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    Operational amplifier in: — AQA A-Level Physics

    Teaching note checked against the official specification.

    An operational amplifier (op-amp) is a high-gain differential voltage amplifier with a very high input impedance and low output impedance, used in circuits such as inverting, non-inverting, summing, and comparator configurations. In AQA A-Level Physics, you must apply the ideal op-amp assumptions (infinite open-loop gain, infinite input impedance, zero output impedance) and the golden rules (no current into inputs, V+ = V-) to analyse circuits.

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    Operational amplifier in: explained

    A summing amplifier uses an operational amplifier with negative feedback to add several input voltages.

    Read the full explanation

    Each input connects through its own resistor to the inverting input, and a single feedback resistor connects the output back to that same input. The non-inverting input is held at zero volts, so the inverting input is a virtual earth. Because negligible current enters the ideal op-amp input, the sum of the input currents equals the current through the feedback resistor. If all input resistors are equal, the output is the negative sum of the inputs scaled by the ratio of the feedback resistance to the input resistance. For example, with input resistors of 10 kΩ and a feedback resistor of 20 kΩ, two inputs of 1.0 V and 2.0 V give an output of −6.0 V.

    Read the Operational amplifier in: study guideFull revision notes for AQA A-Level Physics

    Your focus

    1. Draw and label a summing amplifier circuit with multiple input resistors and one feedback resistor.
    2. Derive and use the current-balance equation to calculate the output voltage for given input voltages and resistances.
    3. Explain how the summing amplifier performs weighted addition and why the output is inverted.

    Which command word is this?

    You must use the correct formula, substitute numerical values with units, and give the final answer to an appropriate number of significant figures with the correct unit. Show all working.

    Operational amplifier in: exam tips

    Topic Overview

    This topic covers the operational amplifier (op-amp) as a fundamental building block in analogue electronics. You will study its ideal properties, the effects of negative feedback, and how it is configured as inverting, non-inverting, summing, and differential amplifiers, as well as comparators. Understanding these circuits is essential for analysing sensor interfaces, audio amplifiers, and control systems.

    In the wider AQA A-Level Physics course, op-amps link to potential dividers, sensors (such as thermistors and LDRs), and the processing of analogue signals. Mastery of op-amp circuits is crucial for tackling exam questions on gain, saturation, and the design of practical amplifier stages, and it provides a foundation for further study in electronics and engineering.

    Key Concepts
    • →Ideal op-amp properties: infinite open-loop gain, infinite input impedance, zero output impedance, and infinite bandwidth.
    • →Golden rules for negative feedback: no current flows into the input terminals, and the voltage at the inverting input equals the voltage at the non-inverting input (virtual earth if non-inverting input is grounded).
    • →Inverting amplifier: gain = -Rf / Rin, input and output are in antiphase (180 degrees).
    • →Non-inverting amplifier: gain = 1 + (Rf / R1), input and output are in phase.
    • →Saturation: output voltage cannot exceed the supply rails; when saturated, the op-amp no longer follows the golden rules and the output clips at approximately ±Vsupply.
    Marking Points
    • Identifies the summing amplifier as an inverting op-amp configuration with several input resistors connected to the inverting input.
    • States that the non-inverting input is connected to zero volts, so the inverting input is a virtual earth.
    • Applies the ideal op-amp rule that negligible current enters the inverting input, so the sum of the input currents flows through the feedback resistor.
    • Writes the current-balance equation in the form V₁/R₁ + V₂/R₂ + ... = −Vout/Rf, preserving the correct signs.
    • Rearranges the equation to make the output voltage the subject, for example Vout = −Rf(V₁/R₁ + V₂/R₂ + ...).
    • Explains that equal input resistors give an output proportional to the negative sum of the input voltages, scaled by Rf/Rin.
    • Describes a practical use, such as mixing audio signals or combining sensor outputs, and notes that the output saturates if the required voltage exceeds the supply rails.
    • Explains that changing an input resistor changes the weighting of that input, allowing weighted addition.
    Examiner Tips
    • 💡Label each input current with its direction towards the inverting node, then write one current-balance equation.
    • 💡If the question gives equal input resistors, state that simplification explicitly before substituting values.
    • 💡Keep the feedback resistor symbol distinct from the input resistors so the algebra is unambiguous.
    • 💡Check the sign and the order of magnitude of your answer against the supply rails to see whether saturation is likely.
    • 💡Always start by stating the two golden rules for an ideal op-amp with negative feedback: no input current and V- = V+. This demonstrates understanding and often earns method marks.
    • 💡When calculating gain, write the formula explicitly with the correct signs and resistor labels. For inverting amplifiers, include the negative sign to show phase inversion.
    • 💡For questions involving saturation, calculate the ideal output first, then compare it to the supply rails. If it exceeds them, state that the output saturates and give the saturated value (approximately ±Vsupply).
    Common Mistakes
    • Omitting the negative sign in the output expression; correct this by remembering that the inputs connect to the inverting terminal, so the output is inverted.
    • Adding the input voltages directly without dividing by their resistances; correct this by using each input current, which is the input voltage divided by its own resistor.
    • Assuming the virtual earth exists without negative feedback; correct this by checking that the feedback resistor connects the output to the inverting input.
    • Mixing units, such as using kilo-ohms for some resistors and ohms for others; correct this by converting all resistances to the same unit before calculating.
    • Students often think the op-amp amplifies the voltage difference by its open-loop gain even in negative feedback. Correction: In negative feedback, the output adjusts to make the input voltage difference nearly zero, and the gain is set by external resistors.
    • Students sometimes believe that current flows into the op-amp inputs. Correction: For an ideal op-amp, input impedance is infinite, so no current flows into the inputs; all current flows through the feedback network.
    • Students may forget that the output saturates when the required output exceeds the supply voltage. Correction: Always check that the calculated output is within the supply rails; if not, the output clips at the rail voltage and the golden rules no longer apply.
    Revision Plan
    1. 1Day 1-2: Learn the ideal op-amp properties and the two golden rules. Practice identifying inverting, non-inverting, and comparator configurations from circuit diagrams.
    2. 2Day 3-4: Derive the gain formulas for inverting and non-inverting amplifiers using Kirchhoff's laws and the golden rules. Memorise the formulas and understand the role of each resistor.
    3. 3Day 5-6: Work through calculations for gain, output voltage, and saturation. Include examples with sensor inputs (e.g., thermistor in a potential divider) to see how op-amps process real signals.
    4. 4Day 7-8: Attempt exam-style questions, focusing on multi-step problems that combine op-amps with potential dividers and saturation. Review mark schemes to identify common pitfalls.
    5. 5Day 9-10: Create a summary sheet with key formulas, golden rules, and circuit diagrams. Test yourself with active recall and past paper questions under timed conditions.
    Exam Question Types
    • 📋Calculation of voltage gain and output voltage for inverting and non-inverting amplifiers: Write the correct formula, substitute values, and include units and sign.
    • 📋Explanation of saturation and its effect on output: Calculate ideal output, compare to supply rails, and state the saturated output voltage.
    • 📋Circuit analysis with sensor inputs: Combine potential divider equations with op-amp gain to find output voltage for a given physical quantity (e.g., temperature).
    • 📋Design or selection of resistor values to achieve a required gain: Rearrange the gain formula and choose appropriate E-series resistor values, explaining your reasoning.
    Command Word Expectations (AQA)
    Calculate

