AQA · GCSE · Physics

    Course version: 8463 · Version from Sept 2016

    The greater the speed of a vehicle the greater the braking force needed to…

    Full specification wording

    Factors affecting braking distance 2: The greater the speed of a vehicle the greater the braking force needed to stop the vehicle in a certain distance.

    A vehicle's kinetic energy is ½ m v², so speed matters far more than anything else in the equation.

    Checked against the AQA 8463 specification (opens in a new tab) on .

    • Point 2 of 5
    • 3 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    A vehicle's kinetic energy is ½ m v², so speed matters far more than anything else in the equation. The brakes must do work equal to that energy: braking force × braking distance = ½ m v². Fixing the distance and rearranging gives F = ½ m v² ÷ d, which shows the force needed rises with the square of the speed. A 1200 kg car stopping in 30 m from 15 m/s needs 1200 × 15² ÷ (2 × 30) = 4500 N; from 30 m/s in the same 30 m it needs 18 000 N, four times as much. Real brakes and tyres cannot supply an unlimited force, which is why the distance stretches instead at higher speeds. It is also why a modest speed limit matters: dropping from 30 m/s to 20 m/s removes more than half the kinetic energy the brakes must deal with.

    What earns the marks

    • Stating that the kinetic energy is greater at the greater speed.
    • Using ½ m v² to show that doubling the speed quadruples the kinetic energy.
    • Equating work done, force × distance, to the kinetic energy.
    • Concluding that the braking force must be four times larger for the same braking distance.

    Common mistakes and how to put them right

    • Saying the required force doubles when the speed doubles.

    • Leaving the mass out of the kinetic energy calculation.

    • Substituting the stopping distance rather than the braking distance.

    • Rearranging F = ½ m v² ÷ d incorrectly and dividing by the speed instead.

    Exam tips

    • Square the speed before you multiply by the mass; doing it in the other order invites slips.
    • Quote the ratio as well as the number: 'four times the force' makes the physics visible.
    • Check the distance in the question is the braking distance, not the total stopping distance.

    Try the lesson

    The start of the Factors affecting braking distance 2: The greater the speed of a vehicle the greater the braking force needed to stop the vehicle in a certain distance. lesson, made from checked teaching notes for this specification point.

    Have a go first

    A lorry and a car have the same mass. The lorry is travelling at twice the speed of the car. Both are stopped in the same distance. The braking force on the car is F. What is the braking force needed on the lorry?

    Listen

    A vehicle's kinetic energy is ½ m v², so speed matters far more than anything else in the equation. The brakes must do work equal to that energy: braking force × braking distance = ½ m v². Fixing the distance and rearranging gives F = ½ m v² ÷ d, which shows the force needed rises with the square of the speed. A 1200 kg car stopping in 30 m from 15 m/s needs 1200 × 15² ÷ (2 × 30) = 4500 N; from 30 m/s in the same 30 m it needs 18 000 N, four times as much. Real brakes and tyres cannot supply an unlimited force, which is why the distance stretches instead at higher speeds. It is also why a modest speed limit matters: dropping from 30 m/s to 20 m/s removes more than half the kinetic energy the brakes must deal with. A strong answer earns marks for these points. stating that the kinetic energy is greater at the greater speed. using ½ m v² to show that doubling the speed quadruples the kinetic energy. equating work done, force × distance, to the kinetic energy. concluding that the braking force must be four times larger for the same braking distance. Exam tip: Square the speed before you multiply by the mass; doing it in the other order invites slips.

    See it

    A top-down flowchart. A node labelled 'Speed of vehicle' points to 'Kinetic energy ½ m v²', which points to 'Work done by brakes = force × braking distance', which points to 'Braking force needed'. The speed node also points separately to 'Doubling the speed', which points to 'Quadruples the kinetic energy', which points to 'Four times the braking force for the same distance'. The 'Braking force needed' node points to 'Brakes and tyres cannot supply unlimited force', which points to 'Distance stretches at higher speeds'.
    Shows how a vehicle's speed sets its kinetic energy, which the brakes must remove as work, so doubling the speed quadruples the braking force needed over the same distance.

    Key words

    Say what each word means before you turn the card.

    kinetic energy

    Try answering aloud or in your head before turning the card.

    braking force

    Try answering aloud or in your head before turning the card.

    work done

    Try answering aloud or in your head before turning the card.

    See every definition
    kinetic energy
    Given by ½ m v², so the greater the speed of a vehicle the greater this is.
    braking force
    The force the brakes must supply, equal to the work done divided by the braking distance.
    work done
    Equal to braking force × braking distance, and must equal the kinetic energy of the vehicle.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. A node labelled 'Speed of vehicle' points to 'Kinetic energy ½ m v²', which points to 'Work done by brakes = force × braking distance', which points to 'Braking force needed'. The speed node also points separately to 'Doubling the speed', which points to 'Quadruples the kinetic energy', which points to 'Four times the braking force for the same distance'. The 'Braking force needed' node points to 'Brakes and tyres cannot supply unlimited force', which points to 'Distance stretches at higher speeds'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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