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    Transmission media (A-level only) — AQA A-Level Physics

    Teaching note checked against the official specification.

    Transmission media are the physical pathways that carry signals from a transmitter to a receiver, including solid metal conductors, optical fibres and free space. At A-level you must compare their attenuation, dispersion, bandwidth, noise immunity and cost, and explain how each property suits a particular communication application.

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    Transmission media (A-level only) explained

    Transmission media (A-level only) covers 5 specification points, including Metal wire, optic fibre, electromagnetic… and Ground wave, refraction and reflection of sky….

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    Open a point below for its explanation and revision guidance.

    Transmission-path media: metal wire, optic fibre, electromagnetic (radio, microwave).

    A transmission medium carries a signal from transmitter to receiver. Metal wire, such as a coaxial cable, guides an electrical signal along conductors and is cheap and easy to connect, but suffers attenuation and can pick up interference. Optic fibre guides infrared or visible light by total internal reflection; it has very low attenuation and is immune to electromagnetic interference, but needs electro-optical converters and careful installation. Free-space electromagnetic links use radio waves, which diffract around obstacles and pass through walls, or microwaves, which need line of sight but support high bandwidth. Compare media by attenuation, bandwidth, interference immunity, cost and suitability for a given link.

    Ground wave, refraction and reflection of sky waves, diffraction of long-wavelength radiation around the Earth’s surface.

    Radio communication depends on how waves interact with the Earth and atmosphere. Ground waves travel along the surface, following its curvature by diffraction; this works best for long wavelengths, which diffract more around obstacles and the Earth. Sky waves travel upwards, refract gradually through the ionosphere as electron density changes, and can return to Earth; reflection is a useful limiting description. The ionosphere's varying ionisation means sky-wave reception changes with frequency, time of day and solar activity. Shorter wavelengths diffract less, so ground-wave range falls. A practical example is long-wave AM broadcasting reaching beyond the horizon by ground wave, while short-wave signals reach distant receivers via sky waves.

    Satellite systems and typical transmission frequencies.

    Satellite communication uses microwaves because they pass through the ionosphere and atmosphere with little absorption or reflection, unlike longer radio waves that may be refracted by the ionosphere. A signal is sent from an Earth station to a satellite, amplified and retransmitted on a different frequency to avoid interference between uplink and downlink. Geostationary satellites orbit above the equator with a period of 24 hours, so a dish can be fixed; they are used for television and telephony but have a long path and noticeable delay. Low-Earth-orbit satellites have shorter delays but move relative to the ground, so tracking or constellations are needed. Typical frequencies are in the microwave region, roughly 1–30 GHz, with specific bands such as C, Ku and Ka used for different services.

    Students should recognise that up- and down-links require different frequencies so that the receivers are not de-sensed.

    In satellite and many duplex radio systems, the up-link (Earth to satellite) and down-link (satellite to Earth) use different carrier frequencies. If both used the same frequency, a receiver would pick up its own transmitted signal as well as the weak incoming signal. The strong local transmission would overload or desensitise the receiver front end, masking the wanted signal. This is why a frequency offset, or duplex spacing, is used. For example, a satellite might receive at 14.25 GHz and transmit at 11.45 GHz, giving a 2.8 GHz separation. The receiver can then filter out its own transmission band and amplify the weak incoming signal without being de-sensed. You should be able to explain the problem and how different frequencies solve it.

    Advantages and disadvantages of various transmission media. Students should consider data transmission rate, cost, and security issues.

    Transmission media carry data between points. You must compare media such as copper cables (twisted pair, coaxial), optical fibres, and wireless (radio, microwave, satellite) in terms of data transmission rate, cost, and security. Copper is cheap and easy to install but has higher attenuation and lower bandwidth than fibre, and can be tapped. Fibre offers very high data rates and immunity to electromagnetic interference, but is more expensive to install and fragile. Wireless is convenient and mobile but can be intercepted, and its data rate depends on frequency and bandwidth. For each medium, you should be able to give at least one advantage and one disadvantage linked to rate, cost, or security, and justify a choice for a given context.

