Amino acids, amides and chirality — OCR A-Level Chemistry
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Amino acids, amides and chirality explained
Amino acids, amides and chirality covers 9 specification points, including Reactions of amino acids and (a) the general formula for an α-amino acid as….
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Reactions of amino acids
An amino acid carries both an amine group and a carboxylic acid group on the same molecule, so it shows the reactions of each functional group and some combined behaviour. The carboxylic acid group reacts with bases and carbonates to form salts, with alcohols in esterification, and with amines to form amides. The amine group behaves as a base, accepting a proton to form a salt with acids, and reacts with acyl chlorides to form amides. Because the two groups can react with each other, an amino acid exists mainly as a zwitterion, with a protonated ammonium group and a deprotonated carboxylate group. In acidic solution the carboxylate is protonated to give a cation; in alkaline solution the ammonium group is deprotonated to give an anion. A carbon bearing four different groups gives chirality, which matters for the α-carbon of most amino acids.
(a) the general formula for an α-amino acid as RCH(NH₂)COOH and the following reactions of amino acids:
An α-amino acid carries two functional groups on the same carbon, the α-carbon: an amine group (NH₂) and a carboxylic acid group (COOH), with a side chain R and one hydrogen also attached. Its general formula is written RCH(NH₂)COOH, which shows the α-carbon bonded to R, H, NH₂ and COOH. The R group varies between amino acids, so glycine has R = H while other amino acids carry different side chains. Because the α-carbon has four different groups when R is not H, the molecule is chiral and can exist as two optical isomers. Recognise the formula in displayed and condensed forms, and identify the amine and carboxylic acid groups so you can predict reactions such as salt formation with acids and alkalis, ester formation and condensation polymerisation to peptides.
(i) reaction of the carboxylic acid group with alkalis and in the formation of esters (see also 6.1.3 c)
The COOH group of an amino acid behaves like any carboxylic acid. With an alkali such as sodium hydroxide it is neutralised to give a carboxylate salt and water: RCH(NH₂)COOH + NaOH → RCH(NH₂)COONa + H₂O. The amine group may also react with acid, so an amino acid can form salts with both acids and alkalis depending on conditions. With an alcohol and an acid catalyst the carboxylic acid group undergoes esterification to give an ester and water, for example RCH(NH₂)COOH + R'OH ⇌ RCH(NH₂)COOR' + H₂O. Recognise the reagents, the products and the balanced equation, and note that the ester link forms between the carboxyl carbon and the alcohol oxygen.
(ii) reaction of the amine group with acids
Amino acids contain both a basic amine group (–NH₂) and an acidic carboxyl group (–COOH). The lone pair on the nitrogen of the amine group accepts a proton from an acid, so the amine behaves as a Brønsted–Lowry base and is protonated to form an ammonium-type cation, –NH₃⁺. With a strong mineral acid such as HCl, the –NH₂ group becomes –NH₃⁺ and a chloride salt forms; the carboxyl group is left unchanged by this reaction. The product is described as the hydrochloride of the amino acid, and the reaction is a simple acid–base neutralisation. Recognise that the amine group, not the carboxyl group, is the site of protonation, and that the resulting species carries a positive charge on nitrogen.
Amides
An amide contains a carbonyl group (C=O) directly bonded to a nitrogen atom, giving the functional group –CONH₂ in a primary amide. The lone pair on the amide nitrogen is delocalised into the carbonyl group, so an amide is much less basic than an amine and does not readily accept a proton in the same way. Amides are formed when a carboxylic acid derivative such as an acyl chloride or acid anhydride reacts with ammonia or an amine, and they can be hydrolysed by heating with aqueous acid or alkali to release the carboxylic acid (or its salt) and ammonia or an amine. Recognise the –CONH– linkage, distinguish it from an amine, and link the structure to its lower basicity and its hydrolysis products.
(b) structures of primary and secondary amides (see also 6.1.3 f, 6.2.3 a–b)
An amide contains a carbonyl group, C=O, bonded directly to a nitrogen atom, giving the functional group –CONH–. In a primary amide the nitrogen is bonded to the carbonyl carbon, to two hydrogen atoms and to one carbon-containing group, written RCONH₂. In a secondary amide the nitrogen is bonded to the carbonyl carbon, to one hydrogen atom and to two carbon-containing groups, written RCONHR′. When classifying, count every group bonded to the nitrogen: the carbonyl carbon counts as one of those groups because it is directly attached to nitrogen. So RCONH₂ is primary and RCONHR′ is secondary. The R and R′ groups may be alkyl or aryl.
