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    Stationary waves — OCR A-Level Physics

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    Stationary waves explained

    Stationary waves covers 10 specification points, including (a) stationary and (standing) waves using microwaves, stretched….

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    Open a point below for its explanation and revision guidance.

    (a) stationary

    A stationary wave forms when two progressive waves of the same frequency and similar amplitude travel in opposite directions through the same medium and superpose. Energy is not transferred along the wave; instead it is stored, oscillating between kinetic and potential forms. The pattern has fixed nodes, where displacement is always zero, and antinodes, where displacement varies with maximum amplitude. Adjacent nodes are separated by half a wavelength, λ/2, and the node-to-antinode distance is λ/4. For example, a stretched string fixed at both ends reflects waves so that the reflected and incident waves superpose, producing a stationary wave whose allowed frequencies depend on the string length and tension.

    (standing) waves using microwaves, stretched strings and air columns

    Stationary waves form by the superposition of two progressive waves of the same frequency travelling in opposite directions. With microwaves, a transmitter directs waves at a metal plate; the reflected wave superposes with the incident wave, and a probe detects nodes and antinodes spaced λ/2 apart. On a stretched string fixed at both ends, boundary conditions dictate that nodes form at the ends. The allowed wavelengths depend only on the string's length (L) and harmonic number (n), given by λ = 2L/n. The string's tension and mass per unit length determine the wave speed and frequency, but not the wavelength of a given mode. In air columns, closed ends form displacement nodes and open ends form antinodes.

    (b) graphical representations of a stationary wave

    A stationary wave can be represented graphically in two ways. A displacement–position graph at a fixed instant shows the wave envelope: a sine or cosine curve with regularly spaced nodes and antinodes, where the curve crosses the axis at nodes and reaches maxima at antinodes. A displacement–time graph for a single point shows simple harmonic oscillation whose amplitude depends on the point's position: zero at a node, maximum at an antinode. Adjacent points between nodes oscillate in phase, while points on opposite sides of a node are in antiphase. For example, on a string fixed at both ends, the fundamental mode has nodes at the ends and one antinode at the centre, and its displacement–position graph is a single half-sine curve.

    (c) similarities and the differences between stationary and progressive waves

    Stationary and progressive waves share several features: both arise from oscillations, both have frequency, wavelength and amplitude, and both can be described by wave equations. They differ in key ways. A progressive wave transfers energy through the medium and its waveform moves; a stationary wave stores energy and its pattern stays in fixed positions. In a progressive wave all points oscillate with the same amplitude and neighbouring points have a continuously changing phase difference; in a stationary wave amplitude varies from zero at nodes to maximum at antinodes, and points between adjacent nodes oscillate in phase. For example, a travelling sound wave from a loudspeaker is progressive, whereas the pattern formed by reflection in a tube is stationary.

    (d) nodes and antinodes

    A stationary wave forms when two identical progressive waves travelling in opposite directions superpose. At a node the two displacements always cancel, so the resultant displacement stays zero and the point never moves. At an antinode the two displacements always reinforce, so the resultant displacement oscillates with maximum amplitude. Nodes and antinodes are fixed in space, spaced half a wavelength apart, and adjacent nodes and antinodes are separated by one quarter of a wavelength. Energy is not transferred past a node; it is stored between nodes. For a string fixed at both ends, the ends must be nodes, so the shortest pattern has one antinode at the centre.

    (e)

    This row is a specification sub-heading marker rather than a taught statement, so treat it as a signpost to the practical work that follows. Read it as the point where the stationary-wave theory of nodes, antinodes and patterns is applied experimentally. The learner should use this heading to organise revision: first secure the theory of stationary waves, then study the techniques and procedures for determining the speed of sound in air using a resonance tube. When reading the specification, note that the sub-heading itself carries no separate content to memorise; the assessable material sits in the statements beneath it. Use the heading to build a checklist linking theory to practical method.