    Your focus

    1. Describe how metal wire, optic fibre and electromagnetic waves carry signals.
    2. Compare the advantages and disadvantages of each transmission medium.
    3. Select a suitable medium for a stated communication context and justify the choice.
    Show all 15 objectives
    1. Describe how ground waves propagate along the Earth's surface and why long wavelengths are used.
    2. Explain how sky waves are refracted in the ionosphere and how reflection can model their return to Earth.
    3. Relate diffraction of long-wavelength radiation to communication beyond the horizon.
    4. Describe how a satellite communication link transfers a signal from Earth to satellite and back.
    5. Compare geostationary and low-Earth-orbit satellite systems in terms of delay, coverage and tracking.
    6. State typical transmission frequencies for satellite systems and explain why microwaves are used.
    7. Describe why up-link and down-link frequencies must differ to prevent receiver de-sensing.
    8. Explain how a frequency offset allows filtering of the local transmission.
    9. Apply the concept to a given satellite or duplex radio scenario.
    10. Describe advantages and disadvantages of copper, fibre, and wireless media.
    11. Compare media in terms of data rate, cost, and security.
    12. Justify the choice of a transmission medium for a given scenario.

    Which command word is this?

    A brief, factual answer with no explanation required. One mark per correct point, often a definition or a named example.

    Transmission media (A-level only) exam tips

    Topic Overview

    Transmission media is the A-level topic that explains how information physically travels from a transmitter to a receiver. You study three main categories: metal conductors such as copper twisted pair and coaxial cable, optical fibres that guide infrared or visible light by total internal reflection, and wireless media such as radio waves, microwaves and satellites that use free space. For each medium you must be able to describe the mechanism of propagation and compare attenuation, dispersion, bandwidth, noise immunity, security and cost.

    This topic matters because every communication system, from a home broadband link to a transatlantic fibre cable, is designed around the trade-offs between these media. It builds directly on waves, refraction and total internal reflection from AS, and it feeds into later work on signal regeneration, multiplexing and the electromagnetic spectrum. Exam questions often ask you to choose a medium for a given application and justify your choice with quantitative or comparative reasoning.

