OCR · A-Level · Physics

    Course version: H556 · Version from Sept 2015

    (b) the centripetal force on a planet is provided by the gravitational…

    Full specification wording

    Planetary motion: (b) the centripetal force on a planet is provided by the gravitational force between it and the Sun

    A planet moving around the Sun follows a curved path, so it must have a centripetal acceleration directed towards the Sun.

    Checked against the OCR H556 specification (opens in a new tab) on .

    • Point 2 of 5
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    A planet moving around the Sun follows a curved path, so it must have a centripetal acceleration directed towards the Sun. The only significant force acting on the planet is the gravitational attraction between the planet and the Sun, so this gravitational force provides the required centripetal force. Equating the two for a circular orbit gives GMm/r² = mv²/r, which simplifies to v² = GM/r. Combining this with v = 2πr/T leads to T² = 4π²r³/(GM), which is Kepler's third law. This shows that the gravitational force is not an additional force but the same force that supplies the centripetal requirement.

    What earns the marks

    • States that the gravitational force between planet and Sun acts towards the Sun and provides the centripetal force.
    • Writes the gravitational force as GMm/r² and the centripetal force as mv²/r or mω²r.
    • Equates the two expressions to derive v² = GM/r for a circular orbit.
    • Combines v = 2πr/T with v² = GM/r to obtain T² = 4π²r³/(GM), linking to Kepler's third law.
    • Explains that no separate centripetal force exists; gravity alone fulfils that role.

    Common mistakes and how to put them right

    • Treating centripetal force as an extra force in addition to gravity.

      Put it right: It is the resultant of the gravitational force.

    • Using the planet's mass incorrectly in v² = GM/r.

      Put it right: The planet's mass cancels, leaving the Sun's mass M.

    • Forgetting that the gravitational force acts towards the Sun, which is the direction of the centripetal acceleration.

    • Mixing up the masses in GMm/r², using the planet's mass for M instead of the Sun's mass.

    Exam tips

    • Start from the force equation GMm/r² = mv²/r and cancel m before substituting numbers.
    • Check that M is the mass of the central body (the Sun) and m is the orbiting body (the planet).
    • Use v = 2πr/T when the period is given rather than the orbital speed.
    • State clearly that gravity provides the centripetal force, not that it is balanced by another force.

    Try the lesson

    The start of the Planetary motion: (b) the centripetal force on a planet is provided by the gravitational force between it and the Sun lesson, made from checked teaching notes for this specification point.

    Listen

    A planet moving around the Sun follows a curved path, so it must have a centripetal acceleration directed towards the Sun. The only significant force acting on the planet is the gravitational attraction between the planet and the Sun, so this gravitational force provides the required centripetal force. Equating the two for a circular orbit gives GMm/r² = mv²/r, which simplifies to v² = GM/r. Combining this with v = 2πr/T leads to T² = 4π²r³/(GM), which is Kepler's third law. This shows that the gravitational force is not an additional force but the same force that supplies the centripetal requirement. A strong answer earns marks for these points. States that the gravitational force between planet and Sun acts towards the Sun and provides the centripetal force. Writes the gravitational force as GMm/r² and the centripetal force as mv²/r or mω²r. Equates the two expressions to derive v² = GM/r for a circular orbit. Combines v = 2πr/T with v² = GM/r to obtain T² = 4π²r³/(GM), linking to Kepler's third law. Exam tip: Start from the force equation GMm/r² = mv²/r and cancel m before substituting numbers.

    See it

    A top-down flowchart. The first box says the planet moves on a curved path around the Sun, leading to a box saying the centripetal acceleration is directed towards the Sun. This leads to a box saying the gravitational force between planet and Sun acts towards the Sun, then to a box saying the gravitational force provides the centripetal force. That leads to the equation GMm/r² = mv²/r, then to cancelling m to give v² = GM/r, then to combining with v = 2πr/T, and finally to T² = 4π²r³/(GM), labelled Kepler's third law.
    Shows how the gravitational force on a planet provides the centripetal force, leading from the force equation to Kepler's third law.

    Put it in order

    Put these steps in the order they happen.

    1. 1. GMm/r² = mv²/r
    2. 2. T² = 4π²r³/(GM): Kepler's third law
    3. 3. Cancel m: v² = GM/r
    4. 4. Planet moves on a curved path around the Sun
    5. 5. Centripetal acceleration directed towards the Sun
    6. 6. Combine with v = 2πr/T
    7. 7. Gravitational force between planet and Sun acts towards the Sun
    8. 8. Gravitational force provides the centripetal force

    Key words

    Say what each word means before you turn the card.

    Gravitational force as the centripetal force

    Try answering aloud or in your head before turning the card.

    Circular orbital motion

    Try answering aloud or in your head before turning the card.

    Derivation of Kepler's third law

    Try answering aloud or in your head before turning the card.

    Mass of the central body determining orbital speed

    Try answering aloud or in your head before turning the card.

    See every definition
    Gravitational force as the centripetal force
    The gravitational attraction between the planet and the Sun acts towards the Sun and provides the required centripetal force.
    Circular orbital motion
    A planet moving around the Sun follows a curved path, so it must have a centripetal acceleration directed towards the Sun.
    Derivation of Kepler's third law
    Combining v = 2πr/T with v² = GM/r leads to T² = 4π²r³/(GM), which is Kepler's third law.
    Mass of the central body determining orbital speed
    In v² = GM/r the planet's mass cancels, leaving the Sun's mass M.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The first box says the planet moves on a curved path around the Sun, leading to a box saying the centripetal acceleration is directed towards the Sun. This leads to a box saying the gravitational force between planet and Sun acts towards the Sun, then to a box saying the gravitational force provides the centripetal force. That leads to the equation GMm/r² = mv²/r, then to cancelling m to give v² = GM/r, then to combining with v = 2πr/T, and finally to T² = 4π²r³/(GM), labelled Kepler's third law.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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