Skip to topic
    ← Back to course topics

    Sensitivity and frequency response (A-level only) — AQA A-Level Physics

    Teaching note checked against the official specification.

    Sensitivity and frequency response describe how an output device (like a loudspeaker, microphone, or earphone) converts electrical signals into sound (or vice versa) across the audible frequency range. Sensitivity measures the sound intensity produced per unit electrical input, while frequency response shows how uniformly a device reproduces all frequencies from about 20 Hz to 20 kHz.

    Test yourself on Sensitivity and frequency response (A-level only) with AQA A-Level practice questions.

    Start free

    A week of Premium from your first lesson · Then the free plan continues · No card, no charge

    Sensitivity and frequency response (A-level only) explained

    Sensitivity and frequency response (A-level only) covers 3 specification points, including Production and interpretation of equal… and Human perception of relative intensity levels….

    Read the full explanation

    Open a point below for its explanation and revision guidance.

    Production and interpretation of equal loudness curves.

    Equal loudness curves show how the sound intensity level needed for a listener to judge a tone equally loud changes with frequency. To produce them, a reference tone at 1 kHz is set to a chosen level, such as 40 dB, and the listener adjusts a test tone at another frequency until it sounds equally loud; repeating this across frequencies gives one curve. Each curve joins points of equal perceived loudness, labelled by the 1 kHz level in phons. Interpretation requires reading the vertical gap between a curve and the 1 kHz line: at low and high frequencies the ear is less sensitive, so a larger intensity level is needed. The curves also flatten at high levels, showing that frequency sensitivity matters less for loud sounds.

    Human perception of relative intensity levels and the need for a logarithmic scale to reflect this.

    Human hearing responds to a very wide range of sound intensities, from about 1 × 10⁻¹² W m⁻² at the threshold to around 1 W m⁻² at the pain threshold, a ratio of about 10¹². A linear scale would compress most everyday sounds into a tiny part of the range and make comparisons awkward. The logarithmic decibel scale compresses this range: sound intensity level in dB is 10 log₁₀(I / I₀), where I₀ is 1 × 10⁻¹² W m⁻². Equal ratios of intensity correspond to equal differences in dB, which matches the way loudness is perceived: a sound must increase by roughly a factor of ten in intensity to be heard as about twice as loud. Thus the logarithmic scale reflects relative, rather than absolute, changes in intensity.

    Definition of intensity.

    Intensity is the power transferred per unit area perpendicular to the direction of energy flow, so I = P/A, measured in W m⁻². It is a scalar describing how concentrated a wave's energy is, not the total energy emitted. For a point source radiating uniformly in three dimensions, the same power spreads over a sphere of area 4πr², giving I = P/(4πr²); doubling distance quarters intensity. In hearing contexts, intensity relates to loudness through the decibel scale, where a tenfold intensity increase corresponds to about 10 dB. When a surface is tilted, use the component of area perpendicular to the beam. Always identify the power and the area at right angles to the flow before substituting values.

    Your focus

    1. Describe a procedure using a 1 kHz reference tone and listener adjustments to produce an equal loudness curve.
    2. Interpret an equal loudness curve to compare the intensity levels needed at different frequencies for equal loudness.
    3. Explain how the shape and spacing of equal loudness curves relate to the ear's changing sensitivity with frequency and level.
    Show all 9 objectives
    1. Explain why a logarithmic scale is needed to represent the wide range of audible sound intensities.
    2. Apply the relationship for sound intensity level to compare intensities and decibel values.
    3. Relate equal intensity ratios to equal decibel differences and to the human perception of loudness.
    4. State the definition of intensity as power per unit area perpendicular to energy flow.
    5. Apply I = P/A and I = P/(4πr²) to calculate intensity in straightforward situations.
    6. Explain how intensity changes with distance from a point source and relate this to loudness.

    Which command word is this?

    Give a precise, formal statement of the quantity, including its units and any necessary conditions (e.g., 'Sensitivity is the sound intensity level produced per watt of input power, measured at a distance of 1 m, in dB/W at 1 m.').

