AQA · GCSE · Combined Science

    Course version: 8464 · Version from Sept 2018

    (HT only) Students should understand and use inverse proportion – the…

    Full specification wording

    Rate of photosynthesis: (HT only) Students should understand and use inverse proportion – the inverse square law and light intensity in the context of photosynthesis.

    Light intensity decreases with distance from a lamp.

    Checked against the AQA 8464 specification (opens in a new tab) on .

    • Point 8 of 10
    • 3 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Light intensity decreases with distance from a lamp. The inverse square law states that intensity is inversely proportional to the square of the distance: intensity ∝ 1 ÷ distance². If distance doubles, intensity falls to one quarter; if distance trebles, intensity falls to one ninth. In photosynthesis, rate increases with light intensity until another factor limits. To use the law, measure distance from lamp to pondweed, calculate 1 ÷ d², and plot rate against this value; a straight line through the origin shows rate is proportional to light intensity. This explains why moving a lamp further away sharply reduces the rate.

    What earns the marks

    • State that light intensity is inversely proportional to the square of the distance from the light source.
    • Use the relationship intensity ∝ 1 ÷ distance² to calculate relative intensity at different distances.
    • Explain that doubling the distance reduces light intensity to one quarter of its original value.
    • Describe how to plot rate of photosynthesis against 1 ÷ distance² to test whether light intensity limits the rate.
    • Interpret a straight line through the origin on a rate against 1 ÷ distance² graph as evidence that rate is proportional to light intensity.

    Common mistakes and how to put them right

    • Using intensity ∝ 1 ÷ distance instead of 1 ÷ distance².

      Put it right by squaring the distance before dividing.

    • Thinking doubling distance halves intensity.

      Put it right by stating intensity becomes one quarter.

    • Plotting rate against distance and expecting a straight line.

      Put it right by plotting against 1 ÷ distance² to linearise the relationship.

    Exam tips

    • Write the relationship as intensity ∝ 1 ÷ d² and show the substitution clearly when calculating.
    • As this is Higher Tier only, when explaining a graph, state that a straight line through the origin supports proportionality between rate and light intensity.

    Try the lesson

    The start of the Rate of photosynthesis: (HT only) Students should understand and use inverse proportion – the inverse square law and light intensity in the context of photosynthesis. lesson, made from checked teaching notes for this specification point.

    Have a go first

    A lamp is moved so that its distance from a plant is doubled. According to the inverse square law, what happens to the light intensity at the plant?

    Listen

    Light intensity decreases with distance from a lamp. The inverse square law states that intensity is inversely proportional to the square of the distance: intensity ∝ 1 ÷ distance². If distance doubles, intensity falls to one quarter; if distance trebles, intensity falls to one ninth. In photosynthesis, rate increases with light intensity until another factor limits. To use the law, measure distance from lamp to pondweed, calculate 1 ÷ d², and plot rate against this value; a straight line through the origin shows rate is proportional to light intensity. This explains why moving a lamp further away sharply reduces the rate. A strong answer earns marks for these points. State that light intensity is inversely proportional to the square of the distance from the light source. Use the relationship intensity ∝ 1 ÷ distance² to calculate relative intensity at different distances. Explain that doubling the distance reduces light intensity to one quarter of its original value. Describe how to plot rate of photosynthesis against 1 ÷ distance² to test whether light intensity limits the rate. A common slip: Using intensity ∝ 1 ÷ distance instead of 1 ÷ distance². Instead, squaring the distance before dividing. Exam tip: Write the relationship as intensity ∝ 1 ÷ d² and show the substitution clearly when calculating.

    See it

    A flowchart running from top to bottom. The first box reads 'Distance from lamp to pondweed' and points to a box reading 'Calculate 1 ÷ distance²'. That points to 'Relative light intensity', which points to 'Rate of photosynthesis'. That points to 'Plot rate against 1 ÷ distance²', which points to 'Straight line through the origin', which finally points to 'Rate is proportional to light intensity'.
    It shows how distance from the lamp gives 1 ÷ distance², which gives light intensity and rate of photosynthesis, and how plotting rate against 1 ÷ distance² gives a straight line through the origin showing proportionality.

    Put it in order

    Put these steps in the order they happen.

    1. 1. Rate is proportional to light intensity
    2. 2. Straight line through the origin
    3. 3. Relative light intensity
    4. 4. Plot rate against 1 ÷ distance²
    5. 5. Distance from lamp to pondweed
    6. 6. Calculate 1 ÷ distance²
    7. 7. Rate of photosynthesis

    Key words

    Say what each word means before you turn the card.

    Inverse square law

    Try answering aloud or in your head before turning the card.

    Light intensity and distance

    Try answering aloud or in your head before turning the card.

    Proportionality

    Try answering aloud or in your head before turning the card.

    See every definition
    Inverse square law
    Light intensity is inversely proportional to the square of the distance from the light source.
    Light intensity and distance
    Light intensity decreases with distance from a lamp, and doubling the distance reduces light intensity to one quarter of its original value.
    Proportionality
    A straight line through the origin on a rate against 1 ÷ distance² graph shows rate is proportional to light intensity.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A flowchart running from top to bottom. The first box reads 'Distance from lamp to pondweed' and points to a box reading 'Calculate 1 ÷ distance²'. That points to 'Relative light intensity', which points to 'Rate of photosynthesis'. That points to 'Plot rate against 1 ÷ distance²', which points to 'Straight line through the origin', which finally points to 'Rate is proportional to light intensity'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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