c. supply as the source of electrical transfer in domestic devices
- Traces the pathway from source through wires or element to the useful output store, such as light in a torch or thermal energy in the water of a kettle
- States that a motor transfers energy electrically to kinetic energy of the moving parts
- Explains that friction in a motor's bearings and resistance heating in its coils waste energy as thermal energy to the surroundings
- Explains that a heating device wastes energy by heating the device body and the surrounding air as well as the intended object
- States that the power rating is the rate at which an appliance transfers energy, measured in watts where 1 W = 1 J/s
- Uses the relationship energy transferred = power × time to compare the energy transferred by two appliances
- Gives an example in which a higher-rated appliance changes a named stored energy faster, such as a 2 kW kettle heating water more quickly than a 1 kW kettle
- Links the energy transferred to a named store that changes, such as thermal energy of water or kinetic energy of a fan
- Calculates the energy transferred correctly for a stated power and time, for example 2000 W × 300 s = 600 000 J
- Selects the useful energy output and the total energy input for the stated transfer before dividing.
- Divides useful energy output by total energy input to give a value between 0 and 1.
- Multiplies the ratio by 100 to express efficiency as a percentage.
- Applies the same ratio to power, dividing useful power output by total power input.
- Keeps units consistent and recognises that efficiency has no unit.
- States that lubricating moving parts reduces friction and so reduces energy dissipated as heat.
- Explains that streamlining reduces air resistance and therefore wasted energy transfer.
- Describes insulation or lagging as reducing heat loss to the surroundings.
- Links each measure to a smaller wasted transfer for the same useful output, raising the useful-to-total ratio.
- Identifies the wasteful transfer reduced and explains why efficiency increases as a result.
- Identifies lubrication as a way of reducing friction between moving surfaces and so reducing energy transferred by heating to the surroundings.
- Identifies thermal insulation as a way of reducing the rate of energy transfer by conduction, convection or radiation from a warm object to cooler surroundings.
- Explains that a lubricant such as oil or grease lowers friction, so less energy is dissipated and more remains in the kinetic store of the moving parts.
- Explains that insulation works by using a material of low thermal conductivity, trapped air or a reflective surface to slow energy transfer to the surroundings.
- States that reducing unwanted transfer does not destroy energy, because total energy is conserved and the energy is simply kept in the intended store for longer.
- States that increasing the thickness of a wall reduces the rate of energy transfer through it, so the building cools more slowly.
- States that using a wall material of lower thermal conductivity reduces the rate of energy transfer, so the building cools more slowly.
- Explains that a thin wall made of a good conductor allows rapid energy transfer, so the building cools fastest.
- Explains that combining greater thickness with lower thermal conductivity gives the slowest rate of cooling.
- Recognises that the comparison concerns the rate of cooling rather than the total energy transferred, which is conserved.
Examiner Tips
- 💡Write the equation down before substituting numbers so the numerator and denominator stay in the right order.
- 💡Convert any answer to a percentage only when the question asks for one, and label it clearly.
- 💡Sanity-check the result: an efficiency above 100% signals the values have been swapped.
- 💡Name a specific device or process and say where the energy goes to secure the example mark.
- 💡Use the phrase 'stored in less useful ways' to match the specification wording.
- 💡Link dissipation to energy conservation to show the energy still exists but is spread out.
- 💡For each device, name the input store, the transfer pathway and the useful and wasted output stores before choosing an option
- 💡Check whether the device is battery-powered or mains-powered, because the source store differs
- 💡Reject any option that says energy is destroyed or used up; energy is always conserved and may be dissipated
- 💡Look for the word 'wasted' and link it to thermal energy transferred to the surroundings
- 💡Convert any time given in minutes to seconds before using E = P × t
- 💡Check the units of the answer and give energy in joules
- 💡Compare two appliances by stating both the rating and the time to decide which transfers more energy
- 💡Name the store that changes so the link between rating and stored energy is explicit
- 💡Write the equation first, then substitute the two values so the useful and total quantities cannot be swapped.
- 💡Convert both energies to the same unit before dividing.
- 💡Sanity-check the answer: a percentage efficiency must lie between 0% and 100%.
- 💡For each measure, name the wasteful transfer it reduces and state the effect on the efficiency ratio.
- 💡Use precise terms such as friction, air resistance and thermal dissipation rather than 'less waste'.
- 💡Give a concrete device example, such as lubricating engine parts or lagging a boiler.
- 💡Link each method to the specific transfer route it reduces: friction for lubrication, conduction, convection or radiation for insulation.
- 💡Use the phrase 'reduces the rate of energy transfer' rather than 'stops energy transfer', because insulation slows rather than halts it.
- 💡Check that the chosen option keeps energy conserved and does not claim energy is created or destroyed.
- 💡Name both variables explicitly in the answer: thickness and thermal conductivity.
- 💡Use comparative language such as 'slower rate of cooling' to match the qualitative demand of the statement.
- 💡Keep the focus on rate of energy transfer rather than on total energy, which stays conserved.
Common Mistakes
- Divides input energy by useful output energy; keep the useful output on top and the input on the bottom.
- Adds a unit such as joules to the efficiency value; treat efficiency as a dimensionless fraction or percentage.
- Uses the wasted energy as the useful output; subtract wasted energy from input to find the useful output first.
- Claims dissipated energy is destroyed; state that it is transferred to the surroundings and stored less usefully.
- Describes dissipation without an example; add a named device or process such as friction or a lamp.
- Says dissipated energy can be fully recovered easily; explain that it is spread out and hard to reuse.
- Treats energy as used up rather than transferred to other stores; state that energy is conserved and dissipated to the surroundings
- Names the battery as a source of electrical energy only; describe it as a chemical store that transfers energy electrically
- Assumes a motor wastes no energy; identify friction and resistance heating as sources of wasted thermal energy
- Claims a kettle transfers all its energy to the water; note that some heats the kettle body and the air
- Confuses power with energy; state that power is the rate of transfer and energy is the total transferred
- Multiplies power by time in the wrong units; convert minutes to seconds before calculating
- Assumes a higher rating always means more total energy; note that a low-rated appliance left on longer can transfer more energy
- Ignores which store changes; name the store, such as thermal energy of the water, that the transfer fills
- Divides total energy input by useful energy output; divide the useful output by the total input instead.
- Adds the wasted energy to the useful energy to find the total; treat the supplied energy as the total input.
- Reports efficiency as a value greater than 1 or 100%; check that the useful output is smaller than the total input.
- Gives efficiency a unit such as joules; state it as a fraction or percentage with no unit.
- Claims a measure increases the total energy input; explain instead that it reduces the wasted output.
- Lists a change such as lubrication without saying which wasteful transfer it reduces; name the friction and heat loss.
- Assumes efficiency can reach 100% in real devices; recognise that some dissipation always remains.
- Confuses increasing power output with increasing efficiency; link the change to the useful-to-total ratio.
- Claims that lubrication adds energy to the moving parts; explain instead that it reduces friction so less energy is dissipated by heating.
- Claims that insulation creates energy or warms the object; explain instead that it slows the rate of energy transfer to the cooler surroundings.
- Treats lubrication and insulation as interchangeable; distinguish friction between moving surfaces from heat transfer through a building's fabric.
- Claims that a thicker wall makes a building cool faster; explain instead that greater thickness slows the rate of energy transfer.
- Confuses thermal conductivity with thickness; treat them as separate factors, where lower conductivity and greater thickness each slow cooling.
- States that insulation stops cooling completely; explain instead that it reduces the rate of cooling.