    Sensitivity and frequency response (A-level only) exam tips

    Topic Overview

    Sensitivity and frequency response are key specifications for any device that converts between electrical signals and sound, such as loudspeakers, microphones, and earphones. Sensitivity tells you how efficiently a device converts electrical power into sound intensity, usually quoted in decibels per watt at a distance of 1 metre. Frequency response describes how the output intensity varies with frequency across the audible range (20 Hz to 20 kHz), often shown as a graph of relative intensity against frequency.

    Understanding these concepts is essential for evaluating audio equipment and for explaining why some devices sound 'better' than others. In AQA A-Level Physics, you need to interpret frequency response graphs, perform calculations involving sensitivity and the inverse square law for sound intensity, and explain the effects of resonance and non-uniform response. This topic builds on your knowledge of waves, intensity, and the decibel scale, and it connects to practical applications in music technology and acoustics.

    Key Concepts
    • →Sensitivity is defined as the sound intensity level produced per unit electrical input power, typically measured in dB/W at 1 m. A higher sensitivity means the device produces more sound for the same input power.
    • →Frequency response is a graph showing how the sound intensity level (or relative output) varies with frequency. A flat frequency response means all audible frequencies are reproduced equally, which is ideal for high-fidelity audio.
    • →Resonances in a device cause peaks in the frequency response at specific frequencies, leading to over-emphasis of those frequencies. Dips occur where the device is less efficient at converting energy.
    • →The decibel scale is logarithmic: a change of +10 dB corresponds to a tenfold increase in intensity. When combining changes (e.g., due to power and distance), you add or subtract decibels.
    • →Sound intensity follows an inverse square law: I proportional to 1/r^2 for a point source radiating uniformly. This means doubling the distance reduces intensity to one quarter, a change of -6 dB.
    Marking Points
    • State that a reference tone, usually 1 kHz, is set to a fixed sound intensity level and the listener adjusts a comparison tone until the two are judged equally loud.
    • Describe repeating the adjustment at many frequencies to obtain a set of points that form one equal loudness curve.
    • Explain that each curve is labelled by the sound intensity level of the 1 kHz reference, measured in phons, so the curve represents one perceived loudness.
    • Interpret a curve by comparing the required intensity level at a given frequency with the value at 1 kHz, noting that greater sensitivity means a lower required level.
    • Use the curves to explain why low and high frequency tones need higher intensity levels than a 1 kHz tone to be perceived as equally loud at moderate levels.
    • Recognise that the curves become flatter at higher levels, so the ear's relative sensitivity to frequency is less pronounced for loud sounds.
    • State that the ear detects sound intensities spanning many orders of magnitude, so a linear intensity scale would be unwieldy.
    • Define sound intensity level using the logarithmic relationship 10 log₁₀(I / I₀), with I₀ equal to 1 × 10⁻¹² W m⁻².
    • Explain that equal ratios of intensity produce equal differences in decibels, so the scale reflects relative changes in intensity.
    • Relate the logarithmic scale to perception by noting that a tenfold increase in intensity corresponds to an increase of 10 dB and is heard as a modest change in loudness.
    • Use the scale to compare sounds, for example recognising that 60 dB is 10³ times the intensity of 30 dB because the difference is 30 dB.
    • States that intensity is power per unit area, with area measured perpendicular to the direction of energy transfer.
    • Recalls the equation I = P/A and uses consistent units, typically W m⁻².
    • Applies the inverse-square relationship I = P/(4πr²) for a point source radiating uniformly in all directions.
    • Explains that intensity decreases with distance because the same power is spread over an increasing spherical surface area.
    • Distinguishes intensity from total power: a source may emit constant power while intensity at a detector falls with distance.
    • Uses the decibel relationship qualitatively or quantitatively to link intensity ratios to loudness changes.
    Examiner Tips
    • 💡When describing production, name the reference frequency and explain the listener's adjustment task rather than describing a purely instrumental measurement.
    • 💡When interpreting, quote a frequency and read the corresponding intensity level from the curve, then compare it with the 1 kHz value to support the conclusion.
    • 💡Use the flattening of the curves at high levels to explain why loudness perception depends less on frequency for loud sounds.
    • 💡Quote the logarithmic equation and the reference intensity when explaining why the decibel scale is used.
    • 💡Convert between intensity ratios and dB differences by using powers of ten, for example a 20 dB difference corresponds to an intensity ratio of 10².
    • 💡Link the mathematical compression of the scale to the everyday observation that very large intensity changes are heard as moderate loudness changes.