    Key Concepts
    • →Attenuation is the loss of signal amplitude or power as it travels, measured in decibels (dB) or dB km-1; it increases with distance and is caused by absorption and scattering in the medium.
    • →Dispersion is the spreading of a signal pulse in time. In optical fibres, modal dispersion arises from different ray paths and chromatic dispersion from different wavelengths travelling at different speeds; both limit the maximum bit rate.
    • →Optical fibres guide light by total internal reflection at the core-cladding boundary, which requires the core refractive index to be greater than the cladding and the angle of incidence to exceed the critical angle.
    • →Copper cables carry electrical signals and suffer from resistive heating, skin effect and electromagnetic interference, but they are cheap, easy to terminate and can carry power.
    • →Wireless media use free-space propagation of electromagnetic waves; their range and data rate depend on frequency, atmospheric absorption, diffraction and the need for line-of-sight at microwave frequencies.
    Marking Points
    • Identify metal wire, optic fibre and free-space electromagnetic waves as transmission media and state that each guides or carries a signal between transmitter and receiver.
    • Describe metal wire as guiding an electrical signal, with advantages such as low cost and simple connection, and disadvantages such as attenuation and susceptibility to electromagnetic interference.
    • Describe optic fibre as guiding light by total internal reflection, with advantages such as low attenuation, high bandwidth and immunity to electromagnetic interference.
    • Describe radio waves as free-space electromagnetic radiation that can diffract around obstacles and travel long distances, and microwaves as higher-frequency radiation suited to line-of-sight, high-bandwidth links.
    • Compare media using criteria such as attenuation, bandwidth, interference, security, cost and installation requirements.
    • Ground waves propagate along or near the Earth's surface and can follow its curvature because long-wavelength radiation diffracts significantly around the Earth.
    • Diffraction is greater when wavelength is comparable to, or larger than, the size of the obstacle or aperture; the Earth itself acts as the obstacle for ground waves.
    • Sky waves travel into the atmosphere and are gradually refracted by the ionosphere, where free electrons make the refractive index vary with height and frequency.
    • Reflection at an ionospheric layer is a simplified model of the continuous refraction that can return a sky wave to the ground.
    • The ionosphere's ionisation varies with time of day, season and solar activity, so sky-wave propagation is variable and frequency-dependent.
    • Shorter wavelengths diffract less around the Earth, so ground-wave communication is more effective at long wavelengths.
    • Multiple hops between the ionosphere and the Earth's surface can allow sky waves to travel very long distances.
    • Satellite links use microwaves because these frequencies pass through the ionosphere and atmosphere with relatively little attenuation.
    • An uplink transmits from a ground station to the satellite; the satellite amplifies and retransmits the signal as a downlink, often using a different frequency to prevent interference.
    • Geostationary satellites have a 24-hour orbital period above the equator, so ground dishes can remain fixed; this suits broadcast and continuous communication.
    • Low-Earth-orbit satellites travel faster and closer, giving shorter signal delay but requiring tracking or a constellation of satellites for continuous coverage.
    • Typical satellite transmission frequencies lie in the microwave region, approximately 1–30 GHz, with bands such as C, Ku and Ka allocated to different services.
    • Higher microwave frequencies allow greater bandwidth but suffer more atmospheric attenuation, especially in heavy rain.
    • States that up-link and down-link use different carrier frequencies.
    • Explains that using the same frequency would cause the receiver to pick up its own transmitted signal.
    • Describes de-sensing as the strong local signal overloading or desensitising the receiver, reducing its ability to detect the weak incoming signal.
    • Explains that a frequency offset (duplex spacing) allows filtering so the receiver is not de-sensed.
    • Applies the idea to a satellite or duplex radio system with a numerical example of frequency separation.
    • Identifies at least two transmission media, such as copper cable, optical fibre, and wireless.
    • States an advantage of a medium in terms of data transmission rate, cost, or security.
    • States a disadvantage of a medium in terms of data transmission rate, cost, or security.
    • Compares media, for example fibre has higher data rate than copper but higher installation cost.
    • Relates the choice of medium to a specific context, such as security needs or budget.
    Examiner Tips
    • 💡When comparing media, name the criterion first and then apply it, for example attenuation: optic fibre has lower attenuation than metal wire.
    • 💡Link each medium to a realistic context, such as fibre for long-haul high-bandwidth links and radio for mobile or broadcast links.
    • 💡Use correct terminology such as total internal reflection, attenuation, bandwidth and electromagnetic interference.
    • 💡When explaining ground-wave range, explicitly link wavelength to the amount of diffraction around the Earth rather than saying only that long waves travel further.
    • 💡For sky waves, describe the change in refractive index with height in the ionosphere and state that the wave bends progressively until it may return to Earth.
    • 💡Use a labelled diagram showing the Earth's surface, the ionosphere and possible paths; annotate where diffraction, refraction and reflection occur.
    • 💡Quote typical frequencies in the microwave region, such as gigahertz values, and link the choice to low atmospheric absorption.
    • 💡Compare geostationary and low-Earth-orbit systems in terms of delay, coverage and tracking rather than listing only one type.
    • 💡Explain why uplink and downlink frequencies differ: to avoid the strong transmitted signal interfering with the much weaker received signal.