    (i) stationary wave patterns for a stretched string and air columns in closed and open tubes

    Stationary-wave patterns depend on the boundary conditions. A stretched string fixed at both ends has nodes at both ends, so its wavelengths are given by L = nλ/2, where n is a whole number of half-wavelengths. An open tube has antinodes at both open ends, giving the same relationship L = nλ/2. A closed tube has a node at the closed end and an antinode at the open end, so the shortest pattern is a quarter wavelength: L = (2n − 1)λ/4. These patterns determine the resonant frequencies, and the end correction must be added to the measured length for real tubes.

    (ii) techniques and procedures used to determine the speed of sound in air by formation of stationary waves in a resonance tube

    A resonance tube is filled with water so the air column length can be varied. A tuning fork of known frequency f is held over the open end, and the air column is adjusted until a loud resonance is heard. At resonance a stationary wave forms with a node at the water surface and an antinode near the open end, so the first resonance length L₁ ≈ λ/4 and the second L₂ ≈ 3λ/4. The difference L₂ − L₁ = λ/2 removes the end correction, giving λ = 2(L₂ − L₁). The speed of sound follows from v = fλ. Repeating with several tuning forks and plotting L against 1/f allows a more reliable value.

    (f) the idea that the separation between adjacent nodes (or antinodes) is equal to /2 m , where m is the wavelength of the progressive wave

    A stationary wave forms when two progressive waves of the same frequency and similar amplitude travel in opposite directions through the same medium. The pattern has fixed nodes, where displacement is always zero, and antinodes, where displacement varies with maximum amplitude. The key relationship is that the distance between one node and the next node is half a wavelength, λ/2. The same spacing applies between adjacent antinodes. For example, if a microwave stationary wave has nodes 1.5 cm apart, then λ/2 = 1.5 cm, so λ = 3.0 cm. This spacing arises because the wave must travel one full wavelength to return to the same phase, and a node-to-node path corresponds to half that cycle. Students should measure across several node spacings and divide to reduce uncertainty.

    (g) fundamental mode of vibration (1st harmonic); harmonics.

    A stationary wave on a stretched string or in a pipe can vibrate in several distinct patterns called harmonics. The simplest pattern is the fundamental mode, also called the first harmonic. For a string fixed at both ends, the fundamental has one antinode in the middle and nodes at each end, so the string length L equals λ/2. The second harmonic has two antinodes and L = λ, the third harmonic has three antinodes and L = 3λ/2, and so on. In general, for a string fixed at both ends, L = nλ/2 where n is the harmonic number. The frequency of each harmonic is an integer multiple of the fundamental frequency: f_n = nf_1. For a pipe open at both ends, the pattern is similar, but a pipe closed at one end has only odd harmonics. Students should be able to identify the harmonic number from a diagram by counting antinodes or half-wavelengths.

    Your focus

    1. Describe how a stationary wave is formed by superposition of two progressive waves travelling in opposite directions.
    2. Distinguish between nodes and antinodes in terms of displacement and amplitude.
    3. Apply the relationships node-to-node = λ/2 and node-to-antinode = λ/4 to simple stationary wave patterns.
    Show all 30 objectives
    1. Describe how to demonstrate stationary waves using microwaves, stretched strings, and air columns.
    2. Explain that the wavelength of a stationary wave on a fixed string depends on its length, while tension affects wave speed.
    3. Calculate wavelength from the spacing of nodes or antinodes in experimental demonstrations.
    4. Interpret displacement–position graphs of stationary waves, identifying nodes, antinodes and wavelength.
    5. Interpret displacement–time graphs for individual points on a stationary wave.
    6. Describe phase relationships between points on either side of a node.
    7. State similarities between stationary and progressive waves in terms of oscillation and wave quantities.
    8. Explain differences in energy transfer, amplitude variation and pattern movement.
    9. Describe phase relationships in progressive and stationary waves using correct terminology.
    10. Define a node and an antinode in terms of resultant displacement.
    11. Relate node and antinode spacing to the wavelength.
    12. Identify nodes and antinodes on a given stationary wave pattern.
    13. Recognise that the sub-heading is a signpost, not a separate taught fact.
    14. Organise revision around the statements that follow the heading.
    15. Connect stationary-wave theory to the resonance-tube practical.
    16. Draw stationary-wave patterns for strings, open tubes and closed tubes.
    17. Derive the length–wavelength relationship for each boundary condition.
    18. Compare fundamental frequencies of open and closed tubes of equal length.
    19. Describe the procedure for finding resonance lengths in a tube.
    20. Use two resonance lengths to determine the wavelength of sound in air.
    21. Calculate the speed of sound from frequency and wavelength.
    22. Describe the formation of a stationary wave from two progressive waves.
    23. State the relationship between adjacent node separation and wavelength.
    24. Calculate wavelength from measurements of node or antinode spacing.
    25. Define the fundamental mode of vibration and identify it as the first harmonic.
    26. Relate the harmonic number to the number of antinodes and the length of the medium.
    27. Distinguish between harmonics supported by strings and pipes with different boundary conditions.