Chirality
A chiral carbon is an sp³ carbon bonded to four different groups, so the molecule and its mirror image cannot be superimposed. In 2-hydroxypropanoic acid the central carbon carries –H, –CH₃, –OH and –COOH, four different groups, so it is chiral. In amino acids such as 2-aminopropanoic acid the alpha carbon carries –H, –NH₂, –CH₃ and –COOH, again four different groups. To test a candidate carbon, list all four substituents and check none repeats; a carbon with two identical groups, such as two hydrogens, is not chiral. Chiral molecules rotate plane-polarised light and exist as two enantiomers, but a 50:50 mixture is optically inactive.
(c) optical isomerism (an example of stereoisomerism, in terms of non-superimposable mirror images about a chiral centre) (see also 4.1.3 c–d)
Optical isomerism is one branch of stereoisomerism, the family of isomers that share the same structural formula but differ in the spatial arrangement of atoms. Two optical isomers, called enantiomers, are related as non-superimposable mirror images. The feature that produces them is a chiral centre: typically a carbon atom bonded to four different groups, so that reflection cannot be rotated onto the original. Take butan-2-ol, CH₃CH(OH)CH₂CH₃; the central carbon carries H, OH, CH₃ and C₂H₅, all different, so two enantiomers exist. Amino acids such as alanine show the same feature at the carbon bearing NH₂, COOH, H and CH₃. Enantiomers have identical physical properties except the direction they rotate plane-polarised light, and they differ in behaviour towards other chiral species.
(d) identification of chiral centres in a molecule of any organic compound.
To find a chiral centre, examine each carbon atom in turn and list the four groups attached to it. A chiral centre is a carbon bonded to four different groups; if any two groups match, that carbon is not chiral. Work through a molecule systematically: in 2-chlorobutane, CH₃CHClCH₂CH₃, the carbon bearing chlorine also carries H, CH₃ and C₂H₅, so it is chiral. In 2-chloropropane, CH₃CHClCH₃, the same carbon carries two identical CH₃ groups, so it is not chiral. Remember that carbon atoms in a C=C double bond or a C≡C triple bond cannot be chiral centres because they do not carry four separate groups. Apply the same test to any organic compound, including amino acids, alcohols and halogenoalkanes.
Your focus
- Describe the reactions of the amine and carboxylic acid groups in an amino acid.
- Explain the zwitterion structure and how the charge changes with pH.
- Identify chirality at the α-carbon of an amino acid.
Show all 29 objectives
- Write and interpret the general formula RCH(NH₂)COOH for an α-amino acid
- Identify the amine and carboxylic acid groups on the α-carbon
- Explain why an α-amino acid can be chiral when the R group differs from H
- Describe the reaction of the carboxylic acid group of an amino acid with an alkali
- Write a balanced equation for ester formation from an amino acid and an alcohol
- Identify the functional group changes in each reaction
- Identify the amine group as the basic site in an amino acid
- Describe the protonation of the amine group by an acid to form a salt
- Explain why the carboxyl group is not the group that reacts with the acid in this reaction
- Recognise and draw the amide functional group
- Explain why amides are much less basic than amines
- Describe the formation and hydrolysis of amides with correct products
- Draw the structures of primary and secondary amides
- Classify an amide as primary or secondary from its structure
- Explain how the groups bonded to nitrogen determine the classification
- Identify a chiral carbon by checking for four different groups
- Explain why a molecule with a chiral centre has non-superimposable mirror images
- Apply chirality to the alpha carbon of a named amino acid
- Define optical isomerism as a form of stereoisomerism.
- Describe enantiomers as non-superimposable mirror images.
- Identify the chiral centre that gives rise to a pair of optical isomers.
- Distinguish optical isomerism from structural isomerism.
- Locate chiral centres in a displayed formula of an organic compound.
- Explain why a given carbon is or is not a chiral centre.
- Apply the four-different-groups test to amino acids and other organic molecules.
- Recognise that carbon atoms in multiple bonds cannot be chiral centres.
Amino acids, amides and chirality exam tips
Marking Points
- States that the carboxylic acid group of an amino acid reacts with bases or carbonates to form a carboxylate salt.
- States that the amine group acts as a base and accepts a proton from an acid to form an ammonium salt.
