Carbonyl compounds — OCR A-Level Chemistry
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Carbonyl compounds explained
Carbonyl compounds covers 13 specification points, including Reactions of carbonyl compounds and (a) oxidation of aldehydes using Cr₂O₇²⁻/H⁺….
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Reactions of carbonyl compounds
Carbonyl compounds react in ways that depend on the C=O bond, which is polar because oxygen is more electronegative than carbon, leaving the carbon δ⁺ and oxygen δ⁻. Nucleophiles therefore attack the carbon. Aldehydes and ketones undergo nucleophilic addition: with HCN (in the presence of a trace of alkali) the product is a hydroxynitrile, and acid hydrolysis of that nitrile gives a hydroxycarboxylic acid. Reduction with NaBH₄ or LiAlH₄ in a suitable solvent converts aldehydes to primary alcohols and ketones to secondary alcohols. Aldehydes are readily oxidised: Fehling's solution changes from blue to a red precipitate of copper(I) oxide, and Tollens' reagent gives a silver mirror. Ketones resist these mild oxidations, which distinguishes them.
(a) oxidation of aldehydes using Cr₂O₇²⁻/H⁺ (i.e. K₂Cr₂O₇/H₂SO₄) to form carboxylic acids
Aldehydes are oxidised to carboxylic acids by acidified dichromate(VI), written Cr₂O₇²⁻/H⁺ and supplied practically as potassium dichromate(VI) in dilute sulfuric acid, K₂Cr₂O₇/H₂SO₄. The aldehyde's carbonyl carbon already carries a hydrogen, so the C–H bond is replaced by a C–O bond and the carbon is oxidised from +1 to +3. The dichromate ion is reduced, changing the solution from orange to green as chromium goes from +6 to +3. Heating under reflux with excess oxidising agent drives the reaction to completion. Ethanal, for example, gives ethanoic acid. Ketones lack the hydrogen on the carbonyl carbon and so are not oxidised in this way, which is why the test distinguishes the two families. Match the reagent, the structural change and the colour change when selecting an answer.
(b) nucleophilic addition reactions of carbonyl compounds with:
The C=O bond is polar, so the carbon carries a partial positive charge and is attacked by nucleophiles. In nucleophilic addition the nucleophile adds to the carbonyl carbon and the π bond opens, giving a tetrahedral intermediate that picks up a proton. With HCN, supplied as KCN acidified in situ, the product is a hydroxynitrile; acid hydrolysis of that nitrile then gives a hydroxycarboxylic acid. With hydride from NaBH₄, aldehydes are reduced to primary alcohols and ketones to secondary alcohols. The mechanism can be shown with curly arrows from the nucleophile to the δ⁺ carbon and from the C=O π bond to oxygen.
(i) NaBH₄ to form alcohols
Sodium tetrahydridoborate, NaBH₄, is a source of hydride ions, H⁻, which act as the nucleophile in addition to a carbonyl group. The reagent is used in aqueous or alcoholic solution, and the reaction is a reduction because the organic compound gains hydrogen. An aldehyde reacts with NaBH₄ to form a primary alcohol, for example ethanal gives ethanol. A ketone reacts to form a secondary alcohol, for example propanone gives propan-2-ol. The mechanism follows nucleophilic addition: H⁻ attacks the δ⁺ carbonyl carbon, the C=O π bond breaks to leave a negative oxygen, and protonation by water or acid gives the OH group. NaBH₄ does not reduce C=C bonds, so it is a selective reducing agent for the carbonyl group.
(ii) HCN [i.e. NaCN(aq)/H⁺(aq)], to form hydroxynitriles (see also 6.2.4 b)
Aldehydes and ketones react with hydrogen cyanide to give hydroxynitriles. Because HCN is a weak acid and hazardous as the pure gas or liquid, the reagent is supplied in practice as sodium cyanide solution followed by dilute acid: NaCN(aq) provides the cyanide ion CN⁻ nucleophile, and H⁺(aq) protonates the intermediate alkoxide. The carbonyl carbon is attacked by CN⁻, the C=O π bond breaks and the oxygen takes the electron pair, giving an alkoxide that is then protonated to an –OH group. The product therefore contains both a hydroxyl group and a nitrile group on the same carbon skeleton, which is why it is called a hydroxynitrile. For ethanal the product is CH₃CH(OH)CN, and for propanone it is (CH₃)₂C(OH)CN. The carbon chain is lengthened by one carbon, so this is a useful carbon–carbon bond-forming step.