    • 💡Write the defining equation before substituting numbers so the power and perpendicular area are clearly identified.
    • 💡When a question mentions a point source, check whether the inverse-square law applies before calculating.
    • 💡Convert distances to metres and areas to square metres before evaluating intensity to avoid unit errors.
    • 💡Link any calculated intensity ratio to the decibel scale if the question asks about loudness or hearing.
    • 💡Always state the units when quoting sensitivity (dB/W at 1 m) and frequency (Hz). Marks are often awarded for correct units in definitions and calculations.
    • 💡When describing a frequency response graph, comment on specific features: peaks (resonances), dips, and the overall range. Use terms like 'flat response', 'resonant peak', and 'attenuation'.
    • 💡In calculations involving distance, remember the inverse square law and that a halving of distance increases intensity by a factor of 4 (+6 dB), while doubling distance reduces it by a factor of 4 (-6 dB). Show your working clearly.
    Common Mistakes
    • Treating an equal loudness curve as a graph of loudness against frequency; correct this by identifying the axes as sound intensity level against frequency, with each curve representing constant perceived loudness.
    • Assuming that equal sound intensity level always means equal loudness; correct this by using the curves to show that equal loudness generally requires different intensity levels at different frequencies.
    • Reading the phon label as a frequency or as a sound intensity level in dB; correct this by stating that the phon value is the sound intensity level of the 1 kHz reference tone for that curve.
    • Treating the decibel value as directly proportional to intensity; correct this by using the logarithmic relationship and noting that equal dB differences correspond to equal intensity ratios.
    • Using the wrong reference intensity or omitting I₀ when calculating sound intensity level; correct this by stating that I₀ is 1 × 10⁻¹² W m⁻².
    • Assuming a 10 dB increase doubles loudness; correct this by explaining that a tenfold intensity increase of 10 dB is perceived as only a moderate loudness change, often described as roughly a doubling of perceived loudness.
    • Using the total surface area of a sphere but forgetting the factor 4π, writing I = P/r²; the corrected form is I = P/(4πr²).
    • Treating intensity as a vector and giving a direction; intensity is a scalar, although energy flow has a direction.
    • Using the full area of a tilted surface rather than its component perpendicular to the beam; the corrected approach uses A cos θ.
    • Confusing intensity with amplitude; intensity is proportional to amplitude squared for a given wave.
    • Students often think that a high sensitivity means a flat frequency response. Correction: Sensitivity is a single number indicating overall loudness for a given input, while frequency response shows how that loudness varies with frequency. A device can be very sensitive but have a very uneven response.
    • Students may assume that a frequency response graph is plotted on a linear frequency axis. Correction: Frequency axes are almost always logarithmic, so equal intervals represent multiplying by 10 (e.g., 10 Hz to 100 Hz is the same visual distance as 100 Hz to 1000 Hz). This affects how you interpret the shape.
    • Students sometimes forget that the decibel scale is logarithmic when calculating changes. Correction: You cannot simply add or subtract intensity values; you must convert to decibels using 10 log10(I/I0) or use the fact that multiplying intensity by a factor adds 10 log10(factor) dB.
    Revision Plan
    1. 1Start by revising the definitions of sensitivity and frequency response. Write them out and ensure you can state the units and typical values for common devices.
    2. 2Practice interpreting frequency response graphs. Find examples online or in textbooks and describe the features (peaks, dips, range) in writing. Focus on the logarithmic frequency axis.
    3. 3Work through calculations involving sensitivity, power, and distance. Use the inverse square law and decibel changes. Check your answers with a peer or teacher.
    4. 4Create a set of flashcards for key terms and formulas. Test yourself on the relationships between intensity, power, distance, and decibels.
    5. 5Attempt past paper questions on this topic. Mark your answers using the mark scheme and note where you lost marks, especially for explanations and graph interpretation.
    Exam Question Types
    • 📋Definition and explanation questions: e.g., 'Define sensitivity and explain what is meant by a flat frequency response.' Advice: Give precise definitions with units, and explain that flat means equal output across frequencies.
    • 📋Graph interpretation: e.g., 'The graph shows the frequency response of a microphone. Describe and explain two features of the graph.' Advice: Identify peaks/dips, relate to resonance, and comment on the logarithmic axis.
    • 📋Calculation questions: e.g., 'Calculate the sound intensity level at a given distance from a loudspeaker of known sensitivity and input power.' Advice: Use the inverse square law and decibel addition/subtraction; show all steps.
    • 📋Practical application: e.g., 'Explain why a loudspeaker with a peak at 100 Hz might be unsuitable for high-fidelity music reproduction.' Advice: Link the peak to over-emphasis of bass frequencies and distortion of the original sound.
    Command Word Expectations (AQA)
    Define

