OCR · A-Level · Physics

    Course version: H556 · Version from Sept 2015

    (b) I = Anev , where n is the number density of charge carriers

    Full specification wording

    Mean drift velocity: (b) I = Anev , where n is the number density of charge carriers

    This equation links current to the microscopic motion of charge carriers.

    Checked against the OCR H556 specification (opens in a new tab) on .

    • Point 2 of 3
    • 2 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    This equation links current to the microscopic motion of charge carriers. I is the current in amperes, A is the cross-sectional area of the conductor in m², n is the number density of charge carriers (number per m³), e is the elementary charge 1.60 × 10⁻¹⁹ C, and v is the mean drift velocity in m s⁻¹. Rearranged, v = I / (Ane). A useful check is that Anev has units m² × m⁻³ × C × m s⁻¹ = C s⁻¹ = A. In a multiple-choice question you may be asked to find v, n or A, or to predict how v changes when A doubles at constant current: v halves. Remember n is a number density, not a mass density, and e is the charge on one carrier, not the total charge.

    What earns the marks

    • States I = Anev and identifies each symbol with its unit: I in A, A in m², n in m⁻³, e in C, v in m s⁻¹.
    • Rearranges correctly to v = I / (Ane) or n = I / (Aev) as required by the question.
    • Uses e = 1.60 × 10⁻¹⁹ C for electrons or the appropriate carrier charge for ions.
    • Applies proportionality reasoning, for example at constant I, doubling A halves v because v ∝ 1/A.
    • Checks that the product Anev has units of current, confirming dimensional consistency.

    Common mistakes and how to put them right

    • Treating n as a mass density in kg m⁻³.

      Put it right: n is a number density of charge carriers per m³, so it is a pure number per unit volume.

    • Using e as the total charge or as 1 C.

      Put it right: e is the elementary charge 1.60 × 10⁻¹⁹ C carried by one electron or proton.

    • Forgetting to convert area from mm² or cm² to m² before substituting.

      Put it right: For example 1 mm² = 1 × 10⁻⁶ m².

    • Assuming v is the speed of individual electrons along the wire.

      Put it right: v is the mean drift velocity, which is very small compared with random thermal speeds.

    Exam tips

    • Write the rearranged equation before substituting numbers so the examiner can follow your method.
    • Convert all lengths to metres and areas to m² at the start of the calculation.
    • Use the unit check Anev → C s⁻¹ = A to confirm you have not inverted the relationship.
    • When comparing two wires, reason with ratios rather than recalculating from scratch.

    Try the lesson

    The start of the Mean drift velocity: (b) I = Anev , where n is the number density of charge carriers lesson, made from checked teaching notes for this specification point.

    Listen

    This equation links current to the microscopic motion of charge carriers. I is the current in amperes, A is the cross-sectional area of the conductor in m², n is the number density of charge carriers (number per m³), e is the elementary charge 1.60 × 10⁻¹⁹ C, and v is the mean drift velocity in m s⁻¹. Rearranged, v = I / (Ane). A useful check is that Anev has units m² × m⁻³ × C × m s⁻¹ = C s⁻¹ = A. In a multiple-choice question you may be asked to find v, n or A, or to predict how v changes when A doubles at constant current: v halves. Remember n is a number density, not a mass density, and e is the charge on one carrier, not the total charge. A strong answer earns marks for these points. States I = Anev and identifies each symbol with its unit: I in A, A in m², n in m⁻³, e in C, v in m s⁻¹. Rearranges correctly to v = I / (Ane) or n = I / (Aev) as required by the question. Uses e = 1.60 × 10⁻¹⁹ C for electrons or the appropriate carrier charge for ions. Applies proportionality reasoning, for example at constant I, doubling A halves v because v ∝ 1/A. Exam tip: Write the rearranged equation before substituting numbers so the examiner can follow your method.

    See it

    A flowchart starting from the equation I = Anev. Five branches lead from it to the meaning and unit of each symbol: I is current in A, A is cross-sectional area in m², n is number density of charge carriers in m⁻³, e is the elementary charge 1.60 × 10⁻¹⁹ C, and v is mean drift velocity in m s⁻¹. A further branch leads to the rearrangement v = I / (Ane), which then leads to the statement that at constant I, doubling A halves v because v ∝ 1/A. A final branch from the equation shows the unit check that Anev gives C s⁻¹ = A.
    It breaks the equation I = Anev into its symbols and units, shows the rearrangement to v = I / (Ane), the proportionality result and the unit check.

    Key words

    Say what each word means before you turn the card.

    Number density of charge carriers

    Try answering aloud or in your head before turning the card.

    Elementary charge

    Try answering aloud or in your head before turning the card.

    See every definition
    Number density of charge carriers
    The number of charge carriers per m³, a pure number per unit volume rather than a mass density.
    Elementary charge
    The charge e of 1.60 × 10⁻¹⁹ C carried by one electron or proton, not the total charge.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A flowchart starting from the equation I = Anev. Five branches lead from it to the meaning and unit of each symbol: I is current in A, A is cross-sectional area in m², n is number density of charge carriers in m⁻³, e is the elementary charge 1.60 × 10⁻¹⁹ C, and v is mean drift velocity in m s⁻¹. A further branch leads to the rearrangement v = I / (Ane), which then leads to the statement that at constant I, doubling A halves v because v ∝ 1/A. A final branch from the equation shows the unit check that Anev gives C s⁻¹ = A.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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