(c) the mechanism for nucleophilic addition reactions of aldehydes and ketones with NaBH₄ and HCN
Both NaBH₄ and HCN deliver a nucleophile to the electrophilic carbonyl carbon, and both follow the same nucleophilic addition sequence. With NaBH₄ the hydride ion H⁻ attacks the carbonyl carbon; the C=O π bond breaks and the oxygen becomes an alkoxide, which is protonated (for example by water or acid) to give a primary alcohol from an aldehyde or a secondary alcohol from a ketone. With HCN supplied as NaCN(aq)/H⁺(aq), the cyanide ion CN⁻ attacks the carbonyl carbon, the π bond breaks to give an alkoxide, and H⁺ protonates the oxygen to give a hydroxynitrile. In each case the mechanism is drawn with a curly arrow from the nucleophile's lone pair to the carbonyl carbon and a second arrow from the C=O π bond onto the oxygen, followed by protonation of the alkoxide.
Characteristic tests for carbonyl compounds
Carbonyl compounds contain the C=O group, found in aldehydes (RCHO) and ketones (RCOR'). Characteristic tests distinguish them from other compounds and from each other. Adding 2,4-dinitrophenylhydrazine (Brady's reagent) gives a yellow-orange precipitate with both aldehydes and ketones, confirming a carbonyl group. Tollens' reagent (ammoniacal silver nitrate) is reduced by an aldehyde on warming to give a silver mirror, but not by a ketone. Fehling's solution, containing Cu²⁺ ions, is reduced by an aldehyde on heating to give a brick-red precipitate of copper(I) oxide, Cu₂O; a ketone gives no change. Acidified potassium dichromate(VI), K₂Cr₂O₇/H⁺, turns from orange to green with an aldehyde but not with a ketone. These tests rely on the aldehyde being readily oxidised to a carboxylic acid while the ketone is not.
(d) use of 2,4-dinitrophenylhydrazine to:
2,4-Dinitrophenylhydrazine (Brady's reagent) reacts with the carbonyl group of aldehydes and ketones to form a yellow-orange crystalline precipitate called a 2,4-dinitrophenylhydrazone. This confirms the presence of a carbonyl compound. The precipitate can be filtered off, purified by recrystallisation and its melting point measured; comparing this melting point with known data identifies the specific aldehyde or ketone. The test does not distinguish an aldehyde from a ketone, because both react. The reagent is used in solution with methanol and sulfuric acid. The reaction is a condensation, releasing water as the C=O group is converted to C=N-NH-Ar.
(i) detect the presence of a carbonyl group in an organic compound
A carbonyl group (C=O) is detected chemically by 2,4-dinitrophenylhydrazine (2,4-DNPH), which condenses with aldehydes and ketones to give an orange or yellow-orange crystalline precipitate of a 2,4-dinitrophenylhydrazone. The test confirms a carbonyl is present but does not by itself distinguish aldehyde from ketone. To distinguish, use Tollens' reagent (ammoniacal silver nitrate), where an aldehyde gives a silver mirror while a ketone does not, or Fehling's solution, where an aldehyde gives a brick-red precipitate of copper(I) oxide and a ketone does not. A carboxylic acid gives no such precipitate with 2,4-DNPH. In an MCQ, select the reagent and observation that together show a carbonyl group is present, and reject options that describe only a colour change in solution without a precipitate or that claim the test alone separates aldehyde from ketone.
(ii) identify a carbonyl compound from the melting point of the derivative
A carbonyl compound is identified by converting it to a solid derivative, usually the 2,4-dinitrophenylhydrazone, then measuring the melting point of the purified solid and comparing it with published values. Each pure derivative has a sharp, characteristic melting point, so a measured value that matches a literature value within a narrow range identifies the original carbonyl compound. The solid is recrystallised to remove impurities, because impurities lower and broaden the melting range. A measured melting point close to a known value but a few degrees low, with a wide range, suggests impurity rather than a different compound. In an MCQ, choose the option that pairs a measured melting point with the matching literature value for the derivative, and reject options that compare the melting point of the original liquid carbonyl or that ignore purification.
