AQA · GCSE · Combined Science

    Course version: 8464 · Version from Sept 2018

    Acceleration: The following equation applies to uniform acceleration:

    This statement introduces the condition for using the kinematic equation v² − u² = 2 × a × s: acceleration must be uniform, meaning it stays constant in magnitude and direction throughout the motion.

    Checked against the AQA 8464 specification (opens in a new tab) on .

    • Point 15 of 21

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    This statement introduces the condition for using the kinematic equation v² − u² = 2 × a × s: acceleration must be uniform, meaning it stays constant in magnitude and direction throughout the motion. Uniform acceleration produces a straight-line velocity–time graph, so the gradient is constant. For example, a ball rolling down a smooth slope may be modelled as uniform acceleration, but a car in stop-start traffic is not. When acceleration is uniform, average velocity is (u + v) / 2 and distance is that average multiplied by time. If acceleration changes, the equation cannot be applied directly; the motion must be split into stages or a graph used. Recognising this condition is part of choosing the correct equation.

    What earns the marks

    • Define uniform acceleration as constant acceleration in magnitude and direction, giving a straight-line velocity–time graph.
    • Explain that v² − u² = 2 × a × s is valid only when acceleration is uniform, and state what happens if it is not.
    • Use the gradient of a velocity–time graph to check whether acceleration is constant before selecting the equation.
    • Apply the equation to a described uniform-acceleration stage, such as a vehicle braking steadily or a trolley accelerating down a ramp.
    • Recognise that average velocity (u + v) / 2 can be used only for uniform acceleration, linking this to distance = average velocity × time.

    Common mistakes and how to put them right

    • Assuming any motion with changing speed has uniform acceleration.

      Put it right: Uniform acceleration requires a constant rate of change of velocity, shown by a straight velocity–time line.

    • Using v² − u² = 2 × a × s for a whole journey that includes different acceleration stages.

      Put it right: Split the journey into stages where acceleration is uniform.

    • Confusing uniform acceleration with constant speed.

      Put it right: Constant speed means a = 0, while uniform acceleration means a is constant and non-zero.

    Exam tips

    • Look for words such as steadily, uniformly or constant acceleration in the question before using the equation.
    • Sketch a velocity–time graph to confirm the gradient is constant; this justifies your choice of equation.
    • If acceleration changes, state that the equation applies only to each uniform stage and calculate stage by stage.

    Try the lesson

    The start of the Acceleration: The following equation applies to uniform acceleration: lesson, made from checked teaching notes for this specification point.

    Have a go first

    A cyclist accelerates uniformly from rest at a rate of 2 m/s². What is the final velocity of the cyclist after travelling a distance of 9 m?

    Listen

    This statement introduces the condition for using the kinematic equation v² − u² = 2 × a × s: acceleration must be uniform, meaning it stays constant in magnitude and direction throughout the motion. Uniform acceleration produces a straight-line velocity–time graph, so the gradient is constant. For example, a ball rolling down a smooth slope may be modelled as uniform acceleration, but a car in stop-start traffic is not. When acceleration is uniform, average velocity is (u + v) / 2 and distance is that average multiplied by time. If acceleration changes, the equation cannot be applied directly; the motion must be split into stages or a graph used. Recognising this condition is part of choosing the correct equation. A strong answer earns marks for these points. Define uniform acceleration as constant acceleration in magnitude and direction, giving a straight-line velocity–time graph. Explain that v² − u² = 2 × a × s is valid only when acceleration is uniform, and state what happens if it is not. Use the gradient of a velocity–time graph to check whether acceleration is constant before selecting the equation. Apply the equation to a described uniform-acceleration stage, such as a vehicle braking steadily or a trolley accelerating down a ramp. A common slip: Assuming any motion with changing speed has uniform acceleration. Instead, uniform acceleration requires a constant rate of change of velocity, shown by a straight velocity–time line. Exam tip: Look for words such as steadily, uniformly or constant acceleration in the question before using the equation.

    See it

    A flowchart starting from 'Motion described' leading to the question 'Is acceleration constant in magnitude and direction?'. The 'Yes' branch goes to 'Uniform acceleration', which leads to three outcomes: 'Velocity–time graph is a straight line', 'v² − u² = 2 × a × s can be used', and 'Average velocity = (u + v) / 2', the last of which leads on to 'Distance = average velocity × time'. The 'No' branch goes to 'Acceleration not uniform', then to 'Equation cannot be applied directly', then to 'Split motion into stages or use a graph'.
    It shows how to decide whether acceleration is uniform, what follows if it is, and what to do if it is not.

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