    Stationary waves exam tips

    Marking Points
    • A stationary wave is produced by the superposition of two progressive waves of the same frequency travelling in opposite directions.
    • Nodes are points of permanently zero displacement; antinodes are points of maximum displacement amplitude.
    • The separation between adjacent nodes is λ/2 and between a node and the nearest antinode is λ/4.
    • No net energy is transferred along a stationary wave; energy oscillates between kinetic and potential stores.
    • The boundary conditions of the medium, such as fixed ends of a string, determine which stationary wave patterns can form.
    • Stationary waves form when incident and reflected waves of the same frequency superpose.
    • In a microwave experiment, a metal reflector creates the reflected wave, and a detector locates nodes and antinodes spaced λ/2 apart.
    • For a stretched string fixed at both ends, the allowed wavelengths are determined by the string length and harmonic number (λ = 2L/n).
    • The tension and mass per unit length of a string affect the wave speed and frequency, but do not change the wavelength of a specific harmonic mode.
    • In air columns, a closed end acts as a displacement node and an open end acts as a displacement antinode.
    • A displacement–position graph at an instant shows the stationary wave envelope with nodes at zero displacement and antinodes at maximum displacement.
    • A displacement–time graph for a chosen point shows simple harmonic oscillation with amplitude set by the point's position.
    • Adjacent points between two nodes oscillate in phase; points on opposite sides of a node are in antiphase.
    • Node-to-node spacing on the graph is λ/2 and node-to-antinode spacing is λ/4.
    • The number of half-wavelengths fitting the boundary conditions identifies the mode of vibration.
    • Similarity: both involve oscillations and can be described using frequency, wavelength and amplitude.
    • Difference: a progressive wave transfers energy through the medium, while a stationary wave stores energy without net transfer.
    • Difference: a progressive wave has the same amplitude at all points, whereas a stationary wave has zero amplitude at nodes and maximum at antinodes.
    • Difference: a progressive wave's waveform moves through space, while a stationary wave's nodes and antinodes remain in fixed positions.
    • Difference: phase relationships vary continuously along a progressive wave, but points between adjacent nodes of a stationary wave oscillate in phase.
    • A node is a point of permanently zero resultant displacement where two waves always cancel.
    • An antinode is a point of maximum resultant displacement where two waves always reinforce.
    • Nodes and antinodes are stationary in position, unlike the travelling wave crests.
    • Adjacent nodes are separated by λ/2; a node and the next antinode are separated by λ/4.
    • No net energy transfer occurs past a node in a stationary wave.
    • A stretched string fixed at both ends has nodes at both ends and L = nλ/2.
    • An open tube has antinodes at both open ends and L = nλ/2.
    • A closed tube has a node at the closed end and an antinode at the open end, giving L = (2n − 1)λ/4.
    • The fundamental frequency of a closed tube is half that of an open tube of the same length.
    • An end correction must be added to the measured tube length to account for the antinode lying just outside the open end.
    • Set up a resonance tube with a variable air column and a tuning fork of known frequency.
    • Adjust the air column until a loud resonance is heard, indicating a stationary wave.
    • Identify the node at the water surface and the antinode near the open end.
    • Use the first and second resonance lengths so that L₂ − L₁ = λ/2, eliminating the end correction.
    • Calculate the speed of sound from v = fλ using the measured wavelength and known frequency.
    • Repeat with different tuning forks and plot a suitable graph to improve reliability.
    • States that the separation between adjacent nodes is λ/2.
    • States that the separation between adjacent antinodes is also λ/2.
    • Explains that a stationary wave is formed by two progressive waves of the same frequency travelling in opposite directions.
    • Uses the relationship λ = 2 × (node separation) to calculate wavelength.