    Give a precise, formal statement of the quantity, including its units and any necessary conditions (e.g., 'Sensitivity is the sound intensity level produced per watt of input power, measured at a distance of 1 m, in dB/W at 1 m.').

    Explain

    Provide a reasoned account that links cause and effect. For example, 'Explain why the frequency response graph has a peak at 100 Hz' requires stating that it is due to resonance and describing the consequence (over-emphasis of that frequency).

    Calculate

    Show your working, substitute numbers into the correct formula, and give the final answer with appropriate units and significant figures. Marks are awarded for correct method and answer.

    Describe

    Give a detailed account of the features or trends without necessarily explaining why. For a graph, state the shape, identify peaks and dips, and mention the frequency range.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students confuse sensitivity with frequency response, or they think a high sensitivity automatically means a flat frequency response.
    ❌ Weak Answer (Loses Marks):A high sensitivity means the speaker is loud at all frequencies, so it has a good frequency response.
    Example improved answer:Sensitivity is a measure of the sound intensity produced for a given electrical input power (usually quoted in dB/W at 1 m). Frequency response is a graph showing how the output sound intensity varies with frequency. A device can be very sensitive (loud) but have a very uneven frequency response, meaning some frequencies are reproduced much more loudly than others.
    Examiner Tip: Always define both terms separately and state the units. Use the phrase 'sound intensity per unit input power' for sensitivity and 'variation of output with frequency' for frequency response.
    Pitfall: When interpreting a frequency response graph, students often ignore the logarithmic frequency axis or fail to identify the resonant peak and its effect.
    ❌ Weak Answer (Loses Marks):The graph shows the speaker is loudest at 100 Hz, so it is a good speaker.
    Example improved answer:The frequency response curve peaks at around 100 Hz, which indicates a mechanical resonance of the speaker cone at that frequency. This means sounds at 100 Hz will be over-emphasised relative to other frequencies, so the speaker does not reproduce all frequencies equally. A flat response is desirable for high-fidelity reproduction.
    Examiner Tip: Always comment on the shape of the graph: peaks indicate resonance and uneven reproduction; a flat line indicates uniform response. Mention that the frequency axis is logarithmic, so equal distances represent multiplying by 10.
    Step-by-Step Worked Solutions

    Question: A loudspeaker has a sensitivity of 90 dB/W at 1 m. Calculate the sound intensity level at a distance of 4 m when the input power is 2 W. Assume the speaker radiates uniformly in all directions and that the reference intensity is 1 x 10^-12 W/m^2.

    1. 1.Step 1: Identify given facts: sensitivity = 90 dB/W at 1 m, input power = 2 W, distance = 4 m. The sensitivity means that for 1 W input, the intensity level at 1 m is 90 dB.
    2. 2.Step 2: Calculate the intensity level at 1 m for 2 W input. Since intensity is proportional to power, doubling the power increases intensity by a factor of 2. In decibels, this is an increase of 10 log10(2) = 3.01 dB. So intensity level at 1 m = 90 + 3.01 = 93.01 dB.
    3. 3.Step 3: Account for distance. Intensity follows an inverse square law: I proportional to 1/r^2. At 4 m, the distance is 4 times greater than 1 m, so intensity is (1/4)^2 = 1/16 of the value at 1 m. In decibels, this is a change of 10 log10(1/16) = -12.04 dB. Therefore, intensity level at 4 m = 93.01 - 12.04 = 80.97 dB.
    4. 4.Step 4: Round to an appropriate number of significant figures (2 or 3). Final answer: 81 dB (or 80.97 dB).
    Final Answer: The sound intensity level at 4 m is approximately 81 dB.

