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    Carboxylic acids — AQA GCSE Chemistry

    Verified courseTeaching note checked against the official specification.

    Carboxylic acids are an organic homologous series containing the -COOH functional group that act as weak acids in aqueous solution by partially ionising to release H+ ions. They react typically with carbonates to form a salt, water, and carbon dioxide, and react with alcohols in the presence of an acid catalyst to produce esters.

    Carboxylic acids explained

    Carboxylic acids covers 4 specification points, including Carboxylic acids have the functional group… and The first four members of a homologous series….

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    Open a point below for its explanation and revision guidance.

    Carboxylic acids have the functional group –COOH.

    A functional group is the reactive part of a molecule that gives a homologous series its characteristic properties. In carboxylic acids the functional group is –COOH, a carbon atom joined to an oxygen by a double bond and to an –OH group. The carbon of –COOH is bonded to one other carbon (or to hydrogen in methanoic acid), so the group sits at the end of a chain. Recognising –COOH lets you identify a carboxylic acid from a displayed, structural or molecular formula, and it explains the acidic reactions you meet later: the –OH hydrogen is released as H⁺ in water, giving a weakly acidic solution, and the group reacts with carbonates and alcohols. For example, CH₃COOH contains the –COOH group, so it is ethanoic acid.

    The first four members of a homologous series of carboxylic acids are methanoic acid, ethanoic acid, propanoic acid and butanoic acid.

    A homologous series is a family of compounds with the same functional group, in which each member differs from the next by a CH₂ unit. For carboxylic acids the first four members are methanoic acid (HCOOH), ethanoic acid (CH₃COOH), propanoic acid (CH₃CH₂COOH) and butanoic acid (CH₃CH₂CH₂COOH). Their names use the stem meth-, eth-, prop- or but- for one, two, three or four carbon atoms, followed by '-anoic acid'. Counting carbons includes the carbon of the –COOH group, so ethanoic acid has two carbons in total. As the chain lengthens, the molecules have greater intermolecular forces, so boiling points rise and solubility in water decreases, while the –COOH group still gives the same acidic reactions.

    The structures of carboxylic acids can be represented in the following forms: CHCOOH or Students should be able to: describe what happens when any of the first four carboxylic acids react with carbonates, dissolve in water, react with alcohols (HT only) explain why carboxylic acids are weak acids in terms of ionisation and pH (see Strong and weak acids (HT only) (page 48)).

    Carboxylic acids can be shown as displayed formulae, structural formulae or molecular formulae such as CH₃COOH. Their reactions follow from the –COOH group. With carbonates they fizz, producing a salt, water and carbon dioxide; for example, ethanoic acid plus sodium carbonate gives sodium ethanoate, water and carbon dioxide. In water they dissolve and ionise only slightly, releasing a small number of H⁺ ions, so their pH is higher than that of a strong acid of the same concentration. At higher tier, carboxylic acids react with alcohols to form esters, typically with an acid catalyst. The limited ionisation explains both the weak acidity and the relatively high pH.

    Students should be able to recognise carboxylic acids from their names or from given formulae.

    Recognising a carboxylic acid means spotting the clues in either its name or its formula. In a name, the ending '-anoic acid' signals the –COOH group, and the stem meth-, eth-, prop- or but- gives the number of carbon atoms. In a formula, look for the –COOH unit, which may be written as COOH, CO₂H or drawn with the carbon double-bonded to oxygen and single-bonded to –OH. For example, CH₃CH₂COOH is propanoic acid because it contains –COOH and has three carbon atoms in total. This skill supports later work on reactions with carbonates, water and alcohols, and on explaining weak acidity, because identifying the functional group tells you which reactions to expect.

    Your focus

    1. Identify the –COOH functional group in a given formula or structure.
    2. Describe the atoms and bonds that make up the –COOH group.
    3. Explain how the –COOH group causes carboxylic acids to behave as weak acids in water.
    Show all 12 objectives
    1. Name the first four carboxylic acids from their formulae.
    2. Write the formula of a carboxylic acid from its name.
    3. Describe how members of the series differ by a CH₂ unit and how properties change along the series.
    4. Describe the products formed when a carboxylic acid reacts with a carbonate.
    5. Explain why carboxylic acids are weak acids in terms of ionisation and pH.
    6. Describe, at higher tier, the reaction of a carboxylic acid with an alcohol to form an ester.
    7. Identify a carboxylic acid from the '-anoic acid' ending in its name.
    8. Identify the –COOH group in a given displayed, structural or molecular formula.
    9. Name a carboxylic acid correctly from its formula by counting all carbon atoms.

    Carboxylic acids flashcards

    Card 1 of 10

    Functional group

    Which command word is this?

    Give reasons based on chemical theory, linking causes and effects (e.g., explaining why pH differs by referring to partial vs complete ionisation).

