OCR · A-Level · Physics

    Course version: H556 · Version from Sept 2015

    (i) e.m.f. = − rate of change of magnetic flux linkage; ( ) E t N T T z =-

    Full specification wording

    Electromagnetism: (i) e.m.f. = − rate of change of magnetic flux linkage; ( ) E t N T T z =-

    This statement gives the quantitative form of Faraday's law: the induced e.m.f.

    Checked against the OCR H556 specification (opens in a new tab) on .

    • Point 4 of 8
    • 3 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    This statement gives the quantitative form of Faraday's law: the induced e.m.f. E equals the negative rate of change of magnetic flux linkage, E = −N ΔΦ/Δt, where N is the number of turns, ΔΦ is the change in flux through one turn in webers and Δt is the time interval in seconds. The negative sign expresses Lenz's law. For a 200-turn coil in which flux through each turn falls from 4.0 × 10⁻³ Wb to zero in 0.050 s, ΔΦ/Δt = −8.0 × 10⁻² Wb s⁻¹, so E = −200 × (−8.0 × 10⁻²) = 16 V. The unit check is Wb s⁻¹ = V.

    What earns the marks

    • The induced e.m.f. is given by E = −N ΔΦ/Δt, the negative rate of change of magnetic flux linkage.
    • N is the number of turns, ΔΦ is the change in flux through one turn in webers and Δt is the time interval in seconds.
    • The unit of ΔΦ/Δt is Wb s⁻¹, which is equivalent to the volt.
    • The negative sign represents Lenz's law: the induced e.m.f. opposes the change in flux linkage.
    • Worked check: N = 200, ΔΦ = −4.0 × 10⁻³ Wb, Δt = 0.050 s gives E = −200 × (−4.0 × 10⁻³ ÷ 0.050) = 16 V.

    Common mistakes and how to put them right

    • Using the total flux linkage change without dividing by the time interval.

      Put it right: e.m.f. is a rate of change, so divide Δ(NΦ) by Δt.

    • Forgetting to multiply the flux change per turn by the number of turns N.

      Put it right: Use the change in flux linkage NΔΦ.

    • Dropping the negative sign when the direction of the induced e.m.f. is required.

      Put it right: Keep the sign to represent Lenz's law.

    Exam tips

    • Write E = −N ΔΦ/Δt and identify N, ΔΦ and Δt before substituting numerical values.
    • Check units: flux in webers, time in seconds, e.m.f. in volts.
    • Use the sign of ΔΦ to decide the direction of the induced e.m.f. and state that it opposes the change.

    Try the lesson

    The start of the Electromagnetism: (i) e.m.f. = − rate of change of magnetic flux linkage; ( ) E t N T T z =- lesson, made from checked teaching notes for this specification point.

    Listen

    This statement gives the quantitative form of Faraday's law: the induced e.m.f. E equals the negative rate of change of magnetic flux linkage, E = −N ΔΦ/Δt, where N is the number of turns, ΔΦ is the change in flux through one turn in webers and Δt is the time interval in seconds. The negative sign expresses Lenz's law. For a 200-turn coil in which flux through each turn falls from 4.0 × 10⁻³ Wb to zero in 0.050 s, ΔΦ/Δt = −8.0 × 10⁻² Wb s⁻¹, so E = −200 × (−8.0 × 10⁻²) = 16 V. The unit check is Wb s⁻¹ = V. A strong answer earns marks for these points. The induced e.m.f. is given by E = −N ΔΦ/Δt, the negative rate of change of magnetic flux linkage. N is the number of turns, ΔΦ is the change in flux through one turn in webers and Δt is the time interval in seconds. The unit of ΔΦ/Δt is Wb s⁻¹, which is equivalent to the volt. The negative sign represents Lenz's law: the induced e.m.f. opposes the change in flux linkage. A common slip: Using the total flux linkage change without dividing by the time interval. Instead, e.m.f. is a rate of change, so divide Δ(NΦ) by Δt. Exam tip: Write E = −N ΔΦ/Δt and identify N, ΔΦ and Δt before substituting numerical values.

    See it

    A flowchart with three inputs feeding one equation. The top input is labelled N = number of turns, the middle input is labelled ΔΦ = change in flux through one turn (Wb), and the bottom input is labelled Δt = time interval (s). All three arrows lead to a central node labelled E = −N ΔΦ/Δt. From this central node three arrows lead to three separate nodes: one labelled Negative sign represents Lenz's law: induced e.m.f. opposes the change in flux linkage; one labelled Unit check: ΔΦ/Δt in Wb s⁻¹ = V; and one labelled Worked check: N = 200, ΔΦ = −4.0 × 10⁻³ Wb, Δt = 0.050 s gives E = 16 V.
    It shows how the number of turns, the change in flux through one turn and the time interval combine in E = −N ΔΦ/Δt, with the meaning of the negative sign, the unit check and the worked check.

    Key words

    Say what each word means before you turn the card.

    Quantitative form of Faraday's law

    Try answering aloud or in your head before turning the card.

    Lenz's law and the negative sign

    Try answering aloud or in your head before turning the card.

    Unit consistency: Wb s⁻¹ equals V

    Try answering aloud or in your head before turning the card.

    See every definition
    Quantitative form of Faraday's law
    The induced e.m.f. E equals the negative rate of change of magnetic flux linkage, E = −N ΔΦ/Δt.
    Lenz's law and the negative sign
    The negative sign represents Lenz's law: the induced e.m.f. opposes the change in flux linkage.
    Unit consistency: Wb s⁻¹ equals V
    The unit of ΔΦ/Δt is Wb s⁻¹, which is equivalent to the volt.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A flowchart with three inputs feeding one equation. The top input is labelled N = number of turns, the middle input is labelled ΔΦ = change in flux through one turn (Wb), and the bottom input is labelled Δt = time interval (s). All three arrows lead to a central node labelled E = −N ΔΦ/Δt. From this central node three arrows lead to three separate nodes: one labelled Negative sign represents Lenz's law: induced e.m.f. opposes the change in flux linkage; one labelled Unit check: ΔΦ/Δt in Wb s⁻¹ = V; and one labelled Worked check: N = 200, ΔΦ = −4.0 × 10⁻³ Wb, Δt = 0.050 s gives E = 16 V.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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