    Question: The frequency response graph of a microphone shows a peak of +6 dB at 5 kHz and a dip of -4 dB at 100 Hz relative to the 1 kHz reference level. Explain what these features mean for the reproduction of sound and suggest one practical consequence for recording music.

    1. 1.Step 1: Identify the key features: a peak of +6 dB at 5 kHz means the microphone produces a signal that is 6 dB higher in intensity at 5 kHz compared to 1 kHz for the same sound input. A dip of -4 dB at 100 Hz means it produces a signal 4 dB lower at 100 Hz.
    2. 2.Step 2: Interpret in terms of frequency response: The microphone does not have a flat response; it emphasises high frequencies around 5 kHz and attenuates low frequencies around 100 Hz.
    3. 3.Step 3: Relate to sound reproduction: This will make sounds with high-frequency components (e.g., cymbals, sibilance in vocals) sound louder or brighter, while bass instruments (e.g., bass drum, bass guitar) will sound weaker or thinner.
    4. 4.Step 4: Practical consequence: When recording a bass-heavy instrument, the recording may lack depth and require equalisation to boost low frequencies. Conversely, vocals may sound overly bright and need de-essing or high-frequency reduction.
    Final Answer: The microphone boosts 5 kHz by 6 dB and cuts 100 Hz by 4 dB, leading to a bright, thin sound; for recording, this may require equalisation to compensate for the uneven response.
    Active Recall Memory Test
    What is the definition of sensitivity for a loudspeaker?
    Key Fact: Sensitivity is the sound intensity level produced per unit electrical input power, measured at a distance of 1 m, typically in dB/W at 1 m.
    What does a flat frequency response indicate about a device?
    Key Fact: It means the device reproduces all audible frequencies with equal intensity, providing accurate and faithful sound reproduction.
    How does sound intensity change with distance from a point source?
    Key Fact: Intensity follows an inverse square law: I proportional to 1/r^2. Doubling the distance reduces intensity to one quarter, a change of -6 dB.
    What causes peaks in a frequency response graph?
    Key Fact: Peaks are caused by mechanical or acoustic resonances in the device, where it vibrates more easily at certain frequencies, leading to over-emphasis.
    Frequently Asked Questions
    What is the difference between sensitivity and frequency response?
    Sensitivity is a single number that tells you how loud a device will be for a given electrical input power, usually in dB/W at 1 m. Frequency response is a graph showing how that loudness varies across different frequencies. A device can be very sensitive but have an uneven frequency response, meaning some frequencies are louder than others.
    Why is a flat frequency response desirable?
    A flat frequency response means the device reproduces all audible frequencies with equal intensity, without adding or removing anything from the original sound. This is ideal for high-fidelity audio, as it ensures accurate and natural reproduction of music and speech.
    How do I calculate sound intensity level at a distance?
    First, use the sensitivity to find the intensity level at 1 m for the given input power. Then apply the inverse square law: intensity is proportional to 1/r^2. For each doubling of distance, subtract 6 dB; for each halving, add 6 dB. Alternatively, use the formula 10 log10(I/I0) with I calculated from power and distance.
    What does a peak in a frequency response graph mean?
    A peak indicates that the device produces a higher sound intensity at that frequency compared to others. This is usually due to resonance, where the device vibrates more readily at that frequency. It means sounds at that frequency will be over-emphasised, potentially making the audio sound unnatural.
    Why is the frequency axis on a frequency response graph logarithmic?
    Human hearing perceives frequency logarithmically, meaning we detect equal ratios (e.g., 100 Hz to 200 Hz) as equal pitch intervals. A logarithmic axis allows a wide range of frequencies (20 Hz to 20 kHz) to be displayed clearly and matches how we hear sound.
    Can a loudspeaker have high sensitivity but poor frequency response?
    Yes, absolutely. Sensitivity is about overall efficiency, while frequency response is about consistency across frequencies. A speaker could be very efficient (high sensitivity) but have large peaks and dips in its response, meaning some frequencies are much louder than others. This would make it unsuitable for accurate sound reproduction.