    Carboxylic acids exam tips

    Topic Overview

    Carboxylic acids constitute a homologous series of organic molecules defined by the functional group -COOH, including common compounds such as methanoic acid and ethanoic acid. They exhibit typical acidic properties but are classified as weak acids because they only partially dissociate into hydrogen ions in water.

    This topic bridges organic chemistry with fundamental concepts of acid-base equilibria, preparing students to understand condensation polymerisation and ester formation. In industry and daily life, carboxylic acids are essential in food preservation, vinegar production, pharmaceutical synthesis, and solvents.

    Key Concepts
    • →Functional Group: All carboxylic acids contain the carboxyl group (-COOH), written structurally with a C=O double bond and a C-OH single bond.
    • →Weak Acid Behaviour: Carboxylic acids partially ionise in aqueous solutions, setting up a reversible reaction that yields a lower H+ concentration and higher pH than strong acids of identical concentration.
    • →Reactions with Bases: Carboxylic acids react with carbonates to yield a metal carboxylate salt, water, and carbon dioxide; they react with metals to yield a salt and hydrogen.
    • →Esterification: Carboxylic acids react reversibly with alcohols in the presence of an acid catalyst (e.g. concentrated sulfuric acid) to produce sweet-smelling esters and water.
    Marking Points
    • State that –COOH is the functional group present in every carboxylic acid.
    • Identify the group as a carbon atom double-bonded to an oxygen atom and single-bonded to an –OH group.
    • Explain that the –COOH carbon also bonds to one carbon of the rest of the molecule, or to hydrogen in methanoic acid.
    • Recognise –COOH within a displayed, structural or molecular formula and name the compound as a carboxylic acid.
    • Link the –OH part of –COOH to the release of H⁺ ions in water, giving a weakly acidic solution.
    • Use the group to predict reactions with carbonates and, at higher tier, with alcohols.
    • Name the first four carboxylic acids as methanoic, ethanoic, propanoic and butanoic acid.
    • State that they form a homologous series with the same –COOH functional group.
    • Explain that successive members differ by a CH₂ unit.
    • Use the prefixes meth-, eth-, prop- and but- to show one, two, three and four carbon atoms.
    • Count the –COOH carbon as part of the chain when working out the name.
    • Write the molecular formulae HCOOH, CH₃COOH, CH₃CH₂COOH and CH₃CH₂CH₂COOH.
    • Represent carboxylic acids using displayed, structural or molecular formulae such as CH₃COOH.
    • Describe the reaction with a carbonate as producing a salt, water and carbon dioxide, with effervescence.
    • Name the salt formed from the acid and the metal in the carbonate, for example sodium ethanoate.
    • Describe dissolution in water as forming an acidic solution that ionises only slightly.
    • Explain weak acidity in terms of partial ionisation giving few H⁺ ions and a higher pH than a strong acid.
    • At higher tier, describe reaction with an alcohol to form an ester, usually with an acid catalyst.
    • Recognise the '-anoic acid' ending in a name as showing a carboxylic acid.
    • Use the stem of the name to count the carbon atoms in the chain.
    • Identify the –COOH unit in displayed, structural or molecular formulae.
    • Count the –COOH carbon when working out the name from a formula.
    • Distinguish carboxylic acids from alcohols and esters by the presence of the complete –COOH group.
    • Link recognition of the group to the reactions and weak acidity expected of the compound.
    Examiner Tips
    • 💡When asked to identify a functional group, circle the whole –COOH unit in the formula before naming it.
    • 💡Practise converting between displayed, structural and molecular formulae of the first four carboxylic acids so recognition is quick.
    • 💡If a question asks why a compound is acidic, refer to the –COOH group releasing H⁺ ions in water rather than saying it 'contains acid'.
    • 💡Count every carbon atom, including the one in –COOH, before choosing the stem of the name.
    • 💡Learn the four names and formulae as a sequence so you can move up or down the series by adding or removing CH₂.
    • 💡When comparing members, separate chemical similarity (same –COOH reactions) from physical trends (boiling point and solubility).
    • 💡For carbonate reactions, write the general word equation acid + carbonate → salt + water + carbon dioxide before substituting names.
    • 💡When explaining weak acidity, compare the extent of ionisation and the resulting pH with a strong acid of the same concentration.
    • 💡At higher tier, link the alcohol and acid names directly to the ester name, remembering the acid provides the '-oate' ending.
    • 💡Scan a formula for the –COOH unit first, then count carbons to choose the correct stem.
    • 💡Check names for the '-anoic acid' ending before deciding a compound is a carboxylic acid.
    • 💡Practise mixed examples of alcohols, carboxylic acids and esters so you can justify your identification by the functional group present.
    • 💡Count all carbon atoms when naming carboxylic acids; methanoic has one carbon (HCOOH), ethanoic has two (CH3COOH), and propanoic has three (C2H5COOH).
    • 💡When asked to write an esterification equation, clearly identify that water (H2O) is eliminated alongside the ester product.
    • 💡Use equilibrium arrows (<=>) when writing the aqueous ionisation of carboxylic acids to clearly signify partial, reversible dissociation.
    Common Mistakes
    • Treating –COOH as an alcohol –OH group; correct this by noting that the –OH is attached to a carbon that is also double-bonded to oxygen, which makes the compound acidic rather than an alcohol.
    • Writing the group as COOH without showing the double bond to oxygen; correct this by drawing C double-bonded to O and single-bonded to O–H.
    • Assuming every molecule containing oxygen is a carboxylic acid; correct this by checking for the complete –COOH unit, since esters and alcohols contain oxygen but not this group.
    • Naming CH₃COOH as methanoic acid by counting only the carbon outside –COOH; correct this by counting the –COOH carbon too, giving ethanoic acid.
    • Writing formulae that omit the –COOH carbon from the chain length; correct this by checking the total carbon count against the prefix.
    • Assuming all members have identical physical properties; correct this by noting that boiling point and solubility change as the chain lengthens, even though the functional group is the same.
    • Saying carboxylic acids fully ionise in water; correct this by stating that ionisation is partial, so only a small proportion of molecules release H⁺ ions.
    • Predicting hydrogen gas when a carboxylic acid reacts with a carbonate; correct this by naming carbon dioxide, water and a salt as the products.
    • Confusing the ester product with the alcohol or acid reactant; correct this by identifying the ester formed from the acid and the alcohol, for example ethyl ethanoate from ethanoic acid and ethanol.
    • Mistaking an alcohol for a carboxylic acid because both contain –OH; correct this by checking whether the –OH is part of a –COOH group.
    • Ignoring the –COOH carbon when counting chain length; correct this by including it so the name matches the total number of carbon atoms.
    • Reading a formula such as CH₃COOH as an ester; correct this by identifying the –COOH unit, which is absent from esters.
    • Equating 'weak' with 'dilute': Students often think a weak acid means a solution with lots of water. In reality, 'weak' describes incomplete ionisation, while 'dilute' refers to a low amount of solute per unit volume.
    • Misnaming the salts: Students frequently name the salt produced by ethanoic acid as 'ethanoate acid' or 'ethane salt' instead of using the metal name followed by 'ethanoate' (e.g., sodium ethanoate).
    • Writing incorrect molecular formulas: Forgetting that the carbon in the -COOH functional group counts toward the total carbon chain, leading to errors like writing propanoic acid as C3H7COOH instead of C2H5COOH.
    Revision Plan
    1. 1Day 1-2: Memorise the names, molecular formulas, and displayed structures of the first four carboxylic acids (methanoic, ethanoic, propanoic, butanoic).
    2. 2Day 3-4: Practise writing balanced symbol equations for carboxylic acid reactions with carbonates, oxides, and hydroxides.
    3. 3Day 5: Master the difference between strong vs weak acids and concentrated vs dilute solutions using particle diagrams and pH values.
    4. 4Day 6-7: Complete exam-style questions on ester formation and revise mark schemes for commonly missed terms.
    Exam Question Types
    • 📋Displayed formula drawing: Questions asking you to draw the displayed structure of an named carboxylic acid showing all bonds.
    • 📋Comparison extended response: Comparing the reactions and pH of a strong acid (like HCl) and a weak acid (like CH3COOH) at equal concentrations.
    • 📋Equation writing: Balanced symbol equations involving the reaction of carboxylic acids with carbonates or alcohols.
    Command Word Expectations (AQA)
    Explain