    • 💡Define de-sensing clearly in your answer, linking it to receiver overload.
    • 💡Use a labelled diagram or numerical example to show the frequency separation.
    • 💡Explain the consequence of not using different frequencies, not just state that they are different.
    • 💡Use a table to compare media across rate, cost, and security for clarity.
    • 💡Give a specific example, such as 'fibre offers data rates of 1 Gbit s⁻¹ over several kilometres'.
    • 💡Link your comparison to the context given in the question, such as a hospital or a home network.
    • 💡When comparing media, always use a point-evidence-application structure. For example: 'Optical fibre has lower attenuation (about 0.2 dB km-1), so repeaters can be 50-100 km apart, reducing cost on long-haul links.'
    • 💡Learn typical numerical values: attenuation of copper is a few dB km-1, optical fibre is about 0.2 dB km-1, and the critical angle for a typical fibre is around 80 degrees. Quoting these earns credit in evaluation questions.
    • 💡In 'explain' questions, always link cause to effect. Do not just say 'there is dispersion'; say 'different rays travel different path lengths, so they arrive at different times, so pulses broaden and overlap, limiting the bit rate'.
    Common Mistakes
    • Saying optic fibre carries an electrical current; correct by stating that it guides light by total internal reflection.
    • Claiming radio waves cannot carry digital data; correct by stating that radio links carry modulated signals, including digital information.
    • Treating microwaves as a different physical phenomenon from radio waves; correct by stating that both are electromagnetic waves and differ mainly in frequency and propagation behaviour.
    • Treating ground waves as travelling in a straight line through the Earth; correct this by explaining that they follow the surface and spread around the curvature by diffraction.
    • Describing sky waves as reflecting perfectly from a sharp mirror-like layer; correct this by explaining gradual refraction in a medium whose refractive index changes with height, with reflection as a limiting description.
    • Assuming the ionosphere is constant; correct this by linking its changing ionisation to time of day, solar activity and frequency, which changes which frequencies return to Earth.
    • Stating that satellites use sound waves or visible light; correct this by identifying microwaves as the typical transmission medium.
    • Confusing uplink and downlink; correct this by defining uplink as Earth-to-satellite and downlink as satellite-to-Earth.
    • Claiming all satellites are geostationary; correct this by distinguishing geostationary orbits from low-Earth orbits and their different delay and tracking requirements.
    • Thinking that different frequencies are needed only to avoid interference between different users; correction: the key issue is the receiver being de-sensed by its own transmission.
    • Confusing up-link and down-link; correction: up-link is Earth to satellite, down-link is satellite to Earth.
    • Assuming the frequency difference must be large; correction: any sufficient offset that allows filtering and avoids de-sensing is adequate, though practical systems use specific bands.
    • Claiming fibre is always cheaper; correction: fibre usually has higher installation cost than copper, though it may have lower long-term maintenance.
    • Ignoring security in comparisons; correction: security is a required consideration, so discuss interception or tapping risks.
    • Confusing data rate with bandwidth; correction: data rate is the actual transmission speed, while bandwidth is the range of frequencies available, though they are related.
    • Students often say that digital signals are immune to noise. In fact noise is added to the signal, but because only two discrete levels must be distinguished, the signal can be regenerated at repeaters, whereas analogue noise accumulates and cannot be removed.
    • Many students think total internal reflection in an optical fibre is reflection from a mirrored coating. It is not; it occurs at the boundary between core and cladding because the core has a higher refractive index, and no light is lost through the cladding.
    • Students frequently confuse attenuation with dispersion. Attenuation is a loss of amplitude or power; dispersion is a spreading of the pulse in time. A signal can be strong but still unreadable if dispersion has caused pulses to overlap.
    Revision Plan
    1. 1Day 1-2: Read the specification and make a comparison table for copper, optical fibre and wireless media with columns for mechanism, attenuation, dispersion, bandwidth, noise immunity, security and cost.
    2. 2Day 3-4: Work through calculations on attenuation in dB and dB km-1, and practise ray diagrams for total internal reflection in a step-index fibre.
    3. 3Day 5-6: Write model answers to 6-mark comparison and explanation questions, using the point-evidence-application structure and quoting typical numerical values.
    4. 4Day 7-8: Complete past-paper questions on this topic, mark them against the scheme, and make a list of every mark you dropped and why.
    5. 5Day 9-10: Use active recall to test yourself on definitions and mechanisms, then redo any questions you found difficult without notes.
    Exam Question Types
    • 📋Calculation of output power or attenuation in dB or dB km-1 for a given cable length. Advice: write the dB equation, substitute carefully and check whether the question asks for power or amplitude, since the factor is 10 for power and 20 for amplitude.
    • 📋Explain why a particular medium is chosen for a given application, often 4-6 marks. Advice: give at least two advantages and one disadvantage, and link each to the specific context such as long-haul internet, LAN or satellite TV.
    • 📋Describe and explain the propagation of light in an optical fibre, including a ray diagram. Advice: label core, cladding, angle of incidence and critical angle, and state that n_core > n_cladding.
    • 📋Compare analogue and digital signals in terms of noise and regeneration. Advice: define both, explain how noise affects each, and state that regeneration restores a digital signal but analogue signals cannot be perfectly restored.
    Command Word Expectations (AQA)
    State

