OCR · A-Level · Physics
Course version: H556 · Version from Sept 2015
(i) e.m.f. = − rate of change of magnetic flux linkage; ( ) E t N T T z =-
Full specification wording
Electromagnetism: (i) e.m.f. = − rate of change of magnetic flux linkage; ( ) E t N T T z =-
This statement gives the quantitative form of Faraday's law: the induced e.m.f.
Checked against the OCR H556 specification (opens in a new tab) on .
- Point 4 of 8
- 3 key terms
Study notes
From the checked teaching notes for this specification point.
The idea
This statement gives the quantitative form of Faraday's law: the induced e.m.f. E equals the negative rate of change of magnetic flux linkage, E = −N ΔΦ/Δt, where N is the number of turns, ΔΦ is the change in flux through one turn in webers and Δt is the time interval in seconds. The negative sign expresses Lenz's law. For a 200-turn coil in which flux through each turn falls from 4.0 × 10⁻³ Wb to zero in 0.050 s, ΔΦ/Δt = −8.0 × 10⁻² Wb s⁻¹, so E = −200 × (−8.0 × 10⁻²) = 16 V. The unit check is Wb s⁻¹ = V.
What earns the marks
- The induced e.m.f. is given by E = −N ΔΦ/Δt, the negative rate of change of magnetic flux linkage.
- N is the number of turns, ΔΦ is the change in flux through one turn in webers and Δt is the time interval in seconds.
- The unit of ΔΦ/Δt is Wb s⁻¹, which is equivalent to the volt.
- The negative sign represents Lenz's law: the induced e.m.f. opposes the change in flux linkage.
- Worked check: N = 200, ΔΦ = −4.0 × 10⁻³ Wb, Δt = 0.050 s gives E = −200 × (−4.0 × 10⁻³ ÷ 0.050) = 16 V.
Common mistakes and how to put them right
Using the total flux linkage change without dividing by the time interval.
Put it right: e.m.f. is a rate of change, so divide Δ(NΦ) by Δt.
Forgetting to multiply the flux change per turn by the number of turns N.
Put it right: Use the change in flux linkage NΔΦ.
Dropping the negative sign when the direction of the induced e.m.f. is required.
Put it right: Keep the sign to represent Lenz's law.
Exam tips
- Write E = −N ΔΦ/Δt and identify N, ΔΦ and Δt before substituting numerical values.
- Check units: flux in webers, time in seconds, e.m.f. in volts.
- Use the sign of ΔΦ to decide the direction of the induced e.m.f. and state that it opposes the change.
Try the lesson
The start of the Electromagnetism: (i) e.m.f. = − rate of change of magnetic flux linkage; ( ) E t N T T z =- lesson, made from checked teaching notes for this specification point.
Listen
This statement gives the quantitative form of Faraday's law: the induced e.m.f. E equals the negative rate of change of magnetic flux linkage, E = −N ΔΦ/Δt, where N is the number of turns, ΔΦ is the change in flux through one turn in webers and Δt is the time interval in seconds. The negative sign expresses Lenz's law. For a 200-turn coil in which flux through each turn falls from 4.0 × 10⁻³ Wb to zero in 0.050 s, ΔΦ/Δt = −8.0 × 10⁻² Wb s⁻¹, so E = −200 × (−8.0 × 10⁻²) = 16 V. The unit check is Wb s⁻¹ = V. A strong answer earns marks for these points. The induced e.m.f. is given by E = −N ΔΦ/Δt, the negative rate of change of magnetic flux linkage. N is the number of turns, ΔΦ is the change in flux through one turn in webers and Δt is the time interval in seconds. The unit of ΔΦ/Δt is Wb s⁻¹, which is equivalent to the volt. The negative sign represents Lenz's law: the induced e.m.f. opposes the change in flux linkage. A common slip: Using the total flux linkage change without dividing by the time interval. Instead, e.m.f. is a rate of change, so divide Δ(NΦ) by Δt. Exam tip: Write E = −N ΔΦ/Δt and identify N, ΔΦ and Δt before substituting numerical values.
See it
Key words
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Quantitative form of Faraday's law
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Lenz's law and the negative sign
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Unit consistency: Wb s⁻¹ equals V
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See every definition
- Quantitative form of Faraday's law
- The induced e.m.f. E equals the negative rate of change of magnetic flux linkage, E = −N ΔΦ/Δt.
- Lenz's law and the negative sign
- The negative sign represents Lenz's law: the induced e.m.f. opposes the change in flux linkage.
- Unit consistency: Wb s⁻¹ equals V
- The unit of ΔΦ/Δt is Wb s⁻¹, which is equivalent to the volt.
Label the diagram
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