    • Recognises that nodes are points of zero displacement and antinodes are points of maximum displacement.
    • Defines the fundamental mode (first harmonic) as the lowest frequency stationary wave pattern.
    • States that for a string fixed at both ends, the fundamental has L = λ/2.
    • Identifies that the nth harmonic has n antinodes and L = nλ/2 for a string fixed at both ends.
    • States that harmonic frequencies are integer multiples of the fundamental frequency.
    • Recognises that a pipe closed at one end supports only odd harmonics.
    Examiner Tips
    • 💡Sketch the envelope of the stationary wave and label nodes and antinodes before answering.
    • 💡Use the relationships node-to-node = λ/2 and node-to-antinode = λ/4 to check numerical options.
    • 💡Eliminate options that claim energy is transferred along the wave or that the pattern moves.
    • 💡When calculating wavelength from a microwave interference pattern, remember to double the distance between adjacent nodes.
    • 💡For string experiments, use λ = 2L/n to find wavelength, then apply v = fλ to link it to wave speed and frequency.
    • 💡Clearly state the boundary conditions (e.g., nodes at fixed ends) when explaining the formation of stationary waves on a string.
    • 💡Label nodes and antinodes on any sketch before interpreting the graph.
    • 💡Use the graph to read node-to-node spacing and convert to wavelength using λ = 2 × spacing.
    • 💡For displacement–time graphs, check the amplitude against the point's position on the envelope.
    • 💡Structure comparison answers as similarities first, then differences, using clear paired statements.
    • 💡Use precise terms such as node, antinode, in phase, antiphase and energy transfer.
    • 💡Support each difference with a brief example, such as a travelling sound wave versus a reflected stationary wave.
    • 💡Sketch the envelope of the stationary wave and mark nodes where the envelope touches zero.
    • 💡Count node-to-node gaps and multiply by two to find the wavelength before substituting into v = fλ.
    • 💡Check whether the boundary is fixed (node) or free (antinode) before choosing the pattern.
    • 💡State clearly that nodes arise from cancellation and antinodes from reinforcement.
    • 💡Use the sub-heading as a revision checklist: theory first, then the practical technique beneath it.
    • 💡When reading the specification, highlight the statements that follow the heading rather than the heading itself.
    • 💡Link each practical step back to a node or antinode condition so explanations are physical, not just procedural.
    • 💡Sketch the pattern first, marking nodes and antinodes, then write the length in terms of λ.
    • 💡Check each boundary: fixed or closed gives a node, open or free gives an antinode.
    • 💡Include the end correction when comparing measured resonance lengths with theory.
    • 💡Use the harmonic number to check whether the pattern is the fundamental or an overtone.
    • 💡Describe the procedure in logical order: set up, adjust, listen for resonance, measure, repeat.
    • 💡State clearly that the difference of two resonance lengths removes the end correction.
    • 💡Show the substitution into v = fλ with consistent SI units.
    • 💡Explain how repeating with several frequencies and plotting a graph improves the result.
    • 💡Sketch the stationary wave pattern and label nodes and antinodes before substituting values.
    • 💡If a question gives the distance between the first and fifth node, count the number of half-wavelength intervals (four) and divide accordingly.
    • 💡Check units carefully: convert cm to m before calculating wavelength in metres.
    • 💡Use the phrase 'adjacent nodes are separated by half a wavelength' in explanations to secure the mark.
    • 💡Count antinodes to identify the harmonic number quickly in diagram questions.
    • 💡Write the general relationship L = nλ/2 and rearrange before substituting numbers.
    • 💡For closed pipes, remember the sequence 1st, 3rd, 5th harmonic and use odd values of n.
    • 💡Check whether the question asks for frequency, wavelength or harmonic number and give the correct quantity with units.
    Common Mistakes
    • Thinking a stationary wave travels along the medium: correct this by stressing that the pattern stays in fixed positions while individual particles oscillate.
    • Confusing nodes with points of maximum amplitude: correct this by defining a node as permanently zero displacement and an antinode as maximum amplitude.