    A brief, factual answer with no explanation required. One mark per correct point, often a definition or a named example.

    Explain

    You must give a reason or mechanism, linking cause to effect. Marks are awarded for each correct logical step, so write in full sentences and use technical terms such as attenuation, dispersion, total internal reflection and bit rate.

    Evaluate

    You must consider both advantages and disadvantages and reach a justified conclusion. Use comparative data where possible, and make a clear judgement linked to the application given in the question.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students confuse attenuation with dispersion, or claim that a digital signal is immune to noise simply because it is digital. Many also forget that in an optical fibre the signal is infrared/visible light, not an electrical current, so they describe total internal reflection incorrectly as reflection off a mirror coating.
    ❌ Weak Answer (Loses Marks):The signal gets weaker because the wire is long, and digital signals do not get noise so they are better.
    Example improved answer:Attenuation is the reduction in signal amplitude or power as the signal travels through the medium, caused by energy transfer to the surroundings; it increases with length and is measured in dB or dB km-1. Dispersion is the spreading of a pulse in time, caused by different rays or wavelengths travelling different path lengths or speeds, which limits the maximum bit rate. Digital signals are not immune to noise, but because the receiver only has to distinguish two discrete levels, noise can be removed by regeneration at repeaters, unlike analogue signals where noise accumulates.
    Examiner Tip: Always define the property, give its cause, then state its practical consequence. Use the words 'amplitude', 'power', 'pulse broadening' and 'bit rate' precisely, and never say a digital signal has no noise.
    Pitfall: In comparison questions students list properties without linking them to the application, or they state that optical fibres are 'better' without quantifying why. They also lose marks by omitting the need for repeaters or by confusing multimode and single-mode fibres.
    ❌ Weak Answer (Loses Marks):Optical fibre is better than copper because it is faster and cheaper.
    Example improved answer:Optical fibre has much lower attenuation per kilometre (about 0.2 dB km-1 compared with several dB km-1 for copper), so repeaters can be spaced 50-100 km apart rather than 1-2 km, reducing cost and complexity. It also has a much higher bandwidth because the carrier frequency is around 10^14 Hz, and it is immune to electromagnetic interference because the signal is light confined within the fibre. However, optical fibre is more expensive to install and terminate, and it cannot carry electrical power to remote equipment, so copper is still used for short links and power-over-Ethernet.
    Examiner Tip: Structure comparison answers as point, evidence, application. Quote typical figures where you can, and always mention at least one disadvantage of the 'better' medium to show balanced evaluation.
    Step-by-Step Worked Solutions

    Question: A copper cable has an attenuation of 4.0 dB km-1. A signal of initial power 20 mW is transmitted along 15 km of cable. Calculate the output power in mW.

    1. 1.Step 1: Identify given facts: attenuation coefficient = 4.0 dB km-1, length = 15 km, input power = 20 mW.
    2. 2.Step 2: Calculate total attenuation in dB: attenuation = 4.0 x 15 = 60 dB.
    3. 3.Step 3: Use the definition of dB for power: attenuation (dB) = 10 log10(Pin/Pout), so 60 = 10 log10(20/Pout).
    4. 4.Step 4: Rearrange: log10(20/Pout) = 6, so 20/Pout = 10^6 = 1 000 000.
    5. 5.Step 5: Pout = 20 / 1 000 000 = 2.0 x 10^-5 mW = 2.0 x 10^-8 W.
    6. 6.Step 6: State final conclusion with units: output power = 2.0 x 10^-5 mW.
    Final Answer: Output power = 2.0 x 10^-5 mW (2.0 x 10^-8 W).

    Question: Explain why a single-mode optical fibre can carry a higher bit rate over a longer distance than a multimode step-index fibre. (6 marks)