- Explains that the amino acid exists as a zwitterion, with an ammonium group and a carboxylate group, and that the charge changes with pH.
- Identifies that reaction of the amine group with an acyl chloride, or of the acid group with an amine, forms an amide linkage.
- Recognises chirality at the α-carbon when it carries four different groups.
- Identifies the α-carbon as the carbon bearing both the NH₂ group and the COOH group in RCH(NH₂)COOH
- States that the R group is a variable side chain that differs between amino acids
- Recognises that an amino acid with four different groups on the α-carbon is chiral and has two optical isomers
- Distinguishes the amine group from the carboxylic acid group when predicting reactions of an amino acid
- States that the carboxylic acid group reacts with an alkali to form a carboxylate salt and water
- Writes a balanced equation for neutralisation of the COOH group by sodium hydroxide
- States that the carboxylic acid group reacts with an alcohol to form an ester and water
- Identifies the ester linkage formed between the carboxyl carbon and the alcohol oxygen
- Identifies the amine group as the basic site that accepts a proton from the acid
- Shows the amine group converted to a protonated ammonium-type group bearing a positive charge on nitrogen
- States that the carboxyl group is not the group protonated in this reaction
- Describes the product as a salt formed by acid–base neutralisation of the amine group
- Identifies the amide functional group as a carbonyl group bonded directly to a nitrogen atom
- Explains that delocalisation of the nitrogen lone pair into the carbonyl group makes an amide much less basic than an amine
- Describes the formation of an amide from a carboxylic acid derivative reacting with ammonia or an amine
- States that hydrolysis of an amide with aqueous acid or alkali gives a carboxylic acid or its salt together with ammonia or an amine
- Identifies the amide functional group as a carbonyl carbon bonded directly to nitrogen
- Draws a primary amide as RCONH₂ with two hydrogen atoms on the nitrogen
- Draws a secondary amide as RCONHR′ with one hydrogen atom on the nitrogen
- Counts the carbonyl carbon as one of the carbon-containing groups bonded to nitrogen when classifying the amide
- Distinguishes primary from secondary amides by the number of carbon-containing groups attached to nitrogen
- Identifies a chiral centre as an sp³ carbon bonded to four different groups
- Lists the four substituents on a candidate carbon and rejects it when two groups are identical
- Recognises the alpha carbon of 2-aminopropanoic acid as chiral because it carries –H, –NH₂, –CH₃ and –COOH
- Explains that a chiral molecule and its mirror image are non-superimposable enantiomers
- States that a racemic 50:50 mixture of enantiomers is optically inactive
- Identifies optical isomerism as a form of stereoisomerism in which isomers differ only in their spatial arrangement.
- States that enantiomers are non-superimposable mirror images of each other.
- Recognises that a chiral centre is usually a carbon atom bonded to four different groups.
- Explains that a molecule with one chiral centre exists as a pair of enantiomers.
- Distinguishes optical isomerism from structural isomerism, where the connectivity of atoms differs.
- Examines each carbon atom and lists the four groups attached to it.
- Identifies a chiral centre as a carbon bonded to four different groups.
- Rejects a candidate carbon when two or more attached groups are identical.
- Excludes carbon atoms in double or triple bonds from being chiral centres.
- Applies the test correctly to a named organic compound such as an amino acid or halogenoalkane.
Examiner Tips
- 💡Identify both functional groups in the structure before predicting a reaction product.
- 💡Link the charge on the amino acid to the pH, since acidic and alkaline conditions give different ions.
- 💡Check the α-carbon substituents when a question asks about optical activity.
- 💡Match the named reagent to the group it attacks, such as acyl chloride with the amine group.
- 💡Write the general formula exactly as RCH(NH₂)COOH and label the α-carbon clearly
- 💡Check each option in a multiple-choice question against the four groups attached to the α-carbon
- 💡Link the functional groups present to the reactions you are asked to predict
- 💡Balance the neutralisation equation and check the salt formula carefully
- 💡Show the ester functional group clearly and name the alcohol used
- 💡Recall that the COOH group is the reactive site in both reactions
- 💡Locate the lone pair on the amine nitrogen before deciding which group reacts with the acid
- 💡Write the protonated group explicitly as –NH₃⁺ with the charge on nitrogen
- 💡Check that the carboxyl group is shown unchanged so the answer stays focused on the amine group
- 💡Check that the nitrogen is bonded directly to the carbonyl carbon before calling a group an amide
- 💡Use delocalisation of the nitrogen lone pair to justify the low basicity of amides
- 💡Name both products of amide hydrolysis and state whether acid or alkali conditions are used
- 💡Draw the full displayed structure and mark the C–N bond before classifying
- 💡Count the carbon-containing groups attached to nitrogen, including the carbonyl carbon
- 💡Use the general forms RCONH₂ and RCONHR′ as quick checks
- 💡Remember that R and R′ can be alkyl or aryl groups
- 💡Write out the four groups on the carbon explicitly before deciding whether it is chiral
- 💡Look for repeated atoms or groups such as two hydrogens, which immediately rule out chirality
- 💡Link chirality to non-superimposable mirror images rather than to the presence of a double bond
- 💡Underline the phrase 'four different groups' whenever a question asks what makes a carbon chiral.
