AQA · GCSE · Chemistry

    Course version: 8462 · Version from Sept 2018

    Students should be able to interpret data for relative reactivity of…

    Full specification wording

    Cells and batteries: Students should be able to interpret data for relative reactivity of different metals and evaluate the use of cells.

    The voltage of a simple cell depends on the difference in reactivity between its two electrodes.

    Checked against the AQA 8462 specification (opens in a new tab) on .

    • Point 7 of 7

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    The voltage of a simple cell depends on the difference in reactivity between its two electrodes. A more reactive metal and a less reactive metal in an electrolyte give a larger voltage than two metals close in the reactivity series. For example, a cell with magnesium and copper gives a higher voltage than one with zinc and copper because magnesium is further from copper in the series. Evaluating the use of cells means weighing practical factors such as voltage, cost, lifetime, rechargeability and environmental impact to judge which cell suits a device.

    What earns the marks

    • The voltage of a cell depends on the difference in reactivity of the two electrode metals.
    • A greater difference in reactivity generally gives a greater cell voltage.
    • Data tables or graphs can be used to compare voltages for different metal pairs.
    • The reactivity series helps explain and predict the pattern in the data.
    • Evaluating cells involves considering voltage, cost, lifetime, rechargeability and environmental impact.
    • A justified choice of cell links the device's needs to the cell's properties.

    Common mistakes and how to put them right

    • Assuming the most reactive metal alone gives the highest voltage.

      Put it right by comparing the difference between the two metals.

    • Ignoring the electrolyte when interpreting data.

      Put it right by noting that the electrolyte is part of the cell and affects its behaviour.

    • Choosing a cell only on voltage.

      Put it right: Also considering cost, lifetime, rechargeability and environmental impact.

    Exam tips

    • Quote values from the data table when comparing voltages.
    • Use the reactivity series to explain why one pair gives a higher voltage than another.
    • When evaluating, give a balanced judgement with at least one advantage and one disadvantage.

    Try the lesson

    The start of the Cells and batteries: Students should be able to interpret data for relative reactivity of different metals and evaluate the use of cells. lesson, made from checked teaching notes for this specification point.

    Have a go first

    A student measures the voltage of simple cells using a copper electrode and an electrode of another metal in an electrolyte. The voltages are: metal W and copper = 0.4 V; metal X and copper = 1.1 V; metal Y and copper = 2.7 V; metal Z and copper = 0.9 V. Assuming copper is the least reactive metal in all pairs, which metal is the most reactive?

    Listen

    The voltage of a simple cell depends on the difference in reactivity between its two electrodes. A more reactive metal and a less reactive metal in an electrolyte give a larger voltage than two metals close in the reactivity series. For example, a cell with magnesium and copper gives a higher voltage than one with zinc and copper because magnesium is further from copper in the series. Evaluating the use of cells means weighing practical factors such as voltage, cost, lifetime, rechargeability and environmental impact to judge which cell suits a device. A strong answer earns marks for these points. The voltage of a cell depends on the difference in reactivity of the two electrode metals. A greater difference in reactivity generally gives a greater cell voltage. Data tables or graphs can be used to compare voltages for different metal pairs. The reactivity series helps explain and predict the pattern in the data. A common slip: Assuming the most reactive metal alone gives the highest voltage. Instead, comparing the difference between the two metals. Exam tip: Quote values from the data table when comparing voltages.

    See it

    A top-down flowchart. It starts with a node labelled 'Two electrode metals in an electrolyte', which leads to 'Difference in reactivity between the two metals'. This splits into two branches: 'Greater difference in reactivity' leading to 'Greater cell voltage', and 'Smaller difference in reactivity' leading to 'Smaller cell voltage'. Both voltage nodes lead to 'Compare voltages using data tables or graphs', which leads to 'Use the reactivity series to explain the pattern'. That leads to 'Evaluate the cell: voltage, cost, lifetime, rechargeability, environmental impact', which finally leads to 'Justified choice of cell for the device's needs'.
    This flowchart shows how the difference in reactivity between two electrode metals leads to a cell voltage, how data and the reactivity series explain the pattern, and how cells are then evaluated for a device.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. It starts with a node labelled 'Two electrode metals in an electrolyte', which leads to 'Difference in reactivity between the two metals'. This splits into two branches: 'Greater difference in reactivity' leading to 'Greater cell voltage', and 'Smaller difference in reactivity' leading to 'Smaller cell voltage'. Both voltage nodes lead to 'Compare voltages using data tables or graphs', which leads to 'Use the reactivity series to explain the pattern'. That leads to 'Evaluate the cell: voltage, cost, lifetime, rechargeability, environmental impact', which finally leads to 'Justified choice of cell for the device's needs'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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