E9c — AQA GCSE Statistics
Test yourself on E9c with AQA GCSE practice questions.
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Your focus
- Understand the distinction between Spearman’s rank correlation and Pearson’s product moment correlation coefficients.
E9c exam tips
Quick Revision Summary (Key Takeaway)
Standardised scores (z-scores) quantify how many standard deviations a data value lies above or below the mean, enabling objective comparison across different datasets. In AQA GCSE Statistics E9c, mastering the calculation z = (x - mean) / standard deviation is essential for comparing performances and interpreting relative positions in normal distributions.
Topic Overview
AQA GCSE Statistics E9c introduces standardised scores, commonly called z-scores, which provide a unit-free measure of how far a particular value lies from the mean of its distribution. Raw scores are frequently misleading when tests or experiments have differing difficulty levels, different maximum marks, or different degrees of dispersion. Standardising adjusts for both the central tendency and the spread.
By transforming raw data into standardised scores, students can make statistically valid comparisons between completely different datasets, such as performances in distinct academic subjects or sporting events. This topic bridges descriptive statistics and continuous probability distributions, consolidating understanding of the mean, standard deviation, and normal distribution properties.
Key Concepts
- →Standardised score formula: z = (x - mean) / standard deviation, where x is the observed value.
- →A standardised score has a mean of 0 and a standard deviation of 1 across any standardised dataset.
- →A positive z-score indicates a value above the mean, zero indicates a value equal to the mean, and a negative z-score indicates a value below the mean.
- →Standardised scores allow fair comparisons between datasets having different units, means, or standard deviations.
- →Context determines whether a higher or lower standardised score is preferable (e.g., higher is better for exam marks, lower is better for race times or golf scores).
Examiner Tips
- 💡Always quote both calculated standardised scores explicitly before making your comparative statement.
- 💡Include the sign (+ or -) when writing z-scores to demonstrate a clear understanding of direction relative to the mean.
- 💡Read the question context carefully to verify whether 'better' corresponds to an above-average score or a below-average score.
Common Mistakes
- Assuming higher z-scores are always 'better': In contexts where lower numeric values are advantageous (such as running times, golf scores, or reaction times), a negative z-score represents a superior performance.
- Comparing raw marks directly instead of calculating z-scores: Students often evaluate absolute scores without accounting for variations in test difficulty and spread.
- Subtracting in the wrong order: Calculating (mean - x) / standard deviation instead of (x - mean) / standard deviation inverts the sign, wrongly turning above-average results into negative scores.
Revision Plan
- 1Day 1-3: Memorise the standardised score formula and practice forward calculations to find z given x, mean, and standard deviation.
- 2Day 4-6: Practice reverse calculations where you rearrange the formula to find the raw score x given z, mean, and standard deviation.
- 3Day 7-9: Solve comparative exam-style questions involving two different subjects or competitions, paying special attention to contextual phrasing.
- 4Day 10-12: Work through past AQA exam questions that invert the meaning of 'better' (such as sprint times or defect counts) to solidify contextual interpretation.
Exam Question Types
- 📋Direct comparative questions: Comparing two individuals or two subject scores to determine who performed better relatively.
- 📋Reverse calculation questions: Given a z-score alongside the mean and standard deviation, finding the original raw score.
- 📋Contextual interpretation questions: Explaining what a specific z-score (e.g. z = -2.1) means in the context of quality control or athletic trials.
Command Word Expectations (AQA)
Show clear mathematical substitution into the standardised score formula and state the resulting numerical z-score clearly.
Calculate standardised scores for both scenarios, explicitly state which value is greater, and conclude what this means within the given real-world context.
Explain the practical meaning of the calculated z-score referring to the specific units, direction from the mean, and contextual significance.
How Students Lose Marks (Examiner Pitfalls)
Step-by-Step Worked Solutions
Question: In a school assessment, Priya scores 74 in Biology where the mean is 62 with a standard deviation of 8. In Chemistry, she scores 78 where the mean is 70 with a standard deviation of 6. Calculate Priya's standardised score for each subject and determine in which subject she achieved the better relative performance.
- 1.Step 1: Identify the values for Biology: raw score x = 74, mean = 62, standard deviation = 8.
- 2.Step 2: Calculate the Biology standardised score: z_Biology = (74 - 62) / 8 = 12 / 8 = +1.5.
- 3.Step 3: Identify the values for Chemistry: raw score x = 78, mean = 70, standard deviation = 6.
- 4.Step 4: Calculate the Chemistry standardised score: z_Chemistry = (78 - 70) / 6 = 8 / 6 = +1.33 (to 2 d.p.).
- 5.Step 5: Compare the two standardised scores: +1.5 > +1.33. Formulate a final concluding sentence in context.
Question: The running times of athletes in a 10 km race follow a distribution with mean 48 minutes and standard deviation 5 minutes. Alex records a standardised score of -1.4. In a running race, a lower time indicates a faster performance. Calculate Alex's actual race time and interpret what his standardised score indicates about his performance relative to other runners.
- 1.Step 1: State the standardised score formula: z = (x - mean) / standard deviation.
- 2.Step 2: Substitute the known values: -1.4 = (x - 48) / 5.
- 3.Step 3: Rearrange to solve for x: x - 48 = -1.4 * 5 = -7.
- 4.Step 4: Add 48 to both sides: x = 48 - 7 = 41 minutes.
- 5.Step 5: Contextual interpretation: Because lower times represent better performance in races, being 1.4 standard deviations below the mean time represents an above-average performance.