- 💡Sketch the two mirror-image forms and test mentally whether one can be rotated to lie exactly on the other.
- 💡Read each option in a multiple-choice item fully; distractors often swap 'superimposable' for 'non-superimposable'.
- 💡Link the answer back to the definition of stereoisomerism so the reasoning is complete.
- 💡Write out the four groups beside each candidate carbon before deciding.
- 💡Circle the chiral centre on the displayed formula so the examiner can see your choice.
- 💡Check for hidden symmetry, such as two methyl groups, that removes chirality.
- 💡In multiple-choice items, eliminate options that name a carbon with two identical substituents.
Common Mistakes
- Treats the amino acid as reacting at only one functional group; describe both the amine and carboxylic acid behaviour.
- Ignores the zwitterion form; explain that the predominant species depends on the pH of the solution.
- Assumes every amino acid is chiral; state that chirality requires four different groups on the α-carbon.
- Places the NH₂ and COOH groups on different carbon atoms; keep both attached to the same α-carbon
- Treats the R group as fixed for all amino acids; recognise that R varies and equals H in glycine
- Claims every amino acid is chiral; note that chirality requires four different groups on the α-carbon
- Omits water as a product of neutralisation; include H₂O alongside the carboxylate salt
- Forms the ester at the amine group; attach the alcohol-derived group to the carboxyl carbon
- Forgets that esterification is reversible and needs an acid catalyst; show the equilibrium and catalyst
- Protonates the carboxyl group instead of the amine group; correct this by protonating the nitrogen lone pair to give the –NH₃⁺ group
- Omits the positive charge on the protonated nitrogen; correct this by showing the ammonium-type cation with a 1⁺ charge on nitrogen
- Treats the reaction as producing water only with no salt; correct this by naming the ammonium-type salt formed with the acid's conjugate base
- Confuses an amide with an amine by placing the nitrogen away from the carbonyl carbon; correct this by bonding the nitrogen directly to the C=O carbon
- Assumes the amide nitrogen is strongly basic like an amine; correct this by explaining delocalisation of the lone pair into the carbonyl group
- Claims hydrolysis gives only one organic product; correct this by naming both the carboxylic acid or its salt and the ammonia or amine released
- Excludes the carbonyl carbon when counting groups on nitrogen; count it, because it is directly bonded to nitrogen
- Labels RCONHR′ as a primary amide; it is secondary because two carbon-containing groups are on nitrogen
- Labels RCONH₂ as a secondary amide; it is primary because only one carbon-containing group is on nitrogen
- Places the nitrogen away from the carbonyl carbon; the nitrogen must be bonded directly to the carbonyl carbon
- Treats any carbon in a chain as chiral; check that the specific carbon carries four different groups
- Accepts a carbon bearing two hydrogen atoms as chiral; reject it because two groups are identical
- Assumes a molecule with a chiral centre always rotates light in a sample; recognise that an equal mixture of enantiomers is optically inactive
- Confuses optical isomers with structural isomers; keep the same structural formula and vary only the 3-D arrangement.
- Treats any carbon with four single bonds as chiral; check that all four attached groups are genuinely different.
- Assumes a molecule with a chiral centre rotates light in a fixed direction; note that the two enantiomers rotate it in opposite directions.
- Describes enantiomers as superimposable; state clearly that they are non-superimposable mirror images.
- Counts a carbon with two identical alkyl groups as chiral; check that all four groups differ.
- Overlooks hydrogen as one of the four groups; include every atom or group shown.
- Selects a carbon in a C=C double bond; note that such a carbon carries only three groups.
- Stops after finding one candidate without checking the rest of the molecule; scan every carbon.