(e) use of Tollens’ reagent (ammoniacal silver nitrate) to:
Tollens’ reagent is ammoniacal silver nitrate: silver nitrate solution treated with ammonia until the grey-brown silver oxide just redissolves, leaving the colourless complex ion [Ag(NH₃)₂]⁺ in alkaline solution. It is a mild oxidising agent that tests for an aldehyde group. Warm the unknown with freshly prepared Tollens’ reagent in a clean test tube; an aldehyde reduces the silver complex, and silver metal deposits as a mirror on the glass or as a grey precipitate. A ketone gives no change. The reagent must be made fresh because it decomposes on standing, and the tube should be clean so the mirror is visible. This row covers the reagent and its use; the positive observation is developed in the linked detect-the-aldehyde row.
(i) detect the presence of an aldehyde group
Aldehydes are carbonyl compounds in which the C=O carbon carries at least one hydrogen, giving the group –CHO. Two standard wet tests distinguish them from ketones. Fehling's solution (blue, containing Cu²⁺ complexes in alkaline tartrate) is warmed with the unknown; an aldehyde reduces Cu²⁺ to a brick-red precipitate of copper(I) oxide, Cu₂O, while a ketone leaves the blue colour unchanged. Tollens' reagent (colourless ammoniacal silver nitrate, [Ag(NH₃)₂]⁺) is warmed gently; an aldehyde reduces Ag⁺ to a silver mirror of metallic silver, whereas a ketone gives no change. Both tests work because the aldehyde is readily oxidised to the carboxylate, so the aldehyde acts as the reducing agent and is itself oxidised. A positive result therefore confirms an aldehyde group is present; a negative result with both reagents indicates no aldehyde group, consistent with a ketone.
(ii) distinguish between aldehydes and ketones, explained in terms of the oxidation of aldehydes to carboxylic acids with reduction of silver ions to silver.
Aldehydes and ketones both contain the carbonyl group, C=O, but only the aldehyde has a hydrogen atom attached to the carbonyl carbon. That hydrogen allows the aldehyde to be oxidised to a carboxylic acid, while the ketone, with two carbon groups on the carbonyl carbon, resists this oxidation under the same mild conditions. Tollens' reagent supplies silver ions in an alkaline ammonia solution; when warmed with an aldehyde, the aldehyde is oxidised to the carboxylate/carboxylic acid and the silver ions are reduced to silver metal, giving a silver mirror. A ketone gives no such change. So the test distinguishes them by whether reduction of Ag⁺ to Ag occurs, which happens only when the aldehyde is oxidised.
Your focus
- Explain why the carbonyl carbon is attacked by nucleophiles
- Describe the products of HCN addition and subsequent acid hydrolysis
- Describe the reduction products of aldehydes and ketones with NaBH₄
Show all 42 objectives
- Describe the observations for Fehling's and Tollens' tests with aldehydes
- State the reagent and conditions for oxidising an aldehyde to a carboxylic acid
- Describe the colour change observed during the oxidation
- Explain the structural change at the carbonyl carbon in terms of oxidation state
- Apply the reaction to a named aldehyde to predict the carboxylic acid formed
- Explain the polarity of the carbonyl group and its effect on reactivity
- Describe the mechanism of nucleophilic addition with HCN
- Predict the alcohol formed when an aldehyde or ketone is reduced
- Draw curly arrows correctly for nucleophilic addition
- Predict the alcohol formed when an aldehyde or ketone is reduced by NaBH₄
- Explain the role of the hydride ion in the reduction
- Justify why NaBH₄ leaves a carbon-carbon double bond unchanged
- Identify the nucleophile and the protonation step when NaCN(aq) and H⁺(aq) react with an aldehyde or ketone
- Draw the structure of the hydroxynitrile formed from a given aldehyde or ketone
- Explain why the product is described as a hydroxynitrile and how the carbon chain is lengthened
- Draw the nucleophilic addition mechanism for an aldehyde or ketone reacting with NaBH₄
- Draw the nucleophilic addition mechanism for an aldehyde or ketone reacting with HCN
- Compare the nucleophile and product for the two reagents
- Describe the positive result of 2,4-dinitrophenylhydrazine with a carbonyl compound
- Distinguish an aldehyde from a ketone using Tollens' reagent and Fehling's solution
- Explain why aldehydes but not ketones are oxidised by these reagents
- Describe the reaction of 2,4-dinitrophenylhydrazine with aldehydes and ketones
- Explain how the resulting precipitate is used to identify a carbonyl compound by melting point
- State the limitation that the test does not distinguish aldehydes from ketones
- Name 2,4-DNPH as the reagent that detects a carbonyl group and describe its positive result.