    1. 1.Step 1: State that in a multimode fibre, rays enter at different angles and travel different path lengths, so they arrive at different times.
    2. 2.Step 2: This causes modal dispersion, which broadens each pulse in time.
    3. 3.Step 3: If pulses broaden too much they overlap, so the receiver cannot distinguish adjacent bits, limiting the bit rate or the maximum link length.
    4. 4.Step 4: In a single-mode fibre the core is very narrow (about 8-10 micrometres), so only one mode propagates and there is essentially no modal dispersion.
    5. 5.Step 5: The only significant dispersion is chromatic, caused by different wavelengths travelling at slightly different speeds, which is much smaller.
    6. 6.Step 6: Therefore pulses stay sharper for longer, allowing higher bit rates and repeater spacing of 50-100 km rather than a few kilometres.
    Final Answer: Single-mode fibre avoids modal dispersion because only one ray path propagates, so pulses broaden far less and a much higher bit rate can be transmitted over a much longer distance before regeneration is needed.
    Active Recall Memory Test
    Define attenuation and state its unit.
    Key Fact: Attenuation is the reduction in signal amplitude or power as it travels through a medium, caused by absorption and scattering. It is measured in decibels (dB), or dB km-1 for the attenuation per unit length.
    What is modal dispersion and how does it limit a fibre-optic link?
    Key Fact: Modal dispersion is the spreading of a pulse because different rays travel different path lengths in a multimode fibre and arrive at different times. This broadens pulses so they overlap, limiting the maximum bit rate or link length.
    State two conditions necessary for total internal reflection in an optical fibre.
    Key Fact: The light must be travelling from a medium of higher refractive index to one of lower refractive index (n_core > n_cladding), and the angle of incidence at the boundary must be greater than the critical angle.
    Give one advantage and one disadvantage of optical fibre compared with copper cable.
    Key Fact: Advantage: much lower attenuation and higher bandwidth, so fewer repeaters and faster data rates. Disadvantage: more expensive to install and terminate, and it cannot carry electrical power to remote equipment.
    Frequently Asked Questions
    What is the difference between attenuation and dispersion in an optical fibre?
    Attenuation is the loss of signal power or amplitude as light travels through the fibre, caused by absorption and scattering, and it is measured in dB km-1. Dispersion is the spreading of a pulse in time, caused by different rays or wavelengths taking different times to travel through the fibre. Attenuation reduces the signal strength, while dispersion blurs the signal and limits the bit rate. Both effects limit the maximum distance between repeaters, but they are fixed in different ways: attenuation by using a longer wavelength or a purer glass, and dispersion by using a single-mode fibre.
    Why is optical fibre better than copper for long-distance communication?
    Optical fibre has a much lower attenuation per kilometre, typically about 0.2 dB km-1 compared with several dB km-1 for copper, so repeaters can be spaced 50-100 km apart instead of 1-2 km. It also has a far higher bandwidth because the carrier frequency is around 10^14 Hz, allowing many more channels or a higher bit rate. In addition, the light signal is confined within the fibre and is not affected by electromagnetic interference, so the signal is more secure and less noisy. However, fibre is more expensive to install and cannot carry electrical power, so copper is still used for short links.
    How do I calculate attenuation in decibels for a transmission line?
    For power, use the equation attenuation in dB = 10 log10(Pin / Pout). For amplitude or voltage, use 20 log10(Ain / Aout). If you are given an attenuation coefficient in dB km-1, multiply it by the length in km to get the total attenuation in dB. Then rearrange the equation to find the unknown power or amplitude. Always check whether the question gives power or amplitude, because using the wrong factor of 10 or 20 is a common source of error.
    What is total internal reflection and how does it keep light inside an optical fibre?
    Total internal reflection occurs when light travelling in a medium of higher refractive index meets a boundary with a medium of lower refractive index at an angle of incidence greater than the critical angle. In an optical fibre, the core has a higher refractive index than the cladding, so light striking the boundary at a shallow enough angle is completely reflected back into the core. This happens repeatedly along the fibre, guiding the light from one end to the other with very little loss. The critical angle is given by sin C = n_cladding / n_core.
    Why do digital signals not suffer from noise as much as analogue signals?
    Noise is added to both analogue and digital signals as they travel. In an analogue signal, the noise is superimposed on the waveform and cannot be removed, so it accumulates with each amplifier and eventually corrupts the signal. In a digital signal, the receiver only needs to distinguish two discrete levels, so as long as the noise is less than half the difference between the levels, the original 1s and 0s can be recovered. At a regenerator, the noisy digital signal is used to produce a clean new pulse, so noise does not accumulate. This is why digital signals can be transmitted over much longer distances without loss of quality.
    What are the main transmission media I need to know for AQA A-level Physics?
    You need to know three main categories. First, metal conductors such as copper twisted pair and coaxial cable, which carry electrical signals and suffer from attenuation and electromagnetic interference. Second, optical fibres, which guide infrared or visible light by total internal reflection and have very low attenuation and high bandwidth. Third, wireless media, including radio waves, microwaves and satellite links, which use free-space propagation and are affected by atmospheric absorption, diffraction and the need for line-of-sight. For each medium you should be able to compare attenuation, dispersion, bandwidth, noise immunity, security and cost.