OCR · A-Level · Physics
Course version: H556 · Version from Sept 2015
The photoelectric effect: (d) work function; threshold frequency
The work function φ is the minimum energy required to remove an electron from the surface of a particular metal; it is a property of the metal and is often quoted in electronvolts, where 1 eV =…
Checked against the OCR H556 specification (opens in a new tab) on .
- Point 5 of 7
- 4 key terms
Study notes
From the checked teaching notes for this specification point.
The idea
The work function φ is the minimum energy required to remove an electron from the surface of a particular metal; it is a property of the metal and is often quoted in electronvolts, where 1 eV = 1.60 × 10⁻¹⁹ J. The threshold frequency f₀ is the lowest frequency of incident radiation that can cause photoelectric emission from that surface. It follows from Einstein’s equation with KEmax = 0, giving hf₀ = φ, so f₀ = φ/h. Radiation below f₀ cannot release electrons no matter how intense it is, because each photon then carries less than φ. The corresponding threshold wavelength is λ₀ = c/f₀ = hc/φ. Work function and threshold frequency are linked by φ = hf₀, so a larger work function means a higher threshold frequency.
What earns the marks
- The work function φ is the minimum energy needed to remove an electron from the surface of a metal.
- φ is a property of the metal surface and may be expressed in joules or electronvolts, with 1 eV = 1.60 × 10⁻¹⁹ J.
- The threshold frequency f₀ is the minimum frequency of incident radiation that produces photoelectric emission from that surface.
- At the threshold, KEmax = 0, so hf₀ = φ and therefore f₀ = φ/h.
- The corresponding threshold wavelength is λ₀ = c/f₀ = hc/φ.
- Radiation below the threshold frequency produces no emission at any intensity, because each photon carries less than the work function.
Common mistakes and how to put them right
Confusing the work function with the threshold frequency.
Put it right: φ is an energy in joules or electronvolts, while f₀ is a frequency in hertz, related by φ = hf₀.
Thinking that a brighter beam below the threshold will cause emission.
Put it right: Intensity adds more photons, but each photon still has energy below φ, so no electrons are released.
Treating the work function as the same for all metals.
Put it right: φ depends on the metal, so different surfaces have different threshold frequencies.
Exam tips
- Convert between joules and electronvolts carefully, using 1 eV = 1.60 × 10⁻¹⁹ J, and keep units consistent in calculations.
- Use f₀ = φ/h or λ₀ = hc/φ to move between work function, threshold frequency and threshold wavelength.
- State that below the threshold frequency no emission occurs at any intensity, and justify this using the one-photon-one-electron model.
Try the lesson
The start of the The photoelectric effect: (d) work function; threshold frequency lesson, made from checked teaching notes for this specification point.
Listen
The work function φ is the minimum energy required to remove an electron from the surface of a particular metal; it is a property of the metal and is often quoted in electronvolts, where 1 eV = 1.60 × 10⁻¹⁹ J. The threshold frequency f₀ is the lowest frequency of incident radiation that can cause photoelectric emission from that surface. It follows from Einstein’s equation with KEmax = 0, giving hf₀ = φ, so f₀ = φ/h. Radiation below f₀ cannot release electrons no matter how intense it is, because each photon then carries less than φ. The corresponding threshold wavelength is λ₀ = c/f₀ = hc/φ. Work function and threshold frequency are linked by φ = hf₀, so a larger work function means a higher threshold frequency. A strong answer earns marks for these points. The work function φ is the minimum energy needed to remove an electron from the surface of a metal. φ is a property of the metal surface and may be expressed in joules or electronvolts, with 1 eV = 1.60 × 10⁻¹⁹ J. The threshold frequency f₀ is the minimum frequency of incident radiation that produces photoelectric emission from that surface. At the threshold, KEmax = 0, so hf₀ = φ and therefore f₀ = φ/h. A common slip: Confusing the work function with the threshold frequency. Instead, φ is an energy in joules or electronvolts, while f₀ is a frequency in hertz, related by φ = hf₀. Exam tip: Convert between joules and electronvolts carefully, using 1 eV = 1.60 × 10⁻¹⁹ J, and keep units consistent in calculations.
Key words
Say what each word means before you turn the card.
Work function
Try answering aloud or in your head before turning the card.
Threshold frequency
Try answering aloud or in your head before turning the card.
Threshold wavelength
Try answering aloud or in your head before turning the card.
No emission below threshold at any intensity
Try answering aloud or in your head before turning the card.
See every definition
- Work function
- The minimum energy required to remove an electron from the surface of a particular metal; it is a property of the metal and is often quoted in electronvolts.
- Threshold frequency
- The lowest frequency of incident radiation that can cause photoelectric emission from that surface.
- Threshold wavelength
- The corresponding wavelength, given by λ₀ = c/f₀ = hc/φ.
- No emission below threshold at any intensity
- Radiation below f₀ cannot release electrons no matter how intense it is, because each photon then carries less than φ.
There is more to this lesson
The full lesson goes on to check your understanding and help you earn the marks. Create a free account to carry on, with your progress saved.
A week of Premium from your first lesson · Then the free plan continues · No card, no charge
Test your understanding of The photoelectric effect: (d) work function; threshold frequency
Active recall beats re-reading. Take an instant quiz now to test what you’ve learned and lock it into long-term memory.
A week of Premium from your first lesson · Then the free plan continues · No card, no charge