- Explain why the 2,4-DNPH test does not distinguish an aldehyde from a ketone.
- Select the correct reagent and observation from a set of options to confirm a carbonyl group.
- Describe how a carbonyl compound is converted to a solid derivative for melting point determination.
- Explain how a measured melting point is compared with literature values to identify a carbonyl compound.
- Explain why purification is needed before a reliable melting point is obtained.
- Describe how Tollens’ reagent is prepared from silver nitrate and ammonia
- Explain why Tollens’ reagent oxidises an aldehyde but not a ketone
- Predict the observation when an aldehyde is warmed with Tollens’ reagent
- Describe the observations when Fehling's solution and Tollens' reagent are warmed with an aldehyde.
- Explain the redox changes that produce copper(I) oxide and metallic silver.
- Use test results to distinguish an aldehyde from a ketone.
- Explain why aldehydes but not ketones are oxidised to carboxylic acids.
- Describe the reduction of silver ions to silver as the basis of the Tollens' test.
- Select the correct observation that distinguishes an aldehyde from a ketone.
Carbonyl compounds exam tips
Marking Points
- Identifies the C=O bond as polar with a δ⁺ carbon that attracts nucleophiles
- States that HCN addition to an aldehyde or ketone forms a hydroxynitrile
- States that acid hydrolysis of the hydroxynitrile forms a hydroxycarboxylic acid
- States that NaBH₄ reduces an aldehyde to a primary alcohol and a ketone to a secondary alcohol
- States that Fehling's solution changes from blue to a red precipitate with an aldehyde
- States that Tollens' reagent gives a silver mirror with an aldehyde but not with a ketone
- States that acidified dichromate(VI) oxidises an aldehyde to a carboxylic acid
- Identifies Cr₂O₇²⁻/H⁺ as equivalent to K₂Cr₂O₇/H₂SO₄ in this oxidation
- Describes the colour change from orange to green as dichromate(VI) is reduced to chromium(III)
- Explains that the aldehyde's carbonyl hydrogen is replaced, oxidising the carbon to the carboxylic acid oxidation state
- Applies the reaction to a named example such as ethanal forming ethanoic acid
- Identifies the carbonyl carbon as δ⁺ and therefore susceptible to nucleophilic attack
- Describes addition of HCN to a carbonyl compound to form a hydroxynitrile
- States that acid hydrolysis of the hydroxynitrile gives a hydroxycarboxylic acid
- Describes reduction of an aldehyde by hydride to a primary alcohol
- Describes reduction of a ketone by hydride to a secondary alcohol
- Uses curly arrows from the nucleophile to the carbonyl carbon and from the π bond to oxygen
- States that NaBH₄ supplies hydride ions, H⁻, which act as the nucleophile
- Predicts a primary alcohol from an aldehyde and a secondary alcohol from a ketone
- Describes the reduction as addition of hydrogen across the C=O bond
- Explains that NaBH₄ reduces the carbonyl group but leaves a C=C bond unchanged
- Identifies CN⁻ from NaCN(aq) as the nucleophile that attacks the electrophilic carbonyl carbon
- States that H⁺(aq) is added to protonate the alkoxide intermediate and form the –OH group
- Names the product class as a hydroxynitrile containing both –OH and –C≡N groups
- Explains that the carbon chain is extended by one carbon because the cyanide carbon becomes part of the skeleton
- Recognises that the C=O π bond breaks and the oxygen retains the electron pair as an alkoxide ion
- Shows a curly arrow from the lone pair on the nucleophile (H⁻ or CN⁻) to the electrophilic carbonyl carbon
- Shows a curly arrow from the C=O π bond onto the oxygen to form the alkoxide intermediate
- States that the alkoxide is protonated to give the final alcohol or hydroxynitrile product
- Distinguishes the nucleophile delivered by NaBH₄ (H⁻) from that delivered by HCN (CN⁻)
- Identifies the reduction product as a primary or secondary alcohol and the HCN product as a hydroxynitrile
- Identifies that 2,4-dinitrophenylhydrazine gives a yellow-orange precipitate with both aldehydes and ketones, confirming a carbonyl group
- States that Tollens' reagent gives a silver mirror with an aldehyde on warming but no change with a ketone
- States that Fehling's solution gives a brick-red precipitate of copper(I) oxide with an aldehyde on heating but no change with a ketone
- States that acidified potassium dichromate(VI) changes from orange to green with an aldehyde but not with a ketone
- Explains that the tests distinguish aldehydes from ketones because aldehydes are readily oxidised while ketones are not
- States that 2,4-dinitrophenylhydrazine forms a yellow-orange precipitate with a carbonyl compound, confirming the carbonyl group
- Names the product as a 2,4-dinitrophenylhydrazone
- Explains that the precipitate is filtered, purified by recrystallisation and its melting point compared with known values to identify the compound
- Recognises that the test does not distinguish an aldehyde from a ketone because both react
- Describes the reaction as a condensation in which the C=O group is converted to a C=N group with loss of water
- Selects 2,4-dinitrophenylhydrazine as the reagent that detects a carbonyl group.