    You must use the correct formula, substitute numerical values with units, and give the final answer to an appropriate number of significant figures with the correct unit. Show all working.

    Explain

    You must provide a reasoned account using correct physics terminology. For op-amps, this often involves stating the golden rules, describing the effect of negative feedback, or explaining saturation with reference to supply rails.

    Determine

    You must use given data or circuit analysis to find a value, often requiring rearrangement of formulas or combining with potential divider equations. Show logical steps and state the final value with units.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often forget that for an ideal op-amp in negative feedback, the voltage at the inverting input equals the voltage at the non-inverting input (virtual earth if non-inverting is grounded), and they incorrectly assume the output saturates.
    ❌ Weak Answer (Loses Marks):The op-amp amplifies the difference between the inputs by a huge gain, so the output is always at the supply voltage.
    Example improved answer:In negative feedback, the op-amp adjusts its output until the voltage difference between the inputs is approximately zero. Therefore V- = V+ (virtual earth if V+ = 0 V). The output voltage is determined by the feedback network, not by the open-loop gain, provided the output does not saturate.
    Examiner Tip: Always state the two golden rules: (1) no current flows into the inputs, (2) V- = V+ when negative feedback is present. Then apply Kirchhoff's laws at the input node.
    Pitfall: When calculating gain for an inverting amplifier, students often swap the resistor values or forget the negative sign, losing marks for direction of output.
    ❌ Weak Answer (Loses Marks):Gain = Rf / Rin, so for Rf = 10 kΩ and Rin = 1 kΩ, gain = 10.
    Example improved answer:For an inverting amplifier, voltage gain = -Rf / Rin. With Rf = 10 kΩ and Rin = 1 kΩ, gain = -10. The negative sign indicates a 180 degree phase inversion between input and output.
    Examiner Tip: Write the formula with the negative sign explicitly and comment on the phase inversion. If the question asks for magnitude only, state that the gain magnitude is 10 but the output is inverted.
    Step-by-Step Worked Solutions

    Question: An inverting amplifier uses an op-amp with Rf = 47 kΩ and Rin = 4.7 kΩ. The input voltage is 0.2 V. Calculate the output voltage and state whether it is in phase or antiphase with the input.