    • Believing energy is transported along a stationary wave: correct this by explaining that energy is stored and exchanged between kinetic and potential forms within the pattern.
    • Stating that the wavelength of a stationary wave on a fixed string depends on tension: wavelength is fixed by the string length and harmonic; tension changes the wave speed and frequency.
    • Assuming the distance between adjacent nodes is a full wavelength: the node-to-node distance is exactly half a wavelength (λ/2).
    • Confusing displacement and pressure nodes in air columns: a closed end is a displacement node but a pressure antinode.
    • Reading a displacement–position graph as if the wave were travelling: correct this by noting that the envelope is fixed in space and only the displacements change with time.
    • Assuming all points on a stationary wave oscillate in phase: correct this by identifying phase differences between adjacent segments separated by nodes.
    • Confusing the amplitude of a point with the amplitude of the whole wave: correct this by stating that amplitude varies from zero at nodes to maximum at antinodes.
    • Claiming stationary waves transfer energy like progressive waves: correct this by stating that stationary waves store energy and show no net energy transfer.
    • Saying all points on a stationary wave have equal amplitude: correct this by describing amplitude variation from zero at nodes to maximum at antinodes.
    • Treating the stationary wave pattern as moving: correct this by emphasising that nodes and antinodes occupy fixed positions.
    • Thinking nodes are points that move slowly: nodes never move, because the two displacements cancel at every instant.
    • Confusing node spacing with wavelength: the node-to-node distance is λ/2, not λ.
    • Believing energy travels along the whole stationary wave: energy is stored between nodes and is not transferred past a node.
    • Assuming an antinode is always a displacement maximum at every instant: the antinode oscillates between positive and negative maximum displacement.
    • Treating the sub-heading as a separate fact to memorise: it is a signpost, and the assessable content is in the statements that follow it.
    • Skipping the practical statements because the heading looks empty: the resonance-tube technique is examinable and must be learned.
    • Learning the practical method without the underlying stationary-wave theory: the two must be linked so that node and antinode positions explain the resonance condition.
    • Using L = nλ/2 for a closed tube: a closed tube has a node at one end and an antinode at the other, so L = (2n − 1)λ/4.
    • Placing an antinode at the closed end of a tube: the closed end must be a node because the air cannot move there.
    • Forgetting the end correction: the antinode forms slightly outside the open end, so the effective length is longer than the measured length.
    • Assuming an open tube and a closed tube of equal length have the same fundamental frequency: the closed tube has half the fundamental frequency.
    • Using a single resonance length and ignoring the end correction: use two resonance lengths and their difference to remove it.
    • Placing the antinode exactly at the open end: the antinode lies slightly outside, which is why the end correction is needed.
    • Assuming the first resonance length equals a full wavelength: it is approximately λ/4.
    • Forgetting to convert lengths to metres before calculating v = fλ: measurements in centimetres must be divided by 100.
    • Confusing node separation with a full wavelength: the distance between adjacent nodes is λ/2, not λ.
    • Thinking that the distance from a node to the next antinode is λ/2: it is actually λ/4.
    • Assuming that all points between nodes vibrate with the same amplitude: amplitude varies from zero at nodes to maximum at antinodes.
    • Measuring only one node spacing and treating it as the wavelength without doubling.
    • Confusing the harmonic number with the number of nodes: the nth harmonic has n antinodes and n+1 nodes for a string fixed at both ends.
    • Assuming that a closed pipe supports all harmonics: it supports only odd harmonics.
    • Using L = λ for the fundamental of a string fixed at both ends instead of L = λ/2.
    • Forgetting that the fundamental frequency is the lowest possible frequency, not the highest.