    Give reasons based on chemical theory, linking causes and effects (e.g., explaining why pH differs by referring to partial vs complete ionisation).

    Describe

    State the key facts, patterns, or observations without necessarily explaining the underlying chemical mechanism (e.g., stating bubbles appear and solid dissolves).

    Compare

    Identify both similarities and differences between two chemicals or processes, addressing both subjects systematically rather than discussing just one.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Confusing weak acids with dilute acids when explaining why carboxylic acids react slower than hydrochloric acid.
    ❌ Weak Answer (Loses Marks):Ethanoic acid reacts slower with sodium carbonate because it is less concentrated and diluted with more water.
    Example improved answer:Ethanoic acid is a weak acid because it only partially ionises in aqueous solution, resulting in a lower concentration of H+ ions compared to a strong acid like hydrochloric acid at the same concentration.
    Examiner Tip: Always link the rate of reaction directly to the concentration of aqueous H+ ions caused by partial ionisation rather than using the word dilute.
    Pitfall: Drawing the carboxyl functional group incorrectly, particularly omitting the double bond between carbon and oxygen or attaching hydrogen directly to carbon.
    ❌ Weak Answer (Loses Marks):C-O-O-H drawn in a straight line with all single covalent bonds.
    Example improved answer:A carbon atom double-bonded to an oxygen atom (C=O) and single-bonded to a hydroxyl group (-O-H), with carbon having four total covalent bonds.
    Examiner Tip: Ensure the bond to the hydroxyl group connects from carbon to oxygen, not directly to hydrogen (C-O-H, not C-H-O).
    Step-by-Step Worked Solutions

    Question: A student adds ethanoic acid (CH3COOH) to solid calcium carbonate (CaCO3). Describe the observations, name the salt formed, and write a balanced symbol equation for the reaction.