    1. 1.Step 1: Identify given facts: Rf = 47 kΩ, Rin = 4.7 kΩ, Vin = 0.2 V. The circuit is an inverting amplifier.
    2. 2.Step 2: Apply the inverting amplifier gain formula: Gain = -Rf / Rin = -47 kΩ / 4.7 kΩ = -10.
    3. 3.Step 3: Calculate output voltage: Vout = Gain × Vin = -10 × 0.2 V = -2.0 V. The negative sign indicates antiphase (180 degree phase difference).
    4. 4.Step 4: State final conclusion with units: Vout = -2.0 V, antiphase with input.
    Final Answer: Output voltage = -2.0 V, meaning the output is 2.0 V in antiphase (180 degrees) relative to the input.

    Question: A non-inverting amplifier has Rf = 22 kΩ and R1 = 2.2 kΩ. The input voltage is 0.5 V. Calculate the voltage gain and the output voltage. The op-amp is powered by ±12 V rails. Comment on whether the output is valid.

    1. 1.Step 1: Identify given facts: Rf = 22 kΩ, R1 = 2.2 kΩ, Vin = 0.5 V, supply rails ±12 V. Non-inverting configuration.
    2. 2.Step 2: Apply non-inverting gain formula: Gain = 1 + (Rf / R1) = 1 + (22 kΩ / 2.2 kΩ) = 1 + 10 = 11.
    3. 3.Step 3: Calculate ideal output: Vout = Gain × Vin = 11 × 0.5 V = 5.5 V.
    4. 4.Step 4: Check saturation: 5.5 V is within the ±12 V rails, so the output is valid and not saturated.
    5. 5.Step 5: State final conclusion: Gain = 11, Vout = 5.5 V, in phase with input.
    Final Answer: Voltage gain = 11, output voltage = 5.5 V (in phase with input), and the output is valid because it is less than the positive supply rail.
    Active Recall Memory Test
    State the two golden rules for an ideal op-amp with negative feedback.
    Key Fact: 1. No current flows into the input terminals (infinite input impedance). 2. The voltage at the inverting input equals the voltage at the non-inverting input (V- = V+), due to the high open-loop gain and negative feedback.
    Write the formula for the voltage gain of an inverting amplifier and explain the meaning of the negative sign.
    Key Fact: Gain = -Rf / Rin. The negative sign indicates that the output voltage is 180 degrees out of phase (antiphase) with the input voltage.
    What is saturation in an op-amp circuit and how does it affect the output?
    Key Fact: Saturation occurs when the required output voltage exceeds the op-amp's supply rails. The output voltage then clips at approximately the positive or negative supply voltage (or slightly less), and the golden rules no longer apply because the op-amp is no longer operating in its linear region.
    For a non-inverting amplifier with Rf = 10 kΩ and R1 = 1 kΩ, what is the voltage gain?
    Key Fact: Gain = 1 + (Rf / R1) = 1 + (10 kΩ / 1 kΩ) = 11.
    Frequently Asked Questions
    What is an operational amplifier and how does it work?
    An operational amplifier (op-amp) is a high-gain electronic voltage amplifier with differential inputs and usually a single output. It amplifies the voltage difference between its two inputs. In ideal conditions, it has infinite gain, infinite input impedance, and zero output impedance. When negative feedback is applied, the op-amp adjusts its output to make the voltage difference between the inputs nearly zero, allowing precise control of gain using external resistors.
    What are the golden rules of an ideal op-amp?
    The two golden rules are: (1) no current flows into the input terminals because the input impedance is infinite, and (2) the voltage at the inverting input equals the voltage at the non-inverting input (V- = V+) when negative feedback is present. These rules simplify circuit analysis and are essential for solving op-amp problems in AQA A-Level Physics.
    How do I calculate the gain of an inverting amplifier?
    For an inverting amplifier, the voltage gain is given by Gain = -Rf / Rin, where Rf is the feedback resistor and Rin is the input resistor. The negative sign indicates that the output is 180 degrees out of phase with the input. For example, if Rf = 20 kΩ and Rin = 2 kΩ, the gain is -10, meaning the output is 10 times larger and inverted.
    What happens when an op-amp saturates?
    When an op-amp saturates, its output voltage cannot exceed the supply rails. If the calculated ideal output would be greater than the positive supply voltage (or less than the negative supply voltage), the output clips at approximately the supply voltage. In saturation, the op-amp no longer follows the golden rules because it is not operating in its linear region, and the output becomes a distorted version of the input.
    What is the difference between inverting and non-inverting amplifiers?
    An inverting amplifier produces an output that is 180 degrees out of phase with the input, and its gain is -Rf/Rin. A non-inverting amplifier produces an output in phase with the input, and its gain is 1 + (Rf/R1). The non-inverting configuration has a higher input impedance, making it suitable for buffering weak signals, while the inverting configuration allows easy summing of multiple inputs.
    Why is negative feedback used in op-amp circuits?
    Negative feedback is used to control the gain of the op-amp precisely and to improve its performance. By feeding a fraction of the output back to the inverting input, the op-amp adjusts its output to minimise the input voltage difference. This results in a stable, predictable gain determined by external resistors, increased bandwidth, reduced distortion, and higher input impedance, making the circuit more reliable for practical applications.