- States that a carbonyl compound gives an orange or yellow-orange crystalline precipitate with 2,4-DNPH.
- Recognises that the 2,4-DNPH test confirms a carbonyl group but does not distinguish an aldehyde from a ketone.
- Identifies Tollens' reagent or Fehling's solution as the follow-up test that separates an aldehyde from a ketone.
- Rejects an option that treats a simple colour change in solution as proof of a carbonyl group.
- Converts the carbonyl compound to a solid derivative, typically the 2,4-dinitrophenylhydrazone, before measuring a melting point.
- Purifies the derivative, for example by recrystallisation, so the melting point is sharp and reliable.
- Compares the measured melting point with published values for derivatives of candidate carbonyl compounds.
- Matches the measured value to the literature value within a narrow range to identify the original compound.
- Explains that an impure sample gives a lower and broader melting range than the pure derivative.
- Identifies Tollens’ reagent as ammoniacal silver nitrate, formed by adding ammonia to silver nitrate solution until the precipitate just redissolves
- States that Tollens’ reagent acts as a mild oxidising agent that is reduced by an aldehyde
- Describes warming the sample with freshly prepared Tollens’ reagent in a clean test tube
- Recalls that a positive result is a silver mirror or grey precipitate of silver metal
- Distinguishes the outcome for an aldehyde, which gives the silver deposit, from a ketone, which gives no change
- Identifies Fehling's solution warmed with the sample as a test giving a brick-red precipitate of copper(I) oxide, Cu₂O, with an aldehyde.
- States that Tollens' reagent warmed with an aldehyde produces a silver mirror of metallic silver.
- Explains that the aldehyde is oxidised to the carboxylate while Cu²⁺ is reduced to Cu⁺ or Ag⁺ is reduced to Ag.
- Recognises that a ketone gives no colour change with Fehling's solution and no silver mirror with Tollens' reagent.
- Selects the observation that confirms an aldehyde group rather than merely a carbonyl group.
- States that both aldehydes and ketones contain the C=O carbonyl group but only aldehydes have a hydrogen on the carbonyl carbon.
- Explains that the aldehyde is oxidised to a carboxylic acid while silver ions are reduced to silver metal.
- Identifies the silver mirror or grey precipitate of silver as the positive result for an aldehyde with Tollens' reagent.
- States that a ketone gives no reaction with Tollens' reagent because it cannot be oxidised in this way.
- Links the distinction to the redox change: aldehyde oxidised, Ag⁺ reduced to Ag.