    1. 1.Step 1: Identify the reaction type. Carboxylic acid + metal carbonate forms a salt + water + carbon dioxide.
    2. 2.Step 2: Note the physical observations. Effervescence or fizzing occurs due to CO2 gas evolution, and the solid calcium carbonate dissolves to leave a colourless solution.
    3. 3.Step 3: Determine the salt formula. Calcium forms Ca2+ ions and ethanoic acid forms ethanoate ions (CH3COO-). Two ethanoate ions balance one calcium ion, yielding (CH3COO)2Ca (calcium ethanoate).
    4. 4.Step 4: Write and balance the chemical equation: 2CH3COOH + CaCO3 -> (CH3COO)2Ca + H2O + CO2.
    Final Answer: Observations: Fizzing/effervescence and the solid disappears. Salt: Calcium ethanoate. Balanced equation: 2CH3COOH + CaCO3 -> (CH3COO)2Ca + H2O + CO2.

    Question: Explain, in terms of ionisation, why a 0.1 mol/dm3 solution of ethanoic acid has a higher pH than a 0.1 mol/dm3 solution of hydrochloric acid.

    1. 1.Step 1: Compare the nature of both acids. Hydrochloric acid is a strong acid, whereas ethanoic acid is a weak acid.
    2. 2.Step 2: Describe their behaviour in water. Hydrochloric acid completely ionises in aqueous solution (HCl -> H+ + Cl-), while ethanoic acid only partially ionises (CH3COOH <=> CH3COO- + H+).
    3. 3.Step 3: Relate ionisation to hydrogen ion concentration. Because ethanoic acid only partially ionises, it has a lower concentration of H+ ions at equal molar concentrations.
    4. 4.Step 4: Connect H+ concentration to pH. A lower concentration of H+ ions corresponds to a higher pH value on the logarithmic scale.
    Final Answer: Ethanoic acid only partially ionises in water while hydrochloric acid completely ionises. At 0.1 mol/dm3, ethanoic acid produces a lower concentration of H+ ions, which results in a higher pH.
    Active Recall Memory Test
    What is the functional group of carboxylic acids?
    Key Fact: -COOH (carboxyl group)
    Why are carboxylic acids termed 'weak' acids?
    Key Fact: They only partially ionise in aqueous solution into H+ ions.
    What are the two products formed when ethanoic acid reacts with sodium carbonate?
    Key Fact: Sodium ethanoate, carbon dioxide, and water.
    What catalyst is required to form an ester from a carboxylic acid and an alcohol?
    Key Fact: An acid catalyst, typically concentrated sulfuric acid.
    Frequently Asked Questions
    What is the general formula for carboxylic acids?
    The general formula for carboxylic acids is CnH2n+1COOH (where n starts at 0 for methanoic acid). Alternatively, it can be written as CnH2nO2 where n represents the total number of carbon atoms in the molecule.
    Why does ethanoic acid fizz slower than hydrochloric acid when reacting with magnesium?
    Although both acids can react to produce hydrogen gas, ethanoic acid is a weak acid that only partially ionises in water. This means there is a lower concentration of hydrogen ions (H+) available in solution at any one time, leading to a lower frequency of successful collisions and a slower rate of reaction.
    Is vinegar just pure ethanoic acid?
    No, vinegar is an aqueous solution containing roughly 5-8% ethanoic acid by volume dissolved in water. Pure ethanoic acid is known as glacial ethanoic acid because it freezes into ice-like crystals just below room temperature (around 16.6 degrees Celsius).
    What is an ester and how is it related to carboxylic acids?
    An ester is an organic compound with the functional group -COO- formed by a condensation reaction between a carboxylic acid and an alcohol. Water is eliminated as a byproduct during this reaction. Esters typically have sweet, fruity aromas and are widely used in perfumes, flavourings, and industrial solvents.
    Do carboxylic acids turn blue litmus paper red?
    Yes, carboxylic acids turn blue litmus paper red because they release H+ ions in water, making the solution acidic with a pH typically between 3 and 5. Even though they are weak acids, they still generate enough hydronium ions to cause the standard acidic colour change.