Examiner Tips
- 💡Read the stem carefully to check whether the question asks about addition, reduction or oxidation before choosing an option
- 💡Link each reagent to its visible observation, such as blue to red precipitate for Fehling's and a silver mirror for Tollens'
- 💡Distinguish aldehydes from ketones by their behaviour with mild oxidising agents rather than by molecular formula alone
- 💡Write the reagent as Cr₂O₇²⁻/H⁺ and note its practical form K₂Cr₂O₇/H₂SO₄ so either version is recognised
- 💡Pair the structural change with the orange-to-green colour change to rule out distractors
- 💡Check the oxidation state of the carbonyl carbon before and after to confirm a genuine oxidation
- 💡Remember that only aldehydes, not ketones, are oxidised here, which is the basis of the distinguishing test
- 💡Check which nucleophile the question names, HCN or hydride, before predicting the product
- 💡Show curly arrows starting at a lone pair or bond and ending at an atom or bond, never at a charge label
- 💡Confirm whether the question asks for the addition product or a later hydrolysis product before selecting an answer
- 💡Write the product structure fully, showing the new O–H bond and the hydrogen on the carbon
- 💡Use the words primary, secondary or tertiary accurately when naming the alcohol formed
- 💡State the conditions as NaBH₄ in water or ethanol rather than inventing a temperature
- 💡Write the reagent as NaCN followed by dilute acid, and state that this supplies HCN in a safe, controlled way
- 💡Show the curly arrow from the lone pair on CN⁻ to the carbonyl carbon and a second arrow from the C=O π bond to the oxygen
- 💡Check the product formula by counting carbons: the cyanide carbon adds one carbon to the chain
- 💡Draw the full mechanism with the dipole on C=O shown, so the electrophilic carbon is clearly identified
- 💡Label the intermediate as an alkoxide ion and show the proton source for the second step
- 💡State the product type explicitly: alcohol for NaBH₄, hydroxynitrile for HCN
- 💡Link each reagent to its specific observable change, such as silver mirror, brick-red precipitate or orange-to-green colour change
- 💡Separate the two purposes: Brady's reagent confirms a carbonyl group, while Tollens' and Fehling's distinguish aldehyde from ketone
- 💡Name the copper(I) oxide precipitate explicitly rather than saying only 'red precipitate'
- 💡Check the oxidation state notation, writing Cu²⁺ and Cr₂O₇²⁻ with correct superscript charges
- 💡State the colour of the precipitate precisely as yellow-orange
- 💡Explain the full identification sequence: filter, recrystallise, measure melting point, compare with known values
- 💡Note explicitly that the test confirms a carbonyl group but does not separate aldehyde from ketone
- 💡Use the term 2,4-dinitrophenylhydrazone for the product
- 💡Read the stem for the word detect, then choose the reagent that confirms a carbonyl group is present rather than the one that identifies which carbonyl.
- 💡Match the observation to the reagent: 2,4-DNPH gives an orange or yellow-orange precipitate, Tollens' gives a silver mirror and Fehling's gives a brick-red precipitate.
- 💡Eliminate options that describe a test for a different functional group, such as bromine water for C=C.
- 💡Check that the option measures the melting point of the solid derivative, not of the starting carbonyl compound.
- 💡Look for the step that purifies the derivative before the melting point is taken.
- 💡Choose the option that compares the measured value with a published value for the same derivative.
- 💡Name the reagent in full as ammoniacal silver nitrate and give its formula as the diamminesilver(I) complex ion
- 💡Link the observation to reduction of silver(I) to silver metal, so the chemistry explains the mirror
- 💡Contrast aldehyde and ketone results in one sentence to show the test is a distinguishing test
- 💡State that the mixture is warmed and that the reagent is prepared fresh
- 💡Name the reagent, the condition (warmed) and the exact observation for each test.
- 💡Link each positive result to the redox change: aldehyde oxidised, Cu²⁺ or Ag⁺ reduced.
- 💡Use a negative result with both reagents to argue the compound is a ketone rather than an aldehyde.
- 💡Name the reagent and the observation, then give the redox explanation, because the question asks for the explanation in terms of oxidation and reduction.
- 💡Use the phrase 'silver mirror' or 'silver precipitate' as the observable for an aldehyde.
- 💡Check the oxidation states: silver goes from +1 in Ag⁺ to 0 in Ag, which is reduction.
Common Mistakes
- Claims that HCN addition followed by acid hydrolysis gives a hydroxynitrile; correct this to say the addition gives the hydroxynitrile and hydrolysis gives the hydroxycarboxylic acid
- Claims that NaBH₄ oxidises an aldehyde to a primary alcohol; correct this to say reduction gives the primary alcohol
- Claims that Fehling's solution turns from blue to a red precipitate with a ketone; correct this to say the red precipitate forms with an aldehyde
- Claims that Tollens' reagent gives a silver mirror with a ketone; correct this to say the silver mirror forms with an aldehyde
- Writes the product of aldehyde oxidation as a primary alcohol; correct this by stating the product is a carboxylic acid
- States that the dichromate solution changes from green to orange; correct this by stating it changes from orange to green as the dichromate(VI) is reduced
- Uses the reagent without acid; correct this by including the H⁺ from sulfuric acid, since the oxidation needs acidic conditions
- Claims a ketone is oxidised to a carboxylic acid by this reagent; correct this by stating that ketones are not oxidised under these conditions
- States that aldehydes are oxidised to primary alcohols by hydride reagents; correct this to say aldehydes are reduced to primary alcohols
- States that HCN addition alone gives a hydroxycarboxylic acid; correct this to say addition gives the hydroxynitrile and hydrolysis gives the acid
- Draws the curly arrow from the nucleophile to the oxygen atom; correct this to show attack at the δ⁺ carbon
- Omits the protonation step after nucleophilic attack; correct this by showing the intermediate gaining a proton
- Predicts a tertiary alcohol from a ketone; correct this by stating that a ketone gives a secondary alcohol
- Claims NaBH₄ also reduces an alkene C=C bond; correct this by noting the reagent is selective for the carbonyl group
- Names the hydride ion as H⁺; correct this by writing H⁻ as the nucleophile
- Treats HCN itself as the attacking nucleophile rather than the cyanide ion CN⁻; correct this by naming CN⁻ as the nucleophile
- Omits the acid protonation step and leaves an alkoxide; correct this by adding H⁺(aq) to convert the alkoxide into the –OH group
- Writes the product without the nitrile group or mislabels it as an alcohol only; correct this by naming the product a hydroxynitrile with both functional groups
- Draws the nucleophile attacking the oxygen rather than the carbonyl carbon; correct this by directing the arrow to the carbon
- Leaves the intermediate as an alkoxide without protonation; correct this by adding the protonation step to form the –OH group
- Uses the same nucleophile for both reagents; correct this by naming H⁻ for NaBH₄ and CN⁻ for HCN
- Claims that 2,4-dinitrophenylhydrazine distinguishes an aldehyde from a ketone; note that it reacts with both, so it only confirms a carbonyl group
- States that Fehling's solution gives a silver mirror; correct this to a brick-red precipitate of copper(I) oxide, and reserve the silver mirror for Tollens' reagent
- Writes that a ketone gives a positive Tollens' or Fehling's result; correct this because ketones are not readily oxidised by these reagents
- Describes the dichromate(VI) colour change as green to orange; correct this to orange to green as the Cr₂O₇²⁻ ion is reduced
- Claims that 2,4-dinitrophenylhydrazine distinguishes an aldehyde from a ketone; correct this because both react to give a precipitate
- States that the precipitate is used directly without purification; correct this by including filtration and recrystallisation before melting point measurement
- Describes the product colour as simply red; correct this to yellow-orange
- Omits the role of melting point comparison; correct this by stating that the measured melting point is compared with known data to identify the compound
- Claims that 2,4-DNPH alone distinguishes an aldehyde from a ketone; add a Tollens' or Fehling's test to separate them.
- Accepts a colour change in solution as the positive result; require the orange or yellow-orange crystalline precipitate.
- Uses bromine water as the carbonyl test; reserve it for testing unsaturation in alkenes.
- Assumes a carboxylic acid gives a 2,4-DNPH precipitate; note that it does not.
- Compares the melting point of the original carbonyl compound rather than its solid derivative; measure the derivative instead.
- Ignores purification and accepts a broad, low melting range as identification; recrystallise the derivative first.
- Treats any melting point as a match without comparing to a literature value; match the measured value to published data.
- Assumes a single melting point measurement identifies the compound without a reference value; always compare with known values.
- Confuses Tollens’ reagent with Fehling’s solution; keep Tollens’ as ammoniacal silver nitrate giving a silver mirror
- Uses acidified silver nitrate as if it were Tollens’ reagent; add ammonia until the silver oxide just redissolves to form the complex
- Expects a ketone to give a silver mirror; state that ketones give no change with Tollens’ reagent
- Omits the need for a clean tube and fresh reagent; explain that dirt or aged reagent spoils the visible mirror
- Confuses the two reagents; keep Fehling's for the brick-red copper(I) oxide precipitate and Tollens' for the silver mirror.
- Claims a ketone also gives a positive Fehling's result; state that ketones are not oxidised this way and leave the blue colour unchanged.
- Describes the Fehling's precipitate as copper metal; name it as copper(I) oxide, Cu₂O, which is brick-red.
- Treats a positive test as proof of a specific aldehyde identity; state that the test detects the aldehyde group, not which aldehyde it is.
- Claims that ketones are oxidised to carboxylic acids by Tollens' reagent; state that ketones resist this oxidation and give no silver mirror.
- Describes the silver mirror as reduction of the aldehyde; state that the aldehyde is oxidised and the silver ions are reduced.
- Says both aldehydes and ketones give a silver mirror; state that only the aldehyde does.
- Writes the silver ion charge with a postfix sign; write Ag⁺ with a superscript plus.